I'm building a search app which uses Ajax to retrieve results, but I'm having a bit of trouble in how exactly to implement this.
I have the following code in Javascript:
if (typeof tmpVariable == "object"){
// tmpVariable is based on the query, it's an associative array
// ie: tmpVariable["apple"] = "something" or tmpVariable["orange"] = "something else"
var sendVariables = {};
sendVariables = JSON.stringify(tmpVariable);
fetchData(sendVariables);
}
function fetchData(arg) {
$.ajaxSetup ({
cache: false
});
$.ajax ({
type: "GET",
url: "script.php",
data: arg,
});
}
And within script.php:
<?php
$data = json_decode(stripslashes($_GET['data']));
foreach($data as $d){
echo $d;
}
?>
What is it that I'm doing wrong?
Thanks.
Your PHP script is expecting a GET var called 'data'. With your code you're not sending that.
Try this:
if (typeof tmpVariable == "object"){
var data = {data : JSON.stringify(tmpVariable)}; // Added 'data' as object key
fetchData(data);
}
function fetchData(arg) {
$.ajax ({
type: "GET",
url: "script.php",
data: arg,
success: function(response){
alert(response);
$("body").html(response); // Write the response into the HTML body tag
}
});
}
Related
I.m want to pass the values from js to php that is stored in local storage
js
let cartItems = localStorage.getItem("productsInCart");
var jsonString = JSON.stringify(cartItems);
$.ajax({
url:"read.php",
method: "post",
data: {data : jsonString},
success: function(res){
console.log(res);
}
})
php
<?php
print_r($_POST)
?>
on .php im getting just "array ()"
using #reyno's method with all the code in the same file called 'store_user_order.php'
<?php
if(isset($_POST["data"])) {
print_r($_POST["data"]);
} else {
?>
<button>SEND</button><br/>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.2.3/jquery.min.js"> </script>
<script>
const cartItems = localStorage.getItem("productsInCart");
const jsonString = JSON.stringify(cartItems);
$("button").click(function() {
$.ajax({
url: 'store_user_order.php',
method: 'post',
data: {
data: jsonString
},
success: function(res) {
$('body').append(res);
},
error: function(err) {
$('body').append(err);
}
});
})
</script>
<?php } ?>
This should work if you have items in the localstorage
While testing, for checking values use method: "get", make sure that your test values aren't huge - you will see submitted values in the address bar.
For testing (php + MySQL) I always use this method:
success ? changes() : errors_list();`
I don't use js, so deal with syntax yourself, please.
on .php im getting just "array ()"
You received an empty $ _POST array - nothing was sent.
Because there was nothing to send, or there was an error sending
I need help for my code as i have been browsing the internet looking for the answer for my problem but still can get the answer that can solve my problem. I am kind of new using AJAX. I want to display data from json_encode in php file to my AJAX so that the AJAX can pass it to the textbox in the HTML.
My problem is Json_encode in php file have data from the query in json format but when i pass it to ajax success, function(users) is empty. Console.log also empty array. I have tried use JSON.parse but still i got something wrong in my code as the users itself is empty. Please any help would be much appreciated. Thank you.
car_detail.js
$(document).ready(function() {
function $_GET(q,s) {
s = (s) ? s : window.location.search;
var re = new RegExp('&'+q+'=([^&]*)','i');
return (s=s.replace(/^\?/,'&').match(re)) ?s=s[1] :s='';
}
var car_rent_id1 = $_GET('car_rent_id');
car_rent_id.value = car_rent_id1;
$.ajax({
type: 'POST',
url: "http://localhost/ProjekCordova/mobile_Rentacar/www/php/car_detail.php",
dataType: "json",
cache: false,
data: { car_rent_id: this.car_rent_id1 },
success: function(users) {
console.log(users);
$('#car_name').val(users.car_name);
}
});
});
car_detail.php
$car_rent_id = $_GET['car_rent_id'];
$query = mysql_query("SELECT c.car_name, c.car_type, c.car_colour,
c.plate_no, c.rate_car_hour, c.rate_car_day, c.car_status,
r.pickup_location
FROM car_rent c
JOIN rental r ON c.car_rent_id=r.car_rent_id
WHERE c.car_rent_id = $car_rent_id");
$users = array();
while($r = mysql_fetch_array($query)){
$user = array(
"car_name" => $r['car_name'],
"car_type" => $r['car_type'],
"car_colour" => $r['car_colour'],
"plate_no" => $r['plate_no'],
"rate_car_hour" => $r['rate_car_hour'],
"rate_car_day" => $r['rate_car_day'],
"car_status" => $r['car_status'],
"pickup_location" => $r['pickup_location']
);
$users[] = $user;
// print_r($r);die;
}
print_r(json_encode($users)); //[{"car_name":"Saga","car_type":"Proton","car_colour":"Merah","plate_no":"WA2920C","rate_car_hour":"8","rate_car_day":"0","car_status":"","pickup_location":""}]
car_detail.html
<label>ID:</label>
<input type="text" name="car_rent_id" id="car_rent_id"><br>
<label>Car Name:</label>
<div class = "input-group input-group-sm">
<span class = "input-group-addon" id="sizing-addon3"></span>
<input type = "text" name="car_name" id="car_name" class = "form-control" placeholder = "Car Name" aria-describedby = "sizing-addon3">
</div></br>
<label>Car Type:</label>
<div class = "input-group input-group-sm">
<span class = "input-group-addon" id="sizing-addon3"></span>
<input type = "text" name="car_type" id="car_type" class = "form-control" placeholder = "Car Type" aria-describedby = "sizing-addon3">
</div></br>
Remove this in this.car_rent_id1 and cache: false this works with HEAD and GET, in your AJAX you are using POST but in your PHP you use $_GET. And car_rent_id is not defined, your function $_GET(q,s) requires two parameters and only one is passed.
$(document).ready(function() {
function $_GET(q,s) {
s = (s) ? s : window.location.search;
var re = new RegExp('&'+q+'=([^&]*)','i');
return (s=s.replace(/^\?/,'&').match(re)) ?s=s[1] :s='';
}
var car_rent_id1 = $_GET('car_rent_id'); // missing parameter
car_rent_id.value = car_rent_id1; // where was this declared?
$.ajax({
type: 'POST',
url: "http://localhost/ProjekCordova/mobile_Rentacar/www/php/car_detail.php",
dataType: "json",
data: { car_rent_id: car_rent_id1 },
success: function(users) {
console.log(users);
$('#car_name').val(users.car_name);
}
});
});
You can also use $.post(), post is just a shorthand for $.ajax()
$(document).ready(function() {
function $_GET(q,s) {
s = (s) ? s : window.location.search;
var re = new RegExp('&'+q+'=([^&]*)','i');
return (s=s.replace(/^\?/,'&').match(re)) ?s=s[1] :s='';
}
var car_rent_id1 = $_GET('car_rent_id');
car_rent_id.value = car_rent_id1;
$.post('http://localhost/ProjekCordova/mobile_Rentacar/www/php/car_detail.php', { car_rent_id: car_rent_id1 }, function (users) {
console.log(users);
$('#car_name').val(users.car_name);
});
});
and in your PHP change
$car_rent_id = $_GET['car_rent_id'];
to
$car_rent_id = $_POST['car_rent_id'];
Here is a code skeleton using .done/.fail/.always
<script
src="https://code.jquery.com/jquery-1.12.4.min.js"
integrity="sha256-ZosEbRLbNQzLpnKIkEdrPv7lOy9C27hHQ+Xp8a4MxAQ="
crossorigin="anonymous"></script>
<script>
$(function(){
$.ajax({
url: 'theurl',
dataType: 'json',
cache: false
}).done(function(data){
console.log(data);
}).fail(function(data){
console.log(data);
}).always(function(data){
console.log(data);
});
});
</script>
I've adapted your code, so you can see the error, replace the ajax call with this one
<script>
$.ajax({
url: "theurl",
dataType: "json",
data: { car_rent_id: car_rent_id1 },
success: function(users) {
console.log(users);
$('#car_name').val(users.car_name);
},
error: function(data) {
console.log(data);
alert("I failed, even though the server is giving a 200 response header, I can't read your json.");
}
});
</script>
A couple of recommendations on this, I would follow jQuery API to try an see where the request is failing http://api.jquery.com/jquery.ajax/. Also, I would access the ids for the input fileds with jQuery. e.g.: $("#theID").val().
I'm trying to grasp more than I should at once.
Let's say I have 2 inputs and a button, and on button click I want to create a json containing the data from those inputs and send it to the server.
I think this should do it, but I might be wrong as I've seen a lot of different (poorly explained) methods of doing something similar.
var Item = function(First, Second) {
return {
FirstPart : First.val(),
SecondPart : Second.val(),
};
};
$(document).ready(function(){
$("#send_item").click(function() {
var form = $("#add_item");
if (form) {
item = Item($("#first"), $("#second"));
$.ajax ({
type: "POST",
url: "post.php",
data: { 'test' : item },
success: function(result) {
console.log(result);
}
});
}
});
});
In PHP I have
class ClientData
{
public $First;
public $Second;
public function __construct($F, $S)
{
$this->First = F;
$this->Second = S;
}
}
if (isset($_POST['test']))
{
// do stuff, get an object of type ClientData
}
The problem is that $_POST['test'] appears to be an array (if I pass it to json_decode I get an error that says it is an array and if I iterate it using foreach I get the values that I expect to see).
Is that ajax call correct? Is there something else I should do in the PHP bit?
You should specify a content type of json and use JSON.stringify() to format the data payload.
$.ajax ({
type: "POST",
url: "post.php",
data: JSON.stringify({ test: item }),
contentType: "application/json; charset=utf-8",
success: function(result) {
console.log(result);
}
});
When sending an AJAX request you need to send valid JSON. You can send an array, but you need form valid JSON before you send your data to the server. So in your JavaScript code form valid JSON and send that data to your endpoint.
In your case the test key holds a value containing a JavaScript object with two attributes. JSON is key value coding in string format, your PHP script does not not how to handle JavaScript (jQuery) objects.
https://jsfiddle.net/s1hkkws1/15/
This should help out.
For sending raw form data:
js part:
$.ajax ({
type: "POST",
url: "post.php",
data: item ,
success: function(result) {
console.log(result);
}
});
php part:
..
if (isset($_POST['FirstPart']) && isset($_POST['SecondPart']))
{
$fpart = $_POST['FirstPart'];
$spart = $_POST['SecondPart'];
$obj = new ClientData($fpart, $spart);
}
...
For sending json string:
js part:
$.ajax ({
type: "POST",
url: "post.php",
data: {'test': JSON.stringify(item)},
success: function(result) {
console.log(result);
}
});
php part:
..
if (isset($_POST['test']))
{
$json_data = $_POST['test'];
$json_arr = json_decode($json_data, true);
$fpart = $json_arr['FirstPart'];
$spart = $json_arr['SecondPart'];
$obj = new ClientData($fpart, $spart);
}
...
Try send in ajax:
data: { 'test': JSON.stringify(item) },
instead:
data: { 'test' : item },
I am trying to pass the form field values to a php function located into a file. The problem is that I can't understand how to pass that serialized form data to the function from this ajax to a function in php.
$('#insert_news').submit(function(event) {
event.preventDefault();
var form = $('#insert_news').serialize();
$.ajax({
type: 'POST',
url: 'includes/ajax.php',
data: {
action: 'insert_news',
$('#insert_news').serialize(); // how do I add this data here?
},
success: function(datas) {
$('#message').html(datas).show() /*fadeIn(1000).fadeOut(1000)*/ ;
}
});
});
This ajax passed the values to the file ajax.php right beyond. And from ajax.php is called the function located in functions.php.
ajax.php
if (isset($_POST['action']) && $_POST['action'] == 'insert_news') {
$cp->insert_into_table('newss', array(
'NewsTitle' => $_POST['title'],
'NewsDescrption' => $_POST['description'],
'Date' => date('Y-m-d H:i:s'),
'status' => '1'
)
);
}
function.php
public function insert_into_table($table_name, array $data){
foreach($data as $col=>$value) {
$cols[] = $col;
$values[] = '\''.$value.'\'';
}
$cols = implode(', ', $cols);
$values = implode(', ', $values);
$this->db->query("INSERT INTO $table_name ($cols) VALUES ($values)");
echo "INSERT INTO $table_name ($cols) VALUES ($values)";
}
The issue is serialize() produces a URL encoded key value paired string, so you can't mix that with your data object.
You can use serializeArray() to get an array of objects, representing the form elements, then iterate over them and add them to a data object:
var data = { action: 'insert_news' };
$.each($('#insert_news').serializeArray(), function(){
data[this.name] = this.value;
});
$.ajax({
type: 'POST',
url: 'includes/ajax.php',
data: data,
success: function(datas) {
$('#message').html(datas).show() /*fadeIn(1000).fadeOut(1000)*/ ;
}
});
Side note: your PHP code is vulnerable to SQL Injection. Consider using a Prepared Statement instead of concatenating user input into the SQL.
You can pass serialized data via ajax to a function the way you are doing but your code needs slight modification.
$('#insert_news').submit(function(event) {
event.preventDefault();
var form = $('#insert_news').serialize();
$.ajax({
type: 'POST',
url: 'includes/ajax.php',
data: {
action: 'insert_news',
serializedData: form // use variable to assign data here
},
success: function(datas) {
$('#message').html(datas).show() /*fadeIn(1000).fadeOut(1000)*/ ;
}
});
});
I think you can use alternate like this
First : add hidden input for action on your form
<input type="hidden" name="action" value="insert_news"/>
Then your ajax post like this
$('#insert_news').submit(function(event) {
event.preventDefault();
$.ajax({
type: 'POST',
url: 'includes/ajax.php',
data: $(this).serialize(), // $(this) is from <form id="insert_news">
success: function(datas) {
$('#message').html(datas).show() /*fadeIn(1000).fadeOut(1000)*/ ;
}
});
});
And then use print_r on your ajax.php
print_r($_POST);
$('#insert_news').submit(function(event) {
var name = $("#t1").val();
var pass = $("#t2").val(); //add more var as u need
var key = 0;
var formName = new FormData();
formName.append(key++,name)
formName.append(key++,pass) //append the the var to formdata
$.ajax({
url : 'includes/ajax.php',
dataType : 'text',
cache : false,
contentType : false,
processData : false,
data : formName,
type : 'post',
success : function(data){
$('#message').html(data).show() /*fadeIn(1000).fadeOut(1000)*/ ;
}
});
});
this works fine for me :-)
I have array containg image path ,
GenerateReport[0] ="../images/Desert1.jpg"
GenerateReport[1] ="../images/Desert2.jpg"
GenerateReport[2] ="../images/Desert3.jpg"
GenerateReport[3] ="../images/Desert4.jpg"
GenerateReport[4] ="../images/Desert5.jpg"
I am trying to pass this array with following code,
$.ajax({
type: "POST",
url: "generatePdf.php",
data: {
genRep: "sample value"
},
success: function(data) {
alert(data);
console.log('getting '+data);
}
});
sample value is passed successfully , but how can i pass array to ajax and use it on another page?? i tried passing array and using with below code but it is not working
$data1 = $_REQUEST['genRep'];
echo "tested".$data1[0];
Try like
genRep = [];
$.ajax({
type: "POST",
url: "generatePdf.php",
data: {
genRep: GenerateReport
},
success: function(data) {
alert(data);
console.log('getting '+data);
}
});
It will send your array as genRep
try to use json object. in object you can store your images path
var data=[]; // array
var data[0] = 'something';
var data[1] = 'something1';
var data = { 'name': name, 'email' : email, 'contact' : contact, 'type' : type, 'msg' : msg }; // object
$.ajax({
url : 'contact.php',
type : 'POST',
data : {contact:JSON.stringify(data)}, // for json object
data : {contact: data}, // for array
success : function (msg)
{
alert(msg);
}
})
contact.php
$info = $_POST['contact'];
$info = json_decode($info,true); // for json object
echo $info.name; // for json object
echo $info[0]; // will print something...
$arr = array();
$arr[0] = "Mark Reed";
$arr[1] = "34";
$arr[2] = "Australia";
echo json_encode ($arr);
use this on the php page
and use the following to get the output
success:function(msg){
id_numbers = JSON.parse(msg);
alert(id_numbers)
}
Try:
$.ajax({
url: "generatePdf.php",
type: 'POST',
data: form_data,
dataType:"json",
success: function(data) {
alert(data[0]);
}
On the PHP side, you'll be wanting to print:
print json_encode($photos);
Made Some Change
print json_encode(array("photolist"=>$photos));
Then on the server, you'd access these with:
data.photolist[0]; //First photo
I have tested it, this will definitely work !
JS:
var GenerateReport = [];
GenerateReport[0] ="../images/Desert1.jpg";
GenerateReport[1] ="../images/Desert2.jpg";
GenerateReport[2] ="../images/Desert3.jpg";
GenerateReport[3] ="../images/Desert4.jpg";
GenerateReport[4] ="../images/Desert5.jpg";
$.ajax({
type: 'POST',
url: 'generatePdf.php',
data: 'image_array='+GenerateReport,
success: function(msg) {
alert(msg);
}
});
generatePdf.php :
<?php
$image_string = $_POST['image_array'];
$image_array = explode(",", $image_string);
print_r($image_array);
?>
Then you can loop over the $image_array to get the values.
try this
GenerateReport[0] ="../images/Desert1.jpg"
GenerateReport[1] ="../images/Desert2.jpg"
GenerateReport[2] ="../images/Desert3.jpg"
GenerateReport[3] ="../images/Desert4.jpg"
GenerateReport[4] ="../images/Desert5.jpg"
corrected code:
var imagedata = '';
$.each(GenerateReport,function(index,value))
{
if(imagedata=='')
{
imagedata = imagedata +'image'+index+'='+value;
}
else
{
imagedata = imagedata +'&image'+index+'='+value;
}
});
$.ajax({
type: "POST",
url: "generatePdf.php",
data: imagedata //pass string imagedata
success: function(data) {
alert(data);
console.log('getting '+data);
}
});
imagedata should have sting like this:
image1=../images/Desert1.jpg&image2=../images/Desert2.jpg and so on
if(isset($_REQUEST['genRep']))
{
$data = $_REQUEST['genRep'];
print_r($data1);
echo "tested".$data1[0];
createPdf($data);
}
My code was correct , there was no value on index 0 , thats why it was not printing anything .My Mistake !!!