Related
I have a form with name orderproductForm and an undefined number of inputs.
I want to do some kind of jQuery.get or ajax or anything like that that would call a page through Ajax, and send along all the inputs of the form orderproductForm.
I suppose one way would be to do something like
jQuery.get("myurl",
{action : document.orderproductForm.action.value,
cartproductid : document.orderproductForm.cartproductid.value,
productid : document.orderproductForm.productid.value,
...
However I do not know exactly all the form inputs. Is there a feature, function or something that would just send ALL the form inputs?
This is a simple reference:
// this is the id of the form
$("#idForm").submit(function(e) {
e.preventDefault(); // avoid to execute the actual submit of the form.
var form = $(this);
var actionUrl = form.attr('action');
$.ajax({
type: "POST",
url: actionUrl,
data: form.serialize(), // serializes the form's elements.
success: function(data)
{
alert(data); // show response from the php script.
}
});
});
You can use the ajaxForm/ajaxSubmit functions from Ajax Form Plugin or the jQuery serialize function.
AjaxForm:
$("#theForm").ajaxForm({url: 'server.php', type: 'post'})
or
$("#theForm").ajaxSubmit({url: 'server.php', type: 'post'})
ajaxForm will send when the submit button is pressed. ajaxSubmit sends immediately.
Serialize:
$.get('server.php?' + $('#theForm').serialize())
$.post('server.php', $('#theForm').serialize())
AJAX serialization documentation is here.
Another similar solution using attributes defined on the form element:
<form id="contactForm1" action="/your_url" method="post">
<!-- Form input fields here (do not forget your name attributes). -->
</form>
<script type="text/javascript">
var frm = $('#contactForm1');
frm.submit(function (e) {
e.preventDefault();
$.ajax({
type: frm.attr('method'),
url: frm.attr('action'),
data: frm.serialize(),
success: function (data) {
console.log('Submission was successful.');
console.log(data);
},
error: function (data) {
console.log('An error occurred.');
console.log(data);
},
});
});
</script>
There are a few things you need to bear in mind.
1. There are several ways to submit a form
using the submit button
by pressing enter
by triggering a submit event in JavaScript
possibly more depending on the device or future device.
We should therefore bind to the form submit event, not the button click event. This will ensure our code works on all devices and assistive technologies now and in the future.
2. Hijax
The user may not have JavaScript enabled. A hijax pattern is good here, where we gently take control of the form using JavaScript, but leave it submittable if JavaScript fails.
We should pull the URL and method from the form, so if the HTML changes, we don't need to update the JavaScript.
3. Unobtrusive JavaScript
Using event.preventDefault() instead of return false is good practice as it allows the event to bubble up. This lets other scripts tie into the event, for example analytics scripts which may be monitoring user interactions.
Speed
We should ideally use an external script, rather than inserting our script inline. We can link to this in the head section of the page using a script tag, or link to it at the bottom of the page for speed. The script should quietly enhance the user experience, not get in the way.
Code
Assuming you agree with all the above, and you want to catch the submit event, and handle it via AJAX (a hijax pattern), you could do something like this:
$(function() {
$('form.my_form').submit(function(event) {
event.preventDefault(); // Prevent the form from submitting via the browser
var form = $(this);
$.ajax({
type: form.attr('method'),
url: form.attr('action'),
data: form.serialize()
}).done(function(data) {
// Optionally alert the user of success here...
}).fail(function(data) {
// Optionally alert the user of an error here...
});
});
});
You can manually trigger a form submission whenever you like via JavaScript using something like:
$(function() {
$('form.my_form').trigger('submit');
});
Edit:
I recently had to do this and ended up writing a plugin.
(function($) {
$.fn.autosubmit = function() {
this.submit(function(event) {
event.preventDefault();
var form = $(this);
$.ajax({
type: form.attr('method'),
url: form.attr('action'),
data: form.serialize()
}).done(function(data) {
// Optionally alert the user of success here...
}).fail(function(data) {
// Optionally alert the user of an error here...
});
});
return this;
}
})(jQuery)
Add a data-autosubmit attribute to your form tag and you can then do this:
HTML
<form action="/blah" method="post" data-autosubmit>
<!-- Form goes here -->
</form>
JS
$(function() {
$('form[data-autosubmit]').autosubmit();
});
You can also use FormData (But not available in IE):
var formData = new FormData(document.getElementsByName('yourForm')[0]);// yourForm: form selector
$.ajax({
type: "POST",
url: "yourURL",// where you wanna post
data: formData,
processData: false,
contentType: false,
error: function(jqXHR, textStatus, errorMessage) {
console.log(errorMessage); // Optional
},
success: function(data) {console.log(data)}
});
This is how you use FormData.
Simple version (does not send images)
<form action="/my/ajax/url" class="my-form">
...
</form>
<script>
(function($){
$("body").on("submit", ".my-form", function(e){
e.preventDefault();
var form = $(e.target);
$.post( form.attr("action"), form.serialize(), function(res){
console.log(res);
});
});
)(jQuery);
</script>
Copy and paste ajaxification of a form or all forms on a page
It is a modified version of Alfrekjv's answer
It will work with jQuery >= 1.3.2
You can run this before the document is ready
You can remove and re-add the form and it will still work
It will post to the same location as the normal form, specified in
the form's "action" attribute
JavaScript
jQuery(document).submit(function(e){
var form = jQuery(e.target);
if(form.is("#form-id")){ // check if this is the form that you want (delete this check to apply this to all forms)
e.preventDefault();
jQuery.ajax({
type: "POST",
url: form.attr("action"),
data: form.serialize(), // serializes the form's elements.
success: function(data) {
console.log(data); // show response from the php script. (use the developer toolbar console, firefox firebug or chrome inspector console)
}
});
}
});
I wanted to edit Alfrekjv's answer but deviated too much from it so decided to post this as a separate answer.
Does not send files, does not support buttons, for example clicking a button (including a submit button) sends its value as form data, but because this is an ajax request the button click will not be sent.
To support buttons you can capture the actual button click instead of the submit.
jQuery(document).click(function(e){
var self = jQuery(e.target);
if(self.is("#form-id input[type=submit], #form-id input[type=button], #form-id button")){
e.preventDefault();
var form = self.closest('form'), formdata = form.serialize();
//add the clicked button to the form data
if(self.attr('name')){
formdata += (formdata!=='')? '&':'';
formdata += self.attr('name') + '=' + ((self.is('button'))? self.html(): self.val());
}
jQuery.ajax({
type: "POST",
url: form.attr("action"),
data: formdata,
success: function(data) {
console.log(data);
}
});
}
});
On the server side you can detect an ajax request with this header that jquery sets HTTP_X_REQUESTED_WITH
for php
PHP
if(!empty($_SERVER['HTTP_X_REQUESTED_WITH']) && strtolower($_SERVER['HTTP_X_REQUESTED_WITH']) == 'xmlhttprequest') {
//is ajax
}
This code works even with file input
$(document).on("submit", "form", function(event)
{
event.preventDefault();
$.ajax({
url: $(this).attr("action"),
type: $(this).attr("method"),
dataType: "JSON",
data: new FormData(this),
processData: false,
contentType: false,
success: function (data, status)
{
},
error: function (xhr, desc, err)
{
}
});
});
I really liked this answer by superluminary and especially the way he wrapped is solution in a jQuery plugin. So thanks to superluminary for a very useful answer. In my case, though, I wanted a plugin that would allow me to define the success and error event handlers by means of options when the plugin is initialized.
So here is what I came up with:
;(function(defaults, $, undefined) {
var getSubmitHandler = function(onsubmit, success, error) {
return function(event) {
if (typeof onsubmit === 'function') {
onsubmit.call(this, event);
}
var form = $(this);
$.ajax({
type: form.attr('method'),
url: form.attr('action'),
data: form.serialize()
}).done(function() {
if (typeof success === 'function') {
success.apply(this, arguments);
}
}).fail(function() {
if (typeof error === 'function') {
error.apply(this, arguments);
}
});
event.preventDefault();
};
};
$.fn.extend({
// Usage:
// jQuery(selector).ajaxForm({
// onsubmit:function() {},
// success:function() {},
// error: function() {}
// });
ajaxForm : function(options) {
options = $.extend({}, defaults, options);
return $(this).each(function() {
$(this).submit(getSubmitHandler(options['onsubmit'], options['success'], options['error']));
});
}
});
})({}, jQuery);
This plugin allows me to very easily "ajaxify" html forms on the page and provide onsubmit, success and error event handlers for implementing feedback to the user of the status of the form submit. This allowed the plugin to be used as follows:
$('form').ajaxForm({
onsubmit: function(event) {
// User submitted the form
},
success: function(data, textStatus, jqXHR) {
// The form was successfully submitted
},
error: function(jqXHR, textStatus, errorThrown) {
// The submit action failed
}
});
Note that the success and error event handlers receive the same arguments that you would receive from the corresponding events of the jQuery ajax method.
I got the following for me:
formSubmit('#login-form', '/api/user/login', '/members/');
where
function formSubmit(form, url, target) {
$(form).submit(function(event) {
$.post(url, $(form).serialize())
.done(function(res) {
if (res.success) {
window.location = target;
}
else {
alert(res.error);
}
})
.fail(function(res) {
alert("Server Error: " + res.status + " " + res.statusText);
})
event.preventDefault();
});
}
This assumes the post to 'url' returns an ajax in the form of {success: false, error:'my Error to display'}
You can vary this as you like. Feel free to use that snippet.
jQuery AJAX submit form, is nothing but submit a form using form ID when you click on a button
Please follow steps
Step 1 - Form tag must have an ID field
<form method="post" class="form-horizontal" action="test/user/add" id="submitForm">
.....
</form>
Button which you are going to click
<button>Save</button>
Step 2 - submit event is in jQuery which helps to submit a form. in below code we are preparing JSON request from HTML element name.
$("#submitForm").submit(function(e) {
e.preventDefault();
var frm = $("#submitForm");
var data = {};
$.each(this, function(i, v){
var input = $(v);
data[input.attr("name")] = input.val();
delete data["undefined"];
});
$.ajax({
contentType:"application/json; charset=utf-8",
type:frm.attr("method"),
url:frm.attr("action"),
dataType:'json',
data:JSON.stringify(data),
success:function(data) {
alert(data.message);
}
});
});
for live demo click on below link
How to submit a Form using jQuery AJAX?
I know this is a jQuery related question, but now days with JS ES6 things are much easier. Since there is no pure javascript answer, I thought I could add a simple pure javascript solution to this, which in my opinion is much cleaner, by using the fetch() API. This a modern way to implements network requests. In your case, since you already have a form element we can simply use it to build our request.
const form = document.forms["orderproductForm"];
const formInputs = form.getElementsByTagName("input");
let formData = new FormData();
for (let input of formInputs) {
formData.append(input.name, input.value);
}
fetch(form.action,
{
method: form.method,
body: formData
})
.then(response => response.json())
.then(data => console.log(data))
.catch(error => console.log(error.message))
.finally(() => console.log("Done"));
Try
fetch(form.action,{method:'post', body: new FormData(form)});
function send(e,form) {
fetch(form.action,{method:'post', body: new FormData(form)});
console.log('We submit form asynchronously (AJAX)');
e.preventDefault();
}
<form method="POST" action="myapi/send" onsubmit="send(event,this)" name="orderproductForm">
<input hidden name="csrfToken" value="$0meh#$h">
<input name="email" value="aa#bb.com">
<input name="phone" value="123-456-666">
<input type="submit">
</form>
Look on Chrome Console > Network after/before 'submit'
consider using closest
$('table+table form').closest('tr').filter(':not(:last-child)').submit(function (ev, frm) {
frm = $(ev.target).closest('form');
$.ajax({
type: frm.attr('method'),
url: frm.attr('action'),
data: frm.serialize(),
success: function (data) {
alert(data);
}
})
ev.preventDefault();
});
You may use this on submit function like below.
HTML Form
<form class="form" action="" method="post">
<input type="text" name="name" id="name" >
<textarea name="text" id="message" placeholder="Write something to us"> </textarea>
<input type="button" onclick="return formSubmit();" value="Send">
</form>
jQuery function:
<script>
function formSubmit(){
var name = document.getElementById("name").value;
var message = document.getElementById("message").value;
var dataString = 'name='+ name + '&message=' + message;
jQuery.ajax({
url: "submit.php",
data: dataString,
type: "POST",
success: function(data){
$("#myForm").html(data);
},
error: function (){}
});
return true;
}
</script>
For more details and sample Visit:
http://www.spiderscode.com/simple-ajax-contact-form/
To avoid multiple formdata sends:
Don't forget to unbind submit event, before the form submited again,
User can call sumbit function more than one time, maybe he forgot something, or was a validation error.
$("#idForm").unbind().submit( function(e) {
....
If you're using form.serialize() - you need to give each form element a name like this:
<input id="firstName" name="firstName" ...
And the form gets serialized like this:
firstName=Chris&lastName=Halcrow ...
I find it surprising that no one mentions data as an object. For me it's the cleanest and easiest way to pass data:
$('form#foo').submit(function () {
$.ajax({
url: 'http://foo.bar/some-ajax-script',
type: 'POST',
dataType: 'json',
data: {
'foo': 'some-foo-value',
'bar': $('#bar').val()
}
}).always(function (response) {
console.log(response);
});
return false;
});
Then, in the backend:
// Example in PHP
$_POST['foo'] // some-foo-value
$_POST['bar'] // value in #bar
This is not the answer to OP's question,
but in case if you can't use static form DOM, you can also try like this.
var $form = $('<form/>').append(
$('<input/>', {name: 'username'}).val('John Doe'),
$('<input/>', {name: 'user_id'}).val('john.1234')
);
$.ajax({
url: 'api/user/search',
type: 'POST',
contentType: 'application/x-www-form-urlencoded',
data: $form.serialize(),
success: function(data, textStatus, jqXHR) {
console.info(data);
},
error: function(jqXHR, textStatus, errorThrown) {
var errorMessage = jqXHR.responseText;
if (errorMessage.length > 0) {
alert(errorMessage);
}
}
});
JavaScript
(function ($) {
var form= $('#add-form'),
input = $('#exampleFormControlTextarea1');
form.submit(function(event) {
event.preventDefault();
var req = $.ajax({
url: form.attr('action'),
type: 'POST',
data: form.serialize()
});
req.done(function(data) {
if (data === 'success') {
var li = $('<li class="list-group-item">'+ input.val() +'</li>');
li.hide()
.appendTo('.list-group')
.fadeIn();
$('input[type="text"],textarea').val('');
}
});
});
}(jQuery));
HTML
<ul class="list-group col-sm-6 float-left">
<?php
foreach ($data as $item) {
echo '<li class="list-group-item">'.$item.'</li>';
}
?>
</ul>
<form id="add-form" class="col-sm-6 float-right" action="_inc/add-new.php" method="post">
<p class="form-group">
<textarea class="form-control" name="message" id="exampleFormControlTextarea1" rows="3" placeholder="Is there something new?"></textarea>
</p>
<button type="submit" class="btn btn-danger">Add new item</button>
</form>
There's also the submit event, which can be triggered like this $("#form_id").submit(). You'd use this method if the form is well represented in HTML already. You'd just read in the page, populate the form inputs with stuff, then call .submit(). It'll use the method and action defined in the form's declaration, so you don't need to copy it into your javascript.
examples
I am trying to get the response from the PHP scripts but the button takes multiple clicks on firing the event. I read about that on Google but unable to understand that why it is going to happen.
Html Code
<form action="javascript:MyResults()">
<input type="submit" value="Search" id ="button1"/>
</form>
Javascript Code
function MyResults(){
$(document).ready(function(){
$("#button1").click(function(){
var searchData = $("#search").val();
alert(searchData);
$.ajax({
url: "http://localhost/test.php",
type:"POST",
async:true,
data:{
"search" : searchDat,
},
success: function(value){
alert( JSON.parse(value));
$.each(value, function(index, value1){
console.log(value1);
});
}
});
});
});
}
</script>
You are declaring $(document).ready(function() inside MyResult function . In first case it will execute the MyFunction & in second case it will execute the code inside the ready function.
Actually there is no need to the action here. Following change will work
HTML
<form id='target'>
<input type="submit" value="Search" id="button1" />
</form>
JS
$(document).ready(function() {
$("#target").submit(function() {
event.preventDefault()
var searchData = $("#search").val();
alert(searchData);
$.ajax({
url: "http://localhost/test.php",
type: "POST",
async: true,
data: {
"search": searchData,
},
success: function(value) {
alert(JSON.parse(value));
$.each(value, function(index, value1) {
console.log(value1);
});
}
});
});
})
The problem is that your current code doesn't set-up the click-handler for button until the form is submitted. That first click triggers the action attribute on the <form>, which sets up the handler. The second click then calls the button handler.
Instead of your current code, you probably want HTML like this:
<form>
<input type="submit" value="Search" id ="button1"/>
</form>
Use $(document).ready(...) without the wrapper function MyResults(), and be sure to cancel the click event to stop traditional form submission:
<script>
$(document).ready(function(){
$("#button1").click(function(event){
event.preventDefault();
event.stopPropagation();
var searchData = $("#search").val();
alert(searchData);
$.ajax({
url: "http://localhost/test.php",
type:"POST",
async:true,
data:{
"search" : searchDat,
},
success: function(value){
alert( JSON.parse(value));
$.each(value, function(index, value1){
console.log(value1);
});
}
});
});
});
</script>
Here fired one event at two times.
First fired when form submit.
action="javascript:MyResults()"
Second fired after form submit which you have defined in the function part.
$("#button1").click(function(){});
I have a formRemote that calls a function in my controller when it is submitted like this:
<g:formRemote name="editIndivRecForm" url="[controller: 'customer', action:'saveEditedIndividualRecord']" onSuccess="doResult();">
This form is submitted by clicking on a button. Rather, a button that is clicked called 'save' will do other things among clicking the form's submit button via Javascript. Here is the click handler for this button:
$('#save').click(function () {
$("#uniqueId").prop('disabled', false); // Have to enable before form submission else it doesn't go back as a param to controller.
$("#secondaryId").prop('disabled', false);
$("#submit").trigger("click"); // formRemote's submit button
$('#editIndivRecForm').reset;
<g:remoteFunction controller="customer"
action="remediationSearch"
update="content_area"
params="{rerender: true}"/>
});
The problem I'm running into is that I need the function of my controller called by the click handler remediationSearch to run AFTER the function of the controller called by the formRemote's submission saveEditedIndividualRecord is done executing. But it is happening the other way around. And for some reason the function onSuccess="doResult();" doesn't even execute otherwise I was going to move the following code into its body to make things work the way I want:
<g:remoteFunction controller="customer"
action="remediationSearch"
update="content_area"
params="{rerender: true}"/>
here is how doResult is now:
function doResult() {
console.log("done.");
}
the formRemote is submitted but the doResult function prints nothing to the console.
Seeing as all of the Grails AJAX related tags have been deprecated, I would recommend trying it this way:
Markup:
<form id="editIndivRecForm" onsubmit="return false;">
<!-- add fields here -->
<input type="text" id="uniqueId" value="${something}">
<input type="text" id="secondaryId" value="${something}">
<button id="save" type="button">
</form>
JavaScript:
// Function to update your content_area div
function updateContentArea() {
var params = { rerender: true };
var url = "${createLink(controller: 'customer', action: 'remediationSearch')}";
$.get(url, params, function(data) {
$("#content_area").empty().append(data);
});
}
$("#save").on('click', function() {
// Collect values from form and submit ajax request
// Using name and description for example fields here:
var data = {
name: $("#name").val(),
description: $("#description").val(),
uniqueId: $("#uniqueId").val(),
secondaryId: $("#secondaryId").val()
};
var url = "${createLink(controller: 'customer', action: 'saveEditedIndividualRecord')}";
// Submit the (first) AJAX request
$.ajax({
type: "post",
url: url,
data: data,
success: function() {
doResult();
$('#editIndivRecForm').reset();
updateContentArea();
}
});
}
I have a login popup that will pop up on every page of my site. What I want to do is once the user clicks submit, to have a single JS file where the jQuery code for handling that request lives, and makes an AJAX call to validate the parameters in the DB.
I am able to get the pop up box to pop up. And the form loads. I am thinking my jQuery code will live in a separate imported file and look like this:
<script type="text/javascript" >
$(function()
{
$("input[type=submit]").click(function()
{
var some_params= $("#param").val();
var dataString = 'Some url to send to ajax';
if( params validated ok )
{
$('.success').fadeOut(200).hide();
$('.error').fadeOut(200).show();
}
else
{
$.ajax({
type: "POST",
url: "/problems/add_problem.php",
dataType: "json",
data: dataString,
success: function(json)
{
$('.success').fadeIn(200).show();
$('.error').fadeOut(200).hide();
}
});
}
return false;
});
});
</script>
So my question is how do I make this get invoked only when the right form is submitted? The form would have some id="some_name" but I don't really understand how to make this jQuery code get executed only when that form element is called.
And here is the form I am calling to display in the popup:
<?php
echo '<div id="login_div">
<form id="login_form" method="post" action="">
<p>
<label for="name"><span>Your Email:</span></label> <input type="text" name="email" />
</p>
<p>
<label for="name"><span>Your Password:</span></label> <input type="password" name="user_pass">
</p>
<p>
<input type="submit" value="Log In" />
</p>
</form>
</div>
<p>
Create Account | Reset Pass
</p>
';
?>
and here is the problemio.js contents with the jQuery to handle the login form submit:
// javascript library
// login_form
$(function()
{
$("#login_form input[type=submit]").click(function()
{
console.log("test");
alert("1");
// var name = $("#problem_name").val();
// var problem_blurb = $("#problem_blurb").val();
// var dataString = 'problem_name='+ name + '&problem_blurb=' + problem_blurb;
// if(name=='' || problem_blurb == '')
// {
// $('.success').fadeOut(200).hide();
// $('.error').fadeOut(200).show();
/// }
// else
// {
// $.ajax({
// type: "POST",
// url: "/problems/add_problem.php",
// dataType: "json",
// data: dataString,
// success: function(json)
// {
// $('.success').fadeIn(200).show();
// $('.error').fadeOut(200).hide();
//
/// // Here can update the right side of the screen with the newly entered information
// //alert (json);
//
// new_string = "<h2>Most Recently Added Problems</h2>";
// Have to figure out how to make this work with the DOM.
// }
// });
// }
return false;
});
});
Two things. First, when you place the code above into a separate javascript file, be sure to remove the <script ..> and </script> HTML tags.
Next, alter the following line:
$("input[type=submit]").click(function()
To instead say:
$("#loginform input[type=submit]").click(function()
And then set id="loginform" on your <form> tag.
You can use .submit() to attach a handler to the form submit event. First you'll need to select your form via the id:
$("#some_form_id").submit(function() {
// the code you have in the click event above goes here.
});
You can specific the form you want to trigger the jquery. http://api.jquery.com/submit/
If you are not sure, just right-click this webpage and read its html code.
<script type="text/javascript" src="some.js"></script>
And also, binding the the function to form.submit is much better than to the submit button.
$('formid').submit(function(){blablabla;return false;})
If you would like to handle the click event for every submit on the page without using ids, you can always use the this keyword in the click event to find the sender and then find the parent form.
I have a form with name orderproductForm and an undefined number of inputs.
I want to do some kind of jQuery.get or ajax or anything like that that would call a page through Ajax, and send along all the inputs of the form orderproductForm.
I suppose one way would be to do something like
jQuery.get("myurl",
{action : document.orderproductForm.action.value,
cartproductid : document.orderproductForm.cartproductid.value,
productid : document.orderproductForm.productid.value,
...
However I do not know exactly all the form inputs. Is there a feature, function or something that would just send ALL the form inputs?
This is a simple reference:
// this is the id of the form
$("#idForm").submit(function(e) {
e.preventDefault(); // avoid to execute the actual submit of the form.
var form = $(this);
var actionUrl = form.attr('action');
$.ajax({
type: "POST",
url: actionUrl,
data: form.serialize(), // serializes the form's elements.
success: function(data)
{
alert(data); // show response from the php script.
}
});
});
You can use the ajaxForm/ajaxSubmit functions from Ajax Form Plugin or the jQuery serialize function.
AjaxForm:
$("#theForm").ajaxForm({url: 'server.php', type: 'post'})
or
$("#theForm").ajaxSubmit({url: 'server.php', type: 'post'})
ajaxForm will send when the submit button is pressed. ajaxSubmit sends immediately.
Serialize:
$.get('server.php?' + $('#theForm').serialize())
$.post('server.php', $('#theForm').serialize())
AJAX serialization documentation is here.
Another similar solution using attributes defined on the form element:
<form id="contactForm1" action="/your_url" method="post">
<!-- Form input fields here (do not forget your name attributes). -->
</form>
<script type="text/javascript">
var frm = $('#contactForm1');
frm.submit(function (e) {
e.preventDefault();
$.ajax({
type: frm.attr('method'),
url: frm.attr('action'),
data: frm.serialize(),
success: function (data) {
console.log('Submission was successful.');
console.log(data);
},
error: function (data) {
console.log('An error occurred.');
console.log(data);
},
});
});
</script>
There are a few things you need to bear in mind.
1. There are several ways to submit a form
using the submit button
by pressing enter
by triggering a submit event in JavaScript
possibly more depending on the device or future device.
We should therefore bind to the form submit event, not the button click event. This will ensure our code works on all devices and assistive technologies now and in the future.
2. Hijax
The user may not have JavaScript enabled. A hijax pattern is good here, where we gently take control of the form using JavaScript, but leave it submittable if JavaScript fails.
We should pull the URL and method from the form, so if the HTML changes, we don't need to update the JavaScript.
3. Unobtrusive JavaScript
Using event.preventDefault() instead of return false is good practice as it allows the event to bubble up. This lets other scripts tie into the event, for example analytics scripts which may be monitoring user interactions.
Speed
We should ideally use an external script, rather than inserting our script inline. We can link to this in the head section of the page using a script tag, or link to it at the bottom of the page for speed. The script should quietly enhance the user experience, not get in the way.
Code
Assuming you agree with all the above, and you want to catch the submit event, and handle it via AJAX (a hijax pattern), you could do something like this:
$(function() {
$('form.my_form').submit(function(event) {
event.preventDefault(); // Prevent the form from submitting via the browser
var form = $(this);
$.ajax({
type: form.attr('method'),
url: form.attr('action'),
data: form.serialize()
}).done(function(data) {
// Optionally alert the user of success here...
}).fail(function(data) {
// Optionally alert the user of an error here...
});
});
});
You can manually trigger a form submission whenever you like via JavaScript using something like:
$(function() {
$('form.my_form').trigger('submit');
});
Edit:
I recently had to do this and ended up writing a plugin.
(function($) {
$.fn.autosubmit = function() {
this.submit(function(event) {
event.preventDefault();
var form = $(this);
$.ajax({
type: form.attr('method'),
url: form.attr('action'),
data: form.serialize()
}).done(function(data) {
// Optionally alert the user of success here...
}).fail(function(data) {
// Optionally alert the user of an error here...
});
});
return this;
}
})(jQuery)
Add a data-autosubmit attribute to your form tag and you can then do this:
HTML
<form action="/blah" method="post" data-autosubmit>
<!-- Form goes here -->
</form>
JS
$(function() {
$('form[data-autosubmit]').autosubmit();
});
You can also use FormData (But not available in IE):
var formData = new FormData(document.getElementsByName('yourForm')[0]);// yourForm: form selector
$.ajax({
type: "POST",
url: "yourURL",// where you wanna post
data: formData,
processData: false,
contentType: false,
error: function(jqXHR, textStatus, errorMessage) {
console.log(errorMessage); // Optional
},
success: function(data) {console.log(data)}
});
This is how you use FormData.
Simple version (does not send images)
<form action="/my/ajax/url" class="my-form">
...
</form>
<script>
(function($){
$("body").on("submit", ".my-form", function(e){
e.preventDefault();
var form = $(e.target);
$.post( form.attr("action"), form.serialize(), function(res){
console.log(res);
});
});
)(jQuery);
</script>
Copy and paste ajaxification of a form or all forms on a page
It is a modified version of Alfrekjv's answer
It will work with jQuery >= 1.3.2
You can run this before the document is ready
You can remove and re-add the form and it will still work
It will post to the same location as the normal form, specified in
the form's "action" attribute
JavaScript
jQuery(document).submit(function(e){
var form = jQuery(e.target);
if(form.is("#form-id")){ // check if this is the form that you want (delete this check to apply this to all forms)
e.preventDefault();
jQuery.ajax({
type: "POST",
url: form.attr("action"),
data: form.serialize(), // serializes the form's elements.
success: function(data) {
console.log(data); // show response from the php script. (use the developer toolbar console, firefox firebug or chrome inspector console)
}
});
}
});
I wanted to edit Alfrekjv's answer but deviated too much from it so decided to post this as a separate answer.
Does not send files, does not support buttons, for example clicking a button (including a submit button) sends its value as form data, but because this is an ajax request the button click will not be sent.
To support buttons you can capture the actual button click instead of the submit.
jQuery(document).click(function(e){
var self = jQuery(e.target);
if(self.is("#form-id input[type=submit], #form-id input[type=button], #form-id button")){
e.preventDefault();
var form = self.closest('form'), formdata = form.serialize();
//add the clicked button to the form data
if(self.attr('name')){
formdata += (formdata!=='')? '&':'';
formdata += self.attr('name') + '=' + ((self.is('button'))? self.html(): self.val());
}
jQuery.ajax({
type: "POST",
url: form.attr("action"),
data: formdata,
success: function(data) {
console.log(data);
}
});
}
});
On the server side you can detect an ajax request with this header that jquery sets HTTP_X_REQUESTED_WITH
for php
PHP
if(!empty($_SERVER['HTTP_X_REQUESTED_WITH']) && strtolower($_SERVER['HTTP_X_REQUESTED_WITH']) == 'xmlhttprequest') {
//is ajax
}
This code works even with file input
$(document).on("submit", "form", function(event)
{
event.preventDefault();
$.ajax({
url: $(this).attr("action"),
type: $(this).attr("method"),
dataType: "JSON",
data: new FormData(this),
processData: false,
contentType: false,
success: function (data, status)
{
},
error: function (xhr, desc, err)
{
}
});
});
I really liked this answer by superluminary and especially the way he wrapped is solution in a jQuery plugin. So thanks to superluminary for a very useful answer. In my case, though, I wanted a plugin that would allow me to define the success and error event handlers by means of options when the plugin is initialized.
So here is what I came up with:
;(function(defaults, $, undefined) {
var getSubmitHandler = function(onsubmit, success, error) {
return function(event) {
if (typeof onsubmit === 'function') {
onsubmit.call(this, event);
}
var form = $(this);
$.ajax({
type: form.attr('method'),
url: form.attr('action'),
data: form.serialize()
}).done(function() {
if (typeof success === 'function') {
success.apply(this, arguments);
}
}).fail(function() {
if (typeof error === 'function') {
error.apply(this, arguments);
}
});
event.preventDefault();
};
};
$.fn.extend({
// Usage:
// jQuery(selector).ajaxForm({
// onsubmit:function() {},
// success:function() {},
// error: function() {}
// });
ajaxForm : function(options) {
options = $.extend({}, defaults, options);
return $(this).each(function() {
$(this).submit(getSubmitHandler(options['onsubmit'], options['success'], options['error']));
});
}
});
})({}, jQuery);
This plugin allows me to very easily "ajaxify" html forms on the page and provide onsubmit, success and error event handlers for implementing feedback to the user of the status of the form submit. This allowed the plugin to be used as follows:
$('form').ajaxForm({
onsubmit: function(event) {
// User submitted the form
},
success: function(data, textStatus, jqXHR) {
// The form was successfully submitted
},
error: function(jqXHR, textStatus, errorThrown) {
// The submit action failed
}
});
Note that the success and error event handlers receive the same arguments that you would receive from the corresponding events of the jQuery ajax method.
I got the following for me:
formSubmit('#login-form', '/api/user/login', '/members/');
where
function formSubmit(form, url, target) {
$(form).submit(function(event) {
$.post(url, $(form).serialize())
.done(function(res) {
if (res.success) {
window.location = target;
}
else {
alert(res.error);
}
})
.fail(function(res) {
alert("Server Error: " + res.status + " " + res.statusText);
})
event.preventDefault();
});
}
This assumes the post to 'url' returns an ajax in the form of {success: false, error:'my Error to display'}
You can vary this as you like. Feel free to use that snippet.
jQuery AJAX submit form, is nothing but submit a form using form ID when you click on a button
Please follow steps
Step 1 - Form tag must have an ID field
<form method="post" class="form-horizontal" action="test/user/add" id="submitForm">
.....
</form>
Button which you are going to click
<button>Save</button>
Step 2 - submit event is in jQuery which helps to submit a form. in below code we are preparing JSON request from HTML element name.
$("#submitForm").submit(function(e) {
e.preventDefault();
var frm = $("#submitForm");
var data = {};
$.each(this, function(i, v){
var input = $(v);
data[input.attr("name")] = input.val();
delete data["undefined"];
});
$.ajax({
contentType:"application/json; charset=utf-8",
type:frm.attr("method"),
url:frm.attr("action"),
dataType:'json',
data:JSON.stringify(data),
success:function(data) {
alert(data.message);
}
});
});
for live demo click on below link
How to submit a Form using jQuery AJAX?
Try
fetch(form.action,{method:'post', body: new FormData(form)});
function send(e,form) {
fetch(form.action,{method:'post', body: new FormData(form)});
console.log('We submit form asynchronously (AJAX)');
e.preventDefault();
}
<form method="POST" action="myapi/send" onsubmit="send(event,this)" name="orderproductForm">
<input hidden name="csrfToken" value="$0meh#$h">
<input name="email" value="aa#bb.com">
<input name="phone" value="123-456-666">
<input type="submit">
</form>
Look on Chrome Console > Network after/before 'submit'
I know this is a jQuery related question, but now days with JS ES6 things are much easier. Since there is no pure javascript answer, I thought I could add a simple pure javascript solution to this, which in my opinion is much cleaner, by using the fetch() API. This a modern way to implements network requests. In your case, since you already have a form element we can simply use it to build our request.
const form = document.forms["orderproductForm"];
const formInputs = form.getElementsByTagName("input");
let formData = new FormData();
for (let input of formInputs) {
formData.append(input.name, input.value);
}
fetch(form.action,
{
method: form.method,
body: formData
})
.then(response => response.json())
.then(data => console.log(data))
.catch(error => console.log(error.message))
.finally(() => console.log("Done"));
consider using closest
$('table+table form').closest('tr').filter(':not(:last-child)').submit(function (ev, frm) {
frm = $(ev.target).closest('form');
$.ajax({
type: frm.attr('method'),
url: frm.attr('action'),
data: frm.serialize(),
success: function (data) {
alert(data);
}
})
ev.preventDefault();
});
You may use this on submit function like below.
HTML Form
<form class="form" action="" method="post">
<input type="text" name="name" id="name" >
<textarea name="text" id="message" placeholder="Write something to us"> </textarea>
<input type="button" onclick="return formSubmit();" value="Send">
</form>
jQuery function:
<script>
function formSubmit(){
var name = document.getElementById("name").value;
var message = document.getElementById("message").value;
var dataString = 'name='+ name + '&message=' + message;
jQuery.ajax({
url: "submit.php",
data: dataString,
type: "POST",
success: function(data){
$("#myForm").html(data);
},
error: function (){}
});
return true;
}
</script>
For more details and sample Visit:
http://www.spiderscode.com/simple-ajax-contact-form/
To avoid multiple formdata sends:
Don't forget to unbind submit event, before the form submited again,
User can call sumbit function more than one time, maybe he forgot something, or was a validation error.
$("#idForm").unbind().submit( function(e) {
....
If you're using form.serialize() - you need to give each form element a name like this:
<input id="firstName" name="firstName" ...
And the form gets serialized like this:
firstName=Chris&lastName=Halcrow ...
I find it surprising that no one mentions data as an object. For me it's the cleanest and easiest way to pass data:
$('form#foo').submit(function () {
$.ajax({
url: 'http://foo.bar/some-ajax-script',
type: 'POST',
dataType: 'json',
data: {
'foo': 'some-foo-value',
'bar': $('#bar').val()
}
}).always(function (response) {
console.log(response);
});
return false;
});
Then, in the backend:
// Example in PHP
$_POST['foo'] // some-foo-value
$_POST['bar'] // value in #bar
This is not the answer to OP's question,
but in case if you can't use static form DOM, you can also try like this.
var $form = $('<form/>').append(
$('<input/>', {name: 'username'}).val('John Doe'),
$('<input/>', {name: 'user_id'}).val('john.1234')
);
$.ajax({
url: 'api/user/search',
type: 'POST',
contentType: 'application/x-www-form-urlencoded',
data: $form.serialize(),
success: function(data, textStatus, jqXHR) {
console.info(data);
},
error: function(jqXHR, textStatus, errorThrown) {
var errorMessage = jqXHR.responseText;
if (errorMessage.length > 0) {
alert(errorMessage);
}
}
});
JavaScript
(function ($) {
var form= $('#add-form'),
input = $('#exampleFormControlTextarea1');
form.submit(function(event) {
event.preventDefault();
var req = $.ajax({
url: form.attr('action'),
type: 'POST',
data: form.serialize()
});
req.done(function(data) {
if (data === 'success') {
var li = $('<li class="list-group-item">'+ input.val() +'</li>');
li.hide()
.appendTo('.list-group')
.fadeIn();
$('input[type="text"],textarea').val('');
}
});
});
}(jQuery));
HTML
<ul class="list-group col-sm-6 float-left">
<?php
foreach ($data as $item) {
echo '<li class="list-group-item">'.$item.'</li>';
}
?>
</ul>
<form id="add-form" class="col-sm-6 float-right" action="_inc/add-new.php" method="post">
<p class="form-group">
<textarea class="form-control" name="message" id="exampleFormControlTextarea1" rows="3" placeholder="Is there something new?"></textarea>
</p>
<button type="submit" class="btn btn-danger">Add new item</button>
</form>
There's also the submit event, which can be triggered like this $("#form_id").submit(). You'd use this method if the form is well represented in HTML already. You'd just read in the page, populate the form inputs with stuff, then call .submit(). It'll use the method and action defined in the form's declaration, so you don't need to copy it into your javascript.
examples