toString() removes the zero at the right [duplicate] - javascript

This question already has answers here:
toString and valueOf truncates trailing 0s after decimal
(2 answers)
Closed 9 years ago.
I have a number, 2.0e-14, and I want to convert it to string. I'm using (2.0e-14).toString(), and what I get is the string 2e-14, because it's removing the zeroes at the right.
Is there any way of keep the zero at the right than to manipulating the string?

Use the Number toPrecision method.
(2.0e-14).toPrecision(2)

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Try with parseInt()
If parseInt encounters a character that is not a numeral in the specified radix, it ignores it and all succeeding characters and returns the integer value parsed up to that point. parseInt truncates numbers to integer values. Leading and trailing spaces are allowed.
let string = "13th";
string = parseInt(string);
console.log(string);

Why is js parseInt not working for this particular integer? [duplicate]

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Closed 4 years ago.
Here is my string: "6145390195186705543"
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I have a string like 12345 and I need to explode it to [1,2,3,4,5]. Normally, I would use split, but there are no separators in here. I could use substr (getting length, making loops), but I will probably have a lot of those strings, so it may not be good for performance. What can I do?
Simply use an empty string as a delimiter:
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Converting from number to string gives strange number in Javascript [duplicate]

This question already has answers here:
How do I work around JavaScript's parseInt octal behavior?
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So I saw this strange scenario. I wanted to convert a number to a String in Node.js and I got the following.
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Any numeric constant prefixed with a 0 is an octal literal (assuming all its digits are valid octal digits).
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How to check two values of text box using JavaScript function [duplicate]

This question already has answers here:
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I have used document.getElementByID("textboxname").value to compare but it checks character by character as it considers integer value a string value.
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Thanks in advance
use parseInt("your string") to convert it into valid integer
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