Best way to search a row in google spreadsheet - javascript

So, been looking at search functions in google spreadsheet, and find it difficult to figure out a smooth way to find which column on row one contain a specific value.
To explain a bit more, its a simple allocation spreadsheet, basically who works as what on which project for how long, and as we have a number of different pipelines, I wanted the pipelines separated. So I created a sheet for each, set up the first five collumns so contain all kind of useful info (like resource, project, project role, chargeable, client) then the rest of the collumns represents weeks, so each collumn have the date of the Monday, and all eight sheets have the same setup, so column 6 to 28 contains the date of the following Monday, allowing me to predict resource allocation a total of 22 weeks or thereabouts.
The next step is to create a report (sheet 1) which tells me by resource how busy they are, either as summary or as detailed+summary, and put some colour in if anyone is allocated to many or to few days in a specific week.
I also wanted to view to allow me to specify a date, easy enough, two drop down menus. First is the list of dates row one sheet two, second one is the same list, so the user can in specify 27/01/2014 - 03/04/2014 from the drop down list.
Now comes my issue, I want to retrieve the numerical value of the columns matching the date, so if the start date is in column F I want a variable with 6 in. And end date is in M thats 14.
Anyone have any good suggestions how this can be done?
Tried reading the row and searching it as an array, did not work particularly well
var vcSheet = SpreadsheetApp.getActiveSpreadsheet().getSheetByName("Office");
var range = vcSheet.getRange(1,1,1,28);
var dates = range.getValue();
var strCol = dates.indexOf(dtStart);
var stpCol = dates.indexOf('Task');
Browser.msgBox('Found start col on ' + strCol + ' end col on ' + stpCol);

Have you tried .getValues(), as opposed to .getValue()? Maybe something like;
var dates=range.getValues();
for (i in dates[0]) {
if (dates[0][i].indexOf(dtStart)>-1) { some stuff }
}

Related

TextFinder StartFrom() not working correctly

I've been trying to tackle a small line of code for some time now, with no luck.
I have a text finder, which I need to start from the 3rd column (C)
var textFinder = responses.createTextFinder(tdate); var search_row = textFinder.startFrom(3).findNext().getRow();
I've also tried
textFinder.startFrom('C').findNext().getRow()
and
textFinder.startFrom(1,3,responses.getLastRow()).findNext().getRow()
Any help would be greatly appreciated, all I need is to get the row number of tdate - searched in column 3
startFrom(range) accepts range as the only argument. You can get a range from sheet or spreadsheet
textFinder.startFrom(responses.getRange('C1')).findNext().getRow()
Note that search starts from "C1" , but not restricted to column C.
Related Answer

Auto-increment dates in two cells if date has passed

Overview:
I'm not a programmer but I managed to get some serious coding into a Gsheets to track my teams project, so we have multiple-variable dropdown menus and integration with google calendar to track projects development and all that.
Why I'm at stackoverflow:
I kind of lack the knowledge to start the code from the scratch, I usually find spare parts of code through forums on the internet and clue them together and it usually works surprisingly well, but this time I couldn't find much informtation.
What I need:
I have 5 cells, and we can put as below,
Date start - Date end - date code* - number** - Priority***
*script to add the date range to gcalendar
** & *** The number is an array that's based on the word written on the priority cell, for example: If priority is written Weekly them
the number colunm will show 7 on the cell to the left and them it
goes. (monthly = 30 and blablabla...)
So I'd like to know if someone could give a hand with a script that would work (at least in my head) as following:
If I set the priority to weekly, it will show 7 on the number colunm and them, every time the "Date end" has passed, it will automatically add 7 days to the "Date start" and "Date end" again.
That way I could keep the projects on a loop where I'll be able to track them constatly.
Thanks in advance for any insights provided,
ps: I've seen some posts about this on sql, but I have no idea also on how to take advantage of the proposals that were presented there.
Edit:
Spreadsheet picture
eDIT2:
Spreadsheet with a increment colunm
Pertinent to the data set and description, you probably do not need any VBA as the increment could be achieved by adding +1 to the reference pointing to previous cell. For example, assuming cell A1 is formatted as Date, enter in cell B1: =A1+1 , then in cell C1: =B1+1 and so on. The result should be as shown below
A B C
9/1/2017 9/2/2017 9/3/2017
It could be further extended with simple logic allowing do display incremented value only if the previous cell is not empty, like : =IF(A1,A1+1,"")
In your case, it could be cell F1 containing =IF(E1,E1+1,"").
FYI, the underlying value of Date is just an Integer value (Time is represented as decimal part), so the arithmetic operations could be applied.
More generic solution would be based on the Excel DATE() Worksheet formula as shown in sample shown below (adding 1 mo. to the date entered in cell A1):
=DATE(YEAR(A1), MONTH(A1)+1, DAY(A1))
In order to implement additional logic, you may consider using Excel Worksheet IF() statement like for example, cell B1 containing:
=A1+IF(C1="week",7,1)
A B C
9/1/2017 9/8/2017 week
so based on the IF() condition it will add either 7 days if C1 contains the word "week" or 1 day otherwise. It could be further extended with nested IF().
Hope this will help.

Search with multiple range values on same item

I'm implementing a search filter via instantsearch.js with a range slider.
The slider filters a range of years based on the year data column of each item. In this DB tho there are some items with no precise year, but a "supposed" period, like "circa XVIII sec" or "End of 1910s". This means that for these items there is not a single year to filter but rather multiple years.
Let's say for ex. that I wish to filter results in a range of years from 1874 to 1930 and I have an item with "Second half 19th century" in the year field. As you can tell it should result in the match, since any year from 1851 to 1900 is correct for this item.
How should I treat this type of data to be part of this filter range?
How should I structure the data in the year column of this DB?
Should I use some script logic in the algolia javascript search rather than use a special way of structuring the data or indexing?
I was thinking of a logic like:
"If value of item is not just digits, convert it to a range of years.
Then check if the range of these years can match with the filter required in
the slider"
I can't really tell how to do this, and it looks a bit cumbersome and silly to me. I'm pretty sure this is no new issue to face in DB data design, so there has to be a proper way to address it.
I tried searching around but I don't even know how to proper word this thing I'm asking.. if you have suggestions to edit the title please do tell me!
I'm using a MySQL database along with PHP.
With Algolia, you'll need to convert this values to timestamp then you would be able to use numericFilter and add a range slider or numeric refinement list component to your UI.
Also the attribute must be defined as an attributesForFaceting in your index configuration.
https://community.algolia.com/instantsearch.js/documentation/#rangeslider
https://community.algolia.com/instantsearch.js/documentation/#numericrefinementlist
Considering your year as a range, you can either add a beggining and an end attribute to those fields. Example:
EventTimes
id SMALLINT NOT NULL PRIMARY,
yearEnd DATETIME,
yearStart DATETIME
In this case, the end and the start will be equal (I use null ends), when the event is an specific time, and becomes a range when the two fields are filled.
When SELECTing, you can always check for both fields, without a significant loss of speed or accuracy. Then check either for specific time, range of times, or if an event begins, ends, re-begins, re-ends and so on, you can check for different fields within the same table.

jQuery issue with the reservation form

I need some help to create a jquery script that will handle the car reservation form.
The form have fields such as the “Start date, End date (in datepicker), localization (city) of rent and return the car with the list of direction and the number of days for which the customer borrowed car. There is only one dependency. If the car is rented for less than 4 days the city of borrowing and returning is the same, and if the number of days are greater than 4 days locations of returning car may be different.
The whole form works pretty well, to the point where client chose the city and the number of days is less than 4. The value of first City is “copying” to the second City field (and other values of city are disabled), and that is correct. Under the first city appear the field with directions, but under second city the list of direction not showing (but should, because the city is selected).
When I change the date and the values of total day is greater then 4 and in second field all of city are active and if I select one of them the directions are showing up, and that is ok, but I have to “click” the City. When it is inserting by the script the list of direction are disabled.
Could anyone help me with this?
The workin example: http://jsfiddle.net/amarcinkowski/EbdFY/
You could "force" the change event to execute with
$('#return_car').change()
And the direction input will be shown.
At the first, you duplicate your bindings of change event on #return_car and #get_car. Delete or comment this rows:
$('select#return_car').change(compute);
$('select#get_car').change(compute);
At the second, as Maxime L writes:
if ( parseInt($("#finish_day").val()) < 4 ) {
$('#return_car')
.children('#return_car option[value=' + $('#get_car').val() + ']')
.attr('selected', true)
.siblings().attr('disabled', true);
if ($('#return_car').val()) $('#return_car').change(); // or $('#return_car').trigger('change');
}

Select random combinations of list elements such that no list element is present in more than one selection (SQL)

I'm running a bit out of ideas how to realize a small project.
What I have:
- a list of users including their ID and name
What I want to achieve:
- I want to combine each user on this list with another user such that no user is assigned to more than one user and no user is assigned to herself.
- The combination has to be random and has to take past combinations into account
My idea so far:
- I have this information:
User (A,B,C,D) (the actual number of users ranges between 50 and 400)
Possible combinations: (A-B,A-C,A-D,B-C,B-D,C-D)
Random draw(1): (A-B, C-D)
Random draw(2): (A-D, B-C)
Random draw(3): (A-C, B-D)
I was able to get all possible combinations using a join of the user table with itself.
I guess I can take previous draws into account by storing the draws in a separate table and limit the possible combinations to those that are not in this special table.
What I can't do:
- I don't know how to randomly draw from the list of possible combinations such that every user is part of only one combination per draw (e.g. A-B,A-D in the same draw is not allowed)
- I try to use sql or a bit php for this (maybe javascript)
Thanks for any help.
An easy solution:
Create a temporary table with a row for each pairing. Loop over the list of users skipping a random number of empty rows from 1 to the number of empty rows -- insert user.
Easy solution number 2:
Given N users. Assign each user a unique random number from 1 to N (remove randomly from the set of all numbers from 1 to N). Pair each user with from 1-N/2 with user from N/2+1 to N.
The solution is the problem "Bergr (s) table", see Wikipedia: http://en.wikipedia.org/wiki/Round-robin_tournament.
The latest (best) solution is from Professor Frončeka (Dalibor Froncek, a professor at the University of Minnesota in the US).
For custom solutions, look in the table of solutions n ^ 2.

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