Develop Reference

How can i call a php function on a dynamically created html element in .js file

This is my product.php file which include the following php function
<?php
function getOfferName($conn,$companyID){
$sql="SELECT `id`, `offer_name`, `offer_discount` FROM `oiw_product_offers`
WHERE `company_id`='$companyID'";
if ($result=mysqli_query($conn,$sql)) {
while ($row=mysqli_fetch_assoc($result)) {
?>
<option value="<?php echo $row['id'] ?>"><?php echo $row['offer_name'] ?></option>
<?php
}
}
}
?>
This product.php file include the custom-js.js file in which i am creating a html element dynamically (Select dropdown).
$('.offerCheckBox').on('change', function() {
var id=$(this).data('id');
if (!this.checked) {
var sure = confirm("Are you sure want to remove offer ?");
this.checked = !sure;
}else{
$(this).parent().parent().append('<select name="" id=""><?php getOfferName($conn,$companyID) ?></select>');
}
});
Here i call php function getOfferName but it is showing me output like this
enter image description here
<select name="" id=""><!--?php getOfferName($conn,$companyID) ?--></select>

You can do by below code
getdata.php
if($_POST['action'] == 1){
$companyID = $_POST['id'];
$sql="SELECT `id`, `offer_name`, `offer_discount` FROM `oiw_product_offers`
WHERE `company_id`='$companyID'";
if ($result=mysqli_query($conn,$sql)) {
$html = '';
while ($row=mysqli_fetch_assoc($result)) {
$html .= '<option value="'.$row['id'].'">'.$row['offer_name'].'</option>';
}
}
echo json_encode($html);
exit(0);
}
?>
Ajax Call to Get Data
$('.offerCheckBox').on('change', function() {
var id=$(this).data('id');
if (!this.checked) {
var sure = confirm("Are you sure want to remove offer ?");
this.checked = !sure;
}else{
$.ajax({
url: "getdata.php",
type: 'POST',
data: {id:id,action:1},
dataType: "json",
contentType: false,
cache: false,
processData: false,
success: function(response) {
if (response) {
$(this).parent().parent().append('<select name="" id="">'+response+'</select>');
} else {
//Error
}
return true;
}
});
}
});

the JavaScript file is on the client side writing code in this file will not will not create a server call that runs the PHP file.
if you want to combine JavaScript with a server call you should use ajax.
JavaScript:
$('.offerCheckBox').on('change', function() {
var id=$(this).data('id');
if (!this.checked) {
var sure = confirm("Are you sure want to remove offer ?");
this.checked = !sure;
} else {
let fd = new FormData();
let companyID = $(this).val();
fd.append('companyID', companyID);
$.ajax
({
url: "getOffer.php",
type: "POST",
data: fd,
processData: false,
contentType: false,
complete: function (results) {
let response = JSON.parse(results.responseText);
my_function.call(this, response);
}
});
}
});
// in this function you will put the append of the select box that php has created
function my_function(response) {
console.log("response", response);
}
PHP code (the file name is : getOffer.php)
<?php
$companyID = $_REQUEST['companyID'];
$options = array[];
$sql="SELECT `id`, `offer_name`, `offer_discount` FROM `oiw_product_offers`
WHERE `company_id`='$companyID'";
if ($result=mysqli_query($conn,$sql)) {
while ($row=mysqli_fetch_assoc($result)) {
$options[$row['id']] = $row['offer_name'];
}
}
$resBack = (json_encode($options, JSON_UNESCAPED_SLASHES | JSON_UNESCAPED_UNICODE));
echo ($resBack);
?>
Now in the callback function my_function as we wrote above you have an array of key value pair from the PHP.
iterate on this array in JavaScript build your option select items and append them to the select box.

How to add php form validation with ajax error handling

How can I add validation and php error handling with ajax. Now the success message come correctly but how can I implement error message on it? I might need to add some php validation please help.
Here is my JS.
$('#edit_user_form').bind('click', function (event) {
event.preventDefault();// using this page stop being refreshing
$.ajax({
data: $(this).serialize(),
type: $(this).attr('method'),
url: $(this).attr('action'),
success: function () {
$(".msg-ok").css("display", "block");
$(".msg-ok-text").html("Profile Updated Successfully!!");
},
error: function() {
//Error Message
}
});
});
PHP
<?php
require_once 'db_connect.php';
if($_POST) {
$fname = $_POST['fname'];
$lname = $_POST['lname'];
$index_no = $_POST['index_no'];
$contact = $_POST['contact'];
$id = $_POST['id'];
$sql = "UPDATE members SET fname = '$fname', lname = '$lname', index_no = '$index_no', contact = '$contact' WHERE id = {$id}";
if($connect->query($sql) === TRUE) {
echo "<p>Succcessfully Updated</p>";
} else {
echo "Erorr while updating record : ". $connect->error;
}
$connect->close();
}
?>

ajax identifies errors based of status code, your php code will always return status code 200 which is success, even when you get error in php code unless its 500 or 404. So ajax will treat response as success.
if you want to handle php error, make following changes in your code
<?php
require_once 'db_connect.php';
if($_POST) {
$fname = $_POST['fname'];
$lname = $_POST['lname'];
$index_no = $_POST['index_no'];
$contact = $_POST['contact'];
$id = $_POST['id'];
$sql = "UPDATE members SET fname = '$fname', lname = '$lname', index_no = '$index_no', contact = '$contact' WHERE id = {$id}";
if($connect->query($sql) === TRUE) {
echo "true";
} else {
echo "false";
}
$connect->close();
}
?>
$('#edit_user_form').bind('click', function (event) {
event.preventDefault();// using this page stop being refreshing
$.ajax({
data: $(this).serialize(),
type: $(this).attr('method'),
url: $(this).attr('action'),
success: function (res) {
if(res == 'true') {
//success code
} else if(res == 'false') {
//error code
}
},
error: function() {
//Error Message
}
});
});

Select value into the textbox FROM ajax using php

I am trying to get the results from the database whether username is available or not . But it is not giving any results i am not getting ajax response this is the html code
<form id="user_form">
<input placeholder="username here" type="text" name="ajax-data" id="ajax-data">
<input type="submit" name="btnSubmit" id="btnSubmit" Value="Submit">
</form>
<span class="php_responce_here"></span>
This is the ajax code which i have used
$(document).ready(function()
{
$("form#user_form").click(function()
{
var textboxvalue = $('input[name=ajax-data]').val();
$.ajax(
{
type: "POST",
url: 'second.php',
data: {ajax-data: textboxvalue},
success: function(result)
{
$(".php_responce_here").html(result);
}
});
});
});​
</script>
final code of php where i have used the validation and the query to find whether the username is available in the database or not the problem is that it is not giving any of the result
<?php
error_reporting(0);
require "config.php";// configuration file holds the database info
$user_name = $_POST['ajax-data']; // textbox in the html
if($user_name)
{
$usernamecheck= mysql_query("SELECT count(*) FROM users WHERE username='$user_name'");
$check= mysql_fetch_row($usernamecheck);
if($check[0]==0)
{
if($user_name!=""){
if(strlen($user_name)>25){
echo "You have reached the maximum limit";
}
else{
echo "User name is valid";
}
}
else
{
echo "username is empty";
}
}
else{
echo "Username Already Taken";
}
}
?>

should be submit event not click:
$("form#user_form").submit(function(e) {
e.preventDefault();
var textboxvalue = $('input[name=ajax-data]').val();
$.ajax(
{
type: "POST",
url: 'second.php',
data: { "ajax-data": textboxvalue },
success: function(result) {
$(".php_responce_here").html(result);
}
});
});
and as #Cyril BOGNOU pointed out;
data: { "ajax-data": textboxvalue }

You should too add data type to be returned with the parameter if you want to return JSON for example
dataType: 'JSON',
and Yes I think you should better write
data: { "ajax-data": textboxvalue }
So the update should be
$(document).ready(function()
{
$("form#user_form").click(function()
{
var textboxvalue = $('input[name=ajax-data]').val();
$.ajax(
{
type: "POST",
url: 'second.php',
dataType: 'JSON',
data: {"ajax-data": textboxvalue},
success: function(result)
{
$(".php_responce_here").html(result.message);
}
});
});
});
and return json string from PHP script
<?php
error_reporting(0);
require "config.php"; // configuration file holds the database info
$user_name = $_POST['ajax-data']; // textbox in the html
if ($user_name) {
$usernamecheck = mysql_query("SELECT count(*) FROM users WHERE username='$user_name'");
$check = mysql_fetch_row($usernamecheck);
if ($check[0] == 0) {
if ($user_name != "") {
if (strlen($user_name) > 25) {
$message = "You have reached the maximum limit";
} else {
$message = "User name is valid";
}
} else {
$message = "username is empty";
}
} else {
$message = "Username Already Taken";
}
echo json_encode(["message" => $message]);
}
?>

NOTE : mysql is deprecated. you should use mysqli or PDO
There are some mistakes in your code. check the below code. it should work.
<script>
$(document).ready(function () {
$("form").submit(function (event) {
var textboxvalue = $("#ajax-data").val();
$.ajax({
data: {ajaxdata: textboxvalue},
type: "POST",
url: 'second.php',
success: function (result)
{
$(".php_responce_here").html(result);
}
});
return false;
});
});
</script>
You can not create variable ajax-data with -.
PHP
$usernamecheck = mysql_query("SELECT * FROM users WHERE username='$user_name'");
$check = mysql_num_rows($usernamecheck);
you should use mysql_num_rows instead of mysql_fetch_row. it will auto calculate the rows.
Check working example

Empty page? Nothing prints out?
<?php
error_reporting(-1);
ini_set('display_errors', 1);
require "config.php";// configuration file holds the database info
if(isset($username = $_POST['ajax-data'])){
if($l = strlen($username) <= 25 && $l > 2){
$sql = "SELECT * FROM users WHERE username='$username'"; // wide open for SQL injections. use mysqli or PDO instead.
if($rsl = mysql_query($sql) != false){ // ALWAYS verify if your query's ran successfully.
if(mysql_num_rows($rsl) != 0){
echo 'Username already exists';
} else {
echo 'Username is available';
}
} else {
echo 'Query failed: ' . mysql_error();
}
} else {
echo $l > 25 ? 'Reached limit' : 'Needs to be longer';
}
} else {
echo "post['ajax-data'] not set<\br>";
print_r($_POST);
}
?>
Then there is your Javascript code that I have questions on. Yet you have a submit button but you want to check if its valid upon change?
$(document).ready(function(){
$("#user_form").submit(function(event){
event.preventDefault();
$.ajax({
url: "second.php",
type: "post",
data: $(this).serialize(),
success: function(result){
$(".php_responce_here").html(result);
}
});
});
});​

Codeigniter if data inserted return true to json again ? it's possible?

I'm using json to post data to controller but i can't do some effects if data is inserted to database successfully,
This if statement does not work in this javascript code ?
I mean .like-btn .html() does not work but data inserted in database ?
My experience in Javascript between 0 and 10 :D
Using Codeigniter 3.0.3
Here's my javascript
<script type="text/javascript">
$(document).ready(function() {
$(".like-btn").click(function(event) {
var liker_id = "<?php echo $this->session->userdata('id'); ?>";
var post_id = $(this).attr('post-id');
jQuery.ajax({
type: "POST",
url: "<?php echo base_url('home/AddLike'); ?>",
dataType: 'json',
data: {liker_id: liker_id, post_id: post_id},
success: function(res) {
if (res)
{
$('.like-btn[post-id = '+post_id+']').html('<span class="fa fa-check"></span> Liked');
}
}
});
});
});
</script>
Here's my controller
function AddLike() {
$this->load->helper('string');
$this->load->model('users_model');
$this->users_model->Add_like();
}
And here's my model method
function Add_like() {
$this->db->where('liker_id', $this->input->post('liker_id'));
$this->db->where('post_id', $this->input->post('post_id'));
$query = $this->db->get('likes_table');
if($query->num_rows() == 0) {
$data = array(
'liker_id' => $this->input->post('liker_id'),
'post_id' => $this->input->post('post_id')
);
$this->db->insert('likes_table', $data);
return true;
}
}

Just change below on your model:
change return to echo
function Add_like() {
$this->db->where('liker_id', $this->input->post('liker_id'));
$this->db->where('post_id', $this->input->post('post_id'));
$query = $this->db->get('likes_table');
if($query->num_rows() == 0) {
$data = array(
'liker_id' => $this->input->post('liker_id'),
'post_id' => $this->input->post('post_id')
);
$this->db->insert('likes_table', $data);
echo true;
}
}

You should debug your code of ajax response. And you should check whether you are getting any response in res variable.
Important
1)In if condition you should use double quotes("") to wrap variable post_id like
$('.like-btn[post-id = "'+post_id+'"]').html...
2) Another thing is you should return "true" as string not as boolean and check with string in ajax success block.

Solved add this line at the end of controller method
echo true;
code after edit
function AddLike() {
$this->load->helper('string');
$this->load->model('users_model');
$this->users_model->Add_like();
echo true;
}

Ajax login issues

I'm having issues with an Ajax login function. There was another question similar to mine that I was able to find but it proved no use.
I have no idea what is the issue, this works on another program as well with no issues, hopefully someone can see my mistake
From testing I think the issue is in the "checkLogIn" function because when I run the application the alert within the function shows
Ajax:
$("#checkLogIn").click(function()
{
$.ajax({
type: 'POST',
contentType: 'application/json',
url: rootURL + '/logIn/',
dataType: "json",
data: checkLogIn(),
})
.done(function(data)
{
if(data == false)
{
alert("failure");
}
else
{
alert("Success");
$.mobile.changePage("#page");
}
})
.always(function(){})
.fail(function(){alert("Error");});
});
function checkLogIn()
{
alert();
return JSON.stringify({
"userName": $("#enterUser").val(),
"password": $("#enterPass").val(),
});
}
I'll also include the PHP but the PHP works 100% after testing it.
PHP:
$app->post('/logIn/', 'logIn');
function logIn()
{
//global $hashedPassword;
$request = \Slim\Slim::getInstance()->request();
$q = json_decode($request->getBody());
//$hashedPassword = password_hash($q->password, PASSWORD_BCRYPT);
$sql = "SELECT * FROM users where userName=:userName AND password=:password";
try {
$db = getConnection();
$stmt = $db->prepare($sql);
$stmt->bindParam("userName", $q->userName);
$stmt->bindParam("password", $q->password);
$stmt->execute();
//$row=$stmt->fetch(PDO::FETCH_ASSOC);
//$verify = password_verify($q->password, $row['password']);
$db = null;
//if($verify == true)
//{
// echo "Password is correct";
//}
//else
// echo "Password is incorrect";
echo "Success";
} catch (PDOException $e) {
echo $e->getMessage();
}
}
I have commented out any and all hashing until I can get this working properly

There is no problem with the ajax script. From my assumption you always get Error alert. That is because you added dataType: "json", which means you are requesting the response from the rootURL + '/logIn/' as json Object. But in the php you simply echoing Success as a plain text. That makes the ajax to get into fail function. So, You need to send the response as json. For more details about contentType and datatype in ajax refer this link.
So you need to change echo "Success"; to echo json_encode(array('success'=>true)); in the php file. Now you'll get Success alert. Below I added a good way to handle the json_encoded response in the php file.
$app->post ( '/logIn/', 'logIn' );
function logIn() {
global $hashedPassword;
$request = \Slim\Slim::getInstance ()->request ();
$q = json_decode ( $request->getBody () );
$hashedPassword = password_hash($q->password, PASSWORD_BCRYPT);
$sql = "SELECT * FROM users where userName=:userName";
try {
$db = getConnection ();
$stmt = $db->prepare ( $sql );
$stmt->bindParam ( "userName", $q->userName );
$stmt->execute ();
$row=$stmt->fetch(PDO::FETCH_ASSOC);
$verify = false;
if(isset($row['password']) && !empty($row['password']))
$verify = password_verify($hashedPassword, $row['password']);
$db = null;
$response = array();
$success = false;
if($verify == true)
{
$success = true;
$response[] = "Password is correct";
}
else
{
$success = false;
$response[] = "Password is incorect";
}
echo json_encode(array("success"=>$success,"response"=>$response));
} catch ( PDOException $e ) {
echo $e->getMessage ();
}
}
And I modified the ajax code. There I showed you how to get the response from the json_encoded Object.
$("document").ready(function(){
$("#checkLogIn").click(function()
{
var post_data = JSON.stringify({
"userName": $("#enterUser").val(),
"password": $("#enterPass").val(),
});
$.ajax({
type: 'POST',
contentType: 'application/json',
url: rootURL + '/logIn/',
dataType: "json",
data: post_data,
})
.done(function(data)
{
// data will contain the echoed json_encoded Object. To access that you need to use data.success.
// So it will contain true or false. Based on that you'll write your rest of the code.
if(data.success == false)
{
var response = "";
$.each(data.response, function(index, value){
response += value;
});
alert("Success:"+response);
}
else
{
var response = "";
$.each(data.response, function(index, value){
response += value;
});
alert("Failed:"+response);
$.mobile.changePage("#page");
}
})
.always(function(){})
.fail(function(){alert("Error");});
});
});
Hope it helps.