I want to submit a form to action page which is a different site however i don't want to be directed to the action page. i've tried everything but its not working for me, i've heard about ajax does the job can someone give me examples
What I want:
i want to submit a form but not be redirected
submit the form as i'm being redirected to action page i get redirected to my original page.
My code:
<form id="user-login-form" accept-charset="UTF-8" action="http://xxxxxn" method="post">
<div>
<div class="user_login_block&op=Log+in"><label for="edit-name"><span class="form-required" title="This field is required.">*</span></label>
<input type="hidden" />
<div>
<div class="user_login_block&op=Log+in"><label for="edit-name"><span class="form-required" title="This field is required.">*</span></label>
<input type="hidden" />
<input class="form-text required" id="edit-name" type="hidden" maxlength="60" name="name" size="15" value="xxxxxx2" /></div>
<div class="form-item form-type-password form-item-pass"><label for="edit-pass"></label>
<input class="form-text required" id="edit-pass" type="hidden" maxlength="60" name="pass" size="15" value="9sQ&zW#7PKhpqbzcCFz9jvY" />
<input type="hidden" /></div>
</div>
<input type="hidden" name="form_build_id" value="form-odWc3MFMsKIL_5vCQtPmiv0AVf0tFwBu7eP2-8" />
<input type="hidden" name="form_id" value="user_login_block" />
<div class="form-actions form-wrapper" id="edit-actions"><input class="form-submit" id="edit-submit" type="submit" name="op" value="submit" />
Check the below example:
check this link:
http://susheel61.0fees.net/ajaxtest.php
NOTE:
This is basic a example for ajax. You cant do it many other ways like using $.post, $.get etc. but $.ajax has many options like showing a loading image before the content loads.
html:
<!doctype html>
<html lang="en">
<head>
<meta charset="utf-8">
<title>ajax example</title>
<script src="http://code.jquery.com/jquery-1.9.1.js"></script>
</head>
<body>
<div id="message"></div>
<form id="myform" action="test.php">
<input type="text" name="test"/>
<input type="submit" value="submit"/>
</form>
<div id="response"></div>
<script>
$(function() {
$("#myform").on("submit", function(e) {
e.preventDefault();
$.ajax({
url: $(this).attr("action"),
type: 'POST',
data: $(this).serialize(),
beforeSend: function() {
$("#message").html("sending...");
},
success: function(data) {
$("#message").hide();
$("#response").html(data);
}
});
});
});
</script>
</body>
</html>
If nothing works, you could redirect to a hidden iframe.
<iframe id="iframe" name="my_iframe"></iframe>
<form class="form" id="userform" target="my_iframe">
try this:
$('form').submit(function(event){
var serialObject = $(this).serialize();
//ex for post request
$.post('path_to file',{
parameters:serialObject
},function(data){
// do something after submitting
});
});
event.preventDefault()
In the php, you can redirect to back to the form by using headers:
header('Location: yourwebsite.com');
Hopefully this works for you
Related
I am trying to code a post form which sends the form to another window and then reloads the window in which the form was submitted in.
page2 is not on the same domain as page1 and i can't access the code of page2.
My current form on page1 looks like this:
<form target="_blank" method="post" action="https://www.page2.com">
<input type="hidden" name="input1" value="input1value">
<input type="submit" value="Submit" onclick="function1();window.location.refresh()">
</form>
The form is being send successfully and the function is being executed but the tab won't refresh.
Try this..
<form target="_blank" method="post" action="https://www.page2.com">
<input type="hidden" name="input1" value="input1value">
<input type="submit" value="Submit"onclick="window.location.reload();">
</form>
While your use case is not obvious at the moment, this might be useful.
Handle submit using script, prevent the default action, post the form and then reload the page.
<form id="myForm" target="_blank">
<input type="submit" value="Submit" onclick="wait(event);" >
</form>
script
function wait(e)
{
e.preventDefault();
document.getElementById('myForm').submit();
console.log('done!')
window.location.reload();
}
try this code this will refresh you page 1.
function function_one(){
$.ajax({
url: 'show.php',
type: 'POST',
data: {'value': $("#input1").val()},
success: function(data){
window.location.refresh();
}
});
}
<form target="_blank">
<input type="text" name="input1" value="input1value" id="input1">
<input type="submit" value="Submit" onclick="function_one()">
</form>
<p id="asfasf"></p>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
Html:
<form class="allforms" method="POST" action="/auth/myaccount/personal">
<input type="hidden" name="_method" value="PATCH">
...
</form>
<button id="allsubmit" class="btn btn-info">Continue</button>
jquery:
$(document).ready(function(){
$("#allsubmit").click(function(){
$('.allforms').submit();
});
});
I have 3 forms in my html code like above.
My button is out of any my forms.
How to have one submit button for all my forms. I tried the click function but it doesn't work. Why?
Form submission is a synchronous action, so when you submit a form and then immediately submit a different form in your page, the first form's submission is canceled.
What you can do instead is make sure the forms are submitted asynchronous (using ajax):
$(function() {
$("#allsubmit").click(function(){
$('.allforms').each(function(){
valuesToSend = $(this).serialize();
$.ajax($(this).attr('action'),
{
method: $(this).attr('method'),
data: valuesToSend
}
)
});
});
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<form class="allforms" method="POST" action="">
<input type="hidden" name="_method" value="PATCH1">
<input type="submit" />
</form>
<br />
<form class="allforms" method="POST" action="">
<input type="hidden" name="_method" value="PATCH2">
<input type="submit" />
</form>
<br />
<form class="allforms" method="POST" action="">
<input type="hidden" name="_method" value="PATCH3">
<input type="submit" />
</form>
<br />
<button id="allsubmit" class="btn btn-info">Continue</button>
A few notes
This will not work with forms that have file-uploading (enctype="multipart/form-data")
You need to decide what to do after the submission is done (because nothing in the page will change).
You can't submit forms in stackoverflow-snippets, so don't try to run this here :)
I didn't test it but try this one:
$("#allsubmit").on("click", function(){
$('.allforms').each(function(){
$(this).submit();
});
});
Note that all of your forms have to have class="allforms" attribute
I know this question has been asked a lot, but there doesn't seem to be an answer for me. I'm sorry if I'm just really dumb, but I've been stuck for a day now..
I want to select a table row(see below), and then delete that user. Since I want to have multiple form's to interact with the table I can't place them in one form.
$("#clickMe").click(function () {
$(".myForms").trigger('submit');
});
$('.myForms').submit(function () {
console.log("SWAGGG");
return false;
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<form id="listForm" action="index.php?p=admin" method="POST">
<?php
$userQuery = "SELECT * FROM usr2";
$row_userQuery = $dbportal->query($userQuery);
if(isset($row_userQuery) && !empty($row_userQuery))
{
//row[0] = ID
//row[1] = username(abbrevation)
//row[2] = admin? 0=normale user 1=admin
echo'
<table id="myTable" class="table table-striped">
<tr><td></td><td>User ID</td><td>username</td><td>Role</td></tr>';
foreach ($row_userQuery as $row)
{
echo'
<tr>
<td id="tdSelect"> <input type="checkbox" name="selectedUser[]" value="'. $row[0] .'" />
<td>'. $row[0] .'</td>
<td>'. $row[1] .'</td>
<td>'. $row[2] .'</td>
</tr>';
}
echo'</table>';
}
?>
<input type="hidden" name="action" value="listForm">
</form>
<form id="deleteForm" class="myForms" action="index.php?p=admin" method="POST">
<div class="leftTextBox">
<p>user ID:</p>
<p class="margin">gebruikersnaam:</p>
</div>
<div class="rightTextBox">
<input class="form-control" type="text" name="userID" placeholder="user ID">
<input class="form-control" type="text" name="login" placeholder="gebruikersnaam" style="margin-top: 8px;">
</div>
<input type="hidden" name="action" value="deleteForm">
</form>
<button id="clickMe" class="btn btn-default" style="margin-top:5px;float:right;">Delete user</button>
I'm sure that its just me overseeing something, but help would greatly be appriciated.
Also, I have ajaxForm plugin installed.
A 'submit' is by definition a jump to a new URL. You know this can only be done for one form at a time.
However, we talking normal 'submits' here, and you don't have to use normal submits to get information from a form and act on it.
Since you're using JQuery, you could use that. Have a look at ajax calls. For instance here:
http://api.jquery.com/jquery.post
Look for the example called: Post a form using ajax and put results in a div, you will find useful code there. It shows you how to get the values of the fields in the form.
Let's imagine you have 3 forms like this:
<form id="form1" action="api/url1">
<input name="field1" type="text" />
</form>
<form id="form2" action="api/url2">
<input name="field2" type="text" />
</form>
<form id="form3" action="api/url3">
<input name="field3" type="text" />
</form>
<button>Submit</button>
Then you can fire the submit of each form like this:
$('button').on("click", function () {
$('form').each(function (index, form) {
$(form).submit();
});
});
Then to prevent form full post back just prevent the default of the submit event and then post the serialized form with ajax:
$('form').on("submit", function (e) {
e.preventDefault();
$.ajax({
type: "POST",
url: $(this).attr("action"),
data: $(this).serialize(),
success: function (data) {
alert(data);
},
error: function (error) {
console.error({ status: error.status, statusText: error.statusText })
}
});
});
JSFIDDLE
If you want to use ajax
you can group a data of all input and post using new FormData()
function fnSubmintAll(){
var formData = new FormData();
$("#form1,#form2,#form3").each(function(idx,item){
var frmValue = $(item).serializeArray();
$.each(frmValue, function (key, input) {
formData.append(input.name,input.value);
});
})
$.ajax({
url: "/PostUrl",
type: "POST",
data: formData,
contentType:false,
processData: false,
success: function (result) {
alert("Success")
},
error: function () {
alert("Error")
}
});
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<fieldset>
<legend>From 1</legend>
<form id="form1">
<input name="field1" type="text" />
</form>
</fieldset>
<fieldset>
<legend>From 2</legend>
<form id="form2">
<input name="field2" type="text" />
</form>
</fieldset>
<fieldset>
<legend>From 3</legend>
<form id="form3">
<input name="field3" type="text" />
</form>
</fieldset>
<br />
<br />
<br />
<button type="button" onclick="fnSubmintAll">Submit All</button>
I have two forms usin ajax on one page, one for uploading an image and the other sending information via mail.
When I submit one it clears the content of the other one.
My html:
<form class="inputform">
<input required size="60" maxlength="80" class="form-control" name="Location[zendernaam]" id="Location_zendernaam" type="text">
<!--more input fields-->
<input type="submit" class="submit" style="display:none;">
</form>
<form id="form" class="imageuploadform" action="<?php echo get_home_url(); ?>/wp-content/themes/PandoraBox/ajaxupload.php" method="post" enctype="multipart/form-data">
<input id="uploadImage" type="file" accept="image/*" name="image" />
<input id="button" class="image-upload" type="submit" value="Upload">
</form>
<div id="preview" style="display:none"></div>
<input id="submitform" type="button" value="Verzend">
My javascript/jquery:
<script type="text/javascript">
$("#submitform").click(function(){
$('.inputform .submit').click();
return false;
});
$(".inputform").submit(function( event ){
event.preventDefault();
post_data = {
'titel' : $("#Location_title").val(),
'hoofdcategorie' : $("#Location_hoofd1").val(),
//more fields
};
$.ajax({
type: "POST",
url: "<?php echo get_home_url(); ?>/wp-content/themes/PandoraBox/verzend-inzending.php",
data: post_data,
success: function(){
alert('top!');
}
});
});
</script>
First the user fills in the fields, after that he can upload an image and preview it.
When you click submit on the image upload form it clears all the values of the first form.
The thing I'm trying to have is a JQuery/JavaScript code that will automatically pass some data from facebook to a form (basically the form doesn't need to be shown). so the first part is ready (the part that pulls the data from facebook).
window.fbAsyncInit = function() {
FB.init({appId: 'xxxxxxxxxxxxxxx', status: true, cookie: true, xfbml: true});
};
FB.Event.subscribe('auth.login', function(response) {
if (response.session) {
FB.api({
method: "fql.query",
query: "SELECT name,email FROM user WHERE uid = " + response.session.uid
}
Now i need to insert the name and the email to the inputs with name="name" and name="email" and auto submit the form.
Thanks in advance!
EDIT: here is the form:
<form method="post" class="af-form-wrapper" action="http://www.aweber.com/scripts/addlead.pl" >
<input type="hidden" name="meta_web_form_id" value="XXXXXXXX" />
<input type="hidden" name="listname" value="XXXXXX" />
<input type="hidden" name="meta_adtracking" value="XXXX" />
<input type="hidden" name="meta_message" value="1" />
<input id="awf_field-22176678" type="text" name="name" class="text" value="" tabindex="500" />
<input class="text" id="awf_field-22176679" type="text" name="email" value="" tabindex="501" />
<input name="submit" class="submit" type="submit" value="Submit" tabindex="502" />
<div class="af-clear">
</form>
EDIT 2: I need to do something like this just simplified with jQuery:
<?php
$formcode = '<form method="post" action="http://www.aweber.com/scripts/addlead.pl" >
<input type="hidden" name="meta_web_form_id" value="864136470" />
<input type="hidden" name="listname" value="fbu-ppv-mmoney1" />
<input type="hidden" name="meta_adtracking" value="FB_Ultralizer_PPV" />
<input type="hidden" name="meta_message" value="1" />
<input id="awf_field-22176678" type="text" name="name" class="text" value="" tabindex="500" />
<input class="text" id="awf_field-22176679" type="text" name="email" value="" tabindex="501" />
<input name="submit" class="submit" type="submit" value="Submit" tabindex="502" />
</form>
'; ?>
<script type="text/javascript">
customar_formcode="$formcode";
customar_formcode=customar_formcode.replace("{email}", user.email);
customar_formcode=customar_formcode.replace("{name}", user.name);
document.getElementById(\'form\').submit();
</script>
Use Jquery's POST to send the data without the need for the markup for a form and using auto submits:
$.ajax({
type: 'POST',
url: url,
data: data,
success: success,
dataType: dataType
});
EDIT:
If you have already got the form setup in the DOM you should just fill it in with JavaScript and submit it with JavaScript
To change the input values use Jquery like so:
$('input[name$="name"]').val('value');
once all the inputs are set to how you want them you can submit the form using this:
if you have the ID form on your form then you can use code like
$('#form').submit();
Hope this helps
with jquery you can pass all data of form at once with something like:
var data = $(#formID).serialize();