I already have grunt-contrib-qunit set up. My Gruntfile.js includes something like this
qunit: { files: ['test/*.html'] }
Now I can run grunt qunit and all my tests run.
Question: how can I run just one single test without running all of them? Is there a way I can overload the value of files from the command line?
You definitely need to look into grunt-contrib-qunit and grunt-contrib-connect (https://github.com/gruntjs/grunt-contrib-qunit and https://github.com/gruntjs/grunt-contrib-connect) as the tandem will provide you with a headless phantom and a local webserver.
UPDATE - as for running just one specific test, you could write something like this, listing your tests as separate targets for your qunit task:
grunt.initConfig({
qunit: {
justSomething: ['test/justsomething.html'],
justSomethingElse: ['test/justsomethingelse.html'],
all: ['test/*.html']
}
});
Then you can call grunt qunit:justSomething, or grunt qunit:all - this is not specific to qunit, though - see http://gruntjs.com/configuring-tasks
Now, if you would really like to use the target to specify a test name, you would go with something like:
module.exports = function(grunt) {
grunt.loadNpmTasks('grunt-contrib-qunit');
grunt.initConfig({
qunit: {
all: ['test/**/*.html']
}
});
grunt.task.registerTask('foo', 'A sample task that run one test.', function(testname) {
if(!!testname)
grunt.config('qunit.all', ['test/' + testname + '.html']);
grunt.task.run('qunit:all');
});
}
Then call grunt foo:testname.
Yet again, this is not specific to qunit - but rather grunt task writing.
Hope that (finally) helps.
Related
So I'm having a slight problem with producing production ready scripts for my project. I'm using gulp to concatenate and minify my css and js, and while the css is working fine the gulp js function isn't generating my final file. Please refer to my code below:
gulp.task('js', function() {
return gulp.src([source + 'js/app/**/*.js'])
.pipe(concat('development.js'))
.pipe(gulp.dest(source + 'js'))
.pipe(rename({
basename: 'production',
suffix: '-min',
}))
.pipe(uglify())
.pipe(gulp.dest(source + 'js/'))
.pipe(notify({ message: 'Scripts task complete', onLast: true }));
});
If anyone has encountered a similar problem or has any tips it would be much appreciated :)
There is nothing wrong with your gulpfile. I tested it and it works perfectly.
The only thing I can guess is that your source is not set correctly. Did you forget the trailing slash '/' ?
I would suggest 2 things to figure it out. Include node path library to check where source is actually pointing to like this:
var path = require('path');
// in gulp task ...
path.resolve(path.resolve(source + 'js/app'));
Make sure it points where you think it does.
Secondly, you could use gulp-debug to establish that any files are found:
npm install gulp-debug
Then
var debug = require('gulp-debug');
// in gulp task ...
return gulp.src([source + 'js/app/**/*.js'])
.pipe(concat('development.js'))
.pipe(debug())
.pipe(gulp.dest(source + 'js'))
.pipe(debug())
// etc.
Good luck!
Based on additional infomation in the comments I realise you are generating JS files in a separate process ...
gulp is asynchronous by default. What this boils down to is that all functions try to run at the same time - if you want a specific order it must be by design. This is great because it's very fast but can be a headache to work with.
Problem
Here is what's basically happening:
// SOME TASK THAT SHOULD BE RUN FIRST
gulp.task('copy-vendor-files-to-tempfolder', function (done) {
// copy files to vendor folder
done()
})
// SOME TASKS THAT DEPEND ON FIRST TASK
gulp.task('complile-styles', function () { /* independent task */ })
gulp.task('concat-vendor-files', function () { /* concat files in vendor folder. depends on vendor files existing */ })
// GENERAL TASK WHICH STARTS OTHERS
gulp.task('ready', ['copy-vendor-files-to-tempfolder', 'compile-styles', 'concat-vendor-files])
When you try to run:
$ gulp ready
GULP TASK WILL FAIL! Folder is being created at the same time!!
NOWHERE TO COPY FILES!
Solution
There are many solutions but the following module has come in handy for me again and again:
npm install run-sequence
Then in your gulpfile.js:
var runSequence = require('run-sequence')
gulp.task('ready', function (done) {
runSequence(
'create-folders', // do this first,
[
'copy-css-files',
'copy-html-files'
], // do these AFTER but in parallel
done // callback when ready
)
})
This will guarantee the folder exists when you try to run the other functions.
In your specific case, you should make sure the task that concatenates the JS files is run after the task that copies them out of vendor.
Note: I'm leaving other answer because it contains useful help for debugging similar issues.
HTH!
So, I've been looking all over for this, found "similar" answers here, but not exactly what I want.
Right now if I want to test a single file with karma, I need to do fit(), fdescribe() on the file in question...
However, what I do want is to be able to just call karma, with the config file, and direct it to a specific file, so I don't need to modify the file at all, ie:
karma run --conf karma.conf.js --file /path/to/specific/test_file.js
is it possible to do this? Or with any helper? (using grunt or gulp?)
First you need to start karma server with
karma start
Then, you can use grep to filter a specific test or describe block:
karma run -- --grep=testDescriptionFilter
Even though --files is no longer supported, you can use an env variable to provide a list of files:
// karma.conf.js
function getSpecs(specList) {
if (specList) {
return specList.split(',')
} else {
return ['**/*_spec.js'] // whatever your default glob is
}
}
module.exports = function(config) {
config.set({
//...
files: ['app.js'].concat(getSpecs(process.env.KARMA_SPECS))
});
});
Then in CLI:
$ env KARMA_SPECS="spec1.js,spec2.js" karma start karma.conf.js --single-run
This option is no longer supported in recent versions of karma:
see https://github.com/karma-runner/karma/issues/1731#issuecomment-174227054
The files array can be redefined using the CLI as such:
karma start --files=Array("test/Spec/services/myServiceSpec.js")
or escaped:
karma start --files=Array\(\"test/Spec/services/myServiceSpec.js\"\)
References
karma-runner source: cli.js
karma-runner source: config.js
I tried #Yuriy Kharchenko's solution but ran into a Expected string or object with "pattern" property error.
Therefore I made the following modifications to his answer and now I'm able to run single files using Karma:
function getSpecs(specList) {
if (specList) {
return specList.toString();
} else {
return ['**/*_spec.js'] // whatever your default glob is
}
}
module.exports = function(config) {
config.set({
//...
files: [
{ pattern: getSpecs(process.env.KARMA_SPECS), type: "module"}
]
});
});
Note: This solution only works with a single file mentioned in the KARMA_SPECS env variable. Ex: export KARMA_SPECS="src/plugins/muc-views/tests/spec1.js"
I have been working on a project setup and deploy Gruntfile but would like to hide the command line output so that the following:
Running "init" task
Running "prompt:init" (prompt) task
[?] If you continue your project information will be overwritten.
Continue? (Y/n)
becomes
[?] If you continue your project information will be overwritten.
Continue? (Y/n)
when running grunt. I know it's only cosmetic but it's something I would like to do and cannot seem to find anything on Grunt's API documentation to indicate this can be done.
This is currently not supported, but possible thanks to the following workaround (from shama on GitHub):
grunt.log.header = function () {};
Basically, this overrides the log header function (which is responsible for the "running x task" message) by an empty function that does nothing, and more importantly, outputs nothing.
There's another way to do it:
First, run npm install grunt-log-headers to install grunt-log-headers.
Then add require('grunt-log-headers')(grunt); to your Gruntfile.js to enable it.
Finally, add this to any task for which you want to hide the log header:
options: {
gruntLogHeader: false
}
Example:
grunt.initConfig({
sometask: {
options: {
gruntLogHeader: false,
}
}
});
In fact, an issue has already been created for this. It's currently being worked on, and will normally be available in the version 0.5.0.
I have been writing a small grunt plugin, and now I am stuck trying to test the plugin end-to-end. What I would like to accomplish is this
Write a test case that configures a grunt instance with a minimal grunt config for my plugin and runs that task
Test that the file produced equals the intended output
Run that test automatically when running grunt nodeunit
So far, I seem stuck on configuring an individual Grunt instance, as the new instance seems to share configuration with that of the already loaded Grunt instance.
I got something like this in my plugin_test.js
var testGrunt = require('grunt');
exports.codekit = {
setUp: function(done) {
testGrunt.initConfig({
myPlugin : {
// the config
}
});
testGrunt.task.run(['myPlugin']);
done();
},
basic_parsing_works: function(test) {
test.expect(1); // no idea what this does
test.equal(1,1,'basic test');
//var actual = testGrunt.file.read('tmp/test01_result.html');
//var expected = testGrunt.file.read('expected/test01_expected.html');
//test.equal(actual, expected, 'should parse file.');
test.done();
}
};
The problem is that when I run the task for myPlugin it uses the configuration loaded in the "outer" (already running) Grunt instance. Even though I have specifically created a new Grunt instance under a different name (testGrunt).
Is there a way to avoid this?
When grunt.loadNpmTasks is used, a grunt task is automatically available to the command line. It can be useful, but sometimes, I would like this task to be private, so it can be used whithin the Grunt file but not available to the command line.
Here is a contrived example. If I do :
module.exports = function(grunt) {
grunt.initConfig({
clean: {
test: ['test'],
release: ['release']
},
});
grunt.loadNpmTasks('grunt-contrib-clean');
grunt.registerTask('build', 'Build the project.', function() {
console.log("building project");
});
grunt.registerTask('release', ['clean:release', 'build']);
};
... I can use the following command :
$ grunt release
However, this one is also available, and both clean:release and clean:test will be executed:
$ grunt clean
I do not want that. I want to control what can be called from the command line, since I may not have foreseen some undesirable effects if the user directly calls some tasks or subtasks.
I thought about registering a new clean task to supersedes the main one, and then choose what to call when clean is invoked (or to call nothing at all), but it does not work well since it cannot call the original clean task:
grunt.registerTask('clean', ['clean:release']);
Use grunt.task.renameTask
var ticks = +new Date();
var clean = 'clean-' + ticks;
grunt.task.renameTask('clean', clean);
grunt.registerTask('release', [clean + ':release', 'build']);
grunt.config.set(clean, grunt.config.get('clean'));
Copying the configuration over is important if you want to preserve the targets configuration