Ajax POST is not posting onclick to current page - javascript

Alright so this has been bugging me for a long time now... I have tried everything but I cant get it to work!
So what I want to have is a link that acts as a button, and once you click it, it POSTs an ID number of the button in the form "{ 'id' : id }"
edit-homepage.php:
<script>
$(function() { // document ready
$('a.inactive').on('click', function(event) {
event.preventDefault(); // instad of return false
var id = $(this).data('id');
// use $.post shorthand instead of $.ajax
$.post('edit-homepage.php', {id: id}, function(response) {
// after you get response from server
editSlide(id);
});
});
});
</script>
The a href button is created using PHP and I want it to call the ajax function postID( id ) which will post the id so that later I can populate a form via PHP using the posted id.
edit-homepage.php:
echo '<li><a class="inactive" id="slide-'.$info["id"].
'" onClick="postID('.$info["id"].'); editSlide('.$info["id"].'); return false;">'
.'<img src="../images/'.$info["img"].'" width="175"/><p>Edit Slide '
. $info["id"] .'</p></a></li>';
Currently, when I click the link, it opens the alert but it is EMPTY or Undefined. It is supposed to display "ID: 1" for example if the link clicked has a ID of 1.
edit-homepage.php:
<script>
function editSlide($id) {
<?PHP
if (isset ($_POST['id'])) {
echo "alert('success!2');";
}$id = !empty($_POST['id']) ? $_POST['id'] : '';
$data = mysql_query("SELECT * FROM slider WHERE id='$id'") or die(mysql_error());
$info = mysql_fetch_array( $data );?>
document.getElementById("edit-slide-id").innerHTML="Edit Slide #"+$id;
document.getElementById("edit-form").style.display = "block";
document.getElementById("short-title").value="<?PHP echo $info['s_title']; ?>";
}
</script>
Thanks!

With jquery, you don't need to use attributes to attach events, like that:
$(function() { // document ready
$('a.inactive').on('click', function(event) {
event.preventDefault(); // instad of return false
var id = $(this).data('id');
// use $.post shorthand instead of $.ajax
$.post('edit-homepage.php', {id: id}, function(response) {
alert('ID:' + response);
// after you get response from server
editSlide(id);
});
});
});
As of server side, try replacing raw
<?PHP echo $_POST['id']; ?>
With
<?php echo !empty($_POST['id']) ? $_POST['id'] : '' ?>
You likely get notice about Undefined index id, which breaks javascript if there is no post data.
UPDATE
edit-homepage.php shold be separated something like that:
if(!empty($_POST)) {
// here you process your post data and return
// only wenever you want to pass to script
// not all the html
} else {
// here you output html and scripts, but don't do request processing
}
You should always remember, that your HTML rendering must always be separated from your logic. It is better to put views in separate files from logic, though it is not required, it is much easier to debug and maintain.

You can not include PHP code that is supposedly to run after the ajax call. The PHP code will be run only to generate the page. Anything you want to include in alert should be provided in the ajax response, in your case the data variable.

You need to use alert('ID: ' + id).
The $_POST['id'] part of the script does not react to the AJAX request. It is whatever the $_POST['id'] value is when the script is output to the browser (i.e. when the page is first loaded).
You will see this if you view the source.

alert ("ID:"+data);
then only you will get response
or
alert("ID"+id);
this will alert the id passes to function

http://jsfiddle.net/U54ME/
$(".checkthisclass").click(function() {
$.ajax({
type: "POST",
url: "edit-homepage.php",
data: { 'id' : $(this).attr("slideid"); },
success: function(data) {
alert(data);
}
});
}
});
--
<ul>
<li><a class="inactive checkthisclass" id="slide-5" slideid = "5" ><img src="http://blog.entelo.com/wp-content/uploads/2013/04/stackoverflow-logo.png" width="175"/><p>Edit Slide 5</p></a></li>
</ul>

Related

problem passing variable from HTML to JS for AJAX request in Wordpress

I have a Wordpress website page where I want to enter two values- gender and manufacturer, then display a list which shows which items match the gender and manufacturer selected.
So that the whole page is not refreshed I want to do this with an AJAX request which has to follow a particular route in Wordpress which has got me completely lost. At the moment I am having trouble even passing my two variables from the HTML page through to the JS and PHP.
For some reason the code always thinks that the user has selected Men even where Women or Junior is chosen.
My HTML
<form>
<br>
<select id="gen" name="gen">
<option value="Men">Men</option>
<option value="Women">Women</option>
<option value="Junior">Junior</option>
</select>
</form>
<div><a class="chartsearch">Search</a></div>
<div id="results">
Results go here if it works
<br>
<br>
</div>
Then my JS and PHP which is currently all contained in the functions.php file in my public_html/wp-content/themes/inspiro folder.
//Load jQuery
wp_enqueue_script('jquery');
//Define AJAX URL
function myplugin_ajaxurl() {
echo '<script type="text/javascript">
var ajaxurl = "' . admin_url('admin-ajax.php') . '";
</script>';
}
add_action('wp_head', 'myplugin_ajaxurl');
//The Javascript
function add_this_script_footer(){ ?>
<script>
jQuery(document).ready(function($) {
// This is the variable we are passing via AJAX
let str = document.getElementById('gen').value;
// This does the ajax request (The Call).
$( ".chartsearch" ).click(function() {
$.ajax({
url: ajaxurl, // Since WP 2.8 ajaxurl is always defined and points to admin-ajax.php
data: {
'action':'example_ajax_request', // This is our PHP function below
'str' : str // This is the variable we are sending via AJAX
},
success:function(data) {
// This outputs the result of the ajax request (The Callback)
$("#results").text(data);
},
error: function(errorThrown){
window.alert(errorThrown);
}
});
});
});
</script>
<?php }
add_action('wp_footer', 'add_this_script_footer');
//The PHP
function example_ajax_request() {
// The $_REQUEST contains all the data sent via AJAX from the Javascript call
if ( isset($_REQUEST) ) {
$str = $_REQUEST['str'];
// This bit is going to process the gender variable and display results
if ( $str = 'Men' ) {
$results = 'Mens results';
} else {
$results = 'Other results';
}
// Now let's return the result to the Javascript function (The Callback)
echo $str;
echo $results;
}
// Always die in functions echoing AJAX content
die();
}
// This bit is a special action hook that works with the WordPress AJAX functionality.
add_action( 'wp_ajax_example_ajax_request', 'example_ajax_request' );
add_action( 'wp_ajax_nopriv_example_ajax_request', 'example_ajax_request' );
If you select Men and click Search it displays Men Mens Results but the same happens if you select Women. This tells me that it is getting the initial value for $str as Men but not ever changing it. So there is no point going any further with my code until it does. Once it does I can get the AJAX request to search my SQL database and show real Mens Results, Women Results, Junior Results rather than just the text.
Can anyone see what I have done wrong? I know I am a clown and a complete novice but any help would be appreciated.
It's because you st your variable at the documentReady event callback. So the var has the default value (the value at the documentReady moment).
move it in the submit event:
// This does the ajax request (The Call).
$( ".chartsearch" ).click(function() {
let str = document.getElementById('gen').value;
$.ajax({
url: ajaxurl, // Since WP 2.8 ajaxurl is always defined and points to admin-ajax.php
data: {
'action':'example_ajax_request', // This is our PHP function below
'str' : str // This is the variable we are sending via AJAX
},
success:function(data) {
// This outputs the result of the ajax request (The Callback)
$("#results").text(data);
},
error: function(errorThrown){
window.alert(errorThrown);
}
});
});
$str = 'Men' is always true, because assigning the value Men to $str won't fail.
To compare them, you should write: $str == 'Men'

how to fetch data from sql server database in php without refreshing the page

I am trying to get some data from the database. I create a function that is located in functions.php file that return a value. On another page, I create a variable and just get that value. I was trying to use the onkey to check the database but then I realize that i need to know the amount of tickets even if they don't type anything.
Here is the function:
function.php
function is_ticket_able($conn){
$query = "select number_of_tickets from [dbo].[TICKETS] " ;
$stmt = sqlsrv_query($conn, $query);
while ($row = sqlsrv_fetch_array($stmt)) {
$amount_of_tickets = $row['number_of_tickets'];
}
return $amount_of_tickets;
}
And, I am trying to check the database (without refreshing the page) and get the value on this page:
application.php
$amount_of_tickets = is_ticket_able($conn);
Then, I just check that $amount_of_tickets is not 0 or 1. Because if is one then some stuff have to change.
I am doing this (inside application.php):
if($amount_of_tickets !=0){
//show the form and let them apply for tickets.
//also
if($amount_of_tickets == 1){
//just let them apply for one ticket.
}
}
EDIT: I saw that AJAX would be the right one to use, but I am so confuse using it.
UPDATE:
function.php
function is_ticket_able($conn){
$query = "select number_of_tickets from [dbo].[TICKETS_LKUP] " ;
$stmt = sqlsrv_query($conn, $query);
while ($row = sqlsrv_fetch_array($stmt)) {
$ticket = $row['number_of_tickets'];
}
return $ticket;
}
application.php
$amount_of_tickets = is_ticket_able($conn);
<script type="text/javascript">
var global_isTicketAble = 0;
checkTicket();
function checkTicket()
{
$.ajax(
{
url: "application.php",
method: 'GET',
dataType: 'text',
async: true,
success: function( text )
{
global_isTicketAble = text;
alert(global_isTicketAble);
if( global_isTicketAble == 0 ){
window.location.replace("http://www.google.com");
}
setTimeout( checkTicket, 5000 ); // check every 5 sec
}
});
}
</script>
So, now the problem is that when I alert(global_isTicketAble); it doesn't alert the value from the database but it does alert everything that is inside application.php...Help plzzz
Server side
Assuming you need to check $amount_of_tickets periodically and this can be computed into application.php, inside that file you'll have
<?php
// $conn is defined and set somewhere
$amount_of_tickets = is_ticket_able($conn);
echo $amount_of_tickets;
exit(0);
?>
This way when the script is invoked with a simple GET request the value is returned in the response as simple text.
Client Side
ajax is the way to go if you want to update information on page without reloading it.
Below is just a simple example (using jQuery) that may be extended to fit your needs.
The code below is a JavaScript snippet. A global is used to store the value (globals should be avoided but it's just for the purpose of the example)
Then a function is invoked and the updated value is fetched from function.php script.
The function -prior termination- schedules itself (with setTimeout) to be re-invoked after a given amount of milliseconds (to repeat the fetch value process).
var global_isTicketAble = 0;
checkTicket();
function checkTicket()
{
$.ajax(
{
url: "application.php",
method: 'GET',
dataType: 'text',
async: true,
success: function( text )
{
global_isTicketAble = text;
// eventually do something here
// with the value just fetched
// (ex. update the data displayed)
setTimeout( checkTicket, 5000 ); // check every 5 sec
}
}
}
Note that $.ajax() sends the request but does not wait for the response (as async is set to true). When the request is received the function specified as success is executed.
Complete jQuery ajax function documentation can be found here
http://api.jquery.com/jquery.ajax/
I assume that you have a page (application.php) that displays a table somewhere.
And that you wish to fill that table with the data found in you database.
I'm not sure about WHEN you want these data to be refreshed.
On button click or periodically (like ervery 5 seconds)... But it doesn't matter for what I explain below.
In application.php:
Assemble all your page as you already know how.
But inside it, somewere, just insert an empty div where your table should show:
<div id="dynamicContent"></div>
Also add this script at the bottom of the page:
<script>
function getData(){
PostData="";
$.ajax({
type: "POST",
url: "function.php",
data: PostData,
cache: true,
success: function(html){
$(Destination).html(html);
}
});
}
getData(); // Trigger it on first page load !
</script>
There is 2 variables here... I named it "PostData" and "Destination".
About PostData:
You can pass data collected on the client side to your PHP function if needed.
Suppose you'd need to pass your user's first and last name, You'd define PostData like this:
Fname=$("#Fname").val(); // user inputs
Lname=$("#Lname").val();
PostData="Fname="+Fname+"&Lname="+Lname;
In your function.php, you will retreive it like this (like any normal POST data):
$Fname=$_POST['Fname'];
$Lname=$_POST['Lname'];
If you do not need to pass data from your client side script to you server side PHP... Just define it empty.
PostData="";
Then, about Destination:
This is the place for the empty "dynamic div" id ( I named it "dynamicContent" above).
Don't forget about the hashtag (#) for an id or the dot for a class.
This is a jQuery selector.
So here, PostData would be defined like this:
Destination="#dynamicContent";
The result of the ajax request will land into that "dynamic div".
This WILL be the result of what's defined in function.php..
So, if you follow me, you have to build your table in function.php...
I mean the part where you do your database query and your while fetch.
echo "<table>";
echo "<tr><th>column title 1</th><th>column title 2</th></tr>"
while ($row = sqlsrv_fetch_array($stmt)){
echo "<tr><td>" . $row['data1'] . "</td><td>" . $row['data2'] . "</td></tr>";
}
echo "</table>";
So if you have no data, the table will be empty.
You'll only get the table and table headers... But no row.
There is then no need for a function that checks if there is data or not.
Finally... About the trigger to refresh:
In application.php, you may place a button that fires getData()... Or you may define a setInterval.
It's up to you.
This is how I use ajax to refresh part of a page without reloading it completly.
Since ajax is new to you, I hope this answer will help.
;)
------------------------
EDIT based on Ariel's comment (2016-05-01)
Okay, I understand! Try this:
In application.php:
<div id="dynamicDiv"></div>
<script type="text/javascript">
// timer to trigger the function every seconds
var checkInterval = setInterval(function(){
checkTicket();
},1000);
function checkTicket(){
$.ajax({
type: "POST",
url: "function.php",
data: "",
cache: true,
success: function(html){
$("#dynamicDiv").html(html);
}
});
}
function noMoreTikets(){
clearInterval(checkInterval);
window.location.replace("http://www.google.com");
}
</script>
In function.php:
// Remove the "function is_ticket_able($conn){" function wrapper.
// Define $conn... Or include the file where it is defined.
// I assume that your query lookup works.
$query = "select number_of_tickets from [dbo].[TICKETS_LKUP] " ;
$stmt = sqlsrv_query($conn, $query);
while ($row = sqlsrv_fetch_array($stmt)) {
$ticket = $row['number_of_tickets'];
}
// Add this instead of a return.
if($ticket>0){
echo "There is still some tickets!"; // Text that will show in "dynamicDiv"
}else{
?>
<script>
$(document).ready(function(){
noMoreTikets();
});
</script>
<?php
}
Remember that your PHP scripts are executed server-side.
That is why your "return $ticket;" wasn't doing anything.
In this ajax way to call function.php, its script is executed alone, like a single page, without any relation with application.php, which was executed long ago.
It produces text (or javascript) to be served to the client.
If you want to pass a PHP variable to the client-side javascript, you have to echo it as javascript.
So here, if the PHP variable $ticket is more than zero, some text saying that there is still tickets available will show in "dynamicDiv" and the application page will not be refreshed. I suppose it shows a button or something that allows students to get a ticket.
Else, it will be the javascript trigger to "noMoreTikets()" that will land in the "dynamicDiv".

Unable to send jQuery variable with string content to PHP using jQuery AJAX function?

The code snippet for the jQuery function looks like:
function addMessage() {
if (textval != "") {
text_string='<div class="alert-box round"><p class="text-left">' + userName + ':' + textval + '</p></div></br>';
alert(text_string);
$.ajax({
type:"POST",
url:"process.php",
data: {'text_string': text_string},
cache:false,
success:function(){
alert("submitted")
}
});
$("input[type=text]:last").val("");
}
enterButton = 0;
}
The process.php code looks like:
<body>
<?php
//$host = "localhost";
$text_string=$_POST['text_string'];
echo "string submitted is".$text_string;
?>
</body>
I get alerts showing value of text_string and then the "submitted", but when I open the php page, it shows an error:
Undefined index: text_string
I've seen various answers, none of them seem to be the case for mine. Is the problem in PHP code or jQuery code or both?
If you want to save the value passed by the AJAX request for the next time you load "process.php", try saving it in the session. So, you could change your code to:
<?php
session_start();
// Store value in session if it is passed
if (isset($_POST['text_string'])){
$_SESSION['text_string'] = $_POST['text_string'];
}
// Read and echo value from session if it is set
else if (isset($_SESSION['text_string'])){
$text_string=$_SESSION['text_string'];
echo "string submitted is".$text_string;
}
?>
Now, your PHP script will store the passed value in the session, and will echo that stored value should you load the page elsewhere. (Another alternative is to store the value in a database...though I'm not sure if you have one set up at the moment.)
Hope this helps! Let me know if you have any questions.

Passing values from jQuery to PHP in same page instantly

I have written a PHP program to confirm deletion of data through jQuery confirm message (Refer: http://rathur.fr/jQuery/MsgBox/) and record the result back to the same page itself instantly. If the page refreshes, it'll return back its state to previous.
The part of line is below:
print "
<script type='text/javascript'>
$(document).ready(function(){
$.msgbox('<br/>Are you sure you want to delete the selected record from the database?', {
type : 'confirm'
}, function(result){
$('#output').text(result);
var output = result;
});
});
</script>";
I want to get the result of the action button to PHP variable instantly, like below (just a trial):
$x = $_SESSION['output']; OR
$x = $_POST['output']; OR
$x = print "<div id=\"output\"></div>"; OR
$x = some_function(output);
Please help me, or suggest if there is other better options.
Here is a simple Ajax call to a Php File by an event : Click on a button.
Javascript client side :
$("body").on("click", "#mybutton", function() {
var mydata = $("#form").serialize();
$.ajax({
type: "POST",
url: "/api/api.php",
data: {data : mydata},
timeout: 6e3,
error: function(a, b) {
if ("timeout" == b) $("#err-timedout").slideDown("slow"); else {
$("#err-state").slideDown("slow");
$("#err-state").html("An error occurred: " + b);
}
},
success: function(a) {
var e = $.parseJSON(a);
if (true == e["success"]) {
$("#action").html(e['message']);
// here is what you want, callback Php response content in Html DOM
}
}
});
return false;
});
Next in your Php code simply do after any success function :
if ($result) {
echo json_encode(array(
'success' => true,
'msg' => "Nice CallBack by Php sent to client Side by Ajax Call"
));
}
You should use jQuery to POST the data to a PHP script using AJAX if you want to use the second pass.
http://api.jquery.com/category/ajax/ has many functions and tutorials on writing AJAX functions and handling return data. In particular, look at the post() function.

How to use Ajax to update a second selectbox in jquery using the first selectbox's value?

First off, I'm using wordpress, and the goal is to choose a dropdown selectmenu item, structured in jquery, to choose a parent category. This choice then updates the second select menu with the sub-categories of the parent.
So far, I have this ajax:
<script>
$(function(){
$( "#categories" )
.selectmenu({
select: function getval() {
var parent = $("#categories").val();
$.ajax({
url: "ajax.php",
data: { parent : parent },
type: "POST",
success: success: function(response){
$(".sub_cat").html(response);
},
error: function() {
alert("Error, possible missing file.");
}
}); //End of ajax
alert(parent);
} //End of getval
}) //End selectMenu
.selectmenu( "menuWidget" )
.addClass( "overflow" );
$( "#sub_cats" )
.selectmenu()
.selectmenu( "menuWidget" )
.addClass( "overflow" );
var categories = $('#categories');
var subcats = $('#sub_cats');
});
</script>
This is the HTML that will be populated:
<fieldset>
<div class=sub_cat>
</div>
</fieldset>
And This is ajax.php:
<?php
$parent = $_POST['parent'];
$subcats = get_categories("child_of=$parent");
$parent = "<label for="sub_cats">Select a Sub-category</label>
<select name="sub_cats" id="sub_cats">
<option selected="selected">Pick a Sub-Category</option>" .
foreach($subcats as $subcat) {
"<option value=" echo $subcat->name ">" . echo $subcat->name . "</option>"
} .
"</select>"
?>
The menus come in as they should, the alerts come in and the parent category is always sent to the ajax when the choice is made. But the success alert is never touched and I have no idea what I'm supposed to put in the ajax.php file. My guess would be to use that file to get the sub-cats in php, and then send it in json format, but I don't know how.
Absolutely any help is appreciated, I've been struggling with this for a while.
I've tried the solutions from below but I never get any code or value back from ajax.php with any of their answers. Thats where it stops. I also don't know how to populate the next selectbox with the new item. Pretend Im a super ignorant programmer who doesn't know a thing about these structures and explain from that standpoint, that might help I hope.
In the ajax.php file ... do this ...
$parent = $_POST['parent'];
// Query the subcategories using parent ..
// then loop and create select box ...
Then the change the ajax success like below ... and fill the data to subcatogory div
success: function(response){
$(".subcat-div").html(response);
}
The simple way is in change event in your #categories
this must send a request to server and response in html format refreshes #sub_cats
Let us see:
//in your js
$(document).ready(function(){
$("#categories").change(function(){
//here we get corrent selected id
//form categories in corrent selected option
var id = $(this).val();
//simple ajax request $.post
$.post("ajax.php",{
id:id
},function(data){
$("#sub_cats").empty()
$("#sub_cats").append(data)
},"html")
});
}
//
On ajax.php your return must be in Html
... your query above end fetching result:
while($sub = mysqli_fetch_array($result, MYSQLI_ASSOC)){
echo "<option value='".$sub['id']."'>".$sub['name']."</option>";
}
Check it out.

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