Develop Reference

Get all text from a Div after a '-' up until the first character

I'm trying to write a function that will find an instance of text within a div and console.log all text that is after the '-' character. After the '-' character there are sometimes spaces and tabs, so I want to remove these up until the first text character. Here's what I have so far (that is not working at all):
var countryData = $(".countries-title").next().text();
//var regex = /(?<= - ).*/g;
let stringArray = countryData.replace(/\t/g, '').split('\r\n');
console.log(stringArray);
Any help is appreciated. Thanks

console.log('here is a - whole bunch of text'.match(/-\s*(.*)$/)[1]) will log out "whole bunch of text". Is that along the lines of what you are looking for? Let me know if you want me to elaborate.

Assuming you want to maintain all hyphens and formatting after the first hyphen and subsequent spaces you could use:
let textAfterHyphen = countryData.replace(/\s*-\s*/, '');

I am not sure if I understood all but here you have my solution:
$(document).ready(function returnString() {
$("#click-target").on("click",function(){
var newString = [];
var resultString = [];
var onlyChar =$(".target").text();
newString = onlyChar.split("");
for(var i = 0; i < newString.length; i++){
if(newString[i] == "-"){
resultString = newString.slice(i+1,newString.length).join("");
}
}
var k = 0;
for(var j = 0; j < resultString.length; j++){
if(resultString.charCodeAt(j) > 64 && resultString.charCodeAt(j) < 91){
k += j;
}
}
console.log(resultString.slice(k,resultString.length));
});
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="target">Text- *^^^***Text to display</div>
<button id ="click-target">Click</button>

How to repeat characters in a string in javascript by using slice function?

Can anyone shed light on how to frame a javascript function with two parameters: string and character, and only by using the slice method, return the number of times "a" appears in "lava"?

without slice method
var fruits= "lavaaagg";
var count=0;
for(var i=0;i<fruits.length;i++){
if(fruits[i]!='a')
count++;
}
console.log(fruits.length-count);

I'm not sure why you need the slice method. The slice method isn't for searching substrings (or characters in your case), it extracts a substring.
This should work fine:
function howManyCharInStr(str, char) {
return str.split(char).length - 1;
}
Step-by-step explanation:
str.split(char)
Creates an array of str substrings, using char as a separator. For example:
'fooXbazXbar'.split('X')
// Evaluates to ['foo', 'baz', 'bar']
'lorem ipsum dolor'.split('m')
// Evaluates to ['lore', ' ipsu', ' dolor']
Notice how the array returned has a length of n+1 where n is the number of separators there were. So use
str.split(char).length - 1;
to get the desired result.

For getting number of charecters count
<script type="text/javascript">
function FindResults() {
var firstvariable= document.getElementById('v1');
var secondvariable = document.getElementById('v2');
var rslt = GetCharecterCount(firstvariable, secondvariable );
}
function GetCharecterCount(var yourstring,var charecter){
var matchesCount = yourstring.split(charecter).length - 1;
}
</script>
using slice method
var arr = yourstring.split(charecter);
for( var i = 0, len = arr.length; i < len; i++ ) {
var idx = yourstring.indexOf( arr[i] );
arr[i] = pos = (pos + idx);
str = str.slice(idx);
}
var x= arr.length-1;
example http://jsfiddle.net/rWJ5x/2/

Using slice method
function logic(str,char){
var count = 0;
for(var i = 0; i < str.length; i++){
if(str.slice(i,i+1) == char){
count++;
}
}
return count;
};
console.log( "count : " + logic("lava","a") );

repeat last character of sting n number of times..
function modifyLast(str, n) {
var newstr = str.slice(-1)
var newlaststr = newstr.repeat(n-1)
var concatstring = str.concat(newlaststr);
return concatstring;
}
//modifyLast();
console.log(modifyLast("Hellodsdsds", 3))

how to extract numbers from string using Javascript?

how to extract numbers from string using Javascript?
Test cases below:
string s = 1AA11111
string s1= 2111CA2
string s result = 111111
string s1 result = 211112
My code below is not working:
var j = 0;
var startPlateNums = "";
while (j <= iStartLength && !isNaN(iStartNumber.substring(j, j + 1))){
startPlateNums = startPlateNums + iStartNumber.substring(j, j + 1);
j++;
}

How about a simple regexp
s.replace(/[^\d]/g, '')
or as stated in the comments
s.replace(/\D/g, '')
http://jsfiddle.net/2mguE/

You could do:
EDITED:
var num = "123asas2342a".match(/[\d]+/g)
console.log(num);
// THIS SHOULD PRINT ["123","2342"]

A regex replace would probably the easiest and best way to do it:
'2111CA2'.replace(/\D/g, '');
However here's another alternative without using regular expressions:
var s = [].filter.call('2111CA2', function (char) {
return !isNaN(+char);
}).join('');
Or with a simple for loop:
var input = '2111CA2',
i = 0,
len = input.length,
nums = [],
num;
for (; i < len; i++) {
num = +input[i];
!isNaN(num) && nums.push(num);
}
console.log(nums.join(''));

Counting vowels in javascript

I use this code to search and count vowels in the string,
a = "run forest, run";
a = a.split(" ");
var syl = 0;
for (var i = 0; i < a.length - 1; i++) {
for (var i2 = 0; i2 < a[i].length - 1; i2++) {
if ('aouie'.search(a[i][i2]) > -1) {
syl++;
}
}
}
alert(syl + " vowels")
Obviously it should alert up 4 vowels, but it returns 3.
What's wrong and how you can simplify it?

Try this:
var syl = ("|"+a+"|").split(/[aeiou]/i).length-1;
The | ensures there are no edge cases, such as having a vowel at the start or end of the string.

Regarding your code, your if condition needs no i2
if('aouie'.search(a[i]) > -1){
I wonder, why all that use of arrays and nested loops, the below regex could do it better,
var str = "run forest, run";
var matches = str.match(/[aeiou]/gi);
var count = matches ? matches.length : 0;
alert(count + " vowel(s)");
Demo

Try:
a = "run forest, run";
var syl = 0;
for(var i=0; i<a.length; i++) {
if('aouie'.search(a[i]) > -1){
syl++;
}
}
alert(syl+" vowels")
First, the split is useless since you can already cycle through every character.
Second: you need to use i<a.length, this gets the last character in the string, too.

The simplest way is
s.match(/[aeiou]/gi).length

You can use the .match to compare a string to a regular expression. g is global which will run through the entire string. i makes the string readable as upper and lower case.
function getVowels(str) {
var m = str.match(/[aeiou]/gi);
return m === null ? 0 : m.length;
}

Retrieve substring between two characters

I have string like this
var str = "#it
itA
itB
_
#et
etA
etB
_
etC
etD"
How can I retrieve elements between # and _. As of now I am splitting the text with new line but unable to workout this. Please help me on this. Please use this fiddle http://jsfiddle.net/h728C/2/

IF you simply want the FIRST string BETWEEN you can use:
var mys= str.substring(str.indexOf('#')+1,str.indexOf("_"));
this returns: "it itA itB"

I've posted some solution in fidde. It uses the Regex
var str = $('#a').text();
var pattern = /#([\s\S]*?)(?=_)/g;
var result = str.match(pattern);
for (var i = 0; i < result.length; i++) {
if (result[i].length > 1) {
result[i] = result[i].substring(1, result[i].length);
}
alert(result[i]);
}
Strip the end and beginning.
Edit
I've updated the fiddle and the code. Now it strips the beginning # and ending _.
You can use either. Whichever is convenient.
​
​

I don't really get why but this works:
var str = $('#a').text();
var results = [];
$.each(str.split("_"), function(){
var a = this.toString().split("#");
if(a.length===2) results.push(a[1]);
});
console.log(results);​

You can use this kind of regex:
str.replace(/\s/g, "").match(/#(.*?)_/g, "$1");
See this fiddle.

one line solution to get the array
var arrStr = str.split(/[#_]/);

I would not recommend using regex here as it can be done more efficiently through other methods.
function extractString(template, initChar, finalChar) {
let i = 0;
let data = [];
do {
if (template[i] == initChar) {
for (let j = i + 1; j < template.length; j++) {
if (template[j] == finalChar) {
data[data.length] = template.slice(i + 1, j);
i = j + 1;
break;
}
}
}
}
while (++i < template.length);
console.log(data)
return data;
}
extractString("#adj#, #brown# fox jumps over the lazy #dog#.","#","#");