Develop Reference

Making a button that’s send you to another page

Hi i am trying to make a button that’s works like a link. I hope it makes sense, can you help?
<button type="submit" value="Login" id="next" class="login-form-submit next" href="lessonB.html">Next</button>

I am thinking you have a form you are submitting with this button. It's not the right solution in your case to add a element inside the button. Here an example of how I would do it:
<form action="https://redirect_link_here.com/foo.html" method="GET">
<input name="name">
<input name="lastname">
<button type="submit">Button name</button>
</form>
When you press the button the user input gets sent to the link you specified in action in the URL. So if the user inputs is "Andreas" and "Köhler" for instance you would be redirected to this URL on submit: https://redirect_link_here.com/foo.html?name=Andreas&lastname=Koehler. Then you can read the data out of the URL in the code of foo.html and your submit button is not messed up.

HTML form - POST or GET depending on button clicked

Let there be a search form with quite many of the input fields. The user may either click:
[Search] and GET the list of the results,
[Save search criteria] for future use and POST the form content to be stored on server (I'm not interested in storing locally in cookies or so).
How do I achieve that? I've only found solutions to make two types of POST request on two separate buttons.
Maybe a JavaScript onclick function to set <form method="??"> right before its submitted? Would that work?

In HTML5, the <input> element got some new attributes
<input type="submit" formmethod="post" formaction="save.php" value="Save" />
<input type="submit" formmethod="get" formaction="search.php" value="Search" />
The same attributes are valid for <button>

Yes you can change form method before submit form using jquery
<form method="POST" id="myForm">
<button onclick="changeMethod()">submit</button>
</form>
Function changeMethod in jquery
function changeMethod(){
$("#myForm").attr("method", "get");
}

Submitting form using button on enter

I have an html form that I want to only submit from a button located outside my form. I am using javascript to perform some verification and do not want the form to submit unless my javascript functions succeed. I found that if I have the button inside the form it will always submit regardless of the javascript, but if I have it outside the form when a user presses enter it simply submits the form. How can I force enter to perform the button javascript instead of submitting?
<form name="form1" action=<?$_SERVER["PHP_SELF"].'?'.$_SERVER["QUERY_STRING"]?> method="post">
<input type="text" maxlength="5" size="5" name="frmZip" value="">
<input type="hidden" name="frmLat" value="200">
<input type="hidden" name="frmLng" value="200">
<input type="submit" disabled="disabled" style="display:none" />
</form>
<button type="button" id="GetCoordinates" onclick="doClick();">Find Stores</button>
EDIT:
Found my solution.
I changed from
</form>
<button type="button" id="GetCoordinates" onclick="doClick();">Find Stores</button>
to
<input type="button" name="frmSubmit" onclick="doClick();" value="Submit">
</form>
This prevented the button from submitting the form so I submitted it in my doClick() via javascript.
EDIT 2:
While this seemed to work for a time, it has stopped catching the enter keystroke. I updated my button to:
<input type="submit" name="frmSubmit" onclick="return doClick();" value="Find Stores">
And always returned false in doClick(). This allowed me to submit the form via javascript once everything had executed.

While this doesn't answer your direct question, you can actually keep the button and simply use your validation on the form submit:
<form onsubmit="return validateForm()">
Then, in your validateForm method, return true or false indicating whether or not the validation has passed.
However to answer your direct question, you can also use the same approach on the submit button which will prevent the form from being submitted.
Update
As pointed out in the comments, an unontrusive solution is often desirable so here's that:
document.getElementById('theForm').onsubmit = function() { return validateForm(); };

Your button inside the form will not submit the form on enter if you add preventDefault...
$("form").submit(function(e) {e.preventDefault();});

How to clear the spring form fields using jQuery?

When I click the 'CLEAR' button, I want the javascipt code to run. It does run but then the form gets submitted. Is there a way to stop the form from getting submitted? Or is there a spring standard to clear the form. I just thought it would be faster if I did it on the client-side.
<input type="submit" value="CLEAR" onclick="javascript:clearForm()"/>
The above code appears inside the spring form tag.

Two options.
1). Using input type="button":
<input type="button" value="CLEAR" onclick="clearForm()"/>
2). Using input type="reset" instead of clearing the form with javascript.
<input type="reset" value="CLEAR" />

Change
<input type="submit"
to:
<input type="button"
That will stop your form being submitted when the button is clicked.

Refresh after submit and avoid message

I need to refresh my page after I click on a submit button or do submit by using shortcut keys provided. I also need to avoid the message which i get from the browser.
I am submitting some text so i get a message that entered data might get lost. However it does not.
Below is the code for my submit.
<input accesskey="s" class="button" id="issue-comment-add-submit" name="Add" title="Press Alt+Shift+s to submit this form" value="Add" type="submit">
Please can someone provide a solution using javascript or Jquery
Thanks in advance :)