This is a case in which the background is scrolling and contains image thumbnails upon clicking it should animate the actual pic.
I am done with everything ,when i click on the thumbnail ,the image pops up,but i want the background to be silent (no scrolling is required).It is still scrolling ,how to stop that
here is my custom.js ,what should i add to achieve that
jQuery(document).ready(function() {
$('.space-image').click(function() {
var image_sel_id = $(this).attr('id');
/*$('.transparent').show();
/*$('.gallery-wrapper').hide(1000);*/
$('#fullimage'+image_sel_id).show().animate({left:'5%',width:'90%'},"slow");
$('#scrollimage').attr("disabled","disabled").off('click');
});
$('.fullimagecont').click(function() {
var image_clicked_id = $(this).attr('id');
/*$('.transparent').hide().animate({width:'20%'},"slow");
/*$('.gallery-wrapper').show(1000);*/
$('#'+image_clicked_id).hide().animate({width:'20%'},500);
});
});
Here is the html part
<div class="content_area">
<div class="transparent" style="display:none;width:100%;height:100%;float:left;position:relative;z-index:900;"></div>
<div class="fullimagecont" id="fullimage5">
<img src="img/5.jpg">
</div>
<div class="fullimagecont" id="fullimage6">
<img src="img/6.jpg">
</div>
<div class="fullimagecont" id="fullimage7">
<img src="img/7.jpg">
</div>
<div class="fullimagecont" id="fullimage8">
<img src="img/8.jpg">
</div>
<div class="fullimagecont" id="fullimage10">
<img src="img/10.jpg">
</div>
<div class="gallery-wrapper" id="scrollimage" style="white-space:nowrap;overflow:hidden;line-height:0;">
<img src="img/gallery/5.jpg" class="space-image" id="5"
/><img src="img/gallery/7.jpg" class="space-image" id="7"
/><img src="img/gallery/8.jpg" class="space-image" id="8"
/><img src="img/gallery/10.jpg" class="space-image" id="10"
/><img src="img/gallery/6.jpg" class="space-image" id="6" />
</div>
<div class="div-slide-effect">
</div>
</div>
PLease help
Here is the .css
.fullimagecont
{
position:absolute;display:none;width:25%;height:100%;left:5%;top:0;z-index:999;
}
I think this should fix it
Set the overflow property of the body hidden,on the click of the popup open event
$('body').css('overflow','hidden');
and set it to auto on popup close
$('body').css('overflow','auto');
Hope this helps, Thank you
Related
I am trying to change an image using jquery upon clicking. So when I click on an image it appears on the viewport then I click on another image above it and it changes to that image and then a third. When I try it only clicks on one image.
HTML CODE:
<div id="vacationimages">
<p>Click on the Image that best represents the kind of vacation you want</p>
<p><img src="mountain.jpg" alt="Mountain Vacation"><br /><br /></p>
<p><img src="desert.jpg" alt="Desert Vacation"><br /><br /></p>
<p><img src="ocean.jpg" alt="Ocean Vacation"><br /><br /></p>
</div>
<div id="bigimage">
<img id="currentimage" src="ocean.jpg" alt="ocean vacation">
<p id="imagedesc"></p>
</div>
jQuery Code:
$("#vacationimages", "src").click(function(){
$("#firstname").text("");
$("#bigimage").show("slow");
var myfirst = $("#firstname").val();
$("#currentimage").attr("src", "ocean.jpg");
$("#currentimage").attr("src", "desert.jpg");
Only the 2nd image displays despite me having different images on the same page.
Use "on" vs. "click" because it will then work for dynamically added elements, and save you headaches later. After that it's simply populating the image properties with those you gathered from the clicked image or $(this) in the scope of your function.
$(function() {
$("#vacationimages img").on("click", function() {
$("#currentimage").attr("src", $(this).attr("src"));
$("#imagedesc").html($(this).attr("alt"));
});
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="vacationimages">
<p>Click on the Image that best represents the kind of vacation you want</p>
<img src="http://fillmurray.com/30/30.jpg" alt="Mountain Vacation">
<img src="http://fillmurray.com/32/32.jpg" alt="Desert Vacation">
<img src="http://fillmurray.com/34/34.jpg" alt="Ocean Vacation">
</div>
<div id="bigimage">
<img id="currentimage" src="" alt="">
<p id="imagedesc"></p>
</div>
Another common approach in a scenario like this is to use an anchor tag around the img (<a>) and populate it's rel attribute with a larger source image, if what you're going for is click a thumbnail to view a larger image. In that case you bind the event listener to the anchor (not the image) and change the src to the anchor's rel (as opposed to the src of the img inside the anchor).
$("#vacationimages img").on("click",function(){
$("#bigimage img").attr("src",$(this).attr("src"));
$("#bigimage p").text($(this).attr("alt"));
});
$("#submitme").on("click",function(){
$("#mymessage").text($("#name").val()+" You want a "+$("#imagedesc").text());
});
img
{
height:32px;
width:32px
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="vacationimages">
<p>Click on the Image that best represents the kind of vacation you want</p>
<label>Name:<input type="text" id="name"></label><br><br>
<img src="https://image.flaticon.com/icons/png/128/181/181549.png" alt="Mountain Vacation"><img src="https://image.flaticon.com/icons/png/128/148/148766.png" alt="Desert Vacation">
<img src="https://image.flaticon.com/icons/png/128/138/138662.png" alt="Ocean Vacation">
</div>
<div id="bigimage">
<img id="currentimage" src="ocean.jpg" alt="ocean vacation">
<p id="imagedesc"></p>
</div>
<br><br>
<div id="submitdiv"> <input id="submitme" type="button" value="Submit ME"> <p id="mymessage"></p> </div>
Hey i am working on a css slider it is working fine without js only with css but i want to make a js script for navigation buttons for slider i mean i want to make a js script that can slide the content left or right by clicking on left or right button and it has to make a loop i mean if you click button once then it has to slide content left or right by 100% each time and max width is 1000% of the content which i want to slide can anyone please help me for this
<div class="slider-10">
<div class="slider-box" style="width: 1000%">
<img src="img/image-1.jpg" />
<img src="img/image-2.jpg" />
<img src="img/image-3.jpg" />
<img src="img/image-4.jpg" />
<img src="img/image-5.jpg" />
<img src="img/image-6.jpg" />
<img src="img/image-7.jpg" />
<img src="img/image-8.jpg" />
<img src="img/image-9.jpg" />
<img src="img/image-10.jpg" />
</div>
</div>
And i want to slide this section:
<div class="slider-box" style="width: 1000%">
<img src="img/image-1.jpg" />
<img src="img/image-2.jpg" />
<img src="img/image-3.jpg" />
<img src="img/image-4.jpg" />
<img src="img/image-5.jpg" />
<img src="img/image-6.jpg" />
<img src="img/image-7.jpg" />
<img src="img/image-8.jpg" />
<img src="img/image-9.jpg" />
<img src="img/image-10.jpg" />
</div>
Please help me
You can set any img in a div element means 1 div for every imgtag then declare a function in js and call it with onclick event for EX: click right button sends 1 to function and left one -1.
then yo can add class for every div that should show.
I have three images that each change to a second image on mouseover. On mouseover they also reset the others to the standard image. This all works fine.
However..
I would like each of the second images to be clickable links to another page.
Hope someone can help, many thanks.
$(document).ready(function(){
$('#s1').mouseover(function(){
$('#s1').attr('src', 'images/object/click-1.png');
$('#s2').attr('src', 'images/object/standard-2.jpg');
$('#s3').attr('src', 'images/object/standard-3.jpg');
});
$('#s2').mouseover(function(){
$('#s1').attr('src', 'images/object/standard-1.jpg');
$('#s2').attr('src', 'images/object/click-2.png');
$('#s3').attr('src', 'images/object/standard-3.jpg');
});
$('#s3').mouseover(function(){
$('#s1').attr('src', 'images/object/standard-1.jpg');
$('#s2').attr('src', 'images/object/standard-2.jpg');
$('#s3').attr('src', 'images/object/click-3.png');
});
});
So the links would need to be on click-1.png, click-2.png, click-3.png.
<div id="section3" class="container-fluid" align="center">
<div class="row row-centered ">
<div id="top-box-1" class="col-sm-4">
<img src="images/object/standard-1.jpg" id="s1" width="300" height="300" />
</div>
<div id="top-box-2" class="col-sm-4">
<img src="images/object/standard-2.jpg" id="s2" width="300" height="300" />
</div>
<div id="top-box-3" class="col-sm-4">
<img src="images/object/standard-3.jpg" id="s3" width="300" height="300" />
</div>
</div>
</div>
Just make each image tag (s1, s2, and s3) a link. The actual src attribute of the img tag can change to display whatever image you want, it's really irrelevant. After all, A user can only click on something they've moused over.
I have a bit of an issue.
I have a grid of images (3x3), and have a function to swap the image, and show a "content" panel.
While the 1st 2 rows appear to show the content area properly, the bottom row goes in and out and in and out and in and out, etc...
What is causing this behavior, and how can I fix it?
Fiddle
http://jsfiddle.net/o7thwd/4s9GT/
Please excuse the hover image... seems jsfiddle doesn't like it or something... but rest assured that in the site, it works..
Code - jQuery 1.7
// panel grid image swapper
$('.panel img').mouseover(function() {
var $this = $(this);
var src = $this.attr("src").match(/[^\.]+/) + "-hover.png";
$this.attr("src", src);
// Show data panel
$('.' + $this.attr('data-panel')).show('fast');
}).mouseout(function() {
var $this = $(this);
var src = $this.attr("src").replace("-hover.png", ".png");
$this.attr("src", src);
// Hide data panel
$('.' + $this.attr('data-panel')).hide('fast');
});
HTML
<div class="panel-3-image-grid">
<div class="panel1 panel">
<img src="/core/images-tmp/panel-images/panel-3/image1.png" alt="" data-panel="panelGrid-1-content" />
<div class="panelGrid-content panelGrid-1-content">Panel 1</div>
</div>
<div class="panel2 panel">
<img src="/core/images-tmp/panel-images/panel-3/image2.png" alt="" data-panel="panelGrid-2-content" />
<div class="panelGrid-content panelGrid-2-content">Panel 2</div>
</div>
<div class="panel3 panel">
<img src="/core/images-tmp/panel-images/panel-3/image3.png" alt="" data-panel="panelGrid-3-content" />
<div class="panelGrid-content panelGrid-3-content">Panel 3</div>
</div>
<div class="panel4 panel">
<img src="/core/images-tmp/panel-images/panel-3/image4.png" alt="" data-panel="panelGrid-4-content" />
<div class="panelGrid-content panelGrid-4-content">Panel 4</div>
</div>
<div class="panel5 panel">
<img src="/core/images-tmp/panel-images/panel-3/image5.png" alt="" data-panel="panelGrid-5-content" />
<div class="panelGrid-content panelGrid-5-content">Panel 5</div>
</div>
<div class="panel6 panel">
<img src="/core/images-tmp/panel-images/panel-3/image6.png" alt="" data-panel="panelGrid-6-content" />
<div class="panelGrid-content panelGrid-6-content">Panel 6</div>
</div>
<div class="panel7 panel">
<img src="/core/images-tmp/panel-images/panel-3/image7.png" alt="" data-panel="panelGrid-7-content" />
<div class="panelGrid-content panelGrid-7-content">Panel 7</div>
</div>
<div class="panel8 panel">
<img src="/core/images-tmp/panel-images/panel-3/image8.png" alt="" data-panel="panelGrid-8-content" />
<div class="panelGrid-content panelGrid-8-content">Panel 8</div>
</div>
<div class="panel9 panel">
<img src="/core/images-tmp/panel-images/panel-3/image9.png" alt="" data-panel="panelGrid-9-content" />
<div class="panelGrid-content panelGrid-9-content">Panel 9</div>
</div>
</div>
CSS
.panel-3{height:515px;width:990px;margin:0 auto;clear:both;position:relative;z-index:1;}
.panel-3-content{width:480px;float:left;padding-top:160px;}
.panel-3-image-grid{width:475px;float:left;padding-top:20px;}
.panel-3-image-grid div.panel{width:154px;height:154px;float:left;margin-right:3px;margin-bottom:3px;}
.panel-3-image-grid div.panel:hover, .panel-3-image-grid div.panel:active, .panel-3-image-grid div.panel.active{
}
.panel-3-image-grid div.panel:last-child{margin-right:0;}
.panelGrid-content{display:none;position:absolute;width:154px;height:310px;background:#c8deed;}
.panelGrid-1-content, .panelGrid-2-content, .panelGrid-3-content{margin-top:3px;}
.panelGrid-4-content, .panelGrid-5-content{margin:-154px 0 0 157px;}
.panelGrid-6-content{margin:-154px 0 0 -157px;}
.panelGrid-7-content, .panelGrid-8-content, .panelGrid-9-content{margin-top:-314px;}
This is caused by the data panel growing until it is beneath the mouse pointer, which triggers a mouseout on the panel image, which causes the data panel to shrink until it's no longer beneath the pointer, which triggers the mouseenter on the panel image again...
The content panel gets shown on top of the image. If you look at the other rows, it is placed next to or under the image.
Because the content panel is in front of the image, the mouseover event is no longer getting fired for the image (because the mouse is now over the content panel). This is causing it to hide the content panel, which means the mouse is over the image again and a loop is formed.
To break this loop, you either need to attach the mouseover event to the .panel elements (because the mouseover event is going to bubble up there if its over either the image or the content panel) or make sure the content panel is never on top of the image.
how to display some information of image in another div by clicking on image and information should be shown/hidden as clicking on this image.
$(document).ready(function () {
$(".cell").click(function () {
$(this).find("span").toggle("slow");
})
});
<div class="cell">
<div class="inner">
<span style="display:none;"> <img src="Images/sachin.jpg" alt="" width="180" height="180" /></span> <span class="name">Sachin Tendulkar</span>
<input type="hidden" class="friend_id" value="22 " />
</div>
</div>
I want that name displayed in another div when i click on particular image
If I'm understanding correctly, I think what you're asking is for the name to be displayed when you click on its image?
$(document).ready(function () {
$(".inner>img").click(function () {
$(this).parent().find("span").toggle("slow");
})
});
<div class="cell">
<div class="inner">
<img src="Images/sachin.jpg" alt="" width="180" height="180" />
<span class="name" style="display: none;">Sachin Tendulkar</span>
<input type="hidden" class="friend_id" value="22 " />
</div>
</div>
Take notice of the reformatted html that removes the span around the image (it's not necessary) and the style attributes of your image and name span.
Try:
$(.cell).click(function() {
$(this).toggle("slow");
$(otherDiv).html( $(this).find('span.name').html() );
// other processing ...
});
But this is for your current code, which should be cleaned up a bit. So see below.
You shouldn't need a span to wrap your image. I would try something more along the lines of:
<div class="cell">
<div class="inner">
<img src="Images/sachin.jpg" data-name="Sachin Tendulkar" alt="" />
<input type="hidden" name="22" class="friend_id" value="22" />
</div>
</div>
Along with:
$('.cell').click(function() {
var img = $(this).find('img');
$(img).toggle('slow');
$(otherDiv).html( $(img).attr('data-name') );
// other processing ...
});