Hi I have numbers of check boxes and below that I have a Button, which will filter data as per check box selection..
When I will click on filter button it will transfer to other page and when I click on back button the checkbox reamains checked.
but I want that when I click on back button then checkbox should be uncheck.
Any help.
For those who have similar issues, add autocomplete="off" to checkbox might help.
https://developer.mozilla.org/en-US/docs/Web/Security/Securing_your_site/Turning_off_form_autocompletion
You can reset the checkboxes on page load using jQuery
$('input:checkbox').prop('checked', false);
Demo (Checkbox will be never checked as onload am getting rid of checked property)
ondomready (Place the below code anywhere in your document)
$(document).ready(function(){
$('input:checkbox').prop('checked', false);
});
You may use below code :
window.onbeforeunload = function() {
//unchecked your check box here.
$("input[type='checkbox']").prop('checked', false)
};
Try this when back button is clicked
Use Jquery to clear the checkboxes
$("input[type='checkbox']").each( function() {
$(this).removeAttr('checked');
});
Related
I want to create a radio button that can have an unchecked value. So I created the code:
$('form').on('click', 'input[type="radio"]:checked', function (event) {
$(this).prop("checked", false);
});
Well, this is pretty straightforward: click on a checked radio, uncheck it.
But, what happens is that it never checks the radio in the first place. When I click an unchecked radio it checks before detecting if is checked, then considers it checked and unchecks it.
Well, this is not a duplicate as it asks a different question. It's not about how to uncheck, but how to automatically uncheck upon clicking.
How can I go around this problem?
You can solve your issue like following.
$('form :radio').attr('data-ischecked', function() {
return this.checked;
}); //set initial status in data-ischecked attribute
$('form').on('click', ':radio', function () {
var status = $(this).data('ischecked'); //get status
status && $(this).prop("checked", false); //uncheck if checked
$(this).data('ischecked', !status); //toggle status
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<form>
<input type="radio"/>
<input type="radio"/>
</form>
Your example only executes when the button is clicked. To have the radio button be checked when the page loads, I would put a $(document).onload() event that sets the button's value to checked.
This code won't work:
$(document).on('change', '#myRadioButton', function(){ // Won't work
});
I want to catch whenever a radiobutton is deselected or selected, but the code above doesn't catch when it's unselected.
What's the proper way to catch radio button deselection?
I guess, you should use something like that, setting onchange event on all radios from same group:
DEMO jsFiddle
$(document).on('change', ':radio[name=mygrp]', function(){
alert($('#myRadioButton').is(':checked'));
});
Do this:
$('#myRadioButton').change(function(){
alert("changed");
});
$('input[type=radio]').not('#myRadioButton').change(function(){
$('#myRadioButton').change();
});
What it does ?
We know that, a radio button only gets deselected when any other radio button gets selected.
So I basically bind a change event for #myRadioButton and then bind all other radio buttons except #myRadioButton to the change event and on it, i invoke #myRadioButton's change event. like $('#myRadioButton').change();
Here is the JsFiddle
I'm damn sure, that it will work.
Mark it as answer if it helps :)
I want to be able to run the jquery UI effect on this page:
http://jqueryui.com/toggle/
but when the user ticks or unticks a checkbox rather than clicking a button. I only want the one effect so I don't need the selection box. Basically I want some form fields to slide in or out depending on if the user checks or unchecks the checkbox.
Thanks
I've adapted the code from the jQuery UI and made this JS fiddle:
http://jsfiddle.net/m5sTY/13/
You can just add a click even to the the checkbox and see if it's checked:
$( "#effect" ).toggle( false );
$("#run_effect").click(function(){
if($('#run_effect').is(':checked')){
runEffect();
//you can do something else if the checkbox is checked here
}else{
runEffect();
//you can do something else if the checkbox is unchecked here
}
});
I removed the return false and it works fine. Try that.
I'm new to JQuery in general and I want to have a function activate when ANY checkbox on the page is checked or not. Then it should check what state the checkbox is "checked" or not.
I'm not sure how to do this as all the examples I'd seen require the name of the checkbox in order to work. I'd be fine if this was in Javascript aswell.
Anyone have any ideas?
$('input[type="checkbox"]') would select all checkboxes on your page.
The following would run a function when any of your checkboxes are changed, and when checked:
$('input[type="checkbox"]').change(function(){
if($(this).is(':checked')) {//do something}
})
Bind dynamically your checkboxes to change event, and check if they are checked, then do a function of your choice.
$(document).on("change", ".chkelement", function(){
if( $(this).is(":checked") )
{
//DO SOMETHING
}
});
I recommend use a container other than "document", as close as possible to where checkboxes will be, but you get the idea right?
im very new in javascript and jquery. I have this checkbox:
<label for="editable">Editable </label><input name="editable" type="checkbox" id="edita"/>
And this jquery action:
$('#slickbox1').toggle(400);
return false;
I want to execute that action when the checkbox is checked. Thanks!
You could try:
$('#edita').change(
function() {
if ($(this).is(':checked')) {
$('#slickbox1').toggle(400);
}
});
Although it's worth noting that running the toggle() method only when it's checked (assuming that it starts off un-checked) involves the user clicking the input once to show it, and then again to remove the check and again to re-check it so that it hides as a result of the toggle().
It might be worth considering:
$('#edita').change(
function() {
if ($(this).is(':checked')) {
// checked
$('#slickbox1').show(400);
}
else {
// un-checked
$('#slickbox1').hide(400);
}
});
Which shows $('#slickbox1') if the check-box is checked, and hides it if not,
Or:
$('#edita').change(
function() {
$('#slickbox1').toggle(400);
});
Which toggles the $('#slickbox1') between show() and hide() when the input is checked and un-checked.
Edited to address the question raised by DomingoSL (the OP) in comments:
...can you please make an edit to see the procedure if now the triger is not a checkbox but a button?
There are two changes that need to be made to accommodate this:
a button has no change event, so it would have to use click() instead, and
a button has no :checked (or equivalent) state, so the if/else becomes redundant.
One way of doing it, though, and I'm assuming your element names remain the same since you've posted no information to the contrary, is:
$('#edita').click(
function(){
$('#slickbox1').toggle(400);
});