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I am looking for a way to count certain words on a string.
$string = "How are you doing today? You are such a nice person!";
My goal is to count how many "are" in the $string variable.
Desire result: 2
Try this:
var count = yourString.match(/\bare\b/g);
count = count? count.length : 0; //checking if there are matches or not.
console.log(count);
var string = "are you bare footed?";
console.log(string.split(/\bare\b/).length - 1);
var str = "How are you doing today? You are such a nice person!";
var matchs;
matchs = str.match(/are/gi);
alert(matchs.length);
try this javascript match it returns match string as array format, and length method returns how many array index match.
try below.
var temp = "How are you doing today? You are such a nice person!.";
var count = countOcurrences(temp,"are");
alert(count);
function countOcurrences(str, value){
var regExp = new RegExp(value, "gi");
return str.match(regExp) ? str.match(regExp).length : 0;
}
Try this:
$string = "How are you doing today? You are such a nice person!";
var count = $string.match(/are/g);
alert(count.length);
Try this:
var string = "How are you doing today? You are such a nice person!";
var num = string.match(/are/g).length;
alert(num);
Here is Demo
You can also try something like this:
var temp = "How are you doing today? You are such a nice person!.";
var arr = [];
for(var i = 0;i< temp.split(' ').length; i++)
{
if(temp.split(' ')[i] === "are"){
arr.push(temp.split(' '));
}
}
alert(arr.length)
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How to remove word before slash using jquery?
/bis/admin
In my case, I want to remove "bis". any help?
You can use the JavaScript split method
var text = "/bis/admin";
var result = text.split("/");
console.log(result[result.length - 1]);
Another example
var text = "/bis/admin/dashboard";
var result = text.split("/");
console.log(result[result.length - 1]);
You could do the following using a regular expression
var el = '/bis/admin';
var newEl = el.replace(/^.*\//, "");
newEl will be 'admin'
You can just do:
let myString = '/bis/admin';
myString.split('/')[myString.split('/').length-1];
var str = "/bis/admin";
var splitStr = str.split("/");
var out = "/" + n[n.length - 1] //Out contains /admin
split string with /.
var strn = "/bis/admin";
console.log(strn.split("/")[2]);
Or you can simply use regex
var strn = "/bis/admin";
console.log(strn.replace(/^\/([^/]*)\//,""));
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I have this code:
var str = 'country/city/area'
var idx = str.lastIndexOf('country/city')
// idx = 0
And idx is always 0. Shouldn't idx be 12? My goal is to use it substr() in order to take the string 'area' out of the str.
var str = 'country/city/area'
var pattern = 'country/city/'
var idx = str.lastIndexOf(pattern) + pattern.length
var substring = str.substring(idx, str.length)
Explanation
1) Define the pattern you are searching for
2) Find the beginning of the pattern and add the length of the pattern => now you are at the end
3) Copy the part behind the pattern to the end of the string
if you want to get the last word, you can search for the last forward slash and get everything after it:
str.substr(str.lastIndexOf('/') + 1)
if you want to get everything after 'country/city/' but for example you don't know if this the first part of the string, you can use
str.substr(str.indexOf('country/city/') + 13);
it's not 100% clear from your question, what exactly you are trying to achieve though.
You're going to want to add the length of the string that you search for:
var str = 'country/city/area';
var checkStr = 'country/city';
var idx = str.lastIndexOf(checkStr);
var lastCharIndex = idx + checkStr.length;
// idx = 0
// idx = 12
note - it would be 12, not 13, because you didn't include the final "/" in your lastIndexOf parameter.
May be you can achieve your goal as follows;
var str = 'country/city/area',
newStr = str.replace("/area","");
console.log(newStr);
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I have a requirement to remove last n characters from string or remove 'page' from a particular string.
Eg:
var string = 'facebookpage';
Expected output string = 'facebook'
I would like to remove 'page' from the string.
Done it using substring.
var str = "facebookpage";
str = str.substring(0, str.length - 4);
Could you help me to find some better way to do it.
Regex for this:
//str - string;
//n - count of symbols, for return
function(str, n){
var re = new RegExp(".{" + n + "}","i");
return str.match(re);
};
EDIT:
For remove last n characters:
var re = new RegExp(".{" + n + "}$","i");
return str.replace(re, "");
UPDATE:
But use regex for this task, not good way; For example, AVG Runtime for 100000 iterations:
Str length solution = 63.34 ms
Regex solution = 172.2 ms
Use javascript replace function
var str = "facebookpage";
str = str.replace('page','');
You can use this regular expression :
(.*)\\w{4}
code :
var regex =(new RegExp("(.*)\\w{4}"))
val output = regex .exec("facebookpage")
// output is : ["facebookpage", "facebook"]
// output[1] is the Expected output which you want.
Hope this helps.
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I need to extract a part of a string. My goal is to extract from this string:
217591953.1396968335.2.2.utmcsr=search_email_alerts|utmccn=(not set)|utmcmd=email
the content between utmcsr= and |
So the output would be : "search_email_alerts".
var str = "217591953.1396968335.2.2.utmcsr=search_email_alerts|utmccn=(not set)|utmcmd=email";
var newStr1 = str.split("utmcsr=");
var newStr2 = newStr1[1].split("|");
var extractedStr = newStr2[0];
The variable extractedStr will be "search_email_alerts".
Use regular expression like following:
var test = "217591953.1396968335.2.2.utmcsr=search_email_alerts|utmccn=(not set)|utmcmd=email";
var result = test.match("/utmcsr=([^|]*)\|/");
alert(result[1]); // result[1] is your desired string
var str = "217591953.1396968335.2.2.utmcsr=search_email_alerts|utmccn=(not set)|utmcmd=email";
match = str.match(/utmcsr=(.*?)\|/);
output = match[1];
var str = "217591953.1396968335.2.2.utmcsr=search_email_alerts|utmccn=(not set)|utmcmd=email"
var result = str.substring(str.indexOf("utmcsr=") + 7,str.indexOf("|"))
Result contains the desired text.
You can do that in two ways
substring
match
Here's how you can do it with regex:
var str= "217591953.1396968335.2.2.utmcsr=search_email_alerts|utmccn=(not set)|utmcmd=email";
var res = str.match(/^.*utmcsr=(.*)\|.*\|.*$/);
res[1]
Here you go -
var str = "217591953.1396968335.2.2.utmcsr=search_email_alerts|utmccn=(not set)|utmcmd=email";
var startIndex = str.indexOf("utmcsr=") + "utmcsr=".length;
var numOfCharsToExtract = str.indexOf("|") - startIndex;
var result = str.substring(startIndex, numOfCharsToExtract);
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I am terrible at regex. Please have pity and give me a hand.
I am trying to split a string by the first occurrence of And (case sensitive), into an array with a length of 2. I have no idea were to begin, so can someone help me?
var strArr = "Thing And other thing".split(/magic regex/);
expect(strArr).to.deep.equal(["Thing","And other thing"]);
var strArr = "Thing and other thing".split(/magic regex/);
expect(strArr).to.deep.equal(["Thing and other thing", ""]);
var strArr = "One Thing And other thing And yet another thing".split(/magic regex/);
expect(strArr).to.deep.equal(["One Thing","And other thing And yet another thing"]);
var strArr = "yep, just one thing".split(/magic regex/);
expect(strArr).to.deep.equal(["yep, just one thing", ""]);
UPDATE this is working exactly the way I need it to, but its still ugly:
parser = function(str) {
var spl;
spl = str.split(/\s(?=And )/);
if (spl.length > 1) {
spl = [spl.shift(), spl.join(" ")];
} else {
spl = [str, ''];
}
return spl;
};
There is no need for a regular expression for that. Just get the first index of "And" in the string:
var i = str.indexOf("And");
var strArr;
if (i == -1) {
strArr = [ str ];
} else {
strArr = [ str.substr(0, i), str.substr(i) ];
}
While Guffa's method works, if you end up needing to do this the regex way, the following will work (via a positive lookahead):
var str = "Thing And other thing";
var spl = str.split(/\s(?=And\s)/);
if (spl.length > 1)
spl = [spl.shift(), spl.join(" ")];
To test:
alert(JSON.stringify(spl));
jsFiddle
Updated to ensure it splits on [space]And[space]
I suggest doing a simple split then checking if the array has one or two
strArr.split("And", 2).length;