I have some functions defined inside an object:
var functions = {
__construct: function(){
console.log(this);
this.prototype.__construct(); // <problem
}
};
I merge this object with another one that is a function (after I create a new instance of the function):
var plugin = function(){};
plugin.prototype.__construct = function(){
console.log('parent');
};
var i = new plugin();
i = $.extend({}, i, functions);
But after that when I try to call the __construct function:
i.__construct();
I get this error:
Uncaught TypeError: Cannot call method '__construct' of undefined
It's because this line:
this.prototype.__construct();
I tried to see if I can call the parent constructor function from the child constructor, but it appears that the object doesn't have a prototype? wtf?
Not sure what you're trying to do here but i does have a __construct function when using the code you provided:
var functions = {
__construct: function(){
console.log(this);
this.prototype.__construct(); // <problem
}
};
var plugin = function(){};
plugin.prototype.__construct = function(){
console.log('parent');
};
var i = new plugin();
i = $.extend({}, i, functions);
console.log(i.__construct===functions.__construct);//true
console.log(i.__construct===plugin.prototype.__construct);//false
Not sure what you think this.prototype is going to be, maybe this answer will clear up what prototype is used for (shared members) and what this means (instance specific). You can shadow shared members that are defined in the prototype further down the prototype chain or in an instance but that's not what you're doing here.
If you dynamically want to extend an instance created with a constructor function you can do something like this:
var functions = {
__construct: function(){
this.constructor.prototype.__construct.call(this);
}
};
var Plugin = function(){};
Plugin.prototype.__construct = function(){
console.log('parent');
};
var i = new Plugin();
i = $.extend(i,functions);
i.__construct();
Related
I'm always getting Cannot set property 'saySomething' of undefined but why?
Am I making a mistake somewhere?
var Person = new Object();
Person.prototype.saySomething = function ()
{
console.log("hello");
};
Person.saySomething();
Debugging tip: You get this ..of undefined errors when you try to access some property of undefined.
When you do new Object(), it creates a new empty object which doesn't have a prototype property.
I am not sure what exactly are we trying to achieve here but you can access prototype of function and use it.
var Person = function() {};
Person.prototype.saySomething = function() {
console.log("hello");
};
var aperson = new Person();
aperson.saySomething();
The prototype property exists on functions, not on instantiated objects.
var Person = new Object();
console.log(Person.prototype); // undefined
var Person2 = function () {}
console.log(Person2.prototype); // {}
This is useful because things put on the prototype of a function will be shared by all object instances created with that function (by using new).
var Person = function() {};
Person.prototype.saySomething = function() {
console.log("hello");
};
console.log(
new Person().saySomething === Person.prototype.saySomething // true. they are the same function
);
If all you want is to add a method to the person object, there's no need for a prototype:
var Person = {};
Person.saySomething = function() {
console.log("hello");
};
Person.saySomething();
You can even use object literal syntax:
var Person = {
saySomething: function() {
console.log("hello");
}
};
Person.saySomething();
i was trying out some code thought of posting it, might help others.
<script>
var MODULE = {};
MODULE = (function (my) {
my.anotherMethod = function () {
console.log("hello ");
};
my.newMethod = function(){
console.log("hi new method ");
}
return my;
}(MODULE));
MODULE.anotherMethod();
MODULE.newMethod();
</script>
And please not var MODULE ={}, if this is not initialized with {} then it give cannot set property.
I know i am late to the party but as you see there is no satisfying answer available to the question so i am providing my own.
In your case when you write
var Person = new Object();
you are creating an instance of Object type.
You can add a property using prototype property to the Object, not to the instance of Object.which you can use by the instance laterly.
so you can define like
Object.prototype.saySomething = function ()
{
console.log("hello");
};
now you can call it like this.
Person.saySomething();
You can check here.
var Person = function(name) {
this.canTalk = true;
this.name = name;
};
Person.prototype.greet = function() {
if (this.canTalk) {
console.log('Hi, I am ' + this.name);
}
};
bob = new Person('bob');
bob.greet();
I'm trying to create an Object containing other Objects and functions, in a prototype, the relevant part is the UI prototype;
var fChat = function() {
this.debug = true;
};
fChat.prototype = {
constructor: fChat,
Log: function(str){
if(this.debug){
console.log(str);
}
},
UI: {
Login: {
Show: function(){
this.Log("UI.Login.Show()");
}
}
}
};
var fChatInstance = new fChat();
fChatInstance.UI.Login.Show();
When i call fChatInstance.UI.Login.Show() It give me an error:
Uncaught TypeError: this.Log is not a function
Is that because by using this is on another scope?
Usually i do var self = this;at the start of a prototype, but i don't know how I can do that by using an Object prototype.
Yes. The problem is the javascript dynamic binding of this, to fix it you can set "this" to the object by using bind function. Change the fchat function refactor it like this:
var fChat = function() {
this.debug = true;
this.UI.Login.Show = this.UI.Login.Show.bind(this);
this.Log = this.Log.bind(this);
};
I'm trying to have a 'class' in JS which tracks how many instances of itself have been instantiated. I am attempting to do so like this...
var myNamespace = {};
myNamespace.myClass = function () {
//fails here as .getNetInstanceNo() not recognised...
var instanceNumber = myNamespace.myClass.getNextInstanceNo();
return {
instanceNo : function() { return instanceNumber; }
}
};
myNamespace.myClass.InstanceNo = 0; //static property?
//should the class itself have this method added to it...
myNamespace.myClass.prototype.getNextInstanceNo = function () { //static method?
return myNamespace.myClass.InstanceNo++;
};
var class1 = new myNamespace.myClass();
alert('class 1 has instance of ' + class1.instanceNo() );
However this fails as the getNextInstanceNo function is not recognised. Even though I think I'm adding it through the myClass.prototype.
What am I doing wrong?
prototype is an object from which other objects inherit properties, as in when you create an instance of an object and that object doesn't have a property/method, when called, the prototype of the class in which the object belongs to is searched for that property/method, here's a simple example:
function Animal(){};
Animal.prototype.Breathe = true;
var kitty= new Animal();
kitty.Breathe; // true (the prototype of kitty breathes)
var deadCat = new Animal();
deadCat.Breathe = false;
deadCat.Breathe; // false (the deadCat itself doesn't breath, even though the prototype does have breath
As you said yourself, you don't need to define getNextInstanceNo on prototype, since that's not how static methods are defined on JavaScript, leave it right right there on the class itself, instead you can define the instanceNo method on prototype, here's how:
var myNamespace = {};
myNamespace.myClass = function () {
this.instanceNumber = myNamespace.myClass.getNextInstanceNo();
};
myNamespace.myClass.prototype.instanceNo = function () {
return this.instanceNumber;
};
myNamespace.myClass.InstanceNo = 0;
myNamespace.myClass.getNextInstanceNo = function () {
return myNamespace.myClass.InstanceNo++;
};
var class1 = new myNamespace.myClass();
alert('class 1 has instance of ' + class1.instanceNo());
I like that in javascript, I can create a function, and then add further methods and attributes to that function
myInstance = function() {return 5}
myInstance.attr = 10
I would like to create a class to generate these objects. I assume I have to inherit from the Function base class.
In other words, I would like to:
var myInstance = new myFunctionClass()
var x = myInstance()
// x == 5
But I don't know how to create the myFunctionClass. I have tried the following, but it does not work:
var myFunctionClass = function() {Function.call(this, "return 5")}
myFunctionClass.prototype = new Function()
myInstance = new myFunctionClass()
myInstance()
// I would hope this would return 5, but instead I get
// TypeError: Property 'myInstance' of object #<Object> is not a function
I also tried the more complicated (and more proper?) inheritance method found here: How to "properly" create a custom object in JavaScript?, with no more luck. I have also tried using the util.inherits(myFunctionClass, Function) found in node.js. Still no luck
I have exhausted Google, and therefore feel that I must be missing something fundamental or obvious. Help would be greatly appreciated.
Your trying to inherit from Function. This is a right pain to do. I suggest you do the following instead
Live Example
var Proto = Object.create(Function.prototype);
Object.extend(Proto, {
constructor: function (d) {
console.log("construct, argument : ", d);
this.d = d;
// this is your constructor logic
},
call: function () {
console.log("call", this.d);
// this get's called when you invoke the "function" that is the instance
return "from call";
},
method: function () {
console.log("method");
// some method
return "return from method";
},
// some attr
attr: 42
});
You want to create a prototype object that forms the basis of your "class". It has your generic methods/attributes. It also has a constructor that gets invoked on object construction and a call method that gets invoked when you call the function
var functionFactory = function (proto) {
return function () {
var f = function () {
return f.call.apply(f, arguments);
};
Object.keys(proto).forEach(function (key) {
f[key] = proto[key];
});
f.constructor.apply(f, arguments);
return f;
}
}
A function factory takes a prototype object and returns a factory for it. The returned function when called will give you a new function object that "inherits" from your prototype object.
var protoFactory = functionFactory(proto);
var instance = protoFactory();
Here you create your factory and then create your instance.
However this isn't proper prototypical OO. we are just shallow copying properties of a prototype into a new object. So changes to the prototype will not reflect back to the original object.
If you want real prototypical OO then you need to use a hack.
var f = function () {
// your logic here
};
f.__proto__ = Proto;
Notice how we use the non-standard deprecated .__proto__ and we are mutating the value of [[Prototype]] at run-time which is considered evil.
JS does not allow a constructor to return a function, even though functions are objects. So you cant have an instantiation of a prototype that is itself executable. (Am I right in this? please correct if I'm not, it's an interesting question).
Though you could do a factory function:
var makeCoolFunc = function() {
var f = function() { return 5 };
f.a = 123;
f.b = 'hell yes!'
return f;
};
var func = makeCoolFunc();
var x = func();
You can extend Function and pass the wanted function body as String to the super constructor. The context of the function can be accessed with arguments.callee.
Example for an observable Attribute class:
export default class Attribute extends Function {
constructor(defaultValue){
super("value", "return arguments.callee.apply(arguments);");
this.value = defaultValue;
this.defaultValue = defaultValue;
this.changeListeners = [];
}
apply([value]){
if(value!==undefined){
if(value!==this.value){
var oldValue = this.value;
this.value=value;
this.changeListeners.every((changeListener)=>changeListener(oldValue, value));
}
}
return this.value;
}
clear(){
this.value=undefined;
}
reset(){
this.value=this.defaultValue;
}
addChangeListener(listener){
this.changeListeners.push(listener);
}
removeChangeListener(listener){
this.changeListeners.remove(listener);
}
clearChangeListeners(){
this.changeListeners = [];
}
}
Example usage:
import Attribute from './attribute.js';
var name= new Attribute();
name('foo'); //set value of name to 'foo'
name.addChangeListener((oldValue, newValue)=>{
alert('value changed from ' +oldValue+ ' to ' +newValue);
});
alert(name()); //show value of name: 'foo'
name('baa'); //set value of name to new value 'baa' and trigger change listener
I have an existing class I need to convert so I can append functions like my_class.prototype.my_funcs.afucntion = function(){ alert(private_var);} after the main object definition. What's the best/easiest method for converting an existing class to use this method? Currently I have a JavaScript object constructed like this:
var my_class = function (){
var private_var = '';
var private_int = 0
var private_var2 = '';
[...]
var private_func1 = function(id) {
return document.getElementById(id);
};
var private_func2 = function(id) {
alert(id);
};
return{
public_func1: function(){
},
my_funcs: {
do_this: function{
},
do_that: function(){
}
}
}
}();
Unfortunately, currently, I need to dynamically add functions and methods to this object with PHP based on user selected settings, there could be no functions added or 50. This is making adding features very complicated because to add a my_class.my_funcs.afunction(); function, I have to add a PHP call inside the JS file so it can access the private variables, and it just makes everything so messy.
I want to be able to use the prototype method so I can clean out all of the PHP calls inside the main JS file.
Try declaring your "Class" like this:
var MyClass = function () {
// Private variables and functions
var privateVar = '',
privateNum = 0,
privateVar2 = '',
privateFn = function (arg) {
return arg + privateNum;
};
// Public variables and functions
this.publicVar = '';
this.publicNum = 0;
this.publicVar2 = '';
this.publicFn = function () {
return 'foo';
};
this.publicObject = {
'property': 'value',
'fn': function () {
return 'bar';
}
};
};
You can augment this object by adding properties to its prototype (but they won't be accessible unless you create an instance of this class)
MyClass.prototype.aFunction = function (arg1, arg2) {
return arg1 + arg2 + this.publicNum;
// Has access to public members of the current instance
};
Helpful?
Edit: Make sure you create an instance of MyClass or nothing will work properly.
// Correct
var instance = new MyClass();
instance.publicFn(); //-> 'foo'
// Incorrect
MyClass.publicFn(); //-> TypeError
Okay, so the way you're constructing a class is different than what I usually do, but I was able to get the below working:
var my_class = function() {
var fn = function() {
this.do_this = function() { alert("do this"); }
this.do_that = function() { alert("do that"); }
}
return {
public_func1: function() { alert("public func1"); },
fn: fn,
my_funcs: new fn()
}
}
var instance = new my_class();
instance.fn.prototype.do_something_else = function() {
alert("doing something else");
}
instance.my_funcs.do_something_else();
As to what's happening [Edited]:
I changed your my_funcs object to a private method 'fn'
I passed a reference to it to a similar name 'fn' in the return object instance so that you can prototype it.
I made my_funcs an instance of the private member fn so that it will be able to execute all of the fn methods
Hope it helps, - Kevin
Maybe I'm missing what it is you're trying to do, but can't you just assign the prototype to the instance once you create it? So, first create your prototype object:
proto = function(){
var proto_func = function() {
return 'new proto func';
};
return {proto_func: proto_func};
}();
Then use it:
instance = new my_class();
instance.prototype = proto;
alert(instance.prototype.proto_func());