This question already has answers here:
How to reset a form using jQuery with .reset() method
(16 answers)
Closed 8 years ago.
I KNOW this question has been asked numerous times as I have used this website's solutions to no avail. I currently have this implementation:
$("input:reset").click(function () {
$('#answer_2').html('License number is not long enough');
$('#answer_1').html('');
$('#data_entry').each (function(){
this.reset();
});
});
I know the selector is correct as the two html changes (I put them in to confirm I was selector for the reset button click correctly) occur as they should.
Here is my form declaration:
<form name="data_entry" id="data_entry" method="post" action="">
The problem is I keep getting the error that there is no 'reset' function and the form is never cleared. This is my most recent attempt at following answers to this problem on stackoverflow site. Please help.
Why reset when you want to clear/empty?
this.empty();
might do the trick?
Your each is wrong and it's unnecessary.
$('#data_entry').get(0).reset();
This should work because you got the right element but $() returns a jQuery object, not a DOM element. get will grab your DOM element and then you can use reset() (which is not a jQuery function)
Related
This question already has answers here:
Is there an "exists" function for jQuery?
(47 answers)
Closed 5 years ago.
Thanks in advance,
I'm trying to create an if statement that will help me solve an issue.
I want to be able to assign an ID for a button and if that ID matches the
"if statement id entered" it will run my script else it wont do nothing.
i'v tried couple of things, but with no luck, I'm new to jQuery hope someone could give a hint,any other suggestion will be great ,cheers.
this is the script I want to run:
jQuery("#myId").append("<i class='fa fa-camera-retro fa-lg'></i>");
this is what iv tried:
if($('a' == '#myId') {
jQuery("#myId").append("<i class='fa fa-camera-retro fa-lg'></i>");
}
thanks to all
Since I don't know when you would like to fire that piece of code: if you are trying to trigger it after an event being dispatched you can Simply use the .on() function to attach the event listener to the element. If you are Just iterating over an element list you can use the .is() function, and check if that $('a').is('#thatID') !
This question already has answers here:
Why isn't my JavaScript working in JSFiddle?
(7 answers)
Closed 5 years ago.
I am new to javaScript, that's why I am unable to find the real root cause for it.
This simple code is to append the value of a button into a paragraph every time i press it; however if the paragraph contains only a zero then it should replace the value, not append.
This is working fine on all of my browsers and also when running the snippet on stackoverflow .
Not working at all on https://jsfiddle.net/
Can you please tell me why I am facing this problem and what changes should I make to make it work on every platform?
function append(a){
if (document.getElementById('text1').innerHTML == '0')
document.getElementById('text1').innerHTML = document.getElementById(a).value;
else
document.getElementById('text1').innerHTML += document.getElementById(a).value;
};
<div>
<p id='text1' style="border-style: inset;
width:200px;
display:inline-block;">0</p><br>
<button value="1" id='a1' onclick="append(this.id)">1</button></div>
By default JSFiddle wraps your JavaScript in an onload function. This means that function append is only defined in that scope, and is not made global.
Global variables (and functions) are generally considered bad practice, as are inline event handlers.
Try:
document.getElementById('a1').onclick = append;
Then, inside function append, simply refer to this.value.
This question already has answers here:
Event binding on dynamically created elements?
(23 answers)
Closed 6 years ago.
I have following simple html block:
<span class="change_ordering show-list" data-ordering-by="product_list" data-ordering-direction="desc">By list</span>
Then, I have following js-code:
$(document).ready(function() {
$('.show-list').click(function() {
console.log('qwe');
});
});
When I click on it - nothing happens. But when I paste this js-code to Google Chrome JS console, it works perfectly. JS works fine on my site, I can make other JQuery actions. I also tried to write $('.change_ordering.show-list') and $('span.change_ordering.show-list') and $('span.show-list'), but still no progress. What I'm missing?
EDIT: This element is not drowing by ajax. I don't understand why it's duplicate.
Please apply click using following way
$(document).on("click",".show-list",function(){})
It will work
This question already has answers here:
How to call multiple JavaScript functions in onclick event?
(14 answers)
Closed 7 years ago.
I was trying to run two JS functions in one click using this. Can anybody show me how to do it correctly?
<button onclick="getlocation" onclick="showDiv()">Try It</button>
I tried adding a ; between the two functions but it didnt work too.
"Adding ";" semicolon didn't work, if you could help.."
It works for sure, you have to do it like that: onclick="getLocation();showDiv()"
Was not relevant in this case:
The problem could be, that both functions are setting the content of your div, so the second function will overwrite the content!
Use .innerHTML += "..."; on you second function, this will append the content to the exisitng content.
This question already has answers here:
Find currently visible div in jquery
(5 answers)
Closed 3 years ago.
Only one jQuery event runs per refresh of the page. What am I doing that's so wrong?
$("#contact_link_email").on("click",function(){
$("#contact-form").replaceWith('<h2>Email heading</h2>');
});
$("#contact_link_facebook").on("click",function(){
$("#contact-form").replaceWith('<h2>Facebook heading</h2>');
});
$("#contact_link_twitter").click(function(){
$("#contact-form").replaceWith('<h2>Twitter heading</h2>');
});
$("#contact_link_gplus").click(function(){
$("#contact-form").replaceWith('<h2>GPlus heading</h2>');
});
Once one of those events runs, $("#contact-form") doesn't reference anything. If you want to replace it with something, try making that something have the same id.