Develop Reference

Return mysql fetch data and insert into form field value

i have a list of clients on a page, each client has an icon to click on to edit the client details.
<i class="fas fa-user-edit gray openModal" data-modal="modal2" client="'.$client['id'].'"></i>
Everything is good up to this point. click the icon the proper modal opens and it triggers the js file just fine. (I did alot of console logs to ensure). The client variable in my jquery file holds fine and i'm able to get it passed to the php file.
in the php file i'm able to pull the information into an array and i was able to just echo the $client['firstName'] and have it show in the console.
when i moved to getting that information and parse it as the Json is when i got lost. Can someone please help me take my result and load into my form fields. The code i have now may be totally off because i've been playing with different code from different searches.
form (shortened to two fields for ease of example)
<form id="form" class="editClient ajax" action="ajax/processForm.php"
method="post">
<input type="hidden" id="refreshUrl" value="?
page=clients&action=view&client=<?php echo $client['id'];?>">
<input type="hidden" name="client" value="<?php echo $client['id'];?>">
<div class="title">
Client Name
</div>
<div class="row">
<!-- first name -->
<div class="inline">
<input type="text" id="firstName" name="firstName" value="<?php echo $client['firstName']; ?>" autocomplete="nope" required>
<br>
<label for="firstName">First Name<span>*</span></label>
</div>
<!-- last name -->
<div class="inline">
<input type="text" id="lastName" name="lastName" value="<?php echo $client['lastName']; ?>" autocomplete="nope" required>
<br>
<label for="lastName">Last Name<span>*</span></label>
</div>
</form>
javascript/jquery file
$('.openModal').on('click', function() {
//$('body, html, div').scrollTop(0);
var that = $(this),
client = that.attr('client');
$.ajax({
type: "post",
url: "ajax/getClient.php",
data: {id:client},
success: function(response){
var result = JSON.parse(response);
var data = result.rows;
$("#firstName").val(data[0]);
}
})
});
php file
<?php
include('../functions.php');
$sql = 'SELECT * FROM clients WHERE id="'.$_POST['id'].'"';
$result = query($sql);
confirmQuery($result);
$data = fetchArray($result);
echo json_encode(['response' => $data, 'response' => true]);
?>
UPDATED ----------
Here is my final js file that allowed my form values to be set.
$('.openModal').on('click', function() {
var that = $(this),
client = that.attr('client');
$.ajax({
type: "post",
url: "ajax/getClient.php",
data: {id:client},
success: function(response){
var result = JSON.parse(response);
$("select#primaryContact").append( $("<option>")
.val(result[0].primaryContact)
.html(result[0].primaryContact)
);
$("select#primaryContact").append( $("<option>")
.val("")
.html("")
);
if (result[0].email !== "") {
$("select#primaryContact").append( $("<option>")
.val(result[0].email)
.html(result[0].email)
);
}
if (result[0].phoneCell !== "") {
$("select#primaryContact").append( $("<option>")
.val(result[0].phoneCell)
.html(result[0].phoneCell)
);
}
if (result[0].phoneHome !== "") {
$("select#primaryContact").append( $("<option>")
.val(result[0].phoneHome)
.html(result[0].phoneHome)
);
}
$("input#firstName").val(result[0].firstName);
$("input#lastName").val(result[0].lastName);
$("input#address").val(result[0].address);
$("input#city").val(result[0].city);
$("input#zip").val(result[0].zip);
$("input#email").val(result[0].email);
$("input#phoneCell").val(result[0].phoneCell);
$("input#phoneHome").val(result[0].phoneHome);
$("input#phoneFax").val(result[0].phoneFax);
$("input#source").val(result[0].source);
$("input#referBy").val(result[0].referBy);
$("input#client").val(result[0].id);
}
})
});

$.post variables not passing to php getting undefined index error

This code almost works, it inserts into the db and it is giving feedback on the page to say it has updated. However I am getting undefined index between lines 5-8 in the insert_message.php and my database is filling with blank entries (except the date).
Apologies for being new to jquery and AJAX. Need some help.
form
<form enctype='multipart/form-data' action='insert_message.php' method='POST' id='contact_form'>
<div class="row">
<div class="col-xs-6">
<div class='form-group'>
<label for='email'>Email:</label>
<input class='form-control' type='email' id='email' name='email' required='required' maxlength='35'/>
</div>
</div>
</div>
<div class="row">
<div class="col-xs-6">
<div class='form-group'>
<label for='subject'>Subject:</label>
<input class='form-control' type='text' id='subject' name='subject' required='required' maxlength='35'/>
</div>
</div>
</div>
<div class="form-group">
<label for='message'>Message:</label>
<textarea class="form-control" placeholder="Message" id='message' required="required"></textarea>
</div>
<input type="hidden" name="reciever" id='receiver' value="Admin">
<input class='btn btn-primary' id='submit' type='submit' value='submit' >
</form>
<span id="result"></span>
jquery
<script>
$(document).ready(function(){
$("#submit").click( function(e) {
e.preventDefault();
var message1 = $('message').val();
var sender1 = $('sender').val();
var receiver1 = $('receiver').val();
var subject1 = $('subject').val();
$.post("insert_message.php", {message:message1, sender:sender1, receiver:receiver1, subject:subject1}, function(info) { $("#result").html(info);
});
clearInput();
});
$("#contact_form").submit( function() {
return false;
});
function clearInput() {
$("#contact_form :input").each( function() {
$(this).val('');
});
}
});
</script>
insert_message.php
<?php
include("connections/conn.php");
$getsubject = mysqli_escape_string($conn,$_POST["subject1"]);
$getmessage = mysqli_escape_string($conn,$_POST["message1"]);
$getsender = mysqli_escape_string($conn,$_POST["sender1"]);
$getreceiver = mysqli_escape_string($conn,$_POST["receiver1"]);
$date = date("Y-m-d");
$insertmessage = "INSERT INTO messages (id,subject,message,date,sender,receiver) VALUES (NULL,'$getsubject','$getmessage','$date','$getsender','$getreceiver')";
$insert = mysqli_query($conn, $insertmessage) ;
if($insert){
echo "Message Sent";
}else{
echo "Message did not send";
}
UPDATE
attempted alternative way but I still get the undefined index in the inser_message.php
$(document).ready(function(){
$("#submit").click( function(e) {
e.preventDefault();
$.ajax({
url: "insert_message.php",
type: "POST",
data: $("#contact_form").serialize(),
success: function(result){
$("#result").html(result);
}
});
});
});

You have several problems in both JS and PHP.
Adjust typo in input hidden where actually name="reciever" instead of name="receiver";
In your $("#submit").click() function you're trying to selecting elements with an invalid selector (e.g. $('message').val() instead of $("#message").val());
Adjust $_POST keys by removing 1 at end. If you have any doubt, print the whole array print_r($_POST);
This is not an error but a suggestion. Since you require conn.php to do your job, I would use require instead of include.

Remove the $conn and the 1's from your 'get' block and, for example:
$getsubject = mysqli_escape_string($_POST["subject"]);
$getmessage = mysqli_escape_string($_POST["message"]);
$getsender = mysqli_escape_string($_POST["sender"]);
$getreceiver = mysqli_escape_string($_POST["receiver"]);

AJAX not submitting fom

I am working with a script wherein I should be able to submit a form without page reload with the help of AJAX. The problem is that the form is not submitted to the database. Any help would be appreciated. I had messed with the codes but nothing works for me.
Here is the javascript code:
<script type="text/javascript">
setInterval(function() {
$('#frame').load('chatitems.php');
}, 1);
$(function() {
$(".submit_button").click(function() {
var textcontent = $("#content").val();
var usercontent = $("#username").val();
var namecontent = $("#nickname").val();
var dataString = 'content=' + textcontent;
var userString = 'content=' + usercontent;
var nameString = 'content=' + namecontent;
if (textcontent == '') {
alert("Enter some text..");
$("#content").focus();
} else {
$("#flash").show();
$("#flash").fadeIn(400).html('<span class="load">Loading..</span>');
$.ajax({
type: "POST",
url: "chatitems.php",
data: {
dataString,
userString,
nameString
},
cache: true,
success: function(html) {
$("#show").after(html);
document.getElementById('content').value = '';
$("#flash").hide();
$("#frame").focus();
}
});
}
return false;
});
});
</script>
this is my form:
<form action="" method="post" name="form">
<input type="hidden" class="form-control" id="username" name="username" value="<?php echo $username; ?>" readOnly />
<input type="hidden" class="form-control" id="nickname" name="nickname" value="<?php echo $nickname; ?>" readOnly />
<input type="hidden" class="form-control" id="chat_role" name="chat_role" value="<?php echo $pm_chat; ?>" readOnly />
<input type="hidden" class="form-control" id="team" name="team" value="<?php echo $manager; ?>'s Team" readOnly />
<input type="hidden" class="form-control" id="avatar" name="avatar" value="<?php echo $avatar; ?>" readOnly />
<div class="input-group">
<input type="text" class="form-control" id="content" name="content" />
<span class="input-group-btn">
<input type="submit" name="submit" class="submit_button btn btn-primary" value="Post"></input>
</span>
</div>
</form>
and finally, this is my PHP code:
<?php
include('db.php');
$check = mysql_query("SELECT * FROM chat order by date desc");
if(isset($_POST['content']))
{
$content=mysql_real_escape_string($_POST['content']);
$nickname=mysql_real_escape_string($_POST['nickname']);
$username=mysql_real_escape_string($_POST['username']);
$ip=mysql_real_escape_string($_SERVER['REMOTE_ADDR']);
mysql_query("insert into chat(message,ip,username,nickname) values ('$content','$ip','$username','$nickname')");
}
$req = mysql_query('select * from chat ORDER BY date desc');
while($dnn = mysql_fetch_array($req))
{
?>
<div class="showbox">
<p><?php echo $dnn['username']; ?> (<?php echo $dnn['ip']; ?>): <?php echo $dnn['message']; ?></p>
</div>
<?php
}
?>
I know there is something wrong with my code somewhere but had spent few days already but no avail. Im hoping that someone would help.
UPDATE
The form is being submitted successfully with this code only data: dataString but when I added the nameString and the userString thats when everything doesnt work as it should. I tried messing around that code but still got nothing.

To find out what is wrong with this you need to establish that:
a) The click event is firing, which you could test by adding a console.log('something'); at the top of that function.
b) The AJAX function is working somewhat correctly, which again you could check by adding a console.log() in the success callback of the AJAX request. You can also check console for errors, e.g if the chatitems.php is 404'ing
c) That all the data you're collecting from the DOM e.g var textcontent = $("#content").val(); contains what you're expecting it to. Again console.log().
d) That the page you're calling is successfully processing the data you're sending across, so die() a print_r() of the $_POST values to check the data it's receiving is in the format your expecting. You also need to add some error handling to your mysql code: https://secure.php.net/manual/en/function.mysql-error.php (or better yet use PDO or MySQLi https://secure.php.net/manual/en/book.pdo.php), which will tell you if there's something wrong with your MySQL code. You can check the return of you're AJAX call (which would include any errors) by console.log(html) in your success callback.
Information you gather from the above will lead you to your bug.

If i understand right, it seem you try to bind event before the button is available. Try (depend on the version of JQuery you use) :
$(document).on('click, '.submit_button', function(){
...
});

jQuery Ajax data to same PHP page not working as INTENDED?

I have 22.php that both form and PHP script reside.
Problems;
1) when I submit, result shows below. But duplicates the form.
2) Further entering in the top (above) form, changes the result accordingly.
3) When I enter in the bottom form, then also the result changes accordingly and disappear the bottom from.
What I have tried so far as solutions;
1) removed totally - url: '',
2) replaced to the same page - url: '22.php',
3) replaced to this - var yourData = $(this).serialize();
4) Placed the PHP script just soon after body tag
None of above solve! Please help!
<html>
<head>
<title>My first PHP page</title>
<script type="text/javascript"
src="http://ajax.googleapis.com/ajax/libs/jquery/2.1.3/jquery.min.js"></script>
<script>
$(document).ready(function() {
$("#btn").click(function(event){
event.preventDefault();
var myname = $("#name").val();
var myage = $("#age").val();
var yourData ='name='+myname+'&age='+myage; // php is expecting name and age
$.ajax({
type:'POST',
data:yourData,//Without serialized
//url: '22.php',
success:function(data) {
if(data){
$('#testform')[0].reset();//reset the form
$('#result').html(data); // here html()
//alert('Submitted');
}else{
return false;
}
}
});
});
});
</script>
</head>
<body>
<?php
if ( isset($_POST['name']) ) { // was the form submitted?
echo "Welcome ". $_POST["name"] . "<br>";
echo "You are ". $_POST["age"] . "years old<br>";
}
?>
<form method="post" id="testform">
Name:
<input type="text" name="name" id="name" />Age:
<input type="text" name="age" id="age" />
<input type="submit" name="submit" id="btn" />
</form>
<div id='result'></div>
</body>
</html>

Just place PHP code top and put exit();. Here is your full code:
<?php
if ( isset($_POST['name']) ) { // was the form submitted?
echo "Welcome ". $_POST["name"] . "<br>";
echo "You are ". $_POST["age"] . "years old<br>";
exit;
}
?>
<html>
<head>
<title>My first PHP page</title>
<script type="text/javascript"
src="http://ajax.googleapis.com/ajax/libs/jquery/2.1.3/jquery.min.js"></script>
<script>
$(document).ready(function() {
$("#btn").click(function(event){
event.preventDefault();
var myname = $("#name").val();
var myage = $("#age").val();
var yourData ='name='+myname+'&age='+myage; // php is expecting name and age
$.ajax({
type:'POST',
data:yourData,//Without serialized
//url: '22.php',
success:function(data) {
if(data){
$('#testform')[0].reset();//reset the form
$('#result').html(data); // here html()
//alert('Submitted');
}else{
return false;
}
}
});
});
});
</script>
</head>
<body>
<form method="post" id="testform">
Name:
<input type="text" name="name" id="name" />Age:
<input type="text" name="age" id="age" />
<input type="submit" name="submit" id="btn" />
</form>
<div id='result'></div>
</body>
</html>

Using php and javascript to put random number in txt file

I have a text input field with a button that generates a random number between 1 and 20 and displays within the text field. The problem I am having, is taking that random number that it generates and saving it into a .txt file. The file chat.txt is stored in the same directory as the rest of these files. Not sure I am going about this the right way. The following is the code. Any ideas would be helpful.
chat.php:
<div id="pageWrap">
<form action="roll.php" name="rollBox" method="post">
<input type="text" name="roll" id="demo">
<button type="button" name="button" onclick="myFunction()">Roll</button>
<script>
function myFunction()
{
var x=document.getElementById("demo")
x.value=Math.floor((Math.random()*20)+1);
}
</script>
<h2>Chat</h2>
<p id="name-area"></p>
<div id="chatWrap"><div id="chat-area"></div></div>
<form id="send-message-area">
<p>Your message: </p>
<textarea id="sendie" maxlength = '100' ></textarea>
</form>
</div>
roll.php:
<?php
if(isset($_POST['button']))
{
$roll = $_POST['roll'];
$file = fopen("chat.txt");
fwrite($file,$roll);
fclose($file);
print_r(error_get_last());
}
?>

If you are interested in your way of generating random number on client end with javascript:
on html:
<script type="text/javascript" src="//ajax.googleapis.com/ajax/libs/jquery/1.7.1/jquery.min.js"></script>
<div id="pageWrap">
<form action="page.php" id="rollBox" name="rollBox" method="post">
<input type="text" name="roll" id="demo">
<button type="submit" name="submit" >Roll</button>
<script>
$(document).ready(function () {
$('#rollBox').submit(function(e) {
var x=document.getElementById("demo");
x.value=Math.floor((Math.random()*20)+1);
e.preventDefault();
var obj = $(this), // (*) references the current object/form each time
url = obj.attr('action'),
method = obj.attr('method'),
data = {};
obj.find('[name]').each(function(index, value) {
var obj = $(this),
name = obj.attr('name'),
value = obj.val();
data[name] = value;
});
$.ajax({
url: url,
type: method,
data: data,
success: function(response2) {}
});
return false;
});
});
function myFunction()
{
var x=document.getElementById("demo")
x.value=Math.floor((Math.random()*20)+1);
document.getElementById("rollBox").submit();
}
</script>
</form>
<h2>Chat</h2>
<p id="name-area"></p>
<div id="chatWrap"><div id="chat-area"></div></div>
<form id="send-message-area">
<p>Your message: </p>
<textarea id="sendie" maxlength = '100' ></textarea>
</form>
</div>
on php change this
<?php
if(isset($_POST['submit']))//on submit
{
//echo 'here';
$roll = $_POST['roll'];
$file = fopen("chat.txt","w");//no mode selected
fwrite($file,$roll);
fclose($file);
print_r(error_get_last());
}
?>
This works and generates the chat.txt

The random number is only generated on the client side: you're not sending it to the server yet. You're starting a form (name=rollbox), which you not sending back to the server (also you seem to be missing a </form>. Either submit the form, or use AJAX to send the information to the back-end.

Why don't you just generate the random number in PHP, and then put it in the file with file_put_contents()like this?
<?php
$roll = rand(1,20);
file_put_contents("chat.txt",$roll);
?>

You have some issues with the HTML of your top FORM.
Try replace it with the following code:
<form action="roll.php" name="rollBox" method="post">
<input type="text" name="roll" id="demo">
<input type="submit" name="button" onclick="myFunction();" value="Roll">
</form>