Develop Reference

Iterate through JSON String in PHP?

it seems to be a really easy question, but I am a little bit struggling: I am receiving a JSON String via JavaScript. Now I would like to iterate through the element. The resulting string has this form: {"title":value,"title2":value}
How can I iterate through this JSON string without knowing the key and value? I would like to get this output:
title -> value
title2 -> value2
I tried it this way:
$json = file_get_contents('php://input');
$array = json_decode($json,true);
$response = "Test";
foreach($array as $key=>$val) {
$response = $response. "$key : $val";
}
echo json_encode($response);
It only returns "Test". If I change it to echo json_encode($array), it returns the mentioned JSON String.

You mention javascript and php in your question, so I'm going to answer for both. Here is JS, two different ways. I believe that foreach is being deemphasized in favor of the (of) construct now, but I don't work primarily in JS:
var json = '{"title": 12, "title2": "text"}';
var data = JSON.parse(json);
Object.keys(data).forEach(function(key) {
console.log(key + ' -> ' + data[key])
})
for(key of Object.keys(data)) {
console.log(key + ' -> ' + data[key]);
}
And for PHP:
You can parse the json string into an array using json_decode:
$json = '{"title": 12, "title2": "text"}';
$arr = json_decode($json, true);
foreach($arr as $key=>$val) {
echo "$key : $val";
}
true parses it into an array instead of a std object.
https://www.php.net/manual/en/function.json-decode.php

Because of response's format you must decode the decoded format in order to take the object as you want
$json = '{"title": 12, "title2": "text"}';
$encoded=json_encode($json);
$decoded=json_decode($encoded);
$ddecode=json_decode($decoded);
foreach($ddecode as $key=>$val) {
echo "$key -> $val";
}
Output :
title -> 12 title2 -> text

How to correctly parse strings received from php

After a call to a php method that loads a value from a table, I am expected to be returned the number 10 but instead I get returned the following weird string:
string(1) "9" 10
How can I extract the value 10 alone? What kind of index does "9" represent?
I have tried also with echo json_encode($newNo); in php but it shows an error.
html:
document.getElementById("output").value = this.responseText; //string(1) "9" 10
php:
$number = 9;
$newNo = $number + 1;
echo $newNo;

How can I access PHP array inside my Javascript?

I have a very simple PHP array
$array = [];
$array['a'] = '1';
$array['b'] = '2';
$array['c'] = '3';
PHP
If I dd($array); out I got
array:3 [▼
"a" => "1"
"b" => "2"
"c" => "3"
]
If I decode dd(json_encode($array));, I got this
"{"a":"1","b":"2","c":"3"}"
JS
I want to be able to access this variable in my Javascript, So I've tried
1
console.log($array);
I got
$array is not defined
2
I'm using Laravel. {{ }} == echo
console.log('{{$array}}');
I got
500 Internal Error
htmlentities() expects parameter 1 to be string, array given (View: /Users/bheng/Sites/portal/resources/views/cpe/index.blade.php)
3
console.log('{{ json_encode($array)}}');
I got
The page to load, but the data is very bad looking
{"a":"1","b":"2","c":"3"}
4
console.log(JSON.parse('{{ json_encode($array)}}'));
I got
Uncaught SyntaxError: Unexpected token & in JSON at position 1
5
console.log(JSON.parse('{{ json_decode($array)}}'));
I got
json_decode() expects parameter 1 to be string, array given
6
console.log('{{ json_decode($array)}}');
I got
json_decode() expects parameter 1 to be string, array given
GOAL
I just want to be able to access my array as Javascript Array or JSON in the Javascript.
Can someone please fill me in on this ?

In Blade, {{ $variable }} will output an escaped version of the string, passed through htmlentities() to make it safe for use in HTML. You want an unescaped version. You can use {!! $variable !!} for that:
console.log({!! json_encode($array) !!});
You don't need to add quotes around it, json_encode() outputs a valid javascript object. It will add quotes where necessary, if you add them yourself you will get the JSON string in your javascript, instead of the JSON object.

In Laravel you can use {!! !!} to skip entity escaping
console.log({!! json_encode($array) !!});

Just echo it as json data and use it in javascript.
<?php
$array = [];
$array['a'] = '1';
$array['b'] = '2';
$array['c'] = '3';
?>
<script>var jsArr = <?=json_encode($array);?>;
alert(jsArr);</script>
EDIT because of clarification that you're using blade. Then it should be:
<?php
$array = [];
$array['a'] = '1';
$array['b'] = '2';
$array['c'] = '3';
?>
<script>var jsArr = {!! json_encode($array) !!};
alert(jsArr);</script>
{ ... } is an escaped version of your string. But you need the unescapt string. This can be achieved by using {!! ... !!}.

First, you have to understand that PHP run on server side and javascript on client side, as PHP make the response you should print a script like this:
echo "<script>
var sheison = JSON.parse(".dd(json_encode($array)).");
console.log(sheison);
</script>";
I didn't test the code, is just the idea.

Can't json_decode() from file - Syntax error

I am stuck with this problem. Here is my code:
<?php
$arr = [
'from_name' => 'Rosresurs1.ru',
'from_email' => 'team#rosresurs.net',
'reply_email' => 'reply#rosresurs.net',
'subject' => 'Вас приветствует Росресурс!',
'reply_us' => 'Вопрос нам',
'charset' => 'UTF-8',
'headers' => ['List-Unsubscribe: <mailto:support#rosresurs.net?subject=Unsubscribe>, <http://rosresurs.net/escript/unsubscribe.php?token=$token>', 'Precedence: bulk']
];
echo 'Var dump array to encode: <br>';
var_dump($arr);
//Encoding
$done = json_encode($arr, JSON_UNESCAPED_UNICODE);
echo 'Echo encoded array to json: <br><br>';
echo $done . "<br><br><br><br>";
//Decoding
echo "Starting decoding from file: <br><br>";
$var = json_decode('mailconfig.json', true);
$json_errors = array(
JSON_ERROR_NONE => 'No error has occurred',
JSON_ERROR_DEPTH => 'The maximum stack depth has been exceeded',
JSON_ERROR_CTRL_CHAR => 'Control character error, possibly incorrectly encoded',
JSON_ERROR_SYNTAX => 'Syntax error',
);
echo 'Last JSON error found: ', $json_errors[json_last_error()], PHP_EOL, PHP_EOL . '<br><br>';
echo 'Var dump variable: <br>';
var_dump($var);
And here is the output:
And here is JSON file, from which I tried to decode json:
{"from_name":"Rosresurs1.ru","from_email":"team#rosresurs.net","reply_email":"reply#rosresurs.net","subject":"Вас приветствует Росресурс!","reply_us":"Вопрос нам","charset":"UTF-8","headers":["List-Unsubscribe: , ","Precedence: bulk"]}
As you see my array contains UTF-8 symbols, so I have encoded them with JSON_UNESCAPED_UNICODE option. But when I try to decode(FROM FILE), it fails. But when I try to decode from encoded variable $done, it works perfectly.
My json file contains the same $done output(copied from the browser and pasted to file). json_last_error said it's a syntax error. But there is no one...
Also I pasted json string from file to online json syntax verify service and it returned "A valid JSON string".
P.S. I made a lot of echo helpers(see screenshot), so you can get into a problem fast(like starting encoding and decoding points).

According to the docs, json_decode() does not take a filename as a parameter, only a string.
If you want to decode JSON from a file you would need to do something like this:
$var = file_get_contents('mailconfig.json');
$var = json_decode($var);
Or, if you have to do this a lot, you could wrap the whole thing in a function:
function file_json_decode($path, $assoc = false){
if(file_exists($path)){
$json = file_get_contents($path);
$result = json_decode($json, $assoc);
} else {
$result = null;
}
return $result
}
And then call it like this:
$var = file_json_decode('mailconfig.json', true);

You are calling json_decode on a wrong parameter. The first parameter is the JSON data, not a filename! So if you want to parse the JSON from a file, you may write
json_decode(file_get_contents('mailconfig.json'), true);

Receive post with description containing '%' and two letter together

I have problems with treatment of Post. I received a string with the symbol '%' and two letters together, like 'Geci%de', but on PHP the var_dump I receive a different string, like 'Geci�', if try to use utf8_encode and utf8_decode, however the error continued, the strings resulted were 'GeciÞ' and'Geci?'. How is the better way to convert in the orignal string? I need to use in postgreSQL, it will be in select.
It is uses to treatment:
$data = strip_tags($data);
$data = trim($data);
$data = get_magic_quotes_gpc() == 0 ? addslashes($data) : $data;
$data = preg_replace("#(--|\|)#s", "", $data);
$data = urldecode($data); // especific to Ajax
return utf8_decode($data);