I have tried removing the JSON.stringify and changing the post to get change cache to false and true. I am at a loss as to what needs to happen. It always goes to the else statement in my php and returns the default JSON. I have allowed crossdomain in my php with the wildcard so that is definitely not the problem.
Code:
$(document).ready(function() {
$('.check').click(function(){
var thisID = $(this).attr('id');
alert(thisID);
$.ajax({
type: "POST",
crossDomain: true,
url: "retrieveColumn.php",
data: JSON.stringify({ ID: thisID}),
cache: true,
async:true,
datatype: "json",
success: function(data)
{
console.log(data);
alert(data);
}
});
});
});
PHP which always goes to the else condition:
if(isset($_POST['ID']))
{
$ID = $_POST['ID'];
{
$stmt = $mysqli->query("SELECT * FROM group2.menu WHERE ItemID = $ID ");
if($stmt->num_rows) //if there is an ID of this name
{
$row = $stmt->fetch_assoc();
echo $row;
print json_encode($row);
}
}
}
else
{
$stmt = $mysqli->query("SELECT * FROM group2.menu WHERE ItemID = 2");
$row = $stmt->fetch_assoc();
print json_encode($row);
}
Unless this is part of a larger document, you have unnecessary brackets which might be causing problems.
if(isset($_POST['ID'])){
$ID = $_POST['ID'];
{ /* <!-- HERE! What is this?? */
$stmt = $mysqli->query("SELECT * FROM group2.menu WHERE ItemID = $ID ");
if($stmt->num_rows) //if there is an ID of this name{
$row = $stmt->fetch_assoc();
echo $row;
print json_encode($row);
}
}
}
else
{
$stmt = $mysqli->query("SELECT * FROM group2.menu WHERE ItemID = 2");
$row = $stmt->fetch_assoc();
print json_encode($row);
}
You don't need to stringify the object you submit as data here:
data: JSON.stringify({ ID: thisID}),
Use:
data: { ID: thisID},
Related
I need to get data from the database with ajax and put that data in the 'select' tag. I need to have every name in a different 'option'... View the code:
Index.php:
<label>Select:</label>
<select id="users"></select>
JS:
$(document).ready(function() {
setInterval(function() {
$.get("frombase.php", function(data) {
data = JSON.parse(data);
for (var id in data) {
$("#users").empty();
$("#users").append("<option value='"+ id +"'>"+ data[id] +"</option>")
}
});
}, 1000);
});
And frombase.php:
$sql = "SELECT * FROM `users`";
$result = mysqli_query($db, $sql);
$name = array();
while ($row = mysqli_fetch_assoc($result)) {
$name[] = $row['name'];
}
echo json_encode(array("name" => $name));
mysqli_close($db);
Look at the result (I do not need this)
(My english is not good, because I use Google Translate)
I would do in this way...
JS:
$(document).ready(function() {
$.ajax({
url :'frombase.php',
type: "POST",
dataType: "json",
success : function(data){
$("#users").empty();
$(data['options']).each(function(k,v){
$("#users").append("<option value='"+ v['id'] +"'>"+ v['name'] +"</option>");
});
},
error:function(){
alert('Error of server comunication');
}
});
});
PHP:
$db = 'YOUR CONNECTION';
$query = $db->prepare("SELECT id,name FROM users");
$query->execute();
$query->bind_result($id,$name);
while ($query->fetch()) {
$result[] = array('id'=>$id,'name'=>$name);
}
$root['options'] = $result;
$root = json_encode($root);
$db->close();
echo $root;
I'm developing a small script of js to edit a profile in the way facebook used to be (click a button, edit and save without reloading the page). The problem is that when I run it, the ajax function returns sucess but akes no changes on the database. The function os js is this:
$('.savebtn').click(function(){
var editdata = $(".editbox").val();
var parameter = $(this).closest("td").find("#parameter").text();
var datastring = "data="+editdata+"¶meter="+parameter;
var $t = $(this);
console.log(datastring);
$.ajax({
type: "POST",
url: BASE_URL + "/API/update_profile.php",
data: datastring,
cache: false,
success: function()
{
$t.closest('td').find('.curr_value').html(editdata);
$t.closest('td').find('.curr_value').hide;
console.log(editdata);
$(this).prev(".edit").hide();
$(this).prev(".curr_value").show();
$(this).prev('.edit_link').show();
$(this).hide();
}
});
});
(Ignore the $t thing, somehow this works like this, but not if I use $(this))
Ajax executes the code for sucess but doesn't update anything on the database.
The PHP code for the database is:
<?php
include_once("../../config/connect_db.php");
include_once("../../database/cliente.php");
$parameter = $_POST['parameter'];
$data = $_POST['data'];
$id = $_SESSION['id'];
var_dump($_POST);
try {
updateProfile($parameter, $data, $id);
}
catch (PDOException $e)
{
echo 'Caught exception: ', $e->getMessage(), "\n";
}
?>
function updateProfile($parameter, $data, $id)
{
global $conn;
$stmt = $conn->prepare("UPDATE biofood.users
SET ? = ?
WHERE id = ?");
$stmt->execute(array($parameter, $data. $id));
}
EDIT: As pointed out, this could be a problem with trying to pass a column name as a parameter. Changed the code to the following, but with no sucess:
function updateProfile($parameter, $data, $id)
{
global $conn;
$query = "UPDATE biofood.users
SET $parameter = $data
WHERE id = $id";
$stmt = $conn->prepare($query);
$stmt->execute();
}
This line:
$stmt->execute(array($parameter, $data. $id));
I think should be
$stmt->execute(array($parameter, $data, $id));
(notice the comma after $data)
This might not solve your problem, but it might give you a better indication on where your problem is.
First, you are not checking whether it works or not as your updateProfile function returns nothing.
Modify your updateProfile function, so that it returns the number of rows affected. (BTW this is a safer way to write your function. If you can check or limit the value of $parameter prior to calling this function, it will be less prone to SQL injection.)
function updateProfile($parameter, $data, $id)
{
global $conn;
$stmt = $conn->prepare("UPDATE biofood.users SET $parameter = ? WHERE id = ?");
$stmt->execute(array($data, $id));
return $stmt->rowCount(); // # of rows affected
}
In the script that calls this function, get the value and send it back as a response. We'll send back a JSON.
$response = array();
try {
$response['success'] = updateProfile($parameter, $data, $id);
} catch (PDOException $e) {
echo 'Caught exception: ', $e->getMessage(), "\n";
}
header('Content-Type: application/json');
echo json_encode($response);
In your JavaScript file, make the following change:
$.ajax({
type: "POST",
url: BASE_URL + "/API/update_profile.php",
data: datastring,
cache: false,
success: function (data) {
if (data.success) {
$t.closest('td').find('.curr_value').html(editdata);
$t.closest('td').find('.curr_value').hide;
console.log(editdata);
$(this).prev(".edit").hide();
$(this).prev(".curr_value").show();
$(this).prev('.edit_link').show();
$(this).hide();
}
},
dataType: 'json'
});
I have an UI in which the user can add objects (stored as JSON in my database). So, when the user is clicking on a button, it calls the ajax wich calls my php to get the desired JSON code.
The problem is that my ajax returns me "success" but with no JSON code. I don't know where the problem is located.
Here's my JS/AJAX:
var object, objectJson;
var objectName = $(this).attr("attr-lib");
var objectId = $(this).attr("attr-id");
$.ajax({
url: 'scriptObject.php',
type: 'POST',
data: {objectId: objectId},
dataType: 'json',
success: function(response) {
console.log("success");
console.log(response);
}
});
Here's my scriptObject.php:
$objectId = $_POST["objectId"];
$query = "SELECT objectJson FROM object WHERE objectId = ' $objectId '";
$result = mysql_query($query);
if($result)
{
if(mysql_num_rows($result) > 0)
{
$objJSON = mysql_fetch_array($result);
$res = array("status"=>"success", "objectJson" => $objJSON['objectJson']);
}
else
{
$res = array("status"=>"error", "message" => "No records found.");
}
}
else
$res = array("status"=>"error", "message" => "Problem in fetching data.");
echo json_encode($res);
[EDIT]
It answers me:
{"status":"error","message":"Problem in fetching data."}
Try following
<script type="text/javascript">
var object, objectJson;
var objectName = $(this).attr("attr-lib");
var objectId = $(this).attr("attr-id");
$.ajax({
url: 'scriptObject.php',
type: 'POST',
dataType : 'json',
data: { objectId: objectId },
success: function(response) {
var json = $.parseJSON(response);
if(json.status == 'error')
console.log(json.message);
else if(json.status == 'success')
console.log(json.objectJson);
}
});
</script>
and in scriptObject.php
<?php
// your database connection goes here
include 'config.php';
$objectId = $_POST["objectId"];
$query = "SELECT objectJson FROM object WHERE objectId = ' $objectId '";
$result = mysql_query($query);
if($result)
{
if(mysql_num_rows($result) > 0)
{
$objJSON = mysql_fetch_array($result);
$res = array("status"=>"success", "objectJson" => $objJSON['objectJson']);
}
else
{
$res = array("status"=>"error", "message" => "No records found.");
}
}
else
$res = array("status"=>"error", "message" => "Problem in fetching data.".mysql_error());
echo json_encode($res);
?>
scriptObject.php
if(isset($_POST['objectId']))
{
$objectId = $_POST["objectId"];
$query = "SELECT objectJson FROM object WHERE objectId = ' $objectId '";
$result=mysql_query($query);
echo json_encode($result);
die;
}
you are execution the php code inside a function.
how does the compiler or the interpreter know to execute a function inside your php file.
Add dataType to your ajax options
$.ajax({
url: 'scriptObject.php',
type: 'POST',
data: objectId,
dataType : 'json',
success: function(response) {
console.log("success");
console.log(response);
}
});
then your php code
function getObjectJson() {
$objectId = $_POST["objectId"];
$query = "SELECT objectJson FROM object WHERE objectId = ' $objectId '";
$result=mysql_query($query);
echo json_encode($result);
}
I'm having issues with an Ajax login function. There was another question similar to mine that I was able to find but it proved no use.
I have no idea what is the issue, this works on another program as well with no issues, hopefully someone can see my mistake
From testing I think the issue is in the "checkLogIn" function because when I run the application the alert within the function shows
Ajax:
$("#checkLogIn").click(function()
{
$.ajax({
type: 'POST',
contentType: 'application/json',
url: rootURL + '/logIn/',
dataType: "json",
data: checkLogIn(),
})
.done(function(data)
{
if(data == false)
{
alert("failure");
}
else
{
alert("Success");
$.mobile.changePage("#page");
}
})
.always(function(){})
.fail(function(){alert("Error");});
});
function checkLogIn()
{
alert();
return JSON.stringify({
"userName": $("#enterUser").val(),
"password": $("#enterPass").val(),
});
}
I'll also include the PHP but the PHP works 100% after testing it.
PHP:
$app->post('/logIn/', 'logIn');
function logIn()
{
//global $hashedPassword;
$request = \Slim\Slim::getInstance()->request();
$q = json_decode($request->getBody());
//$hashedPassword = password_hash($q->password, PASSWORD_BCRYPT);
$sql = "SELECT * FROM users where userName=:userName AND password=:password";
try {
$db = getConnection();
$stmt = $db->prepare($sql);
$stmt->bindParam("userName", $q->userName);
$stmt->bindParam("password", $q->password);
$stmt->execute();
//$row=$stmt->fetch(PDO::FETCH_ASSOC);
//$verify = password_verify($q->password, $row['password']);
$db = null;
//if($verify == true)
//{
// echo "Password is correct";
//}
//else
// echo "Password is incorrect";
echo "Success";
} catch (PDOException $e) {
echo $e->getMessage();
}
}
I have commented out any and all hashing until I can get this working properly
There is no problem with the ajax script. From my assumption you always get Error alert. That is because you added dataType: "json", which means you are requesting the response from the rootURL + '/logIn/' as json Object. But in the php you simply echoing Success as a plain text. That makes the ajax to get into fail function. So, You need to send the response as json. For more details about contentType and datatype in ajax refer this link.
So you need to change echo "Success"; to echo json_encode(array('success'=>true)); in the php file. Now you'll get Success alert. Below I added a good way to handle the json_encoded response in the php file.
$app->post ( '/logIn/', 'logIn' );
function logIn() {
global $hashedPassword;
$request = \Slim\Slim::getInstance ()->request ();
$q = json_decode ( $request->getBody () );
$hashedPassword = password_hash($q->password, PASSWORD_BCRYPT);
$sql = "SELECT * FROM users where userName=:userName";
try {
$db = getConnection ();
$stmt = $db->prepare ( $sql );
$stmt->bindParam ( "userName", $q->userName );
$stmt->execute ();
$row=$stmt->fetch(PDO::FETCH_ASSOC);
$verify = false;
if(isset($row['password']) && !empty($row['password']))
$verify = password_verify($hashedPassword, $row['password']);
$db = null;
$response = array();
$success = false;
if($verify == true)
{
$success = true;
$response[] = "Password is correct";
}
else
{
$success = false;
$response[] = "Password is incorect";
}
echo json_encode(array("success"=>$success,"response"=>$response));
} catch ( PDOException $e ) {
echo $e->getMessage ();
}
}
And I modified the ajax code. There I showed you how to get the response from the json_encoded Object.
$("document").ready(function(){
$("#checkLogIn").click(function()
{
var post_data = JSON.stringify({
"userName": $("#enterUser").val(),
"password": $("#enterPass").val(),
});
$.ajax({
type: 'POST',
contentType: 'application/json',
url: rootURL + '/logIn/',
dataType: "json",
data: post_data,
})
.done(function(data)
{
// data will contain the echoed json_encoded Object. To access that you need to use data.success.
// So it will contain true or false. Based on that you'll write your rest of the code.
if(data.success == false)
{
var response = "";
$.each(data.response, function(index, value){
response += value;
});
alert("Success:"+response);
}
else
{
var response = "";
$.each(data.response, function(index, value){
response += value;
});
alert("Failed:"+response);
$.mobile.changePage("#page");
}
})
.always(function(){})
.fail(function(){alert("Error");});
});
});
Hope it helps.
Im new In AJAx. My problem is I have ajax Function to pass variable ID in php when the page is load the error is Undefined variable: id but when I look in firebug post id is past successfully . Here is my ajax.
$('.btn_edit').click(function(e){
e.preventDefault();
var $this = $(this);
var id_id = $(this).attr('id');
alert(id_id);
$.ajax({
type: "POST",
url: "edit_query.php",
data:{id: id_id},
success: function() {
alert("Success Input");
and this is my php page to pass.
$id = $_POST['id'];
$sql = mysql_query("select * from user where uid = ".$id."");
$table = mysql_fetch_assoc($sql);
?>
$sql = mysql_query("select * from user where uid = ".$id."");
should be
$sql = mysql_query("select * from user where uid = $id ");
and
var id_id = $(this).attr('id');
alert(id_id);
$.ajax({
type: "POST",
url: "edit_query.php",
data:"id="+id_id,
success: function() {
alert("Success Input");
}
try this
$.post( "edit_query.php", { id: id_id })
.done(function( data ) {
alert( data );
});
try this
edit_query.php
<?php
$id = $_POST['id'];
$sql = mysql_query('SELECT * FROM user WHERE uid = '.$id);
$row = mysql_fetch_assoc();
header('Content-Type: application/json');
echo json_encode($row);
exit;
your.js
$(function(){
var onClick, successHandler;
onClick = function (e) {
e.preventDefault();
$.post('edit_query.php',{id:$(this).attr('id')},successHandler,'json');
};
successHandler = function (json) {alert(json.uid);};
$('.btn_edit').click(onClick);
});