I am trying to update the $_SESSION['state'] whenever the user clicks on the anchor tag by firing the onclick event. The variable $state_names_array as all the names of the states of a specific country. But problem is that no matter whichever of the anchor tag I click on, the $_SESSION['state'] is always getting updated by the last element of the $state_names_array.
<?php
foreach($state_names_array as $value){
$temp = '<?php $_SESSION["state"]=$value;?>';
?>
<?php echo $value ?><br>
<?php
}
?>
I will not code whole code, I will just show you an example, how to do it:
<?php
foreach ($state_names_array as $value) {
echo ''.$value.'<br>';
}
?>
Then you will have javascript function change_value:
here you will send ajax call to some PHP file, where you will process $_SESSION["state"]=$value;
Also you didnt say, what you want after anchor is clicked, because you will be able to access new $_SESSION["state"] only after refreshing your site...
Also maybe you just want to redirect to index.php, after clicking on some anchor, and that will be enough for you, then just use value as $_GET parameter, f.e.:
<?php
foreach ($state_names_array as $value) {
echo ''.$value.'<br>';
}
?>
and add to you index.php file this lines:
if (isset($_GET['new_value'])) {
$_SESSION["state"] = $_GET['new_value'];
}
Related
I am a newbie working on a screen which has a conditional button which should appear only if $step==2. In this case, the button is shown and on click, redirects me to another page within my project. However, the url to which it should redirect me is not fixed, but has a parameter within it. I am having trouble getting the onclick to work!
I have tried defining a $path variable in which I store the relocation string. I do this in the following way:
<?php $path = '"window.location=\'{{ url("/location/'.$location->id.'/description") }}\'"'?>
When I echo this $path, I get exactly the string I need, which is:
"window.location='{{ url("/location/2/description") }}'"
(Note: The $location->id in my test case is 2)
However, I then try using this $path for the onclick of the button and it's not working! Here is the whole thing:
<?php if ($step == 2) : ?>
<?php $path = '"window.location=\'{{ url("/location/'.$location->id.'/description") }}\'"'?>
<button class="button_s_red" onclick=<?php echo $path; ?>>{{ trans('setup_process.STEP2_Button') }}</button>
<?php endif; ?>
When I inspect this button in chrome, it seems that on the onclick, the / character is not getting through. But this is odd since when I echo the $path I do get this character, and / doesn't seem to be an escape character from what I've googled.
I've tried pretty much everything and googled every possible help but can't seem to make it work! Thanks in advance for your help!
id.'/description") }}\'"'?> >{{
trans('setup_process.STEP2_Button') }}
I think u must use " in Your code like this.
<?php if ($step == 2) : ?>
<?php $path = '"window.location=\'{{ url("/location/'.$location->id.'/description") }}\'"'?>
<button class="button_s_red" onclick=("<?php echo $path; ?>")>{{ trans('setup_process.STEP2_Button') }}</button>
<?php endif; ?>
I have some php that connects to a database and creates a drop down list. I have a specific form in the HTML that I'd like to put the list in.
<body>
<form>
// some text inputs
// where i'd like the drop down to go
<?php makeList(parameter1, parameter2); ?>
// submit button
</form>
<?php
// connect to database
function makeList(arg1, arg2) {
echo '<select>';
while ($row = mysqli_fetch_array($result)){
echo "<option">;
echo $row[$column];
echo "</option>";
echo '</select>';
}
</body>
The only languages I'm allowed to use (apart from the sql) are php, html and javascript. As it is right now, makeList() returns an empty list. When I include opening and closing form tags in the function it returns a fully functional list, but then it acts as it's own form and I need to to be a part of the original form. Thanks.
EDIT: Sorry, forgot to mention the makeList function works fine when called within the php tags. It's when I call it in the HTML that it returns an empty list.
Firstly, you have some syntax issues with your script. It's not a valid HTML file, not a valid PHP file, and not a valid JS file.
If it were up to me, I'd define the PHP function at the stop of my script. Be careful to balance your opening and closing PHP tags. Something like this:
<?php
// connect to database
function makeList($arg1, $arg2) {
echo '<select>';
while ($row = mysqli_fetch_array($result)){
echo "<option">;
echo $row[$column];
echo "</option>";
echo '</select>';
}
?>
And only after that would I start to output my HTML.
Now there are a couple of important things to note about that script I just posted:
the database code is not in here...I don't see any connection or query getting run or anything
In your script, this function doesn't look valid. arg1 and arg2 need a $ in front of each to be a valid PHP function. If it's a JS function you want then well, you are very confused and probably need to go back and figure out why this is not a valid JS function.
Your function refers to a variable, $result, that you have not bothered to define. It is not mentioned anywhere else in your script. It is most certainly not mentioned anywhere inside your function. For $result to be defined inside your function, you either need to pass it in as an array or declare it as a global:
global $result
Your function doesn't return anything at all. It just echoes stuff. This doesn't mean you can't use it, but it does mean that the function has no return value. Echoing the result of makeList won't output anything at all
So after that script above, you might have something like this:
<body>
<form>
// some text inputs
<?php makeList($parameter1, $parameter2); ?>
// submit button
</form>
Depending on what your parameters ($parameter1 and $parameter2) are this should work.
<body>
<form>
// some text inputs
<?php echo makeList($parameter1, $parameter2); ?>
// submit button
</form>
<?php
// connect to database
function makeList($arg1, $arg2) {
echo '<select>';
while ($row = mysqli_fetch_array($result)){
echo "<option>";
echo $row[$column];
echo "</option>";
echo '</select>';
}
</body>
The php in method signout is executing without call . At first the username is echoed fine , but second echo below signout method shows that its null. It should be called when the singout link is clicked . Why is this happening ?
<?php echo $_SESSION['username']; ?> // this echo show real value
<script>
function singout()
{
<?php $_SESSION['username']='null'; ?>
window.alert("<?php echo $_SESSION['username'];?>");
}
<?php echo $_SESSION['username']; ?> // but this echo show null value
</script>
<a onclick="singout();" href="login.html" style="float: right">singout</a>
Your PHP is being called without the JS Function being called because on browser load each PHP line is procedurally called. Just because your PHP line is within a JS function doesn't mean it isn't called on browser load
I want to change the href of morestorieslink depending on the data received from mysql database i.e. if there is no row returned from server then the href for DOM element morestorieslink should change
I am using this for changing the href value
if (mysql_num_rows($result) == 0) {
?>
<script type="text/javascript">
document.getElementById("morestorieslink").href="select.php?<?php echo $selecturl?>=<?php echo $select; ?>&select=Continue";
</script>
<?php
echo "Url Changed";
}
In this case javascript doesn't work but the echo is displayed, I also tried embedding javascript inside php echo.
Thankyou
if (mysql_num_rows($result) == 0) {
?>
<script type="text/javascript">
// wait for dom to finish loading properly.
document.addEventListener("DOMContentLoaded", function(event) {
document.getElementById("morestorieslink").href="select.php?<?php echo $selecturl?>=<?php echo $select; ?>&select=Continue";
});
</script>
<?php
echo "Url Changed";
}
Put this at the last of your page make it a point that no java script is executed after this. Rest all looks good.
Hope that helps.
Note :
the href you mentioned will append to the exsisting url.
Also check that $selecturl or $select is not null and isset.
You can also check the page source to check wether the link is generating properly or not (using Firebug in mozilla)
you can use ternary operator. Something like:
<?php echo $select ? $selecturl.$select : $otherURL;?>
I assumed your url is changing based on value of $select
I save the data using POST method from a form.
After the data has been saved, page reloaded, I want to show a hidden div in the page.
onsubmit="showHide(this); return false;"
shows the specified div but does not save data.
any ideas?
LE:
to make it more complicated: the form that trigges the page reload is on the div that i want to re-show. initialy i make the div visible with:
<a class="articleLink" href="javascript:void(0);" onclick='$("#ModAdd<?php echo $rrows['id_']; ?>").show("slow");'></a>
No data will be sent since you have a return false; in your onSubmit.
If you want the user to stay on the same page, you'll need Ajax.
Else, you have to show your div on the page that receives the data from your form.
You have to display the div after the reload.
onsubmit will display it right away (on the same page). So check if the $_POST is set in php after reloading the site and then display the div
Example
<?php
if (isset($_POST)):
?>
<div>Saved successfully</div>
<?php
endif;
?>
You might try something like this after reloading the page, instead of onsubmit:
$POST = $POST['myPost'];
$Message = '<script type="text/javascript">';
$Message .= 'document.getElementById("' . $IDName . '").style.display="block";'; // Show the hidden DIV
$Message .= 'document.getElementById("' . $IDName . '").innerHTML="' . $POST . '";'; // Output POST value
$Message .= '</script>';
echo $Message;