Develop Reference

Not able to reload the div while using jQuery $.ajax()

I am trying to reload a div with id #todos after the data is saved in the database.
I tried using .load() in $.ajax()
$('.todo--checkbox').change(function () {
let value = $(this).data('value');
$.ajax({
url: `/todo/${value}`,
type: 'PUT',
data: { done: this.checked },
success: function (data) {
if (data.success) {
$('#todos').load(location.href + ' #todos');
}
},
});
});
The problem with this, that it is not reloading the page but it is updating the data in database correctly.
I also tried this
$('.todo--checkbox').change(function () {
let value = $(this).data('value');
$.ajax({
url: `/todo/${value}`,
type: 'PUT',
data: { done: this.checked },
success: $('#todos').load(location.href + ' #todos'),
});
});
In this, it is reloading the page as well as updating the data in the database but the problem is that it only reload and update the data at the first request, and after that I need to reload the whole page to update next data.
I tried to check if I am getting any data or not
$('.todo--checkbox').change(function () {
let value = $(this).data('value');
$.ajax({
url: `/todo/${value}`,
type: 'PUT',
data: { done: this.checked },
success: function (data) {
console.log(data);
},
});
});
It returned nothing, but my data in the mongoDB compass is changing.
I already read this articles so, please don't mark this question as duplicate.
Refresh/reload the content in Div using jquery/ajax
Refresh Part of Page (div)
refresh div with jquery
reload div after ajax request

I suggest you checking requests between your page and the server in the Network tab of browser's Development Console (F12).
Make sure you see PUT request going out to the server to update todo
Make sure that response you receive looks like { success: true } otherwise the following piece of code won't be triggered
if (data.success) {
$('#todos').load(location.href + ' #todos');
}
Make sure you see GET request going out to the server to pull '#todos' asynchronously.
If you don't see request #3 try the following:
replace location.href with window.location.href
try reloading it manually via console (for Chrome, F12 -> Console tab -> paste $('#todos').load(location.href + ' #todos') and hit Enter). That way you are going to skip first ajax request and just will check whether '#todo' section is loadable/reloadable.

I think it’s a cache problem. Try it like this
$('.todo--checkbox').change(function () {
let value = $(this).data('value');
$.ajax({
url: '/todo/${value}?t=202103010001',
type: 'PUT',
data: { done: this.checked },
success: $('#todos').load(location.href + ' #todos'),
});
});
t=202103010001 Set to a random number

CRUD - Add and Delete not working one after other if page is not refreshed

I have one annoying problem that I am not able to solve.
I am generating CRUD operations in my Symfony project. I made an AJAX request for Add method which works as it should.
After that I have created AJAX request for Delete method.
When I add my new entity object the table is reloaded without page refresh.
Problem is that if I click delete after it's added it throws an error that ID is not found.
/**
* #Route("/user/{id}", name="user_delete", options={"expose"=true})
*/
public function delete($id)
{
$em = $this->getDoctrine()->getManager();
$$user = $em->getRepository(User::class)
->findOneby(['id' => $id]);
if (!$user) {
throw $this->createNotFoundException('No User found for id '.$id);
}
$em->remove($user);
$em->flush();
return $this->json(["message" => "SUCCESS"]);
}
So, for example I have added entity with ID = 2 . DIV is reloaded. Now I click in delete of 2 and it's says:
No user found for id 1
Problem is it always fatches the last ID I deleted after page refresh.
Now, if I refresh the page and then try delete it will catch ID = 2 and delete it. Now, I add ID = 3 without refreshing the page and it will throw:
No user found for id 2
I think maybe it has to do with my add form:
Add form:
$('#form-submit').on('click', function (e) {
e.preventDefault();
$.ajax({
type: "POST",
url: '/subscription/add',
data: $('form#subscription-form').serialize(),
processData: false,
success: function () {
$("#user-table").load(location.href + " #user-table");
$('#addUser').modal('hide');
displayNotif('success', 'check', 'User created successfully');
},
error: function (xhr, status, error) {
var ErrorMessage = JSON.parse(xhr.responseText);
$('#general-error').html(ErrorMessage.message);
}
});
});
Can someone please help?
$(document).ready(function () {
$('.user_delete').on('click', function () {
let removeUrl = $(this).attr('data-remove-url');
$('.remove-user').attr('data-remove-url', removeUrl);
});
$(".remove-user").click(function (e) {
let removeUrl = $(this).attr('data-remove-url');
e.preventDefault();
$.ajax({
url: removeUrl,
type: 'DELETE',
success: function()
{
$("#user-table").load(location.href + " #user-table");
$('#confirmDelete').modal('hide');
displayNotif("danger", "warning", "User deleted successfully");
}
});
});
});
I am adding everything so you can get an idea of what I am doing:
<a href data-toggle="modal" data-target="#confirmDelete" data-remove-url="{{ path('user_delete', {'id':user.id}) }}" class="btn user_delete">x</a>

Option 1:
The click event is not working properly for the delete button.
Try to replace
$(".remove-user").click
With
$(".remove-user").on(“click”
Option 2:
data-remove-url
this attribute is not updated accordingly. Check your DOM to verify

How to call ajax again when user click back button to go back last webpage?

Below is my code..
HTML Code
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<div class="body">
<div class="dropdown_div">
<select id="q_type" class="dropdown" onchange="getSubject(this.value)">
<option>Question1</option>
<option>Question2</option>
</select>
</div>
<div class="dropdown_div">
<select id="q_subject" class="dropdown">
<option>Subject1</option>
</select>
</div>
</div>
JS Code
function getSubject(val){
$("option", $("#q_subject")).remove();
var option = "<option>Subject</option>";
$("#q_subject").append(option);
$.ajax({
url: "api.path",
type: 'POST',
dataType: 'json',
data: {id: id},
async: true,
cache: false,
success: function(response) {
alert("Hi");
$("option", $("#q_subject")).remove();
var option = "<option>Subject1</option>";
option += "<option value=1234>Subject2</option>";
$("#q_subject").append(option);
}
});
}
How do I use pushState into my code and let user can click back button to return last page and then still see the ajax data?

First of all, you should save data received from ajax request to browser local storage. Afterwards, in order to show ajax result when browser "back" button was fired, you should bind statements that you are calling in ajax.success() method to window onpopstate event. To omit code duplication, it`s better to use a declared function instead of anonymous one.
function success(response) {
alert("Hi");
$("option", $("#q_subject")).remove();
var option = "<option>Subject1</option>";
option += "<option value=1234>Subject2</option>";
$("#q_subject").append(option);
}
Save data to localstorage and call success function:
$.ajax({
url: "api.path",
type: 'POST',
dataType: 'json',
data: {id: id},
async: true,
cache: false,
success: function(response) {
localStorage.setItem("response", response);
success(response);
}
});
Call success() when "back" button was fired:
window.onpopstate = function (e) {
var res = localStorage.getItem('response');
success(res);
}

I would rather suggest you to use sessionStorage which expires when the browser window is closed :)
$.ajax({
url: "api.path",
type: 'POST',
dataType: 'json',
data: {id: id},
async: true,
cache: false,
success: function(response) {
sessionStorage.setItem("DataSaved", response);
success(response);
}
});
And then
window.onpopstate = function (e) {
var res = sessionStorage.getItem('DataSaved');
success(res);
}

You can solve this using the local Storage or Session storage. You will also need to have a onload function callback, to check if there are any previous values that you stored in the local/session storage, if yes, then show that data in the select box.

I noticed this Back() issue when using Ajax to navigate an MVC-5 application from within a JavaScript generated diagram. All clicks in the diagram are handled by Ajax.
Above solutions do not replace the complete body, in the repaired cases a Back() would restore just the edit fields. In my case, I don't need that. I need to replace the entire page from the AJAX and also enable the Back button to return to my original diagram context.
I tried above solution to replace body, and I have to note, it would only trigger the window.pop event after
history.pushState({}, '')
But when the event triggered and it uses Ajax to fill the body, my Javascript would not properly re-initialize the diagram page.
I decided to use another pattern, to circumvent the the window.pop event and avoid the back-issue. Below code will not return into the Ajax code context, but instead simply replace current page, processing the Ajax return information from the server (=Controller) as a redirect link, like
var url = "/ProcessDiagram/MenuClick?command=" + idmenuparent+"_"+citem; // my Ajax
$.get(url,
function (data) {
window.location = data; // Server returns a link, go for it !
return true; // Just return true after going to the link
});
.. this will preserve the Back() context, because the browser will take care of things.
Controller side composes the redirect link, like
public ActionResult MenuClick(string command)
{
List<string> sl = command.Split(new char[] {'_'}).ToList();
var prId = int.Parse(sl[0].Substring(3));
if (sl[1] == "PU")
return Content("/ProductionUnitTypes/Details/" + UnitContextId(prId) );
if (sl[1] == "IR")
return Content("/ItemRoles/Details/" + RoleContextId(prId) );
// etcetera
}

I solved it by including the below code just before the $.get() function
$.ajaxSetup({cache: false});
It works! Try it :)

I need to get a variable between jQuery function and AJAX

I have two buttons on the form I'm getting, this first piece of coce allow me to know which was the button clicked by getting the id of it.
var button;
var form = $('.register_ajax');
$('#vote_up, #vote_down').on("click",function(e) {
e.preventDefault();
button = $(this).attr("id");
});
and this other send the form data through AJAX using the info already obtained from the button using the script above.
form.bind('submit',function () {
$.ajax({
url: form.attr('action'),
type: form.attr('method'),
cache: false,
dataType: 'json',
data: form.serialize() + '&' + encodeURI(button.attr('name')) + '=' + encodeURI(button.attr('value')) ,
beforeSend: function() {
//$("#validation-errors").hide().empty();
},
success: function(data) {
if(data.message == 0){
$("#fave").attr('src','interactions/favorite.png');
$("#favorite").attr('value',1);
console.log(data.errors);
}
if(data.message == 1)
{
$("#fave").attr('src','interactions/favorite_active.png');
$("#favorite").attr('value',0);
}
if(data.message == "plus")
{
$("#vote_up").attr('class','options options-hover');
$("#vote_down").attr('class','options');
console.log(data.message);
}
if(data.message == "sub")
{
$("#vote_down").attr('class','options options-hover');
$("#vote_up").attr('class','options');
console.log("sub");
}
},
error: function(xhr, textStatus, thrownError) {
console.log(data.message);
}
});
return false;
});
The problem is that the data is not being passed to the ajax function, the button info is being saved on the button var, but it's not being obtained at time on the ajax call to work with it (or at least that is what I think). I'd like to know what can I do to make this work, any help appreciated.
1st edit: If I get the button data directly like button = $('#vote_up'); it doesn't work either, it only works if I get the button directly like this but without using the function.
2nd edit: I found the solution, I posted below.

var button is in the scope of the .on('event', function(){})
You need to declare the variable in the shared scope, then you can modify the value inside the event callback, i.e.
var button,
form = $('.register_ajax');
$('#vote_up, #vote_down').on("click",function(e) {
e.preventDefault();
button = $(this).attr("id");
});

You are being victim of a clousure. Just as adam_bear said you need to declare the variable outside of the function where you are setting it, but you are going to keep hitting these kind of walls constantly unless you dedicate some hours to learn the Good Parts :D, javascript is full of these type of things, here is a good book for you and you can also learn more from the author at http://www.crockford.com/.

I Found the solution, I just changed a little bit the click function like this:
var button;
var form = $('.register_ajax');
var data = form.serializeArray();
$('#vote_up, #vote_down').on("click",function(e) {
e.preventDefault();
button = $(this).attr("id");
data.push({name: encodeURI($(this).attr('name')), value: encodeURI($(this).attr('value'))});
form.submit();
});
using e.preventDefault(); and form.submit(); to send the form. also I changed the data.serialize to serializeArray(); because it's more effective to push data into the serializeArray(). in the second script I just changed the data.serialize() and used the data variable that I already filled with the serializeArray() and the data.push():
form.bind('submit',function () {
alert(button);
$.ajax({
url: form.attr('action'),
type: form.attr('method'),
cache: false,
dataType: 'json',
data: data,
//here goes the rest of the code
//...
});
return false;
});
it worked for me, it solved the problem between the click and submit event that wasn't allowing me to send the function through ajax.

Ajax link to run codeigniter controller then update html

Sorry for the most simplest of questions but I can't seem to get anything to work. It's the first time I've really played around with AJAX.
I'm developing in codeigniter and I have a link that when clicked runs the controller: photo function: like and allows the logged in user to like the photo then redirects the user back to the photo and displays a slightly different version of the button showing that the user likes the photo.
<?php if ( $like_count > '0' ) { echo $like_count; } ?>
It works fine but I thought it would be cool to replace it with an ajax function so it's more of a fluid motion instead of navigating off the page and then back again.
Any help would be greatly appreciated.

$(".uk-button").click(function(e) {
e.preventDefault();
//Here you can add your ajax
$.ajax({
url: site_url + 'photo/like',
data: {
liked : 1
},
type: 'POST',
dataType: 'json',
async : false,
success: function(success_record) {
console.log(success_record,":success_record");
//You might receive your like count from PHP here
}
});
});
In your success record you would get your PHP record values. Based on that you can increment or decrement count in success function

You can do something like this:
$(document).ready(function()
{
$('.likeLink').on('click', funciton()
{
var obj = $(this);
var id = obj.attr('id'); //anything you want to pass to update your like somewhere
$.ajax(
{
type: 'POST',
url: 'YourFilePathWhereYouWillDoTheLike',
data:
{
id: id,
},
cache: false,
success: function(response)
{
obj.html("You have liked this!");
}
});
return false;
})
})