not pretty sure how you do this. But I want to save my javascript variables as data(1,2,3,4,...) in my while loop. Happy for any help! Thanks
$id = 0;
while($rows = mysql_fetch_array($data)){
$id = $id + 1;
$data = $rows['data'];
?>
<script>
var id = '<?php echo $id; ?>'; //1,2,3,4,5,6,...
var data = '<?php echo $id; ?>'; // Example - Data 1 = Frog, Data 2 = Bird
// So here I want to sava variables so the name will be
// var "data+'id'";
// And the output is data for that row
</script>
<?php
}
?>
//And here outside I want to use the variables like this:
document.write(data1); writes out "Frog"
document.write(data2); writes out "Pig"
<script>
var jsData = [];
<?php
$id = 0;
while($rows = mysql_fetch_array($data)){
$data = $rows['data'];
?>
jsData[<?php echo $id; ?>] = '<?php echo $data; ?>';
<?php
$id++;
}
?>
</script>
This would yield a JS Array called jsData where your ID is the index and which is filled with the PHP $data values.
Declare $data = new Array(); just before the WHILE LOOP then in the WHILE LOOP you could do $data['id'][$id]= $id which will collect all the IDS.
Add $data['data'][$id]= $row['data'] below it so as also to collect each data that you want.
in the script tag do this:
var id = <?php echo '['.join(',', $data['id']).']' ?> //will create --> [1,2,3,4,5,6,7]
var data = <?php echo '['.join(',', $data['data']).']' ?> //--> ['cat', 'dog', 'cow', 'sheep']
now you can access the variable in the Javascript array created eg. $data[0] // 'cat'
Related
I am fetching an array from a MySQL result into a array variable. I can successfully use a simple php echo line in the javascript beneath to grab the first $row element, but I want to use json_encode to get the whole array at once.
When I do this and try to set a javascript var to the first array element something goes wrong and even the single var method stops working.
<?php
.
.
.
while($row = $result->fetch_array(MYSQLI_NUM)) {
$row1 = $row[0];
}
?>
<script type="text/javascript">
var RowArray = <?php echo json_encode($row); ?>;
var RA1 = RowArray[0];
window.alert(RA1);
var Row1 = '<?php echo $row1; ?>';
window.alert(Row1);
</script>
Make an array containing all the records:
$rows = [];
while ($row = $result->fetch_array(MYSQLI_NUM))
{
// do custom modifications to $row if neededed
$rows[] = $row; // push to array
}
Or just:
$rows = $result->fetch_all(MYSQLI_NUM);
And then use json_encode() with $rows.
hei,
$i=0;
while($row = $result->fetch_assoc()) {
echo "
<tr><td>".$row["Number"]."</td><td>".$row["MusikName"]." ".$row["MusikURL"]."</td></tr>";
this part works...it give me -> 1 test1 url1.de 2 test2 url2.de ...
So what I want is to pass the URL to a JavaScript Array...by doing in phpscript
$urlarray[]=$row["MusikURL"];
echo $urlarray[$i]; // gives me url1.de url2.de url3.de
i++; // to fill $urlarray[1] [2] [...] with urls
How do I pass the urls to a JavaScript Array so that I can access to those by
javascriptarrayurl[1] javascriptarrayurl[2] (result should be a clear url) ... I got troubles with JSON :c
thanks in advance !!
You can use jQuery and have something like
<?php
$returnArray = array();
while ($row = $result->fetch_assoc()) {
array_push($returnArray, $row);
}
$jsonArray = json_encode($returnArray);
?>
<script>
$(document).ready(function () {
var objArray = $.parseJSON("<?php echo $jsonArray; ?>");
for (var i = 0; i < objArray.length; i++) {
var row = objArray[i];
console.log(row);
// Now here you have access to row.Number row.MusikURL
}
});
You can use json_encode() to convert a PHP variable to its Javascript literal notation.
<script>
var urlarray = <?php echo json_encode($urlarray); ?>;
</script>
var phpCode = '<?php
$sql = "SELECT Name,Surname,id_room FROM timatable.professors WHERE p.id_professor = '".mysqli_real_escape_string($_POST['hiddenProfId'])."'";
$resutl = mysqli_query($db,$sql);
if ($result == 1 ) {
$row = mysqli_fetch_array($result);
$professorName = $row['Name'];
$professorSurname = $row['Surname'];
} else echo "Error";
?>';
alert(phpCode);
this is my code. how to make it work ????
Try this.
First initialize, variables to null.
$professorName = "";
$professorSurname = "";
This is because, if php code enters else part, you will not get any error in javascript part.
<?php
$sql = "SELECT Name,Surname,id_room FROM timatable.professors WHERE p.id_professor = '".mysqli_real_escape_string($_POST['hiddenProfId'])."'";
$resutl = mysqli_query($db,$sql);
if ($result == 1 ) {
$row = mysqli_fetch_array($result);
$professorName = $row['Name'];
$professorSurname = $row['Surname'];
} else echo "Error";
?>
<script>
var professorName = "<?php echo $professorName ?>";
var professorSurname = "<?php echo $professorSurname ?>";
alert(professorName);
alert(professorSurname);
</script>
PHP is a server-side language. So it is processed on a server. Therefore you cannot have a PHP code in javascript.
If you want to have javascript managed some editing in database, you can use AJAX to do it without reloading the page.
I am currently having trouble with this. I would like to make one of my variables in Javascript have a PHP value. Here is what I mean:
<script>
JSvariable = <?php echo $PHPvariable; ?>;
</script>
For some reason that is not working. Here is my full (snippet) of code:
<script>
currentreplyid = <?php echo $allpostcomments[$key]['replyid']; ?>;
$('#parentcommentholder').val(currentreplyid);
</script>
I am sure it is some stupid mistake, but I can not seem to find it! What is the problem? Thank you!
PS #parentcommentholder is an input field, and it just had the value 0 after the field is supposed to of been changed.
Here is some source:
<?php
$postcommentsquery = "SELECT * FROM comments WHERE parent = :parent AND postid = :postid ORDER BY datecreated DESC";
$postcommentsparams = array(':parent' => $allreplies[$key]["postid"],
':postid' => $postid);
try{
$postcommentsstmt = $connection->prepare($postcommentsquery);
$postcommentsresult = $postcommentsstmt->execute($postcommentsparams);
}
catch(PDOException $ex){
echo ("Failed to run query: " . $ex->getMessage());
}
$allpostcomments = $postcommentsstmt->fetchAll();
foreach ($allpostcomments as $key => $value) {
?>
<script>
var currentreplyid = <?php echo $allpostcomments[$key]['replyid']; ?>;
$('#parentcommentholder').val(currentreplyid);
</script>
<input id="parentcommentholder"></div>
Don't forgot for give quotes ' or ". Use following:
<script>
var JSvariable = '<?php echo $PHPvariable; ?>';
//or
var JSvariable = "<?php echo $PHPvariable; ?>";
</script>
Reason: If php variable contains string and if while assigning it to javascript variable we shall not give quote like:
<?php $PHPvariable = 'String';?>
var JSvariable = <?php echo $PHPvariable; ?>;
Will transform into :
var JSvariable = String;//which will give error in javascript
But this will work fine if PHP variable contains a numeric value like:
<?php $PHPvariable = 2;?>
var JSvariable = <?php echo $PHPvariable; ?>;
Will transform into :
var JSvariable = 2;//which will work perfect
Complete code should be:
<script>
var currentreplyid = "<?php echo $allpostcomments[$key]['replyid']; ?>";
//or if you are sure your variable contains int value
var currentreplyid = parseInt("<?php echo $allpostcomments[$key]['replyid']; ?>");
$('#parentcommentholder').val(currentreplyid);
</script>
Try the below instead of using javascript (as I don't think you need it):
<?php
$postcommentsquery = "SELECT * FROM comments WHERE parent = :parent AND postid = :postid ORDER BY datecreated DESC";
$postcommentsparams = array(':parent' => $allreplies[$key]["postid"],
':postid' => $postid);
try{
$postcommentsstmt = $connection->prepare($postcommentsquery);
$postcommentsresult = $postcommentsstmt->execute($postcommentsparams);
}
catch(PDOException $ex){
echo ("Failed to run query: " . $ex->getMessage());
}
$allpostcomments = $postcommentsstmt->fetchAll();
foreach ($allpostcomments as $key => $value) {
?>
<input id="parentcommentholder" value="<?php echo ((int)$allpostcomments[$key]['replyid']>0) ? $allpostcomments[$key]['replyid'] : 0; ?>" />
<?php
}
?>
If your defiantly sure $allpostcomments[$key]['replyid'] is bringing back a value, this should work without any issues.
I have found these two ways:
1st way (width incorrect)
<?php
$arr = new Array (...);
?>
<input id="arr" value="<?php echo json_encode($arr); ?>" hidden>
<script>
$(function (){
var arr = $("#arr").val(); // array with trash
});
</script>
2nd (we need control sequence)
<?php
$arrJS = json_encode($arr);
?>
<script>
var arrJS = <?php echo $arrJS; ?>; // good array
</script>
Question: Is there a better attempt?
Have you considered using AJAX? Here's an example:
Javascript:
$.ajax( "example.php" )
.done(function(json) {
var jsObject = json;
})
and in your 'example.php' file:
<?php
$arr = new Array ('element1'=>'value1', 'element2'=>'value2');
header("Content-type: text/json");
echo json_encode($arr);
exit;
?>