how does jquery make the $ do what it does? [duplicate] - javascript

This question already has answers here:
Immediate function invocation syntax
(3 answers)
Closed 9 years ago.
In order to use the $ symbol in jquery and not have to use jQuery.functionname, we use this
(function($) {
})(jQuery);
(In drupal, you actually have to specify this implicitly).
I don't understand this javascript syntax, why is there an initial parentheses? How is the (jQuery) at the end used?

It's just an anonymous function with an argument that's automatically invoked.
For example, if we were to expand it out a bit you'd end up with something like this:
var anon = function($) {
...
};
anon(jQuery);
The $ is a valid identifer in JavaScript and we pass in the existing jQuery object into the function for use through $, as it could be replaced later.

All that's doing is declaring an anonymous function and executing it immediately, passing in one argument (jQuery) into the function. That argument is given the name $ which can be used throughout the scope of the function.
The brackets around the function aren't strictly necessary in all contexts; see the comment under this answer for details. The gist is that they're needed here to make the function behave like an expression instead of a statement (function declaration).

Related

What does "+" means in +function($)? [duplicate]

This question already has answers here:
JavaScript plus sign in front of function expression
(4 answers)
Closed 5 years ago.
I had look at this question to know about what this means.
(function($) {
})(jQuery);
I am looking at different bootstrap plugins, which have +function ($), while defining the function.
What does + does here, does it appends this function to other functions ?
To guide the javascript parser, that the thing written near the unary operator + is an expression.
EDIT: You can create javascript functions anonymously. This is one of the syntaxes to create the same. By doing so, when they are called (i.e evaluated), they act like a returning a function value. You can read more from the second link which provides a good description of it.
This link explains it well
Once declared, if not named, these can be executed inline like IIFE (Immediately invoked function expressions) as well. And in this form, they can then be used to create plugins or used as namespaces and attached to window object or jquery object for use later.
Good sample file to see anonymous function code in action
http://www.programering.com/a/MTMwITMwATk.html
It's a bang function
the + operator is faster than usual !
see more at
javascript function leading bang ! syntax

What is the difference between writing a function with or without parentheses inside a function in jQuery? [duplicate]

This question already has answers here:
When to use () after a callback function name? [duplicate]
(5 answers)
Closed 6 years ago.
Well I'm starting with jQuery and I'm wondering what is the difference between writing a function with or without parentheses inside a function.
For example if I have the following function:
function test(){
alert("pen pineapple apple pen");
}
This:
$(document).ready(test);
and this:
$(document).ready(test());
both show the same result: "pen pineapple apple pen"
Putting parentheses () at the end of a function causes that function to be invoked immediately, and use its return value in the expression.
This code $(document).ready(test); is using test as a callback function. It essentially says: when the document becomes ready, call the function that I'm providing you with (test).
This code $(document).ready(test()); is immediately invoking the function test, having it return a value, and then passing that value to the ready method. It's possible that test is returning a different function here, which in turn will act as the required callback function. It could also just be an error though, with someone inadvertently including the parentheses when they shouldn't have.

Context binding syntax [duplicate]

This question already has answers here:
Explain the encapsulated anonymous function syntax
(10 answers)
Closed 6 years ago.
Lets assume we have
function () {}.bind(null);
and
(function () {}).bind(null);
Why the first one doesn't work in developer console (it throws syntax error) but both of them work in code (".js" file in website).
I think its because you are trying to define an anonymous function. Console has no future way of referencing it so its a pointless endeavour, youre defining a function you have no way of calling. If you define it as a variable it works:
var a = function () {}.bind(null);
Also I dont think its binding related. Defining an anonymous function without binding and you have the same error
Edits
A statement that begins with the keyword "function" must be a valid
function declaration statement. That requires a name for the function.
In an expression (or expression statement), that rule is different; no
name is necessary because the function acts as a value in that
context. No name is required then.
via #Pointy from this answer
A function declaration cannot be anonymous, but a function expression
can. A stand alone anonymous function looks like a function
declaration that is missing an identifier to JavaScript. But, combined
with an operator, JavaScript treats an anonymous function as the
operator's operand expression.
via #gilly3 from this answer

Is this jQuery related, and what does this mean? [duplicate]

This question already has answers here:
What does the exclamation mark do before the function?
(8 answers)
Closed 9 years ago.
I have been searching, but no clues... or I haven't search the proper way (so please excuse me if duplicate)
Does the following code, mean: If there is no jQuery defined, or no document ready?
!function ($) {
///
!function ($) {
$(function(){ // I know this is an alias to $(document).ready()
.....
}(window.jQuery) // Ending of !function
I'm asking, because I saw it here: http://twitter.github.io/bootstrap/assets/js/application.js and have no I really don't know what it means.
In this case, ! is being used because it's an operator, so the rest of the line will be treated as an expression rather than a statement. This is a way of writing an immediately invoked function expression. The more common idioms can be found here:
Javascript immediately invoked function patterns
! on a function(){}() simply flips (or negates) the value that's returned after immediately calling the function that's defined. Notice that immediately after the function definition, at the very last line, it says (window.jQuery) — that's passing jQuery as the argument to the function and calling it immediately.
But in this case it doesn't appear to do anything important since the return value won't be used anyway. The function will still be executed though.
Also, it says this at the top of the file:
// NOTICE!! DO NOT USE ANY OF THIS JAVASCRIPT
// IT'S ALL JUST JUNK FOR OUR DOCS!
// ++++++++++++++++++++++++++++++++++++++++++
So that's evidence further that it's not meant to serve any real purpose.

what does !function in Javascript mean? [duplicate]

This question already has answers here:
What does the exclamation mark do before the function?
(8 answers)
Closed 5 years ago.
Sorry for posting this but !function is not google-able and I did not find it in my JavaScript code.
Here is how Twitter uses it:
Tweet
<script>!function(d,s,id){var js,fjs=d.getElementsByTagName(s)[0];if(!d.getElementById(id)){js=d.createElement(s);js.id=id;js.src="//platform.twitter.com/widgets.js";fjs.parentNode.insertBefore(js,fjs);}}(document,"script","twitter-wjs");</script>
from https://twitter.com/about/resources/buttons#
It is short-hand or alternative of self-invoking anonymous function:
(function(){
// code
})();
Can be written:
!function(){
// code
}();
You can also use + instead of !.
If you simply did:
function(){
// code
}();
That will create problems, that's why you need to add ! before it which turns the function declaration into function expression.
Quoting docs, section 12.4:
An ExpressionStatement cannot start with the function keyword because
that might make it ambiguous with a FunctionDeclaration.
To better understand the concept, you should check out:
Function Declarations vs. Function Expressions
they're negating the result, not the function itself:
!function( x ){ return x }( true );
!true
false
In reality, it's a slightly compressed form of:
(function(){}())
since it requires 1 less character. The reason it's needed is that you can't call a function declaration directly, e.g. this is invalid:
function(){}()
but adding the ! at the beginning turns it into a function expression and makes it work.
It's usually used to work around a quirk in the JavaScript syntax. This gives a syntax error:
function() {
}();
It's read as a function declaration (like function foo () {}), rather than a function expression. So adding the ! before it, or wrapping it in parentheses, forces the parser to understand that it's an expression.

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