I have two radiobuttons in one group.
The first is checked if you visit the page by 'checked' in html..
I want to use javascript to adjust some css (through javascript, not by adding a class).
So if the first is selected, I want a certain class to get a display:none and an other class a display:block, but when the second radio button is selected, I want the the same as with the other radio button only and vice versa.
My html is:
<li><input type="radio" name="kosten" id="maand" checked><label for="maand">per maand</label></li>
<li><input type="radio" name="kosten" id="jaar" ><label for="jaar">per jaar</label></li>
I tried some jquery but I'm really bad at it.
if ($('input#maand').is(':checked'){
$('.bedrag-jaar').css('display', 'none');
}
Some examples of the divs I want to show up and disappear.
<li><strong><span class="bedrag-maand">some text</span> <span class="bedrag-jaar">some other text</span></strong></li>
Do you have any idea how i can get this working?
Try something like
jQuery(function(){
var $spans = $('span[class*="bedrag"]').hide();
$('input[name="kosten"]').change(function(){
$spans.hide();
$spans.filter('.bedrag-' + this.id).show();
})
})
Demo: Fiddle
it can be done much powerful, if you can add an additional class to the bedrag-* elements like
<li><strong><span class="bedrag bedrag-maand">some text</span> <span class="bedrag bedrag-jaar">some other text</span></strong></li>
then
jQuery(function(){
var $spans = $('.bedrag').hide();
$('input[name="kosten"]').change(function(){
$spans.hide();
$spans.filter('.bedrag-' + this.id).show();
})
})
Demo: Fiddle
Here is the code and try this:
$( "input[type=radio]" ).on( "click",function(){
if ($('#maand').is(':checked')){
$('.bedrag-maand').css('display', 'block');
$('.bedrag-jaar').css('display', 'none');
} else {
$('.bedrag-jaar').css('display', 'block');
$('.bedrag-maand').css('display', 'none');
}
});
JSFIDDLE
Related
When I click on an element, it should (only) activate/tick a checkbox, but it doesn't work.
HTML:
<input type="checkbox" id="collapsible" name="collapsible" /> <br />
<p class="member">
Activate Checkbox
</p>
Javascript:
$(".member").on("click", function() {
$('input[id $=collapsible]').attr('checked', this.checked);
});
http://jsfiddle.net/et7uym09/
I changed your code a little bit, you got already the right base.
this.checked is not defined in this context, so you have manually set it to true.
$(".member").on("click", function() {
$('#collapsible').attr('checked', true);
});
also you can use $('#collapsible').attr('checked', true); instead of $('input[id $=collapsible]').attr('checked', true);
working jsfiddle here: http://jsfiddle.net/zsL15wog/5/
if you want to toggle the checked state of the checkbox do something like this:
$(".member").on("click", function() {
var isChecked = $('#collapsible').prop('checked');
$('#collapsible').attr('checked', !isChecked);
});
fiddle: http://jsfiddle.net/zsL15wog/4/
Hope i could clear the things a bit more up :)
If you got other problems with this code, let me know.
What about <label>? Nothing extra necessary (unless you want a little styling on your text).
<label for="collapsible" style="cursor: pointer;">
Activate Checkbox
<input type="checkbox" id="collapsible" name="collapsible" />
<label>
$(".member").on("click", function() {
$('#collapsible').attr('checked',true);
});
Please try the above code
i am trying to learn and create a jquery which $("#answer") and find all the checkbox inside and check. As an example if checkbox inside #a1 is checked other div (a2,a3,a4) is hidden or other message come out. if i uncheck the #a1 all the div will come out again.
Please enlighten me on the code.
<div id="answer">
<div id="a1">A.<input type="checkbox" name="a1" onclick="cbox()" ></input></div>
<div id="a2">B. <input type="checkbox" name="a2"onclick="cbox()"></input></div>
<div id="a3">C. <input type="checkbox" name="a3"onclick="cbox()"></input></div>
<div id="a4">D. <input type="checkbox" name="a4"onclick="cbox()"></input></div>
</div>
function cbox() {
if (this checkbox is checked) {
target other div inside (#answer) and add .hide()
}
}
2)Is there anyway to add a trigger where i don't need to use onlick="cbox" ?
tq
It's better to use .click() instead of inline javascript onclick.
However, you should use .change() event for input elements instead of click:
$('input[type="checkbox"]').change(function() {
$(this).parent().siblings('div').toggle(!this.checked);
});
Fiddle Demo
Use .change() event instead of .click(). Try this:
$('input[type="checkbox"]').change(function() {
$(this).parent('div').siblings('div').toggle(!this.checked);
});
DEMO
Try this:
$("#answer input").change(function () {
if ($(this).is(":checked")) {
$("#answer input").not(this).each(function () {
$(this).parent().css("display", "none");
})
} else {
$("#answer input").not(this).each(function () {
$(this).parent().css("display", "block");
})
}
});
DEMO
I'm trying to use Bootstrap's collapse functionality to show/hide divs based on which radio button is checked. I was able to get things to work fine when I don't use Bootstrap's collapse function, however, in order to give a more consistent feel I'd like to take advantage of this function.
Here's a snippet of the HTML in question:
<div class="col-xs-12 form-group">
<label class="radio-inline">
<input type="radio" id="send-now-radio" name="when" value="send-now" checked> <strong>Send Now</strong>
</label>
<label class="radio-inline">
<input type="radio" id="pickup-radio" name="when" value="pickup"> <strong>Hold for pickup</strong>
</label>
<label class="radio-inline">
<input type="radio" id="fax-radio" name="when" value="fax"> <strong>Fax</strong>
</label>
<label class="radio-inline">
<input type="radio" id="email-radio" name="when" value="email"> <strong>Email</strong>
</label>
</div>
<div class="col-xs-12">
<div id="send">Send</div>
<div id="pickup">Pickup</div>
<div id="fax">Fax</div>
<div id="email">Email</div>
</div>
And here's my javascript code:
$(document).ready(function()
{
// Hide all but one method div (since all are shown in case the user has JS disabled)
$('#send').show();
$('#pickup').hide();
$('#fax').hide();
$('#email').hide();
// Attach to the radio buttons when they change
$('#send-now-radio, #pickup-radio, #fax-radio, #email-radio').on('change', function () {
// Make sure that this change is because a radio button has been checked
if (!this.checked) return
// Check which radio button has changed
if (this.id == 'send-now-radio') {
$('#send').collapse('show');
$('#pickup').collapse('hide');
$('#fax').collapse('hide');
$('#email').collapse('hide');
} else if (this.id == 'pickup-radio') {
$('#send').collapse('hide');
$('#pickup').collapse('show');
$('#fax').collapse('hide');
$('#email').collapse('hide');
} else if (this.id == 'fax-radio') {
$('#send').collapse('hide');
$('#pickup').collapse('hide');
$('#fax').collapse('show');
$('#email').collapse('hide');
} else // if (this.id == 'email-radio') {
$('#send').collapse('hide');
$('#pickup').collapse('hide');
$('#fax').collapse('hide');
$('#email').collapse('show');
}
});
};
Here's a link to a JS fiddle with all of this: http://jsfiddle.net/DTcHh/156/
Unfortunately I'm missing something, cause the behavior is weird and not what I would expect.
First of all, excellent question. You provided code, made it clear what you tried, etc. Love it.
I forked your JSFiddle, and came up with this:
http://jsfiddle.net/emptywalls/EgVF9/
Here's the Javascript:
$('input[type=radio]').on('change', function () {
if (!this.checked) return
$('.collapse').not($('div.' + $(this).attr('class'))).slideUp();
$('.collapse.' + $(this).attr('class')).slideDown();
});
I wouldn't recommend using the collapse functionality from Bootstrap, it relies on a very different DOM structure from what you need. My fiddle uses just jQuery to accomplish what you need. My approach was to pair the radio buttons and divs with classes, so you can DRY up your code.
As #emptywalls mentioned, the Bootstrap collapse function won't work. I tried it and it almost does, except that it is based on clicking the source element, not it's state. A radio button needs to pay attention to it's state.
But I wanted something that allowed me to mark up the element with data tags and have it inherit the functionality, as the bootstrap collapse does. So I came up with this:
<input data-target="#send" data-toggle="radio-collapse" id="send_now_radio" name="when" type="radio" value="send-now">
<div id="send" class="collapse">Send</div>
And then have this included once in your site and it will apply to all such buttons.
$('input[type=radio][data-toggle=radio-collapse]').each(function(index, item) {
var $item = $(item);
var $target = $($item.data('target'));
$('input[type=radio][name="' + item.name + '"]').on('change', function() {
if($item.is(':checked')) {
$target.collapse('show');
} else {
$target.collapse('hide');
}
});
});
This uses the collapse function of Bootstrap for the animation. You could just as easily use jQuery hide() and show().
Unless I'm mistaken, #jwadsack code won't work if you have another group of radio buttons with a different name attribute.
That's because the $item and $target variables are declared globally. The $item variable will be overidded by the last group and only this one will hide/show the collaspe.
Adding var before the variable definition seems to fix the problem.
The code is then
$('input[type=radio][data-toggle=radio-collapse]').each(function(index, item) {
var $item = $(item);
var $target = $($item.data('target'));
$('input[type=radio][name="' + item.name + '"]').on('change', function() {
if($item.is(':checked')) {
$target.collapse('show');
} else {
$target.collapse('hide');
}
});
});
I have the following markup, below the closing span tag is a number list items.
<div class="header_block">
<span class="background_flag_container">
<input id="block_background" type="checkbox" name="block_background">
<span class="background_flag_text">Has Banner Background</span>
</span>
...
</div>
This is my jQuery. What I am looking to do is check if the one and only checkbox, with a name of 'block_background' is checked. There are a number of 'block_background' checkboxes on the page, but there will only ever be one within $(this) which is the .header_block div.
$(this).find(".background_flag_container input:checkbox[name='block_background']").each(function(){
if ($(this).checked) {
console.log('is checked');
}
});
How can I check if it's checked?
You can use is(':checked') to check if something is selected
$(this).find(".background_flag_container input:checkbox[name='block_background']").each(function(){
if ($(this).is(':checked')) {
console.log('is checked');
}
});
Although seeing that the checkbox has the id block_background which should be unique. You could just do this:
if ($('#block_background').is(':checked')) {
console.log('is checked');
}
$("input#block_background]").is(':checked')
I have a form with multiple inputs / radio buttons.
I also have a series of Yes & No radio buttons. When the "Yes" radio button is checked, I have some data slide down beneath.
HTML:
<div class="item seperator first clearfix">
<label>test</label>
<div class="radioWrap">
<label class="yes">
<input class="homepageContent" name="homepageContent" type="radio" value="yes" />
</label>
<label class="no">
<input class="homepageContent" name="homepageContent" type="radio" value="no" checked />
</label>
</div>
</div>
<div class="extrasInner">
<div class="item clearfix">
<label for="theContent">Your Content:</label>
<textarea id="theContent" name="theContent"></textarea>
</div>
</div>
<div class="extrasOuter hide clearfix">
Make Changes
<span>Click "Make Changes" to update.</span>
</div>
The jQuery:
$("input:radio[name=homepageContent], input:radio[name=addSocialIcons], input:radio[name=addTracking]").click(function() {
var value = $(this).val();
if (value == 'yes') {
$(this).parent().parent().parent().next().slideDown();
$(this).parent().parent().parent().next().next().slideDown();
} else {
$(this).parent().parent().parent().next().slideUp();
$(this).parent().parent().parent().next().next().slideUp();
}
});
Question 1) This works absolutely fine in Google Chrome, but not in Firefox and IE. It doesn't seem to recognise the click function?
Solved: I had a function within one of my files that removes the value from input fields on focus and this was stripping the value of the radio buttons as well in IE / Firefox (but not chrome!).
Question 2) Is my DOM traversing for the slideUp / slideDown an acceptable way of achieving what I'm trying to do? Are there any disadvantages to how I'm doing it and can it be improved?
Answer to #1
As Anthony Grist pointed out, there doesn't seem to be an issue with the click function.
Answer to #2
Your DOM traversal seem a bit unnecessary. In fact, your DOM structure is in need of rearrangement.
Using a checkbox instead of radio buttons. A checkbox only accepts two values: true or false, or in your case, yes or no. It seems more suitable.
Encapsulate your extras inner and extras outer divs inside your item div instead of having it next to the checkbox. This way, you make it easier to traverse within the item.
Also, you should read up on the different types of traverse functions JQuery has:
.parent() / .parents()
.children()
.closest()
.next()
.prev()
.siblings()
.find()
and many more.
Knowing all of these traverse functions, you'll most likely never ever do parent().parent().parent()... again. :)
Here's a JSFiddle example | Code
HTML
<ul>
<li class='item'>
<label>
<input class="homepageContent" name="homepageContent" type="checkbox" value="yes" />
Item 1
</label>
<div class='extras'>
<div class='inner'>
<label>
Your Content:<textarea name="content"></textarea>
</label>
</div>
<div class='outer'>
Make Changes
<span>Click "Make Changes" to update.</span>
</div>
</div>
</li>
</ul>
Javascript
$("input:checkbox").click(function() {
var $this = $(this),
$item = $(this).closest(".item");
if($this.is(':checked')){
$(".extras", $item).slideDown();
}else{
$(".extras", $item).slideUp();
}
});
CSS
.extras{
display: none;
}
Value of the radio button will always be same, no matter it is checked or not. If you want to know the particular radio button is checked or not then use this code. Based on the status of the radio button do your stuff.
var value = $(this).attr('checked')
That is working for me in FF (jsfiddle), although the DOM looks a little convoluted (I'm guessing because it's missing a lot of your other CSS/resources).
I think you can simplify the jQuery selectors a lot. Generally, using simple ID or class selectors will make the your page much more performant (and simpler!)
$('.homepageContent').click(function() {
var value = $(this).val();
if (value == 'yes') {
$('.extrasInner').slideDown();
$('.extrasOuter').slideDown();
} else {
$('.extrasInner').slideUp();
$('.extrasOuter').slideUp();
}
});
Hopefully doing something like this makes it work cross browser better too.
try this way
$("input:radio[name=homepageContent], input:radio[name=addSocialIcons], input:radio[name=addTracking]").click(function() {
var value = $(this).val();
if (value == 'yes') {
$(this).parents('.seperator').next().slideDown();
$(this).parents('.seperator').next().next().slideDown();
} else {
$(this).parents('.seperator').next().slideUp();
$(this).parents('.seperator').next().next().slideUp();
}
});
EDIT
and also a point
wrap your code inside
$(document).ready(function(){});
like this
$(document).ready(function(){
$("input:radio[name=homepageContent], input:radio[name=addSocialIcons], input:radio[name=addTracking]").click(function() {
var value = $(this).val();
if (value == 'yes') {
$(this).parents('.seperator').next().slideDown();
$(this).parents('.seperator').next().next().slideDown();
} else {
$(this).parents('.seperator').next().slideUp();
$(this).parents('.seperator').next().next().slideUp();
}
});
});