Develop Reference

use getJSON with variable

I apologize beforehand if the question is not clear, but i'll try.
I currently have this code that pull the status of all the devices from my home automation controller.
function pull_light_status (lights_array) {
$.getJSON( "resources/php/getjson.php", function( json ) {
var vera_obj = json;
$.each(lights_array,function(myindex, myvalue){
var id_del_object = myvalue;
var id_status = vera_obj.devices[id_del_object].states[0].value;
})
})
}
Due to the structure of the object i get its getting really hard for me to work with that object so I'm thinking in using another route.
I can get the status of an specific device by using this php called change_state.php
<?php
$url = 'http://ip:port/data_request?id=variableget&DeviceNum' . $_POST['device_id'] . "&serviceId=urn:upnp-org:serviceId:SwitchPower1&Variable=Status";
$jsondata_send = file_get_contents($url);
//echo $jsondata_send;
?>
My question is:
Is it possible to replace the JS to something that will allow me to request the json response of a device variable I specify?
Something like this?
function pull_light_status (lights_array) {
$.each(lights_array,function(myindex, myvalue){
$.getJSON( "resources/php/change_state.php",{ device_id: + myvalue})
.done(function(json) {
var vera_obj = json;
console.log (vera_obj);
})
})
}
What I would expect in return is a 0 or 1, that way I can play with the status of the devices.

Try using $.post since you are expecting a POST payload on the php side.
function pull_light_status (lights_array) {
$.each(lights_array,function(myindex, myvalue){
$.post( "resources/php/change_state.php", { device_id: myvalue })
.done(function( data ) {
var vera_obj = json;
console.log (vera_obj);
});
})
}
While on the php side you need to make sure that you are sending back a json encoded string.
So a var_dump($jsondata_send); would be in order, if it's all right, print it out along with the headers.
<?php
$url = 'http://ip:port/data_request?id=variableget&DeviceNum' . $_POST['device_id'] . "&serviceId=urn:upnp-org:serviceId:SwitchPower1&Variable=Status";
$jsondata_send = file_get_contents($url);
header('Content-Type: application/json');
print $jsondata_send;
?>
If you want to use getJSON instead, in the php file, change $_POST['device_id'] into $_GET['device_id']

Display a session var without refresh the page

I set a session var in an ajax file like that :$_SESSION['id_essai']=$ligne[1];. The value of this var should change at each submit of the form.
Without recharge the page, I want to get the value of this var. So I echo it like that : echo $_SESSION['id_essai'];
My problem is, when I try to echo it, I get the previous value until I recharge the page. I want to refresh this var without recharge the page. How can I do that ?
EDIT :
I send a handsontable grid to my ajax file like that :
$(document).ready(function(){
$('#submit_button_essai').click(function(){
$.post("ajax_insert_essai.php",{arr:data_essai}, insert_essai_callback,'json');
return session;
});
});
In this ajax file, I declare my session var with one value of this grid and I can return it like that :
array_unshift($tab_erreur,$_SESSION['id_essai']);
echo json_encode($tab_erreur);
So I send an array of errors AND the session var that I process like that in my callback function:
function insert_essai_callback(responseObject,ioArgs) //ajax renvoie les indices des cases erronnées et les messages correspondants.
{
var jsonobject = eval(responseObject);
console.log(jsonobject);
//alert(jsonobject[0]);
var session = jsonobject[0];
for(var item in jsonobject)
{
if((item % 2 ) == 0) //Si l'indice est pair, on affiche la couleur
{
$("td").eq(jsonobject[item-1]).after("<div class=\"message\">"+jsonobject[item]+"</div>");
}else //Si l'indice est impair, on affiche le message
{
$("td").eq(jsonobject[item]).css("background-color","red");
}
}
}
My session var is in jsonobject[0].
That's my code after trying to return the session var in ajax.

I think the problem is that every reuqest will start a new session on the server.
<?php
session_start();
// Restart the last session if a session-id is given
if (isset($_GET['session-id'])
session_id($_GET['session-id']);
/* ... your code here .. */
$response = array('session-id' => session_id());
/* ... add some more values/results to your response */
header('Content-Type: application/json');
die(json_encode($response));
?>

Set up a new PHP file. Then send the value you need to update to the session variable using ajax on a click event or change event or something. When it receives the value , PHP will update the session value. Then return that variable's value in JSON. Tada You got the updated value. I hope you understood..
example code look like this
in ajax (jquery ajax i am using here)
$.ajax({
url : 'session.php',
method : 'POST',
data : your value to update ,
dataType : json,
success : function(data){
alert(data.value);
}
})
In session.php file
<?php
session_start();
$value = $_POST['value'];
$_SESSION['value'] = $value;
$json = array('value' => $_SESSION['value'] );
print_r(json_encode($json));
?>
If you need to get value without refresh , call the ajax function on an event. Then update the returned data in to div or something. I hope this one helps ! :)

create a process.php file and post/get the form there.
<form method = 'post' action = 'process.php'>
<input type = 'hidden' value = 'some_Hidden_Value_that_You_Want' id = 'hidden_id'>
<!--Some other stuff (Grid may be) -->
<input type = 'button' value = 'Submit' id = 'submit_form'>
</form>
$("#hidden_id").click(function(){
var hidden_id = $('#hidden_id').val()
$.ajax({
url: 'process.php',
type: 'POST',
data:{
want_this: hidden_id
},
success: function(posted){
alert(posted);
}
});
});
This will post your stuff to process page.
and on process.php or in your case ajax_insert_essai.php
do this to view what you're getting
<?php
print_r($_POST);
?>
EDIT
in callback
obj = $.parseJSON(jsonobject[0]);
console.log(obj);
// this was to update the page without refreshing the page
// $this = $('#'+obj.ID).find('td');
// $this.eq(2).html(obj.username);
// $this.eq(3).html(obj.password);
//ignore these lines
/*You can access all your stuff then like that*/
condole.log('some id' + obj.id);
//and so on...

If the data that will become the new session variable is sent from the page just have it also use the data already on the page to update to page using JavaScript.
If the data you want to get returned is being sent from the page there is no need to re-get the data because it is already on the page.

Unable to send jQuery variable with string content to PHP using jQuery AJAX function?

The code snippet for the jQuery function looks like:
function addMessage() {
if (textval != "") {
text_string='<div class="alert-box round"><p class="text-left">' + userName + ':' + textval + '</p></div></br>';
alert(text_string);
$.ajax({
type:"POST",
url:"process.php",
data: {'text_string': text_string},
cache:false,
success:function(){
alert("submitted")
}
});
$("input[type=text]:last").val("");
}
enterButton = 0;
}
The process.php code looks like:
<body>
<?php
//$host = "localhost";
$text_string=$_POST['text_string'];
echo "string submitted is".$text_string;
?>
</body>
I get alerts showing value of text_string and then the "submitted", but when I open the php page, it shows an error:
Undefined index: text_string
I've seen various answers, none of them seem to be the case for mine. Is the problem in PHP code or jQuery code or both?

If you want to save the value passed by the AJAX request for the next time you load "process.php", try saving it in the session. So, you could change your code to:
<?php
session_start();
// Store value in session if it is passed
if (isset($_POST['text_string'])){
$_SESSION['text_string'] = $_POST['text_string'];
}
// Read and echo value from session if it is set
else if (isset($_SESSION['text_string'])){
$text_string=$_SESSION['text_string'];
echo "string submitted is".$text_string;
}
?>
Now, your PHP script will store the passed value in the session, and will echo that stored value should you load the page elsewhere. (Another alternative is to store the value in a database...though I'm not sure if you have one set up at the moment.)
Hope this helps! Let me know if you have any questions.

ajax request all return error 500

When ever I am doing an ajax request with jquery I always get an error 500 return,
I am posting to the following URL
http://localhost/domain/index.php/my_profile/interests_music
using this javascript,
$("#add").click(function(e){
//set some process variables, we need to get the forms action,
//and any post data it is sending appending isAjax into the params
//gives us a point in the controller to gracefully check for ajax.
var action = $(this).parent('form').attr('action');
var formData = $(this).parent('form').serialize()+"&isAjax=1";
$.ajax({
type: "POST",
url: action,
data: formData
}).done(function( msg ) {
alert( "Data Saved: " + msg );
});
e.preventDefault();
});
The params that are being sent are,
music=Savage Garden&isAjax=1
And the PHP method the ajax is requesting looks like this,
public function interests_music()
{
if($this->input->post('music'))
{
$this->rest->initialize(array('server' => 'https://www.googleapis.com/freebase/v1'));
$response = $this->rest->get('mqlread?query={"type":"/music/artist","name":"' . urlencode($this->input->post('music')) . '","id":[]}');
$data['image'] = 'https://usercontent.googleapis.com/freebase/v1/image'.$response->result->id[0].'?mode=fillcrop&maxwidth=80&maxheight=80';
$data['category'] = 'music';
$data['user_id'] = $this->session->userdata('id');
$data['name'] = $this->input->post('music', TRUE);
$this->profile_model->add_interest($data);
Events::trigger('interests_music');
Events::trigger('badge_stagediver');
if($this->input->post('isAjax') == 1)
{
echo json_endcode($data);
$this->_buttons();
}
redirect('my_profile/interests');
}
else
{
show_404();
}
}
Am I missing something, is this a common problem?

Well for one there's a typo in your PHP which could be what your server is choking on: echo json_endcode($data); should be echo json_encode($data);. Aside from that there could be other issues with your HTTP server. What server are you using? A good practice is to find the server error log and PHP error log and use tail -f or some other method of monitoring the logs which should give you more information when you have 505s.

Codeigniter ajax CSRF problem

I've made a simple autoload function that loads content when you scroll down on a website. However, there seems to be a few problems when i enable CSRF protection in Codeigniter.
I'm not using a form, so i don't know how i can send the token from A to B when i'm doing my post request as you scroll.
My JavaScript
if (location.href == baseurl) {
$(window).scroll(function(){
if ($(window).scrollTop() > $('body').height() / 2) {
if(doScroll == 1) {
$.post(baseurl + 'ajax/images',{'id' : ID}, function(data) {
$("#wrapper_content").append(data);
if(data == 'Det finnes ikke flere bilder i databasen, WTF!? Send inn forslag ASAP!') {
doScroll = 0;
}
ID++;
});
}
}
});
}
Since Codeigniter expects a TOKEN on all POST request i can't get this to work when CSRF i enabled. Any suggestions?
Error when CSRF is Enabled
Failed to load resource: the server responded with a status of 500 (Internal Server Error)
If i turn CSRF off, everything works great...

You might like to try this code I've used. It works great:
<script type="text/javascript">
$(function(){
$('.answerlist').each(function(e){
$(this).click(function(){
var valrad = $("input[#name=answer]:checked").val();
var post_data = {
'ansid': valrad,
'<?php echo $this->security->get_csrf_token_name(); ?>' : '<?php echo $this->security->get_csrf_hash(); ?>'
};
$.ajax({
type: "POST",
url: "<?php echo base_url(); ?>online/checkanswer",
data: post_data,
success: function(msg){
/// do something
}
});
});
});
});
</script>

As others say - you have to post the CSFR token name and its value with the AJAX request parameters. Here is a simple solution to append it automatically to every AJAX request.
Here is what I put on my main view, so this code is on every page before loading the other javascript files:
<script>
var csfrData = {};
csfrData['<?php echo $this->security->get_csrf_token_name(); ?>']
= '<?php echo $this->security->get_csrf_hash(); ?>';
</script>
<!-- ... include other javascript files -->
</body>
</html>
And here is a part of a javascript file that I include on every page:
$(function() {
// Attach csfr data token
$.ajaxSetup({
data: csfrData
});
});

If you want, you can echo both the token name and the hash somewhere appropriate. Something like this.
echo $this->security->get_csrf_token_name()
and
echo $this->security->get_csrf_hash()
Or, you could use form_open() as usual and use the hidden input that is generated for you from your javascript. Disabling the CSRF-functionality is the wrong way to go.

Having reviewed my situation I believe the best option is to use CSRF but reset the token on each attempt. Otherwise the ideas expressed earlier about re-using the cookie token would allow an attacker to resubmit data hundreds of times using the same token which defeats the object of the point.
As such I have created the following function:
public function resetCSRF(){
$this->security = null;
$_COOKIE[$this->config->item('csrf_cookie_name')] = null;
load_class('Security', 'core');
$this->security->csrf_set_cookie();
return $this->security->get_csrf_hash();
}
If for example an ajax based login form fails - call this function in your PHP and then on the javascript side that receives the failure (this solution uses Jquery and a getCookie function from w3schools) would then simply call:
$('input[name="csrf_test_name"]').val(getCookie('csrf_cookie_name'));

Basically what you need to do is get the expected csrf value from the cookie (named 'ci_csrf_token' by default), then post it along with your other data.
You would need to modify this line:
$.post(baseurl + 'ajax/images',{'id' : ID}, function(data) {
to:
$.post(baseurl + 'ajax/images',{'id' : ID,'ci_csrf_token' : $.cookie('ci_csrf_token')}, function(data) {
Might need to install the cookie addon (I'm not really sure; I use mootools). Here is more information: http://aymsystems.com/ajax-csrf-protection-codeigniter-20.

Previous suggestions work great, but rather than using a variable that you can apply in every data-post, I find it simpler to use the ajax-setting to automatically apply this token to every post:
$(document).ajaxSend(function(elm, xhr, s){
if(s.data){
s.data += '&';
}
s.data += '<?php echo $this->security->get_csrf_token_name(); ?>=<?php echo $this->security->get_csrf_hash(); ?>';
});
(works with jquery-1.9.1. I'm not sure about other jquery-versions)

The only problem with a few of the above answers is that a csrf token is only valid for one request, so if you make a post request via ajax and do not refresh the page you will not have the current csrf token for your next ajax post request. This is my solution:
In your CodeIgniter Controller:
$data = array('data'=> 'data to send back to browser');
$csrf = $this->security->get_csrf_hash();
$this->output
->set_content_type('application/json')
->set_output(json_encode(array('data' => $data, 'csrf' => $csrf)));
$data = the data to return to the browser
$csrf = new csrf token to be used by the browser for next ajax post request
Obviously you can output this in other ways but JSON is used mostly with ajax calls. Also include this token in every post response to be used for the next post request
Then in your next ajax request (javascript):
var token = data.csrf;
$.ajax({
url: '/next/ajax/request/url',
type: 'POST',
data: { new_data: 'new data to send via post', csrf_token:token },
cache: false,
success: function(data, textStatus, jqXHR) {
// Get new csrf token for next ajax post
var new_csrf_token = data.csrf
//Do something with data returned from post request
},
error: function(jqXHR, textStatus, errorThrown) {
// Handle errors here
console.log('ERRORS: ' + textStatus + ' - ' + errorThrown );
}
});
Also remember that where I've got csrf_token:token replace crf_token with the name of your token found in application/config/config.php on line that states $config['csrf_token_name'] = 'csrf_token';