The scenario is...
A visitor comes to my landing page and completed the form, which included a telephone number.
Using Zapier I then pass that form data to ActiveCampaign.com using a "ZAP".
However as ActiveCampaign is in USA, they require the phone number formatting to international standard, instead of local UK.
Most numbers in UK are 07788990022
But it needs to be presented as +447788990022
So I need to use this built in function of Zapier listed below
https://zapier.com/help/code/
And need some Javascript code writing that will check the number
Is it valid UK mobile number? I.e. 11 digits
Remove all spaces, and trim
If 2nd character is a 7 then replace 1st character (which should be a 0) with +44
I really dont have any idea how to do this! I was hoping for a built in function on Zapier, but apparently not. Any ideas would be awesome!!!
David here, from the Zapier Platform team.
This seems like a pretty straightforward js question! This will be pretty "dumb" validation, but will work assuming the input is correct.
You'll have a code (javascript) step and set the input to be phone: input from step 1. Your code will look like this:
var ph = inputData.phone.replace(/\s+/g, '') // remove all whitespace from string
if (ph.length !== 11) {
// invalid phone number. do nothing?
return []
}
if (ph[1] === '7') {
ph = '+44' + ph.substr(1)
}
return {formattedNumber: ph}
I am trying to format a number by using a selector, both jQuery of JavaScript are fine.
I have a dynamic number that comes back from the API, but that comes back with many decimal place (i.e 3.5847549875398). I want to format it to 2 decimal places (i.e 3.58). Rounding is not necessary, but if there is an example with rounding that would be great!
Here is what I have, but it fails to round:
JSP:
<span class="floatRight distanceNum">
<#= storeInfo.distance #> miles
</span>
JavaScript/jQuery (Within the onLoad function)
$(".distanceNum").toFixed(2);
You need to convert your value from api to float then you should be able to achieve what you want. toFixed function will round your value also.
Here is the working code for you.
$(".distanceNum").text(parseFloat($(".distanceNum").text()).toFixed(2));
Let me know if it worked for you.
Happy Coding.
So I know how to format a string or integer like 2000 to 2K, but how do I reverse it?
I want to do something like:
var string = "$2K".replace("/* K with 000 and remove $ symbol in front of 2 */");
How do I start? I am not very good regular expressions, but I have been taking some more time out to learn them. If you can help, I certainly appreciate it. Is it possible to do the same thing for M for millions (adding 000000 at the end) or B for billions (adding 000000000 at the end)?
var string = "$2K".replace(/\$(\d+)K/, "$1000");
will give output as
2000
I'm going to take a different approach to this, as the best way to do this is to change your app to not lose the original numeric information. I recognize that this isn't always possible (for example, if you're scraping formatted values...), but it could be useful way to think about it for other users with similar question.
Instead of just storing the numeric values or the display values (and then trying to convert back to the numeric values later on), try to update your app to store both in the same object:
var value = {numeric: 2000, display: '2K'}
console.log(value.numeric); // 2000
console.log(value.display); // 2K
The example here is a bit simplified, but if you pass around your values like this, you don't need to convert back in the first place. It also allows you to have your formatted values change based on locale, currency, or rounding, and you don't lose the precision of your original values.
Can anyone let me know how can I format a telephone number automatically using javascript.
I have seen some of the code samples in the internet....But my point is not all the countries have the country code just 3 numbers.....and moreover if someone write the country code 0091 and the number will be like 9878...... Then the codes I have seen in the internet formats them like (009)-(19878...) . If u see the country code will be taken wrong ......
Can someone clear out this
Thanks
Try to look at libphonenumber:
http://code.google.com/p/libphonenumber/
I am after a regular expression that validates a percentage from 0 100 and allows two decimal places.
Does anyone know how to do this or know of good web site that has example of common regular expressions used for client side validation in javascript?
#Tom - Thanks for the questions. Ideally there would be no leading 0's or other trailing characters.
Thanks to all those who have replied so far. I have found the comments really interesting.
Rather than using regular expressions for this, I would simply convert the user's entered number to a floating point value, and then check for the range you want (0 to 100). Trying to do numeric range validation with regular expressions is almost always the wrong tool for the job.
var x = parseFloat(str);
if (isNaN(x) || x < 0 || x > 100) {
// value is out of range
}
I propose this one:
(^100(\.0{1,2})?$)|(^([1-9]([0-9])?|0)(\.[0-9]{1,2})?$)
It matches 100, 100.0 and 100.00 using this part
^100(\.0{1,2})?$
and numbers like 0, 15, 99, 3.1, 21.67 using
^([1-9]([0-9])?|0)(\.[0-9]{1,2})?$
Note what leading zeros are prohibited, but trailing zeros are allowed (though no more than two decimal places).
This reminds me of an old blog Entry By Alex Papadimoulis (of The Daily WTF fame) where he tells the following story:
"A client has asked me to build and install a custom shelving system. I'm at the point where I need to nail it, but I'm not sure what to use to pound the nails in. Should I use an old shoe or a glass bottle?"
How would you answer the question?
It depends. If you are looking to pound a small (20lb) nail in something like drywall, you'll find it much easier to use the bottle, especially if the shoe is dirty. However, if you are trying to drive a heavy nail into some wood, go with the shoe: the bottle with shatter in your hand.
There is something fundamentally wrong with the way you are building; you need to use real tools. Yes, it may involve a trip to the toolbox (or even to the hardware store), but doing it the right way is going to save a lot of time, money, and aggravation through the lifecycle of your product. You need to stop building things for money until you understand the basics of construction.
This is such a question where most people sees it as a challenge to come up with the correct regular expression to solve the problem, but it would be much better to just say that using regular expressions are using the wrong tool for the job.
The problem when trying to use regex to validate numeric ranges is that it is hard to change if the requirements for the allowed range is changes. Today the requirement may be to validate numbers between 0 and 100 and it is possible to write a regex for that which doesn't make your eyes bleed. But next week the requirment maybe changes so values between 0 and 315 are allowed. Good luck altering your regex.
The solution given by Greg Hewgill is probably better - even though it would validate "99fxx" as "99". But given the circumstances that might actually be ok.
Given that your value is in str
str.match(/^(100(\.0{1,2})?|([0-9]?[0-9](\.[0-9]{1,2})))$/)
^100(\.(0){0,2})?$|^([1-9]?[0-9])(\.(\d{0,2}))?\%$
This would match:
100.00
optional "1-9" followed by a digit (this makes the int part), optionally followed by a dot and two digits
From what I see, Greg Hewgill's example doesn't really work that well because parseFloat('15x') would simply return 15 which would match the 0<x<100 condition. Using parseFloat is clearly wrong because it doesn't validate the percentage value, it tries to force a validation. Some people around here are complaining about leading zeroes and some are ignoring trailing invalid characters. Maybe the author of the question should edit it and make clear what he needs.
I recomend this, if you are not exclusively developing for english speaking users:
[0-9]{1,2}((,|\.)[0-9]{1,10})?%?
You can simply replace the 10 by a 2 to get two decimal places.
My example will match:
15.5
5.4366%
1,43
50,55%
34
45%
Of cause the output of this one is harder to cast, but something like this will do (Java Code):
private static Double getMyVal(String myVal) {
if (myVal.contains("%")) {
myVal = myVal.replace("%", "");
}
if (myVal.contains(",")) {
myVal = myVal.replace(',', '.');
}
return Double.valueOf(myVal);
}
None of the above solutions worked for me, as I needed my regex to allow for values with numbers and a decimal while the user is typing ex: '18.'
This solution allows for an empty string so the user can delete their entire input, and accounts for the other rules articulated above.
/(^$)|(^100(\.0{1,2})?$)|(^([1-9]([0-9])?|0)\.(\.[0-9]{1,2})?$)|(^([1-9]([0-9])?|0)(\.[0-9]{1,2})?$)/
(100|[0-9]{1,2})(\.[0-9]{1,2})?
That should be the regex you want. I suggest you to read Mastering Regular Expression and download RegexBuddy or The Regex Coach.
#mlarsen:
Is not that a regex here won't do the job better.
Remember that validation msut be done both on client and on server side, so something like:
100|(([1-9][0-9])|[0-9])(\.(([0-9][1-9])|[1-9]))?
would be a cross-language check, just beware of checking the input length with the output match length.
(100(\.(0){1,2})?|([1-9]{1}|[0-9]{2})(\.[0-9]{1,2})?)