PHP $_POST not working with jquery - javascript

i am using this jquery code:
<script type="text/javascript">
$(document).ready(function () {
$("#message").hide();
$("#please_wait_box").hide();
$("#editcustomer").submit(function (e) {
$("#message").hide();
$("#please_wait_box").show();
e.preventDefault();
dataString = $("#editcustomer").serialize();
$.ajax({
type: "POST",
url: "editcustomer_go.php",
cache: false,
data: dataString,
success: function (res) {
$("#please_wait_box").hide();
$("#message").html(res);
$('#message').fadeIn('slow');
if (res.indexOf("success") != -1) {
window.location.href = res.substr(8);
}
}
});
});
});
</script>
to submit forms without changing the page.
then the editcustomer_go.php echoed results display in:
<div id="message" class="messagebox"></div>
<div id="please_wait_box" class="messagebox">Please Wait...</div>
i am using tinymce for text editors - its working okay but when the data is posted in the PHP, its not seeing the changed data in the tinymce text editor - it has to be plain text.
how can i get round this?

To grab the data from TinyMCE you need to use their getContent() function.
So in your case it'd be
// Grab a reference to the editor
var ed = tinyMCE.get('tinymceeditorname');
// Get it's content
var editordata= ed.getContent();
... and then just pass editordata along with the rest of the form as the AJAX call data.

Related

Submit form array fields using Ajax [duplicate]

I have a form with name orderproductForm and an undefined number of inputs.
I want to do some kind of jQuery.get or ajax or anything like that that would call a page through Ajax, and send along all the inputs of the form orderproductForm.
I suppose one way would be to do something like
jQuery.get("myurl",
{action : document.orderproductForm.action.value,
cartproductid : document.orderproductForm.cartproductid.value,
productid : document.orderproductForm.productid.value,
...
However I do not know exactly all the form inputs. Is there a feature, function or something that would just send ALL the form inputs?
This is a simple reference:
// this is the id of the form
$("#idForm").submit(function(e) {
e.preventDefault(); // avoid to execute the actual submit of the form.
var form = $(this);
var actionUrl = form.attr('action');
$.ajax({
type: "POST",
url: actionUrl,
data: form.serialize(), // serializes the form's elements.
success: function(data)
{
alert(data); // show response from the php script.
}
});
});
You can use the ajaxForm/ajaxSubmit functions from Ajax Form Plugin or the jQuery serialize function.
AjaxForm:
$("#theForm").ajaxForm({url: 'server.php', type: 'post'})
or
$("#theForm").ajaxSubmit({url: 'server.php', type: 'post'})
ajaxForm will send when the submit button is pressed. ajaxSubmit sends immediately.
Serialize:
$.get('server.php?' + $('#theForm').serialize())
$.post('server.php', $('#theForm').serialize())
AJAX serialization documentation is here.
Another similar solution using attributes defined on the form element:
<form id="contactForm1" action="/your_url" method="post">
<!-- Form input fields here (do not forget your name attributes). -->
</form>
<script type="text/javascript">
var frm = $('#contactForm1');
frm.submit(function (e) {
e.preventDefault();
$.ajax({
type: frm.attr('method'),
url: frm.attr('action'),
data: frm.serialize(),
success: function (data) {
console.log('Submission was successful.');
console.log(data);
},
error: function (data) {
console.log('An error occurred.');
console.log(data);
},
});
});
</script>
There are a few things you need to bear in mind.
1. There are several ways to submit a form
using the submit button
by pressing enter
by triggering a submit event in JavaScript
possibly more depending on the device or future device.
We should therefore bind to the form submit event, not the button click event. This will ensure our code works on all devices and assistive technologies now and in the future.
2. Hijax
The user may not have JavaScript enabled. A hijax pattern is good here, where we gently take control of the form using JavaScript, but leave it submittable if JavaScript fails.
We should pull the URL and method from the form, so if the HTML changes, we don't need to update the JavaScript.
3. Unobtrusive JavaScript
Using event.preventDefault() instead of return false is good practice as it allows the event to bubble up. This lets other scripts tie into the event, for example analytics scripts which may be monitoring user interactions.
Speed
We should ideally use an external script, rather than inserting our script inline. We can link to this in the head section of the page using a script tag, or link to it at the bottom of the page for speed. The script should quietly enhance the user experience, not get in the way.
Code
Assuming you agree with all the above, and you want to catch the submit event, and handle it via AJAX (a hijax pattern), you could do something like this:
$(function() {
$('form.my_form').submit(function(event) {
event.preventDefault(); // Prevent the form from submitting via the browser
var form = $(this);
$.ajax({
type: form.attr('method'),
url: form.attr('action'),
data: form.serialize()
}).done(function(data) {
// Optionally alert the user of success here...
}).fail(function(data) {
// Optionally alert the user of an error here...
});
});
});
You can manually trigger a form submission whenever you like via JavaScript using something like:
$(function() {
$('form.my_form').trigger('submit');
});
Edit:
I recently had to do this and ended up writing a plugin.
(function($) {
$.fn.autosubmit = function() {
this.submit(function(event) {
event.preventDefault();
var form = $(this);
$.ajax({
type: form.attr('method'),
url: form.attr('action'),
data: form.serialize()
}).done(function(data) {
// Optionally alert the user of success here...
}).fail(function(data) {
// Optionally alert the user of an error here...
});
});
return this;
}
})(jQuery)
Add a data-autosubmit attribute to your form tag and you can then do this:
HTML
<form action="/blah" method="post" data-autosubmit>
<!-- Form goes here -->
</form>
JS
$(function() {
$('form[data-autosubmit]').autosubmit();
});
You can also use FormData (But not available in IE):
var formData = new FormData(document.getElementsByName('yourForm')[0]);// yourForm: form selector
$.ajax({
type: "POST",
url: "yourURL",// where you wanna post
data: formData,
processData: false,
contentType: false,
error: function(jqXHR, textStatus, errorMessage) {
console.log(errorMessage); // Optional
},
success: function(data) {console.log(data)}
});
This is how you use FormData.
Simple version (does not send images)
<form action="/my/ajax/url" class="my-form">
...
</form>
<script>
(function($){
$("body").on("submit", ".my-form", function(e){
e.preventDefault();
var form = $(e.target);
$.post( form.attr("action"), form.serialize(), function(res){
console.log(res);
});
});
)(jQuery);
</script>
Copy and paste ajaxification of a form or all forms on a page
It is a modified version of Alfrekjv's answer
It will work with jQuery >= 1.3.2
You can run this before the document is ready
You can remove and re-add the form and it will still work
It will post to the same location as the normal form, specified in
the form's "action" attribute
JavaScript
jQuery(document).submit(function(e){
var form = jQuery(e.target);
if(form.is("#form-id")){ // check if this is the form that you want (delete this check to apply this to all forms)
e.preventDefault();
jQuery.ajax({
type: "POST",
url: form.attr("action"),
data: form.serialize(), // serializes the form's elements.
success: function(data) {
console.log(data); // show response from the php script. (use the developer toolbar console, firefox firebug or chrome inspector console)
}
});
}
});
I wanted to edit Alfrekjv's answer but deviated too much from it so decided to post this as a separate answer.
Does not send files, does not support buttons, for example clicking a button (including a submit button) sends its value as form data, but because this is an ajax request the button click will not be sent.
To support buttons you can capture the actual button click instead of the submit.
jQuery(document).click(function(e){
var self = jQuery(e.target);
if(self.is("#form-id input[type=submit], #form-id input[type=button], #form-id button")){
e.preventDefault();
var form = self.closest('form'), formdata = form.serialize();
//add the clicked button to the form data
if(self.attr('name')){
formdata += (formdata!=='')? '&':'';
formdata += self.attr('name') + '=' + ((self.is('button'))? self.html(): self.val());
}
jQuery.ajax({
type: "POST",
url: form.attr("action"),
data: formdata,
success: function(data) {
console.log(data);
}
});
}
});
On the server side you can detect an ajax request with this header that jquery sets HTTP_X_REQUESTED_WITH
for php
PHP
if(!empty($_SERVER['HTTP_X_REQUESTED_WITH']) && strtolower($_SERVER['HTTP_X_REQUESTED_WITH']) == 'xmlhttprequest') {
//is ajax
}
This code works even with file input
$(document).on("submit", "form", function(event)
{
event.preventDefault();
$.ajax({
url: $(this).attr("action"),
type: $(this).attr("method"),
dataType: "JSON",
data: new FormData(this),
processData: false,
contentType: false,
success: function (data, status)
{
},
error: function (xhr, desc, err)
{
}
});
});
I really liked this answer by superluminary and especially the way he wrapped is solution in a jQuery plugin. So thanks to superluminary for a very useful answer. In my case, though, I wanted a plugin that would allow me to define the success and error event handlers by means of options when the plugin is initialized.
So here is what I came up with:
;(function(defaults, $, undefined) {
var getSubmitHandler = function(onsubmit, success, error) {
return function(event) {
if (typeof onsubmit === 'function') {
onsubmit.call(this, event);
}
var form = $(this);
$.ajax({
type: form.attr('method'),
url: form.attr('action'),
data: form.serialize()
}).done(function() {
if (typeof success === 'function') {
success.apply(this, arguments);
}
}).fail(function() {
if (typeof error === 'function') {
error.apply(this, arguments);
}
});
event.preventDefault();
};
};
$.fn.extend({
// Usage:
// jQuery(selector).ajaxForm({
// onsubmit:function() {},
// success:function() {},
// error: function() {}
// });
ajaxForm : function(options) {
options = $.extend({}, defaults, options);
return $(this).each(function() {
$(this).submit(getSubmitHandler(options['onsubmit'], options['success'], options['error']));
});
}
});
})({}, jQuery);
This plugin allows me to very easily "ajaxify" html forms on the page and provide onsubmit, success and error event handlers for implementing feedback to the user of the status of the form submit. This allowed the plugin to be used as follows:
$('form').ajaxForm({
onsubmit: function(event) {
// User submitted the form
},
success: function(data, textStatus, jqXHR) {
// The form was successfully submitted
},
error: function(jqXHR, textStatus, errorThrown) {
// The submit action failed
}
});
Note that the success and error event handlers receive the same arguments that you would receive from the corresponding events of the jQuery ajax method.
I got the following for me:
formSubmit('#login-form', '/api/user/login', '/members/');
where
function formSubmit(form, url, target) {
$(form).submit(function(event) {
$.post(url, $(form).serialize())
.done(function(res) {
if (res.success) {
window.location = target;
}
else {
alert(res.error);
}
})
.fail(function(res) {
alert("Server Error: " + res.status + " " + res.statusText);
})
event.preventDefault();
});
}
This assumes the post to 'url' returns an ajax in the form of {success: false, error:'my Error to display'}
You can vary this as you like. Feel free to use that snippet.
jQuery AJAX submit form, is nothing but submit a form using form ID when you click on a button
Please follow steps
Step 1 - Form tag must have an ID field
<form method="post" class="form-horizontal" action="test/user/add" id="submitForm">
.....
</form>
Button which you are going to click
<button>Save</button>
Step 2 - submit event is in jQuery which helps to submit a form. in below code we are preparing JSON request from HTML element name.
$("#submitForm").submit(function(e) {
e.preventDefault();
var frm = $("#submitForm");
var data = {};
$.each(this, function(i, v){
var input = $(v);
data[input.attr("name")] = input.val();
delete data["undefined"];
});
$.ajax({
contentType:"application/json; charset=utf-8",
type:frm.attr("method"),
url:frm.attr("action"),
dataType:'json',
data:JSON.stringify(data),
success:function(data) {
alert(data.message);
}
});
});
for live demo click on below link
How to submit a Form using jQuery AJAX?
I know this is a jQuery related question, but now days with JS ES6 things are much easier. Since there is no pure javascript answer, I thought I could add a simple pure javascript solution to this, which in my opinion is much cleaner, by using the fetch() API. This a modern way to implements network requests. In your case, since you already have a form element we can simply use it to build our request.
const form = document.forms["orderproductForm"];
const formInputs = form.getElementsByTagName("input");
let formData = new FormData();
for (let input of formInputs) {
formData.append(input.name, input.value);
}
fetch(form.action,
{
method: form.method,
body: formData
})
.then(response => response.json())
.then(data => console.log(data))
.catch(error => console.log(error.message))
.finally(() => console.log("Done"));
Try
fetch(form.action,{method:'post', body: new FormData(form)});
function send(e,form) {
fetch(form.action,{method:'post', body: new FormData(form)});
console.log('We submit form asynchronously (AJAX)');
e.preventDefault();
}
<form method="POST" action="myapi/send" onsubmit="send(event,this)" name="orderproductForm">
<input hidden name="csrfToken" value="$0meh#$h">
<input name="email" value="aa#bb.com">
<input name="phone" value="123-456-666">
<input type="submit">
</form>
Look on Chrome Console > Network after/before 'submit'
consider using closest
$('table+table form').closest('tr').filter(':not(:last-child)').submit(function (ev, frm) {
frm = $(ev.target).closest('form');
$.ajax({
type: frm.attr('method'),
url: frm.attr('action'),
data: frm.serialize(),
success: function (data) {
alert(data);
}
})
ev.preventDefault();
});
You may use this on submit function like below.
HTML Form
<form class="form" action="" method="post">
<input type="text" name="name" id="name" >
<textarea name="text" id="message" placeholder="Write something to us"> </textarea>
<input type="button" onclick="return formSubmit();" value="Send">
</form>
jQuery function:
<script>
function formSubmit(){
var name = document.getElementById("name").value;
var message = document.getElementById("message").value;
var dataString = 'name='+ name + '&message=' + message;
jQuery.ajax({
url: "submit.php",
data: dataString,
type: "POST",
success: function(data){
$("#myForm").html(data);
},
error: function (){}
});
return true;
}
</script>
For more details and sample Visit:
http://www.spiderscode.com/simple-ajax-contact-form/
To avoid multiple formdata sends:
Don't forget to unbind submit event, before the form submited again,
User can call sumbit function more than one time, maybe he forgot something, or was a validation error.
$("#idForm").unbind().submit( function(e) {
....
If you're using form.serialize() - you need to give each form element a name like this:
<input id="firstName" name="firstName" ...
And the form gets serialized like this:
firstName=Chris&lastName=Halcrow ...
I find it surprising that no one mentions data as an object. For me it's the cleanest and easiest way to pass data:
$('form#foo').submit(function () {
$.ajax({
url: 'http://foo.bar/some-ajax-script',
type: 'POST',
dataType: 'json',
data: {
'foo': 'some-foo-value',
'bar': $('#bar').val()
}
}).always(function (response) {
console.log(response);
});
return false;
});
Then, in the backend:
// Example in PHP
$_POST['foo'] // some-foo-value
$_POST['bar'] // value in #bar
This is not the answer to OP's question,
but in case if you can't use static form DOM, you can also try like this.
var $form = $('<form/>').append(
$('<input/>', {name: 'username'}).val('John Doe'),
$('<input/>', {name: 'user_id'}).val('john.1234')
);
$.ajax({
url: 'api/user/search',
type: 'POST',
contentType: 'application/x-www-form-urlencoded',
data: $form.serialize(),
success: function(data, textStatus, jqXHR) {
console.info(data);
},
error: function(jqXHR, textStatus, errorThrown) {
var errorMessage = jqXHR.responseText;
if (errorMessage.length > 0) {
alert(errorMessage);
}
}
});
JavaScript
(function ($) {
var form= $('#add-form'),
input = $('#exampleFormControlTextarea1');
form.submit(function(event) {
event.preventDefault();
var req = $.ajax({
url: form.attr('action'),
type: 'POST',
data: form.serialize()
});
req.done(function(data) {
if (data === 'success') {
var li = $('<li class="list-group-item">'+ input.val() +'</li>');
li.hide()
.appendTo('.list-group')
.fadeIn();
$('input[type="text"],textarea').val('');
}
});
});
}(jQuery));
HTML
<ul class="list-group col-sm-6 float-left">
<?php
foreach ($data as $item) {
echo '<li class="list-group-item">'.$item.'</li>';
}
?>
</ul>
<form id="add-form" class="col-sm-6 float-right" action="_inc/add-new.php" method="post">
<p class="form-group">
<textarea class="form-control" name="message" id="exampleFormControlTextarea1" rows="3" placeholder="Is there something new?"></textarea>
</p>
<button type="submit" class="btn btn-danger">Add new item</button>
</form>
There's also the submit event, which can be triggered like this $("#form_id").submit(). You'd use this method if the form is well represented in HTML already. You'd just read in the page, populate the form inputs with stuff, then call .submit(). It'll use the method and action defined in the form's declaration, so you don't need to copy it into your javascript.
examples

CkEditor conflict with jquery form

I am using CKEditor and trying to submit my form with jquery but I have a conflict
Jquery
$(document).ready(function (e) {
$("#form").on('submit',(function(e) {
e.preventDefault();
console.log(new FormData(this))
$('.loading-container').show();
$.ajax({
url: "store-course-teacher",
type: "POST",
data: new FormData(this),
contentType: false,
cache: false,
processData:false,
success: function(data)
{
$('.loading-container').hide()
if(data.status == 'done')
{
$('#form').hide();
$('#add-section').show();
$('#course-title').html($('#title').val());
$('.course-id').val(data.course_id)
}
}
});
}));
});
and from my controller I dumped the result and all text area with ckeditor is NULL
I am trying to be clear as possible but that's all I got
I believe with ckeditor, you have to get the HTML from the text editor like this:
var data = CKEDITOR.instances.editor1.getData();
So before calling your ajax, perhaps set data to a hidden input in your form so that your new FormData(this) remains intact?
var data = CKEDITOR.instances.editor1.getData();
$('#MyHiddenInput').val(data);
More info here
best way to send ckEditor with the from was updating the ckEditor instanes
for (instance in CKEDITOR.instances) {
CKEDITOR.instances[instance].updateElement();
}
I found the solution here

How to pass form input field value to external page using jquery

I have a form where I would like to pass the value of an text input field to an external page without a form submit event. I would like to field value to become a php variable on the external page.
Here is what I have so far:
<script type="text/javascript">
jQuery(document).ready(function() {
$(function() {
cityField = $('#the_form input[id=city]');
$.ajax({
type: "POST",
url: "external.php",
data:{ city: cityfield },
success: function(data){
console.log(data);
}
});
});
});
</script>
Within the external.php page, I would like to declare the city form field value as a php variable as
$city = $_POST['city'];
To start with
jQuery(document).ready(function() {
and
$(function() {
are equivalent. The $(function() should be something like
$("input[type='button']").click(function() {
so that when you click the button, it runs the ajax request.
I cleaned up the code but the data is not being sent to external.php. It is being set but not posting. Here is my revised code
<script type="text/javascript">
$('#city').blur(function() {
var cityField = document.querySelector('#city').value;
$.ajax({
type: "post",
url: "external.php",
data: {'cityField': cityField },
dataType: "text",
success: function(data, status){
if(status=="success") {
alert("You typed: " + cityField);
}
}
});
});
I dont feel right posting an answer for a single change... But
EDIT: There are actually a few things...
<!-- For .click() -->
Click Me!
<script type="text/javascript">
// $(function() { // Trigger on page load
// $('#doStuff').click(function() { // Trigger on a click
$('#city').blur(function() { // Trigger when the focus on the field is lost (click away, tab to another field, ect)
// $('#city').change(function() { // Trigger when the fields value changes
var cityField = $('#city');
$.ajax({
type: "POST",
url: "external.php",
data:{ 'city': cityField.val() },
success: function(data){
console.log(data);
}
});
});
</script>
Changes:
You dont need jQuery(document).ready(function() {}) AND $(function(){ }). Its the same thing.
Its smart to put a var in front on your variables.
Case is important. cityField and cityfield are not the same thing
You were just sending the whole dom element to your external script. (which I assume you only wanted the contents of the input)
Also, you dont need to look for "an input, with an 'id' attribute , with a value of 'city'". Just look for #city
EDIT:
Your updated code (just putting it here so its easier to see):
<script type="text/javascript">
$('#city').blur(function() {
var cityField=$('#city').val();
$.ajax({
type:"post",
url:"autosuggest.php",
data:{'cityField':cityField },
dataType:"text",
complete:function(data, status) {
alert("You typed: "+cityField);
}
});
});
</script>
Your data will should be available in autosuggest.php as $_POST['cityField'];
Having a status check within the success function, is a little redundant, in my opinion.
It would be better to move the success:function(data,... to a complete:function(data,...

showing velue from php file in div in html file

Basicly, In my html I have a form that consists of 2 selects and 2 text inputs. I would like to send values from that form into a php file called solve.php. This file will produce a variable called $cenaCelkom. I want to show the value of that variable in one of my divs.
I have to send tvalues from my form without redirecting to the solve.php. I have this for sending values to my php, but I cant find out if it works.
<script type="text/javascript">
$(document).ready( function () {
$('form').submit( function () {
var formdata = $(this).serialize();
$.ajax({
type: "POST",
url: "solve.php",
data: formdata
});
return false;
});
});
If this is ok, I would like to know how to get the value from my php after executing it. BTW: I am not an experienced js or jquery programmer, so please go easy on me :)
Thank you.
<div id="myresult"><div>
<script type="text/javascript">
$(document).ready( function () {
$('form').submit( function (e) {
e.preventDefault();
var formdata = $(this).serialize();
$.post('solve.php', $(this).serialize(), function(result){
$('#myresult').html(result);
});
});
});
You can grab the values of the inputs by using $_POST['inputnamehere'] from your solve.php page.
You can use $.load() method in jQuery
<script type="text/javascript">
$(document).ready( function () {
$('form').submit( function () {
$( "#yourDivId" ).load(
'solve.php',
$('form').serialize(),
complete(responseText, textStatus, XMLHttpRequest){
//do whatever after ajax operation
}))
return false;
});
});
</script>
On solve.php simply get the values via $_GET and use print() for output:
<?php
print( $_GET['val1'] + $_GET['val2']) // Show a summation of two numbers
?>

jquery ajax form submit

Is this code correct? I'm trying to submit it and also I would like on submit if text area would be empty again.
<script type="text/javascript">
$(document).ready(function(){
$("form#submit").submit(function() {
// we want to store the values from the form input box, then send via ajax below
var fid = $(".messag").attr("id");
var val = $("#mess_ar").val();
$.ajax({
type: "POST",
url: "send_message.php",
data: "fid="+ fid +"&val="+ val,
success: function(){
$("#mess_ar").
}
});
return false;
});
}):
</script>
I'm trying to upload this:
<form id="submit" method="POST">
<textarea name="mess_cont" id="mess_ar" autofocus="autofocus" cols="70" rows="5"> </textarea>
<button id="mess_but" type="submit">Send</button>
</form>
Thankx...
Looks good. To empty the textarea use the following in the ajax success callback:
$("#mess_ar").val('');
​$(function(){
$("form#submit").submit(function(e){
e.preventDefault();
var fid = $(".messag").attr("id");
var val = $("#mess_ar").val();
$.ajax({
type: "POST",
url: "send_message.php",
data: "fid="+ fid +"&val="+ val,
success: function(){
$("#mess_ar").val("");
}
});
});
});​
Use
$("#submit").on('submit', function(e){...});
instead of
$("#submit").submit(function(e){...});
if you are using latest version of jquery.
What are you actually looking for? Does it return the data in response too? Add the functions to track your the error case too. Make something like
<script type="text/javascript">
$(document).ready(function(){
$("form#submit").submit(function() {
// we want to store the values from the form input box, then send via ajax below
var fid = $(".messag").attr("id");
var val = $("#mess_ar").val();
$.ajax({
type: "POST",
url: "send_message.php",
data: "fid="+ fid +"&val="+ val,
success: function(incoming_data){
// ALERT incoming data if coming
$("#mess_ar").text(""); // DO YOUR JOB CONTINUOU
},
error: function() {
alert("BROKEN REQUEST.");
}
});
return false;
});
});
</script>
Else, seems all fine.

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