How to retain the state of input radio button after page refresh - javascript

I have a form on which there are 20 radio buttons. I need to store the state of the radio buttons if there are errors on the page(whereby page would refresh). I managed to get it working 50%. However, if i select different radio buttons on the second refresh, it would still retain the sate of the first submit.
Here is my code:
var x= $("input[id^='question-']");
$(x).click(function(){
localStorage['radios'] = this.checked;
});
$(x).prop('checked', localStorage['radios'] == 'true');
Any help would much be appreciated!

I think the unique form of getting the values after refreshing the page is send the information with POST or GET, after sending the form. It's recomendable using PHP script to process the form, and make validations.
If you have any doubt, you can see here how to catch information of the forms

Your code looks like its just overwriting the same value again and again regardless of what input it's for, and also should use the change event rather than click. Try something like (untested):
var $x = $("input[id^='question-']");
// Set localstorage on change event per radio button
$x.on('change', function(){
localStorage[$(this).attr('name')] = this.checked;
});
// Check all radio buttons on page load against localStorage
$x.each(function(){
$(this).prop('checked', localStorage[$(this).attr('name')] == 'true');
}

Related

Avoid multiple form submit in html

I'm facing a sort of dummy problem.
On my site there is an order form (simple html form) and I noticed that I get double commands from time to time.
I realized that if I clicked repeatedly few times the submit button (before the action page is loaded) I got as many commands as I have clicked.
So I wonder if there are simple solution to make form submission asyncronous?
Thanks
P.S. I added JQuery UI dialog on submit "wait please..." but I get still double commands.
UPDATE
As GeoffAtkins proposed I will:
disable submit after dialog is shown
make use of unique form's token (as it is already added by Symfony) Do not use Symfony token as unique form token as it is always the same for current session. Use just random or something like that.
I would consider doing this (jQuery since you said you used that)
$(function() {
$("#formId").on("submit",function() {
$("#submitBut").hide();
$("#pleaseWait").show();
});
});
if you submit the form and reload the page.
If you Ajax the order, then do
$(function() {
$("#formId").on("submit",function(e) {
e.preventDefault();
var $theForm = $(this);
$("#submitBut").hide();
$("#pleaseWait").show();
$.post($(this).attr("action"),$(this).serialize(),function() {
$theForm.reset();
$("#submitBut").show(); // assuming you want the user to order more stuff
$("#pleaseWait").hide();
});
});
});
NOTE that disabling the submit button on click of the submit button may stop the submission all together (at least in Chrome): https://jsfiddle.net/mplungjan/xc6uc46m/
Just disable the button on click, something like:
$("#my-button-id").on("click", function() {
$(this).attr("disabled", "disabled");
});
var bool = true;
function onclick()
{
if(bool)
{
//do stuff
bool = false;
}
else
{
//ignore
}
}
You could disable the button on the form when it is clicked, and then continue to perform the action. You would probably change the text to say "loading..." or some such.
You may also want to re-enable the button on fail or complete of the ajax request.
I've done this many times similar to this: https://stackoverflow.com/a/19220576/89211

jQuery disable double click prevention breaking functionality of a PHP function in a form

I have a jquery bug that I cant solve - hoping for help with a solution. Dont know if it is browser bug related (probably not), jQuery related, or Yii (our backend) related - but I need to try to solve it with the jQuery portion. Code at bottom of message.
Requirement: Disable accidental double submissions on forms.
Current Solution: Check for form submission state through a delegate and when the DOM form state changes to submit - append the disable attribute to the form submit button to prevent accident double form submission.
jQuery double click disabler:
$( document ).ready(function() {
$('html').delegate('form', 'submit', function() {
$(this).find(':submit').attr('disabled', true);
});
});
Problem: This works perfectly on every part of the CRM we are developing EXCEPT for a single timekeeper (clock in/clock out) feature. With the timekeeper the form has two submit buttons (one for clock in, one for clock out). Only one submit button shows at a time (Either "In" or "Out". When you click the button - it submits the form and changes the submit button to the other state by checking a session var to determine what state it is in and determines which of the two submit buttons are to be displayed. Problem is if you click it, the form appears to submit, but the state don't change. If you click it really fast a few times you can get it to change state. I suspect this is a timing or order of operations issue, but I have no idea how to fix it. The fix MUST be done on the front end, so here is the code (both the PHP being impacted and jQuery double click prevention). Perhaps a different method of disabling double submissions may work, please post your solution if you have one to try. Commenting out the current jQuery allows the form to function as designed. What might be causing this, and how might I change the jQuery double click prevention to solve it?
On page PHP for the time clock:
<form action = "<?=$clockUrl?>" method = "post" >
<input type = "hidden" name = "previousUrl" value = "<?=$currentUrl?>">
<?php if ($sessionVar->timeclockin) {?>
<input type = "submit" name = "submit-clockout" value = "Out">
<class="clock-time" ><?=$sessionVar->timeclockin?></class="clock-time">
<?php } else {?>
<input type = "submit" name = "submit-clockin" value = "In">
<?php }?>
</form>
Thank you for pointing me in the right direction Tyler! I was able to fix the issue with the following alteration to my script.
function do_nothing() {
console.log("click prevented");
return false;
}
$('html').delegate('form', 'submit', function(e) {
$(e.target).find(':submit').click(do_nothing);
setTimeout(function(){
$(e.target).unbind('click', do_nothing);
}, 10000);
});
Update 1:
If you are looking to prevent the button from being pressed twice then inside of your onclick or submit function, you should use something similar to the following:
$('#yourButton').prop('disabled', true);
If the page then redirects then you won't have to undo this. If it does, then do the opposite by changing true to false.
The submit function should instead disable the submit button until it either returns or fails.
An alternative is to use a lambda style function and replace it temporarily with an empty function until the request returns or fails.

Disable Submit button after clicking once with validation in Magento

I need to disable or place a loading image over the form once the submit has been validated. Either one works for me. I have found numerous ways to disable the submit button after you click once, but this does not take in account for validation errors.
I've tried to look this up in many different ways but I can't seem to find something that works.
I am using the default prototype form Magento uses on my current form.
This is what I currently have:
var contactForm = new VarienForm('productcontactForm', true);
contactForm.submit = function(){
if (this.validator.validate()) {
$('#productcontactForm').submit(function(){
$('input[type=submit]', this).attr('enabled', 'enabled');
});
} else {
$('#productcontactForm').submit(function(){
$('input[type=submit]', this).attr('disabled', 'disabled');
});
}
}.bind(contactForm);
I'm sorry, I don't run Magento, but I do see a problem. There is no such thing as an 'enabled' attribute in html, javascript or jquery. To enable an input use:
<..selector..>.removeAttr('disabled');
So to disable an input you add the 'disabled' attribute and to enable it again you remove that attribute.

Disable button on form submission but post button value

I want to prevent multiple form submissions, but I need to have the value of the submit element posted back to the server (so that I know which button the user clicked on).
Most of the Internet Wisdom concerning suppression of multiple form submissions seems to involve disabling the submit button during form submission. This prevents the button from being clicked a second time, but also prevents its value from being posted.
I've found a few examples of JS code that hides the submit button(s), which allows their values to be posted. But those examples all replace the (now hidden) button with some sort of "processing..." message. I really want a solution that presents the user with a disabled button but still posts the button value.
I should add that I'd prefer a solution that works with standard HTML one would find in most forms. No magic IFrames, hidden fields, id or class names, etc. I want a JS function I can stash away in a library and reference from all of my existing forms to enable this new behavior.
(I have a solution, which I will post as an answer. But I had to ask the question to comply with the Zen of SO.)
Here is (yet another) answer to the question of how to deal with preventing the user from clicking on the form submission button more than once. This solution makes it appear that the button has been disabled.
Under the covers, it creates a disabled button to display to the user, and hides the actual button so that its value is posted. I also move the hidden button so that the extra element doesn't mess up CSS selectors.
Also note the check for invalid form fields. If you omit this check, and form validation fails, then the user winds up with a form that wasn't posted (because client-side validation failed) but the buttons are disabled.
// Disables buttons when form is submitted
$('form').submit(function () {
// Bail out if the form contains validation errors
if ($.validator && !$(this).valid()) return;
var form = $(this);
$(this).find('input[type="submit"], button[type="submit"]').each(function (index) {
// Create a disabled clone of the submit button
$(this).clone(false).removeAttr('id').prop('disabled', true).insertBefore($(this));
// Hide the actual submit button and move it to the beginning of the form
$(this).hide();
form.prepend($(this));
});
});
Because you can submit a form other ways than simply clicking the submit button it's better to add a listener to the form's submit event rather than the click event on the submit button. This jQuery event listener should work on any form and prevent it from being submitted more than once.
$('form').on('submit', function(e) {
if (!$(this).data('submitted')) {
$(this).data('submitted', true);
}
else {
e.preventDefault();
}
});
To make the form look disabled you could add some css that makes the form look disabled and then add the classname on form submission.
$('form').on('submit', function(e) {
if (!$(this).data('submitted')) {
$(this).data('submitted', true).addClass('disabled');
}
else {
e.preventDefault();
}
});
I wanted to stop the user from causing multiple form submissions by double clicking the submit button or hitting the enter key twice. I like this solution, because it doesn't require a hidden form field or hiding the submit button.
The two key points are:
Return true/false instead of using e.preventDefault() and form.submit(), because form.submit() doesn't know which button was clicked and therefore, can't pass the button name/value.
Disable the button with pointer-events: none; instead of disabled="disabled", because the disabled attribute won't send the button name/value. I believe pointer-events: none; is not supported by Internet Explorer 10 or below.
javascript/jquery code:
var form_selector = 'form',
button_selector = 'button, input[type=submit], input[type=button], input[type=reset]',
deactivated_classname = 'state-submitting',
deactivated_class = '.'+'state-submitting';
// Capture the submit event so it will handle both the
// enter key and clicking the submit button.
$(document).on('submit', form_selector, function(e) {
var form = e.target,
buttons = $( form ).find( button_selector );
// Returns, because the form is already being submitted by a previous attempt.
if( $( form ).find( deactivated_class ).length > 0 ) return false;
disableButtons( buttons );
// Safari (version 11) bugfix: Safari needs a timeout or it won't
// show the deactivated styles.
setTimeout(function() {
// Must use return true, because using form.submit(), won't pass the button value.
return true;
}, 50 );
});
function disableButtons( buttons ) {
// Disables all buttons in the form.
$( buttons ).each(function( index, elem ) {
$( elem ).addClass( deactivated_classname );
});
}
For AJAX forms, you will want to re-enable the buttons after the response is returned.
$( document ).on( 'ajax:complete', form_selector, function(e) {
var form = e.target,
buttons = $( form ).find( button_selector );
enableButtons( buttons );
});
function enableButtons( buttons ) {
$( buttons ).each(function( index, elem ) {
$( elem ).removeClass( deactivated_classname );
});
}
CSS:
// The button is disabled while it is submitting.
.state-submitting {
// Turns off hover and click events. Not supported in IE 10 and below.
pointer-events: none;
opacity: 0.5;
}
You can simulate disabled look behavior. E.g. if you have a button like this:
<input id="btn" type="button" onclick="disableMe(this)" value="Submit" />
You can define CSS like this
.disabled {
backround-color:grey;
color:darkgrey;
}
And JS like this
function disableMe(btn) {
btn.className = "disabled";
btn.onclick = function(){return false}
}
What will happen - on first click button will become grey (via applied CSS) and onclick event will change to "return false" for all the consecutive calls preventing future click actions. The button will appear and act as disabled, but will not be, so it will not prevent button submission.
Here's a couple options:
1. You could create hidden inputs and dynamically change the value of it before the form is submitted either onClick or onHover of the said button:
2. You could create an hidden iframe which is the target of the said form. Once the submit button is click, you could cancel the submit event, grab all of the data and send it programatically through the iframe instead.
I was having the same issue as OP, and I found that disabling the submit button(s) after a short (maybe 0 seconds) timeout via setTimeout does the trick. The submit button's name value is still posted with the rest of the form data as desired, but the button disables itself (almost) immediately, preventing further clicks.
The timeout is a bit ugly, but it seems preferable to more elaborate swapping/covering schemes.
This could be combined with also altering the form's onsubmit property for extra precaution, but I'm not doing that in the example below for clarity's sake. Either way, I like the appearance/behavior of a disabled button after the first submission click… the user experience seems better to me… it's more clear what's happening.
My form element's start tag:
<form onsubmit="return formSubmit(this);" method="post" action="">
In my JavaScript (sorry, I'm not up-to-date with the latest JS tech like jQuery, etc, so I'm posting this in old-fashioned-native-JavaScript-5-with-no-dependencies-compatible code):
function formSubmit(form) {
// MUST DELAY so as not to break input/button[type=submit] name submission
setTimeout(function () {
var els = form.elements;
for (var i = 0; i < els.length; i++) {
var el = els[i];
if (el.getAttribute('type') == 'submit') {
el.setAttribute('disabled', 'disabled');
}
}
}, 0);
return true;
}
I think better solution would be to use JQuery :
<form onsubmit="$('#submit').hide();" method="post" action="">
No chance of double clicking.
Sometimes we use name field in submit button for validation so if this is disabled then that could failed.
Using .hide() the button will be hidden.
so no chance of double clicking it.
Be honest with you I was not able to understand fully most of the posts on this page, but I think I have faced this problem before, and solved it by allowing the page to post the first time the button is clicked, so when the page comes back from server it has the new value assigned to it, and it looks clickable, and enabled. But if a 2nd attempt is made to press it, then it becomes disabled, and page will not post, and send to the server again by clicking this button. I hope this helps:
#section scripts
{
<script type="text/javascript">
$('#edit').click(function () {
if (document.getElementById("edit").value == '') {
// This portion should execute onlythe
// first time button is clicked, and it
// will assign a new value to the button,
//and posts the value
//to the server
}
else {
edit.disabled = true;
}
});
</script>
}
A much much much simpler way is to enclose whatever code you use to disable the button in a setTimeout() with 0 delay. That way the button is still enabled in the thread that handles the form submission while another parallel thread is spawned to do the disabling.
Example (using jQuery):
<form method="POST" onsubmit="javascript:setTimeout(() => $('*[type=submit]', this).attr('disabled', 'disabled'), 0)">

Disable submit button after click to prevent users from sending multiple requests to server

I want to prevent users from clicking on a server button multiple times causing multiple similar requests to be sent to the server.
Buttons are ASP.Net buttons (Webforms). There are many pages on the website and I don't want to write some codes for every button. I want to do it on the Masterpage for all buttons.
A possible solution would be finding the button and disabling it after it has been clicked. like:
$("input[type='submit']").click(function(){
$(this).attr('disabled','disabled');
});
This code works fine but overrides the previous onclick event of the button. So the button doesn't do the submission or any other tasks that it wants to do.
Another solution is disabling all submit buttons on "onbeforesubmit" event. They will be enabled right after the postback. This is also not a good solution because there are some buttons that update part of the page by Ajax and they can not re-enable other buttons beyond the ajax panel after the postback.
Is there a way to find the clicked submit button and disable it and allow it to do it's onclick event?
I found the answer. Because I use asp.net server buttons, Page won't be submitted if I disable the button in client side onclick event. Instead I disable the button in the second click. In this case I can be sure that page has been submitted one time:
$("input[type='submit']").click(function (e) {
if (e.target && Page_IsValid) {
var attr = $(this).attr('submitting');
if (typeof attr !== 'undefined' && attr !== false) { // If button has submitting attribute then do not submit it again.
$(this).prop('disabled', true);
$(this).removeAttr("submitting");
e.preventDefault();
}
else {
$(this).attr("submitting", "true"); // Add "submitting" attribute to prevent multiple submissions.
}
}
});
Try to use .one():
Attach a handler to an event for the elements. The handler is executed
at most once per element per event type.
$("input[type='submit']").one('click',function(){
$(this).prop('disabled',true);
});
Also, you should use .prop() instead of .attr() to set the state of your input
Or what about this?
$("body").on("click", ".js-submit-button", function() {
var $this = $(this);
$this.prop("disabled", true);
$this.closest("form").submit();
});

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