Get parent div id of second javascript? [closed] - javascript

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I have a div which is like this:
<div id="mainDiv">
<script>
javascript here...
</script>
</div>
I basically want to get the ID of the div it is inside.
I have tried using jQuery and classic javascript to do this but it keeps returning undefined.
Does anyone have any idea's? Thanks

Since broswer read the code from up to down, you can do this:
Vanilla JS
var scriptTags = document.getElementsByTagName('script');
var id = scriptTags[scriptTags.length - 1].parentNode.id;
jQuery
var id = $('script').last().parent().prop('id');
when it will read this code, the last script tag is the one the browser is reading.
Here's a fiddle : http://jsfiddle.net/nb234/

Check this out http://jsfiddle.net/78N9A/1/
<div id="parent">
<script id="scr">
function show()
{
alert('hello');
}
</script>
</div>
window.onload = function(){
var ele = document.getElementById('scr').parentNode;
alert(ele.id);
}

<script id="script">
Then
$('#script').parent();

If I understand correctly, you are saying that the id on the parent div is unknown in advance, and you want to use JS to determine what it is.
If you can't edit the script tag to add an id, maybe you could do a document.write() within that block to add in a little hidden element, then you can test to see what that element's parent is.
http://jsfiddle.net/AtRYF/

JAVASCRIPT:
Give your script an ID and then use parentNode to move up the DOM.
var the_div_you_want = document.getElementById("skript").parentNode.id;
JQUERY:
Pretty sure .parent() is what you're after
$('#scriptId').parent().attr("id");
Regardless, you need to find some way to locate the script and the move up the dom to find that relationship. Hope this helps.
http://jsfiddle.net/Zbuf8/1/

jQuery(document).ready(function($) {
$('div').attr('id');
});
should get you the value you need.

Related

Get the height of a div using Javascript [closed]

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Closed 7 months ago.
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When I type
console.log(document.getElementById('kitHeight').offsetHeight);
It prints 30 on the console, which is wrong.
But, when I type the same using developer console, it gives me 65, this is correct.
The height of the div is 65px.
Kindly help me why this behaves like it does and how to get 65px as the correct answer using javascript
#CBroe already told you that the information you are offering is too little to help you.
But it might be the case, that you are trying to run the script before the DOM actually rendered the div. See this example:
<script>
console.log(document.getElementById("class").offsetHeight);
//Errors
</script>
<div id="class"></div>
<script>
console.log(document.getElementById("class").offsetHeight);
//Returns: 0
</script>
<script>
const i = document.getElementById("class");
i.innerHTML = "John Doe";
console.log(document.getElementById("class").offsetHeight);
//Return: 19
</script>
The second and third pieces of code will return the height. The first one will error because the div is not in the DOM yet. The third one will return an updated size from dynamic content.

How to get content of div without JavaScript script blocks [closed]

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I have the following HTML
<div id="example">
...some text...
<script type="text/javascript">
... some javascript...
</script>
</div>
How to get content of #example but also without the JavaScript tags or JavaScript code?
And to answer the general question, if you need to get the contents of a node with some of the children not included, you probably need to remove the tags you don't want in there, in your case the script tags.
If you need to keep the original intact, take a look at cloneNode (https://developer.mozilla.org/en-US/docs/Web/API/Node/cloneNode) on how to get a clone of the node that you can work on without touching the original.
If you just want to grab the text that's inside the id="example", you could just use:
var getExample = document.getElementById('example').innerHTML;
or with jQuery:
var $getExample = $('#example').html();
I'm assuming you just didn't want the JavaScript inside the id="example" div, being as you tagged this JavaScript. In that case you could create a JavaScript file and add it with
<script src="javascriptFileName.js"></script>
this would be placed at the bottom of the body.
With jquery you can try this way. See here http://jsfiddle.net/AnjJa/129/
var el = $('#example').clone();
el.find('script').remove();
alert(el.html());
But why you put the JS there?

style not showing up [closed]

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Closed 8 years ago.
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I am building an expandable grid portfolio but the styles for the .showcase <a> tag and <p> tag are not showing up. I am not sure why. I think it has something to do with .html() not grabbing the <a> and <p> selector but just the content inside it. Though this does not happen to the <img> tag. I am a little baffled. Here is my jsfiddle
http://jsfiddle.net/theMugician/L2xyatfd/38/
Hey everyone I figured out what my problem was. I was calling html() twice which makes a lot of sense now. In the variables $aTag and $html I didn't need to call the html() because I was going to call it again in the .showcase div.
var $aTag = $a.eq($item.data('rel'));
var $html = $p.eq($item.data('rel'));
<!---.showcase div--->
$link.html($aTag).show(0);
$details.html($picture).show(0);
Here is the new fiddle
http://jsfiddle.net/theMugician/L2xyatfd/47/
Simply try :
var $aTag = $a.eq($item.data('rel'));
var $html = $p.eq($item.data('rel'));
$link.append($aTag).show(0);
$images.append($picture).show(0);
It will wrap the element, not just its html content

how can i call javascript function when clicking on image? [closed]

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Questions asking for code must demonstrate a minimal understanding of the problem being solved. Include attempted solutions, why they didn't work, and the expected results. See also: Stack Overflow question checklist
Closed 9 years ago.
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How can I call a js function so it work on click image?
$("#closeButton").click(function () {
$("#sheet").css("display", "none");
});
image code?
<img src="images/divclose.png" alt="*" onclick="function()"/>
Add an ID (remove your onclick thingy):
<img src="images/divclose.png" alt="*" id="closeButton" />
Write this (note that you don't need the outer function anymore if you already have it);
$(function () {
$("#closeButton").click(function () {
$("#sheet").css("display", "none");
});
});
Now, go reading a beginner tutorial, a book or whatever. Learn the basics ;)
You try to access the image using an id in your code, but you don't have any id on the image element. Just add that, and it will work (provided that you have your code inside the ready or load event, so that the element exists when it runs):
<img src="images/divclose.png" alt="*" id="closeButton"/>
Don't have any onclick attribute on the element if you want to bind the event using jQuery. The event model is somewhat different for jQuery, and may conflict with plain DOM events.
tag must have the "id" and you can use the same method you described
I assume you want to use jquery so you should check jquery documentation.
What you did is declaring an "oldschool" pure javascript way to call "function()" on the click.
Therefor you need to declare the function "function" in the javascript itself the old fashioned way.
Using jquery and your code all you need is to assign your id to your image.
<img src ="foo.png" id="closeButton"/>
and it should work.

click and if in Javascript [closed]

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I've this function in my script :
$("#image4").click(function(){
if($(this).attr("src")=="http://XXX.jpg"){
$(this).attr("src","http://YYYY.jpg");
}else{
$(this).attr("src","http://XXX.jpg");
}
return false;});
HTML
<img src="http://XXX.jpg" id="image4"/>
I don't understand why when I click on my image, the if part doesn't works. I explain : If I use this code, nothing change. If I add and alert un my click function, I see the alert twice and see the image change twice to.
It seems, "if" doesn't works and apply "if" and "else" at each time
Someone can help me about that. I think it a basic feature, I don't understand why it doesn't works.
Thanks
("#image4").click(function(){
^^
you missed a bracket!
Working: http://jsfiddle.net/MAVyb/
The sysntax and everything on your code is right so it is definetly value problem. Problem may be src have leading or trailing space in it.
try alert like
alert("-"+$(this).attr("src")+"-")
and whether is there any space between -(hypen) and src value.
also try
alert(($(this).attr("src")=="http://XXX.jpg")), it should return true if the src is equal
Update: i can reproduce your problem -- you should have attached the event listener function for two times. check your original code. that is the problem. check your code. you can verify this by changing id to some other in jquery method and img tag

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