Javascript: Checking object child array length even if object is not defined - javascript

I would like to display some content only if an object's child array has elements in it. But sometimes the object itself is not defined so doing this fails if object or object.child is not present at the scope:
if(object.child.length){
alert('hello world');
}
Which results in:
Uncaught ReferenceError: object is not defined
So I have to add two additional if conditions to check if the object and it's child is defined or not:
if(typeof object !== 'undefined'){
if(typeof object.child !== 'undefined'){
if(object.child.length){
alert('hello world');
}
}
}
Writing a function around this is problematic too:
function isset(value){ ... }
if(isset(object.child.length)({ ... } // <-- still raises error that object is not defined
Is there a cleaner, shorter way to do this?

You can put a guard on:
if(object && object.child && object.child.length){
The above defends against object and object.child being undefined or null (or any other falsey value); it works because all non-null object references are truthy, so you can avoid the verbose typeof object !== "undefined" form. You may not need both of the guards above, if you know for sure that object.child will exist if object does. But having both is harmless.
It's worth noting that this is useful even when retrieving values, not just for testing them. For instance, suppose you have (or may not have!) object.foo, which contains a value you want to use.
var f = object && object.foo;
If object is falsey (undefined or null are the typical cases), then f will receive that falsey value (undefined or null). If object is truthy, f will receive the value of object.foo.
|| is curiously powerful in a similar way.

Related

Is there a difference between typeof x === 'undefined' vs if (x)

I've always maintained the practice of checking if a value is undefined using
if (typeof x === 'undefined')
However, a colleague is suggesting that using if (x) { is better.
Is there any difference between these two methods from a computational point of view?
There are at least two differences off the top of my mind:
Checking the type as undefined only checks for undefined, unlike if(x), which checks for any truthy values (e.g. true, a non-empty string, a non-zero number, etc)
You can perform typeof on non-existent variables, even in strict mode. You'll get a reference error if you never declared x and did if(x)
"use strict";
const a = undefined;
const b = "truthy value";
if(a) {
console.log("a in if"); // never executes
}
if(typeof a !== "undefined") {
console.log("a with typeof"); // never executes
}
if(b) {
console.log("b in if"); // executes
}
if(typeof b === "undefined") {
console.log("b with typeof"); // never executes
}
try {
if(c) console.log("this should error");
} catch(e) {
console.log("Can't access non-existent variable");
}
console.log("No error:", typeof c);
When should I use which one?
Generally:
Use if(x) when...
You're checking for a boolean
You're checking for (not) 0
You're checking for a non-empty empty string (probably use if(string.length) instead)
Checking the return value of a function (e.g. a function returns null when there's no result for a query or an object when there is (DOM functions like document.getElementById return null when no element with that ID exists))
Use if(typeof x !== "undefined") when...
You're checking whether an object key exists (if(typeof obj.key !== "undefined")) (the proper way as a commentator pointed out is with Object.hasOwn(obj, "key"))
You're checking whether a variable exists (not sure when or why you would do that though)
Checking whether an argument has been passed
Other uses like when you're writing an Express server and checking user-provided content
Something else I probably forgot...
Something that's useful to keep in mind is that Javascript is dynamically typed, even if it looks like it's just variables. There are a handful of types in JS, and Undefined (with caps) is one, and the only value it can hold is undefined. Think of it like saying you have the Number type and it only accepts 42. This is important to know because JS engines have to observe spec.
The Undefined type has exactly one value, called undefined. Any variable that has not been assigned a value has the value undefined.
There is a lot of variation in application code, but you can know that variables that have not been assigned are of type Undefined with value undefined and not something else. Next to Undefined is Null, which has a single value, null. Null, unlike Undefined, needs to be assigned.
In the spec you'll also the find the table for the result you get for each variable type.
You'll notice that Undefined has its own return value, as well as Boolean, but Null returns "object", which is reported to be a mistake in the original spec that we can't get rid of.
With types out of the way, we get to Boolean coercion, which is how if statements work out the condition. The spec has a table of cases that define when a value should be coerced into true or false.
You'll see that an if clause receives the Undefined type, it returns false. The same happens with Null. There are a few other cases that can also return false even if they are not Undefined or Null.
The Number type with values 0, -0, NaN
The String type with length 0 ("")
The BigInt type with value 0
As others have already answered, applications of the spec come in a few different places. The reasons as for why typeof exists and there is an overlap with the falsey evaluation arise from how the JS engines handle values and perform coercion into Boolean.

Javascript typeof of undefined objects subproperty

Let's say I would like to check if a property to the object Foo is defined or not, I would use in this scenario:
typeof Foo.property != 'undefined'
But if not only the property does not exists, but also the object is undefined, this results in an error.
Is there any single line way to check if an objects property is defined, and return false in the following cases:
if the object property is not defined
if the object is not defined
WHY I WANT THIS: I am writing a script in NodeJS, which uses a class, which would be used in the front end also, and instead of maintaining two different files, which would end up being basically the same except for minor changes for the two environments, I would like to differentiate between the environments with some basic IF logic.
OTHER POSSIBLE USE CASES: Let's say we have the following object:
function Foo() {
this.case1={
info1: 'something',
info2: 'something',
.....
info1000: 'something'
}
this.case2={
info1: 'something',
info2: 'something',
......
info1000: 'something'
}
}
If I would like to decide which case applies to me, and the decision lies in one of the inner info's, I would first have to check if the respective case exists, and then if the respective info exists(2 conditions):
if (typeof Foo.case1 != 'undefined') && (typeof Foo.case1.info1 != 'undefined')
If this is a much deeper nested object, there would be a lot of condition checking and typing, to get some basic information: if case1 does not exist at all, then I will use case2.
You could use an and (&&) clause.
typeof Foo !== 'undefined' && typeof Foo.property !== 'undefined'
Or put more simply:
Foo !== undefined && Foo.property !== undefined
Edit: As David Titarenco pointed out, this works due to something known as short-circuit evaluation. That basically means that if the first part evaluates to false (Foo !== undefined) then the second part is never evaluated.
The simplest answer that comes to mind is this. It is not as 100%-strict as yours, but it would take a very unusual situation to break it:
if (Foo && 'property' in Foo) {
The Foo object is evaluated as boolean. A null or undefined type will be false, any object will be true. We also check the "key" side of the key/value pair, rather than the value. It is technically possible to have the key property, but for it to have the actual value undefined. This will return false in that case.
The one caveat: If Foo is another value type: true, 12, function()..., then the first condition may pass (but I don't believe the second one will)
Okay, I came up with a small function, which on initial testing does what I wanted, but I've only tested it for like 5 minutes, so there could be errors in it, if yes, please point it out:
function isDefined(path, namespace) {
if (typeof namespace == 'undefined') {
namespace=global;
// global is the default namespace for NodeJS,
// change this to window if you use it in a browser
}
path=path.split(".");
for (var i=0;i<path.length ;i++)
{
if (typeof namespace[path[i]] == 'undefined') return false;
else namespace=namespace[path[i]];
}
return true;
}
Usage: if you would want to test for example if Test.Test1.Test2.Test3.Test4.Test5.Test6 is defined you can use it like this:
if (isDefined('Test.Test1.Test2.Test3.Test4.Test5.Test6')===true) {
//it is defined
}

Comparing undefined value in JavaScript

I have an object whose value may be undefined sometimes. So is it possible / valid / good practice to test it with an if case like below :
if(params === undefined)
{
alert("sound." + params);
}
If not, why can't we do it?
As of now, it is working fine. Yet, I would like to know if it can go wrong anytime?
Thanks
Since in theory undefined can be redefined (at least pre-JS 1.8.5), it's better to use
if (typeof params === 'undefined')
This also works without throwing an error if params is not a known variable name.
Use typeof varName for safer usage:-
This will not throw any error if params is not a variable declared anywhere in your code.
if(typeof params === "undefined")
{
//it is not defined
}
if(params === undefined) //<-- This will fail of you have not declared the variable
//param. with error "Uncaught ReferenceError: params is not defined "
{
}
Refer Undefined
The typeof answers are good, here's a bit extra. To me, this is a case where you need to explain what you are doing with params. If you are doing say:
function foo(paramObject) {
// determine if a suitable value for paramObject has been passed
}
then likely you should be testing whether paramObject is an object, not whether it has some value other than undefined. So you might do:
if (typeof paramObject == 'object') {
// paramObject is an object
}
but you still don't know much about the object, it could be anything (including null). So generally you document the object that should be passed in and just do:
if (paramObject) {
// do stuff, assuming if the value is not falsey, paramObject is OK
}
now if it throws an error, that's the caller's fault for not providing a suitable object.
The corollary is that all variables should be declared so that the test doesn't throw an error (and you don't need to use typeof, which is one of those half useful operators that promises much but doesn't deliver a lot).

localStorage alerts undefined but if undefined is false

Can not quite understand the reasoning for this. In the following code the localStorage of an item is alerted as undefined, but if I use an if(x==undefined) syntax it does not work. Can somebody explain what is the problem. Thank you.
alert(localStorage["x"]);
if(localStorage["x"]=="undefined"){alert("y");}
The top line alerts undefined
The bottom line does not alert y for me.
It doesn't contain the string "undefined", it contains a value of the type undefined:
if (localStorage["x"] == undefined) { alert("y"); }
The value undefined is possible to change in older browsers, so good practice is to check the type instead:
if (typeof localStorage["x"] == 'undefined') { alert("y"); }
Try:
if(typeof( localStorage["x"]) == 'undefined'){alert("y");}
OR
if( localStorage["x"] == undefined){alert("y");}
OR
if( !localStorage["x"] ){alert("y");}
The two ways of checking for something being undefined are:
typeof foo === "undefined"
and
foo === undefined
In the first case, it will be true if foo was never defined or the value of foo is undefined.
In the second case, it will only be true if foo was defined (otherwise it'll break) and its value is undefined.
Checking its value against the string "undefined" is not the same at all!
UPDATE:
When I said that if you try to perform an operation on an object literal's property that isn't defined, I guess I meant if it's undefined at all, and what I meant was something more like this:
obj["x"].toLowerCase()
// or
obj["x"]["y"]
where you are attempting to access/operate on something that is originally undefined. In this case, simply comparing in an if statement should be fine, because of the way object literals report the value...but is very different with normal Javascript variables.
With object literals, if a key (say "x") is not defined, then
obj["x"]
returns a value of undefined, so both the typeof and basic === undefined checks will work and be true.
The whole difference of not being defined or having a value of undefined is different with normal variables.
If you had:
var a;
// or
var a = undefined;
then both the typeof and basic === undefined checks I provided earlier would work and be true. But if you never even declared a, then only the typeof check would work and be true. The === undefined check would break.
Take a look at: http://jsfiddle.net/7npJx/
If you notice in the console, it says b is not defined and breaks the if statement.
Since you're basically looking at an object literal with localStorage, the way to distinguish whether an item is not defined or has a value of undefined is to use in first. So, you could use:
if (!("x" in localStorage)) {
to check if "x" is not a defined property at all, and:
else if (localStorage["x"] === undefined) {
to then check if it is defined but has a value of undefined. Then, using:
else {
would signify that localStorage["x"] is both defined and does not have the value undefined.
In your code though, it's okay to use the typeof or in checks (based on what you want to know) because of the way object literals report properties that aren't defined. Using the basic === undefined is also okay, but as Guffa pointed out, it's possible for the actual value of undefined to be overwritten and then wouldn't work in this comparison. When it comes to normal Javascript variables, typeof and === undefined checks aren't the same.

What reason is there to use null instead of undefined in JavaScript?

I've been writing JavaScript for quite a long time now, and I have never had a reason to use null. It seems that undefined is always preferable and serves the same purpose programmatically. What are some practical reasons to use null instead of undefined?
I don't really have an answer, but according to Nicholas C. Zakas, page 30 of his book "Professional JavaScript for Web Developers":
When defining a variable that is meant
to later hold an object, it is
advisable to initialize the variable
to null as opposed to anything else.
That way, you can explicitly check for the value null to determine if
the variable has been filled with an object reference at a later time
At the end of the day, because both null and undefined coerce to the same value (Boolean(undefined) === false && Boolean(null) === false), you can technically use either to get the job done. However, there is right way, IMO.
Leave the usage of undefined to the JavaScript compiler.
undefined is used to describe variables that do not point to a reference. It is something that the JS compiler will take care for you. At compile time the JS engine will set the value of all hoisted variables to undefined. As the engine steps through the code and values becomes available the engine will assign respective values to respective variables. For those variables for whom it did not find values, the variables would continue to maintain a reference to the primitive undefined.
Only use null if you explicitly want to denote the value of a variable as having "no value".
As #com2gz states: null is used to define something programmatically empty. undefined is meant to say that the reference is not existing. A null value has a defined reference to "nothing". If you are calling a non-existing property of an object, then you will get undefined. If I would make that property intentionally empty, then it must be null so you know that it's on purpose.
TLDR; Don't use the undefined primitive. It's a value that the JS compiler will automatically set for you when you declare variables without assignment or if you try to access properties of objects for which there is no reference. On the other hand, use null if and only if you intentionally want a variable to have "no value".
Sidebar: I, personally, avoid explicitly setting anything to undefined (and I haven't come across such a pattern in the many codebases/third party libs I've interacted with). Also, I rarely use null. The only times I use null is when I want to denote the value of an argument to a function as having no value, i.e.,:
function printArguments(a,b) {
console.log(a,b);
}
printArguments(null, " hello") // logs: null hello
null and undefined are essentially two different values that mean the same thing. The only difference is in the conventions of how you use them in your system. As some have mentioned, some people use null for meaning "no object" where you might sometimes get an object while undefined means that no object was expected (or that there was an error). My problem with that is its completely arbitrary, and totally unnecessary.
That said, there is one major difference - variables that aren't initialized (including function parameters where no argument was passed, among other things) are always undefined.
Which is why in my code I never use null unless something I don't control returns null (regex matching for example). The beauty of this is it simplifies things a lot. I never have to check if x === undefined || x === null, I can just check x === undefined. And if you're in the habit of using == or simply stuff like if(x) ... , stop it.
!x will evaluate to true for an empty string, 0, null, NaN - i.e. things you probably don't want. If you want to write javascript that isn't awful, always use triple equals === and never use null (use undefined instead). It'll make your life way easier.
undefined is where no notion of the thing exists; it has no type, and it's never been referenced before in that scope; null is where the thing is known to exist, but it has no value.
Everyone has their own way of coding and their own internal semantics, but over the years I have found this to be the most intuitive advice that I give people who ask this question: when in doubt, do what JavaScript does.
Let's say you are working with object properties like options for a jQuery plugin...ask yourself what value JavaScript gives a property that has yet to be defined -- the answer is undefined. So in this context, I would initialize these types of things with 'undefined' to be consistent with JavaScript (for variables, you can do var myVar; instead of var myVar = undefined;).
Now let's say you are doing DOM manipulation...what value does JavaScript assign to non-existent elements? The answer is null. This is the value I would initialize with if you are creating a placeholder variable that will later hold a reference to an element, document fragment, or similar that relates to the DOM.
If you're working with JSON, then a special case needs to be made: for undefined property values, you should either set them to "" or null because a value of undefined is not considered proper JSON format.
With this said, as a previous poster has expressed, if you find that you're initializing stuff with null or undefined more than once in a blue moon, then maybe you should reconsider how you go about coding your app.
You might adopt the convention suggested here, but there really is no good reason to. It is not used consistently enough to be meaningful.
In order to make the convention useful, you first must know that the called function follows the convention. Then you have to explicitly test the returned value and decide what to do. If you get undefined, you can assume that some kind of error occurred that the called function knew about. But if an error happened, and the function knew about it, and it is useful to send that out into the wider environment, why not use an error object? i.e. throw an error?
So at the end of the day, the convention is practically useless in anything other than very small programs in simple environments.
A few have said that it is ok to initialise objects to null. I just wanted to point out that destructuring argument defaults don't work with null. For example:
const test = ({ name } = {}) => {
console.log(name)
}
test() // logs undefined
test(null) // throws error
This requires performing null checks prior to calling the function which may happen often.
A useful property in null that undefined does not qualifies:
> null + 3
3
> undefined + 3
NaN
I use null when I want to 'turn off' a numeric value,
or to initialize some. My last use was manipulating css transform:
const transforms = { perspective : null, rotateX : null };
// if already set, increase, if not, set to x
runTimeFunction((x) => { trasforms.perspective += x; });
// still useful, as setting perspective to 0 is different than turning it off
runTimeFunction2((x) => { transforms.perspective = null; });
// toCss will check for 'null' values and not set then at all
runTimeFunction3(() => { el.style.transform = toCss(transforms); });
Not sure if I should use this property thought...
DOM nodes and elements are not undefined, but may be null.
The nextSibling of the last child of an element is null.
The previousSibling of the first child is null.
A document.getElementById reference is null if the element does not exist in the document.
But in none of these cases is the value undefined; there just is no node there.
Unknown variable: undefined.
Known variable yet no value: null.
You receive an object from a server, server_object.
You reference server_object.errj. It tells you it’s undefined. That means it doesn’t know what that is.
Now you reference server_object.err. It tells you it’s null. That means you’re referencing a correct variable but it’s empty; therefore no error.
The problem is when you declare a variable name without a value (var hello) js declares that as undefined: this variable doesn’t exist; whereas programmers mostly mean: “I’ve not given it a value yet”, the definition of null.
So the default behavior of a programmer—declaring a variable without a value as nothing—is at odds with js—declaring it as not existing. And besides, !undefined and !null are both true so most programmers treat them as equivalent.
You could of course ensure you always do var hello = null but most won’t litter their code as such to ensure type sanity in a deliberately loosely-typed language, when they and the ! operator treat both undefined and null as equivalent.
In JavaScript, the value null represents the intentional absence of any object value. null expresses a lack of identification, indicating that a variable points to no object.
The global undefined property represents the primitive value undefined.
undefined is a primitive value automatically assigned to variables.
undefined is meant to say that the reference is not existing.
I completely disagree that usage null or undefined is unnecessary.
undefined is thing which keeping alive whole prototype chaining process.
So compiler only with null can't check if this property just equal to null, or its not defined in endpoint prototype. In other dynamic typed languages(f.e. Python) it throws exception if you want access to not defined property, but for prototype-based languages compiler should also check parent prototypes and here are the place when undefined need most.
Whole meaning of using null is just bind variable or property with object which is singleton and have meaning of emptiness,and also null usage have performance purposes. This 2 code have difference execution time.
var p1 = function(){this.value = 1};
var big_array = new Array(100000000).fill(1).map((x, index)=>{
p = new p1();
if(index > 50000000){
p.x = "some_string";
}
return p;
});
big_array.reduce((sum, p)=> sum + p.value, 0)
var p2 = function(){this.value = 1, p.x = null};
var big_array = new Array(100000000).fill(1).map((x, index)=>{
p = new p2();
if(index > 50000000){
p.x = "some_string";
}
return p;
});
big_array.reduce((sum, p)=> sum + p.value, 0)
I'm working through this exact question right now, and looking at the following philosophy:
Any function that is intended to return a result should return null if it fails to find a result
Any function that is NOT intended to return a result implicitly returns undefined.
For me, this question is significant because anyone calling a function that returns a result should have no question as to whether to test for undefined vs null.
This answer does not attempt to address:
Property values of null vs undefined
Variables within your functions being null vs undefined
In my opinion, variables are your own business and not a part of your API, and properties in any OO system are defined and therefore should be defined with value different from what they would be if not defined (null for defined, undefined is what you get when accessing something that is not in your object).
Here's a reason: var undefined = 1 is legal javascript, but var null = 1 is a syntax error. The difference is that null is a language keyword, while undefined is, for some reason, not.
If your code relies on comparisons to undefined as if it's a keyword (if (foo == undefined) -- a very easy mistake to make) that only works because nobody has defined a variable with that name. All that code is vulnerable to someone accidentally or maliciously defining a global variable with that name. Of course, we all know that accidentally defining a global variable is totally impossible in javascript...
Just wanna add that with usage of certain javascript libraries, null and undefined can have unintended consequences.
For example, lodash's get function, which accepts a default value as a 3rd argument:
const user = {
address: {
block: null,
unit: undefined,
}
}
console.log(_.get(user, 'address.block', 'Default Value')) // prints null
console.log(_.get(user, 'address.unit', 'Default Value')) // prints 'Default Value'
console.log(_.get(user, 'address.postalCode', 'Default Value')) // prints 'Default Value'
Another example: If you use defaultProps in React, if a property is passed null, default props are not used because null is interpreted as a defined value.
e.g.
class MyComponent extends React.Component {
static defaultProps = {
callback: () => {console.log('COMPONENT MOUNTED')},
}
componentDidMount() {
this.props.callback();
}
}
//in some other component
<MyComponent /> // Console WILL print "COMPONENT MOUNTED"
<MyComponent callback={null}/> // Console will NOT print "COMPONENT MOUNTED"
<MyComponent callback={undefined}/> // Console WILL print "COMPONENT MOUNTED"
There are already some good answers here but not the one that I was looking for. null and undefined both "technically" do the same thing in terms of both being falsy, but when I read through code and I see a "null" then I'm expecting that it's a user defined null, something was explicitly set to contain no value, if I read through code and see "undefined" then I assume that it's code that was never initialized or assigned by anything. In this way code can communicate to you whether something was caused by uninitialized stuff or null values. Because of that you really shouldn't assign "undefined" manually to something otherwise it messes with the way you (or another developer) can read code. If another developer sees "undefined" they're not going to intuitively assume it's you who made it undefined, they're going to assume it's not been initialized when in fact it was. For me this is the biggest deal, when I read code I want to see what it's telling me, I don't want to guess and figure out if stuff has "actually" been initialized.
Not even to mention that using them in typescript means two different things. Using:
interface Example {
name?: string
}
Means that name can be undefined or a string, but it can't be null. If you want it null you have to explicitly use:
interface Example {
name: string | null
}
And even then you'll be forced to initialize it at least with "null".
That's of course only true if you're using "strictNullChecks": true in tsconfig.json.
Based on a recent breakage we ran into, the example below shows why I prefer to use undefined over null, unless there is a specific reason to do otherwise:
function myfunc (myArg) {
if (typeof myArg === 'string') {
console.log('a', myArg);
} else if (typeof abc === 'object') {
console.log('b', myArg);
if (myArg.id) {
console.log('myArg has an id');
} else {
console.log('myArg has an id');
}
} else {
console.log('no value');
}
}
The following values will play nicely:
'abc'
{}
undefined
{ id: 'xyz' }
On the other hand the assumption of null and undefined being equivalent here breaks the code. The reason being is that null is of type of object, where as undefined is of type undefined. So here the code breaks because you can't test for a member on null.
I have seen a large number of cases with code of similar appearance, where null is just asking for problems:
if (typeof myvar === 'string') {
console.log(myvar);
} else if (typeof myvar === 'object') {
console.log(myvar.id);
}
The fix here would be to explicitly test for null:
if (typeof myvar === 'string') {
console.log(myvar);
} else if (myvar !== null && typeof myvar === 'object') {
console.log(myvar.id);
}
My attitude is to code for the weaknesses of a language and the typical behaviours of programmers of that language, hence the philosophy here of going with 'undefined' bey default.
To write simple code you need to keep complexity and variation down. When a variable or a property on an object does not have a value it is undefined , and for a value to be null you need to assign it a null value.
Undeclared vs Null
null is both an Object "type" and one of the 7 unique primitive value types called null
undefined is both a global scope property and type called undefined and one of the 7 unique primitive value types called undefined (window.undefined) .
It is the primitive types we use as values we are interested in.
In the case of null, as a value type it means an empty value has been assigned to a variable, but the variable type (Number, String, etc) is still defined. It just has no value. That is what null means. It means a variable has an empty value but it is still a value. It also reinitializes the variable with some kind of value, but is not undefined as a type.
undefined is a special case. When you declare a variable (or use a missing value not yet declared) it is of type undefined, as the browser does not know what type of data has been assigned to it yet. If the variable is declared but not assigned a value is is assigned the primitive calue undefined by default prior to assigning a value, and implies the variable does not exist or exists but has no value assigned.
Like null, undefined is also a primitive value type. But unlike null it means the variable does not exist, where null means the value does not exist. That is why its always better to check if the variable exists and has been assigned a variable using undefined before checking if the value is null or empty. undefined implies no variable or object exists in the compilation at all. The variable has either not been declared or declared with a missing value so not initialized. So checking for undefined is a very good way to avoid many types of errors in JavaScript and supersedes null.
That is why I would not rely on "truthy" checks for true/false with null and undefined, even though they will both return a false response, as undefined implies an additional step for missing feature, object, or variable, not just a true/false check. It implies something more. If you have a missing undeclared variable, truthy statements will trigger an ERROR!
Let's look at undefined first:
//var check1;// variable doesnt even exist so not assigned to "undefined"
var check2;// variable declared but not initialized so assigned "undefined"
var check3 = 'hello world';// variable has a value so not undefined
console.log('What is undefined?');
//console.log(check1 === undefined);// ERROR! check1 does not exist yet so not assigned undefined!
console.log(check2 === undefined);// True
console.log(check3 === undefined);// False
console.log(typeof check1 === 'undefined');// True - stops the ERROR!
console.log(typeof check2 === 'undefined');// True
console.log(typeof check3 === 'undefined');// False
As you can see undeclared variables, or declared but not initialized, both are assigned a type of undefined. Notice declared variables that are not initialized are assigned a value of undefined, the primitive value type but variables that do not exist are undefined types.
null has nothing to do with missing variables or variables not yet assigned values, as null is still a value. So anything with a null is already declared and initialized. Also notice a variable assigned a null value is actually an object type unlike undefined types. For example...
var check4 = null;
var check5 = 'hello world';
console.log('What is null?');
console.log(check4 === undefined);// False
console.log(check5 === undefined);// False
console.log(typeof check4 === 'undefined');// False
console.log(typeof check5 === 'undefined');// False
console.log(typeof check4);// return 'object'
console.log(typeof check5);// return 'string'
As you can see each act differently and yet both are primitive values you can assign any variable. Just understand they represent different states of variables and objects.

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