Develop Reference

Searching keywords in JavaScript

Here's an example of the customer codes:
C000000123
C000000456
If I input C123 in the search box, "C000000123" will automatically display.
9 numbers are fixed.
Please help me, a short sample was shown to me but I don't get it.
function test(key, num, digit) {
let retStr;
xxxx (condition)
retun retStr;
}
here's an elaboration:
**
input:123
output:A00000123
input:1
output:A00000001
input:99999
output:A00099999
**
here's the detailed demand:
Since it takes time and effort to enter the management number “alphabet + numeric value 9 digits” on the search screen, when the alphabetic number and the number excluding the leading 0 are entered, it is automatically complemented so that it becomes 9 padded with zeros.
sorry i'm very very new to programming in javascript

Try this:
May be what you want...
Please test it and tell if its what you want.
function getOutput(input){
var str=input.substring(1,input.length);
var padd0=9-str.length;
var zr="000000000";
var zrsub=zr.substring(0,padd0);
var output=input[0]+zrsub+""+str;
return output;
}
//Example: Call it like (NB any letter can be used):
getOutput("C123"); //or
getOutput("D123");

You can use .endsWith in js which takes a string and a search string and returns true if the specified string ends with the search string.
This function takes an array of customer ids and a search string and returns the matching customer id
function searchCustomer(customers, searchString) {
return customers.find(customer => customer.endsWith(searchString));
}
searchCustomer(['C000000123', 'C000000456'], 123); // "C000000123"
searchCustomer(['C000000123', 'C000000456'], 456); // "C000000456"
searchCustomer(['C000000123', 'C000000456', 'A00000001'], 1); //"A00000001"

JavaScript regex: capturing optional groups while having a strict matching

I am trying to extract some data from user input that should follow this format: 1d 5h 30m, which means the user is entering an amount of time of 1 day, 5 hours and 30 minutes.
I am trying to extract the value of each part of the input. However, each group is optional, meaning that 2h 20m is a valid input.
I am trying to be flexible in the input (in the sense that not all parts need to be input) but at the same time I don't watch my regex to match some random imput like asdfasdf20m. This one should be rejected (no match).
So first I am getting rid of any separator the user might have used (their input can look like 4h, 10m and that's ok):
input = input.replace(/[\s.,;_|#-]+/g, '');
Then I am capturing each part, which I indicate as optional using ?:
var match = /^((\d+)d)?((\d+)h)?((\d+)m)?$/.exec(input);
It is kind of messy capturing an entire group including the letter when I only want the actual value, but I cannot say that cluster is optional without wrapping it with parentheses right?
Then, when an empty group is captured its value in match is undefined. Is there any function to default undefined values to a particular value? For example, 0 would be handy here.
An example where input is "4d, 20h, 55m", and the match result is:
["4d20h55m", "4d", "4", "20h", "20", "55m", "55", index: 0, input: "4d20h55m"]
My main issues are:
How can I indicate a group as optional but avoid capturing it?
How can I deal with input that can potentially match, like abcdefg6d8m?
How can I deal with an altered order? For example, the user could input 20m 10h.
When I'm asking "how to deal with x" I mean I'd like to be able to reject those matches.

As variant:
HTML:
<input type="text">
<button>Check</button>
<div id="res"></div>
JS:
var r = [];
document.querySelector('button').addEventListener('click', function(){
var v = document.querySelector('input').value;
v.replace(/(\d+d)|(\d+h)|(\d+m)/ig, replacer);
document.querySelector('#res').innerText = r;
}, false);
function trim(s, mask) {
while (~mask.indexOf(s[0])) {
s = s.slice(1);
}
while (~mask.indexOf(s[s.length - 1])) {
s = s.slice(0, -1);
}
return s;
}
function replacer(str){
if(/d$/gi.test(str)){
r[0] = str;
}
else if(/h$/gi.test(str)){
r[1] = str;
}
else if(/m$/gi.test(str)){
r[2] = str;
}
return trim(r.join(', '), ',');
}
See here.

What's the best way to mask a credit card in JavaScript?

In Node, I need to turn a credit card into something like this before rendering the view layer: ************1234.
Without loops and ugliness is there a utility or one liner for this? The credit card can potentially look one of these ways:
1234567898765432
1234-5678-9876-5432
1234 5678 9876 5432

Here's one way with Ramda and some RegEx:
var ensureOnlyNumbers = R.replace(/[^0-9]+/g, '');
var maskAllButLastFour = R.replace(/[0-9](?=([0-9]{4}))/g, '*');
var hashedCardNumber = R.compose(maskAllButLastFour, ensureOnlyNumbers);
hashedCardNumber('1234567898765432'); // ************5432
Demo : http://jsfiddle.net/7odv6kfk/

No need for a regex:
var cc='1234-5678-9012-3456';
var masked = '************'+cc.substr(-4); // ************3456
Will work for any format provided the last four digits are contiguous.

This is for everyone who said they didn't need another way to mask a credit card. This solution will append the last 4 chars of the card number with asterisk.
var cardNumber = '4761640026883566';
console.log(maskCard(cardNumber));
function maskCard(num) {
return `${'*'.repeat(num.length - 4)}${cardNumber.substr(num.length - 4)}`;
}
jsfiddle example

I use this function that is useful for me, because mask the credit card number and format it in blocks of four characters like this **** **** **** 1234, here the solution:
const maskCreditCard = (card) => {
return card
.replace(/.(?=.{5})/g, "*")
.match(/.{1,4}/g)
.join(" ");
};

Here's plain JavaScript using Regex with lookahead
var cardNumbers = [
"1234567898765432",
"1234-5678-9876-5432",
"1234 5678 9876 5432"
];
console.log(cardNumbers.map(maskCardNumber));
//> ["************5432", "************5432", "************5432"]
function maskCardNumber(cardNumber) {
return cardNumber.replace(/^[\d-\s]+(?=\d{4})/, "************");
};
Unlike AllienWebguy's implementation:
doesn't require an external library
does everything in one replace() call
replaces whatever number of digits with the constant number of asterisks (it should be a bit faster, but it may not be what you want)
supports only described formats (will not work, for example, with "1B2C3D4E5F6G7H89876-5432" or "1234+5678+9876=54-32")

Remove non digits, generate an asterisk string of that length - 4, append the last 4:
var masked = Array(cc.replace(/[^\d]/g, "").length - 3).join("*") + cc.substr(cc.length - 4);
Or to include space/hyphens in the mask:
var masked = Array(cc.length - 3).join("*") + cc.substr(cc.length - 4);

title casing and Abbreviations in javascript

I am trying to Titlecase some text which contains corporate names and their stock symbols.
Example (these strings are concatenated as corporate name, which gets title cased and the symbol in parens): AT&T (T)
John Deere Inc. (DE)
These corporate names come from our database which draws them from a stock pricing service. I have it working EXCEPT for when the name is an abbreviation like AT&T
That is return, and you guessed it right, like At&t. How can I preserve casing in abbreviations. I thought to use indexof to get the position of any &'s and uppercase the two characters on either side of it but that seems hackish.
Along the lines of(pseudo code)
var indexPos = myString.indexOf("&");
var fixedString = myString.charAt(indexPos - 1).toUpperCase().charAt(indexPos + 1).toUpperCase()
Oops, forgot to include my titlecase function
function toTitleCase(str) {
return str.replace(/([^\W_]+[^\s-]*) */g, function (txt) {
return txt.charAt(0).toUpperCase() + txt.substr(1).toLowerCase();
});
}
Any better suggestions?

A better title case function may be
function toTitleCase(str) {
return str.replace(
/(\b.)|(.)/g,
function ($0, $1, $2) {
return ($1 && $1.toUpperCase()) || $2.toLowerCase();
}
);
}
toTitleCase("foo bAR&bAz a.e.i."); // "Foo Bar&Baz A.E.I."
This will still transform AT&T to At&T, but there's no information in the way it's written to know what to do, so finally
// specific fixes
if (str === "At&T" ) str = "AT&T";
else if (str === "Iphone") str = "iPhone";
// etc
// or
var dict = {
"At&T": "AT&T",
"Iphone": "iPhone"
};
str = dict[str] || str;
Though of course if you can do it right when you enter the data in the first place it will save you a lot of trouble

This is a general solution for title case, without taking your extra requirements of "abbreviations" into account:
var fixedString = String(myString).toLowerCase().replace(/\b\w/g, String.toUpperCase);
Although I agree with other posters that it's better to start with the data in the correct format in the first place. Not all proper names conform to title case, with just a couple examples being "Werner von Braun" and "Ronald McDonald." There's really no algorithm you can program into a computer to handle the often arbitrary capitalization of proper names, just like you can't really program a computer to spell check proper names.
However, you can certainly program in some exception cases, although I'm still not sure that simply assuming that any word with an ampersand in it should be in all caps always appropriate either. But that can be accomplished like so:
var titleCase = String(myString).toLowerCase().replace(/\b\w/g, String.toUpperCase);
var fixedString = titleCase.replace(/\b\w*\&\w*\b/g, String.toUpperCase);
Note that your second example of "John Deere Inc. (DE)" still isn't handled properly, though. I suppose you could add some other logic to say, put anything word between parentheses in all caps, like so:
var titleCase = String(myString).toLowerCase().replace(/\b\w/g, String.toUpperCase);
var titleCaseCapAmps = titleCase.replace(/\b\w*\&\w*\b/g, String.toUpperCase);
var fixedString = titleCaseCapAmps.replace(/\(.*\)/g, String.toUpperCase);
Which will at least handle your two examples correctly.

How about this: Since the number of registered companies with the stock exchange is finite, and there's a well-defined mapping between stock symbols and company names, your best best is probably to program that mapping into your code, to look up the company name by the ticker abbreviation, something like this:
var TickerToName =
{
A: "Agilent Technologies",
AA: "Alcoa Inc.",
// etc., etc.
}
Then it's just a simple lookup to get the company name from the ticker symbol:
var symbol = "T";
var CompanyName = TickerToName[symbol] || "Unknown ticker symbol: " + symbol;
Of course, I would be very surprised if there was not already some kind of Web Service you could call to get back a company name from a stock ticker symbol, something like in this thread:
Stock ticker symbol lookup API
Or maybe there's some functionality like this in the stock pricing service you're using to get the data in the first place.

The last time I faced this situation, I decided that it was less trouble to simply include the few exceptions here and there as need.
var titleCaseFix = {
"At&t": "AT&T"
}
var fixit(str) {
foreach (var oldCase in titleCaseFix) {
var newCase = titleCaseFix[oldCase];
// Look here for various string replace options:
// http://stackoverflow.com/questions/542232/in-javascript-how-can-i-perform-a-global-replace-on-string-with-a-variable-insi
}
return str;
}

Trouble with adding numbers in Javascript?

I want to add the price of some books when each one checked but I have a problem.
It just adds a string. For example, when I select a book(10$), the price becomes 10 and when I select another book(20$) it becomes 1020, and so on...
My code :
For book one :
<input
name="bookList"
type="checkbox"
id="bookList_1"
onChange="
if (document.getElementById('bookList_1').checked) {
document.getElementById('priceDes').innerHTML=' total: ';
document.getElementById('price').innerHTML+=10;
}
"
value="book1"
>
For book two :
<input
name="bookList"
type="checkbox"
id="bookList_2"
onChange="
if (document.getElementById('bookList_2').checked) {
document.getElementById('priceDes').innerHTML=' total: ';
document.getElementById('price').innerHTML+=20;
}
"
value="book1"
>
And the price and priceDes are <p> tags ...
Thanks for your solutions ;)

It's because you're concatenating strings, instead of adding numbers. '10'+'20' gives '1020' and not 30.
Try:
document.getElementById('price').innerHTML=parseInt(document.getElementById('pr‌​ice').innerHTML)+10;
Be careful with this though, it would only work if your p tags have only the numbers inside their HTML. parseInt('10$') gives 10 but parseInt('$10') gives NaN. You can experiment with number-type input tags.

document.getElementById('price').innerHTML=Number(document.getElementById('price').innerHTML)+20;

InnerHTML is a string. The + operator is also the String concatenate operator in JavaScript. So, "cast" the values first.
Easy way to "cast" numerical strings in JavaScript: multiply by 1:
var rv = 1*a.innerHTML + 1*b.innerHTML;
Or, use the Number constructor:
var rv = Number(a.innerHTML) + Number(b.innerHTML);