var elementMoveWithScroll = $('.thing_to_scroll');
$('.container_overflow').scroll(function() {
var scrollElementPosition = elementMoveWithScroll.position();
console.log(scrollElementPosition);
elementMoveWithScroll.css('margin-left', scrollElementPosition+'px');
});
When a I use a hardcoded value in the place of scrollElementPosition for example 50 this seem add the margin-left:50px on scrolling the container.
I want to be able to update the value of the elementMoveWithScroll so that it moves with the horizontal scroll, how can I do this?
Use scrollElementPosition.left for horizontal and scrollElementPosition.top for vertical corresponding values.
Related
The scrollX option in Datatables allows the user to scroll the grid horizontally - however, in my table, I am needing to keep the first two columns in place, but allow the next x columns scroll horizontally. I'm not seeing any good examples of how to do this.
Example:
https://datatables.net/examples/basic_init/scroll_x.html
You could achieve this by changing the relative position of each cell based on the scrollLeft value.
$('.dataTables_scrollBody').scroll(function (){
var cols = 2 // how many columns should be fixed
var container = $(this)
var offset = container.scrollLeft()
container.add(container.prev()).find('tr').each(function (index,row){ // .add(container.prev()) to include the header
$(row).find('td, th').each(function (index,cell){
if(index>=cols) return
$(cell).css({position:'relative',left:offset+'px'})
})
})
})
I am creating a site in which there are a number of fixed background images that you scroll past. Associated with each fixed background is an image slider (or text) that is hidden until the title is clicked on. These items are all fixed positioned.
I was able to make this work by using z-index to place items in order top to bottom/first to last and then have each disappear in turn using:
$(document).scroll(function() {
$('#porttitle').toggle($(this).scrollTop() < 225);
});
However, I am unable to use this because the length pixel distance down on the page changes based on the screen size. I am pretty new to Jquery but wanted to try to use .offset .top to have the item disappear not based on the pixel length to the top of the page but instead when an element appears on the screen. This is what I have so far but it isn't seeming to work.
$(document).scroll(function() {
$('#porttitle').toggle($(this).scrollTop() < $(‘article.post-100’).offset().top);
});
Here is the link to the site: http://s416809079.onlinehome.us (not final location - just developing)
Any thoughts?
Thanks!
I think this may work for you, read the comments on the code for a line by line explanation.
Working Example
$(window).scroll(function () { // When the user scrolls
$('div').each(function () { // check each div
if ($(window).scrollTop() < $(this).offset().top) { // if the window has been scrolled beyond the top of the div
$(this).css('opacity', '1'); //change the opacity to 1
} else { // if not
$(this).css('opacity', '0'); // change the opacity to 0
}
});
});
I'm conditionally changing the opacity rather than using toggle because:
...jQuery does not support getting the offset coordinates of hidden
elements or accounting for borders, margins, or padding set on the
body element.
While it is possible to get the coordinates of elements with
visibility:hidden set, display:none is excluded from the rendering
tree and thus has a position that is undefined.
Related documentation:
.offset()
.each()
.scroll()
.scrollTop()
I have a text slider on my home page, that should display slides individually according to which arrow is selected. Currently, only the first slide is showing and each slide thereafter is blank. What am I missing to make each individual slide show?
jsfiddle
jQuery(document).ready(function($){
// Setup Variables
var slides = $('#slider_mask .slide_container').children();
var total_slides = slides.children().length;
var slide_width = $('#slider_mask').width();
var current_slide = 0;
slides.not(':first').hide();
// Set the width of the slide_container to total width of all slides
$('#slider_mask .slide_container').width(slide_width*total_slides);
// Handle Right Arrow Click
$('#slider_mask .right_button').on('click', function() {
current_slide++;
if(current_slide == total_slides){ current_slide = 0; }
var negative_margin_required = current_slide*slide_width;
$('#slider_mask .slide_container').stop().animate({marginLeft:-negative_margin_required+'px'},'fast');
});
// Handle Left Arrow Click
$('#slider_mask .left_button').on('click', function() {
current_slide--;
if(current_slide < 0){ current_slide = total_slides-1; }
var negative_margin_required = current_slide*slide_width;
$('#slider_mask .slide_container').stop().animate({marginLeft:-negative_margin_required+'px'},'fast');
});
});
Check out this fiddle. I scaled it down to a minimum.
I started with the slider mask having the fixed width and set the other widths off of that.
Ludovico Grossi is correct about making the slide element float left. When they are "block" elements without the float, they stack. If they are changed to "inline" elements, they cannot have a fixed width. It worked to set them to "inline-block", but I don't know if that is supported in all browsers. Having them as "block" and float left works.
I also had to make some other changes. One of which was that the .animate() function does not cause a hidden element to be shown. It says this on the documenation page. Instead of hiding the slides by calling .hide(), they simply are out of view by having overflow set to hidden for the mask element.
I also put the text-align center on the slide elements, rather than the container element.
UPDATE:
I created another fiddle that starts with the code from adeneo's fiddle and includes the necessary changes. I put comments next to all the code and CSS that was added, removed, or changed. I had to make one change to the html. I added the <div id="home"> element that wraps everything. Without it the CSS selectors don't match anything.
Check your css:
slide: fixed width, float left.
container: width n_slide * slide_(outer)_width
slide mask: the same as a single slide width, overflow hidden.
I would like to scroll horizontally the given element. The only way I find is using ScrollIntoView DOM method, which allows either align the element's bottom with the view bottom or the top - with the view top.
But what if the element is OK with respect to the Y axis, and I only want to scroll it horizontally? How can I align its left with the view left or its right with the view right?
EDIT
Here is more context. I have a YUI table with a horizontal scrollbar. I wish to scroll it programmatically to a certain TD node. I do not think window.scrollTo is of any help to me, since the scrollbar is on a div element, not on the whole page.
EDIT2
Turns out there is a duplicate SO question with the right answer - How can I scroll programmatically a div with its own scrollbars?
Voting to close mine.
I've recently had a problem with a table header that had inputs as filters for each column. Tabbing through the filters would move the focus, but if one of the inputs wasn't visible or if it was partly visible, it would only JUST bring the input into view, and I was asked to bring the full input and column into view. And then I was asked to do the same if tabbing backwards to the left.
This link helped to get me started: http://www.webdeveloper.com/forum/showthread.php?197612-scrollIntoView-horizontal
The short answer is that you want to use:
document.getElementById('myElement').scrollLeft = 50;
or:
$('#myElement')[0].scrollLeft = 50;
Here's my solution (which may be overkill for this question, but maybe it'll help someone):
// I used $.on() because the table was re-created every time the data was refreshed
// #tableWrapper is the div that limits the size of the viewable table
// don't ask me why I had to move the head head AND the body, they were in 2 different tables & divs, I didn't make the page
$('#someParentDiv').on('focus', '#tableWrapper input', function () {
var tableWidth = $('#tableWrapper')[0].offsetWidth;
var cellOffset = $(this).parent()[0].offsetLeft;
var cellWidth = $(this).parent()[0].offsetWidth;
var cellTotalOffset = cellOffset + cellWidth;
// if cell is cut off on the right
if (cellTotalOffset > tableWidth) {
var difference = cellTotalOffset - tableWidth;
$('#tableWrapper').find('.dataTables_scrollHead')[0].scrollLeft = difference;
$('#tableWrapper').find('.dataTables_scrollBody')[0].scrollLeft = difference;
}
// if cell is cut off on the left
else if ($('#tableWrapper').find('.dataTables_scrollHead')[0].scrollLeft > cellOffset) {
$('#tableWrapper').find('.dataTables_scrollHead')[0].scrollLeft = cellOffset;
$('#tableWrapper').find('.dataTables_scrollBody')[0].scrollLeft = cellOffset;
}
});
This is something I used a while back. There might be better and more efficient way of doing it but this gets the work done:
$(".item").click(function(event){
event.preventDefault();
// I broke it down into variable to make it easier to read
var tgt_full = this.href,
parts = tgt_full.split("#"),
tgt_clean = parts[1],
tgt_offset = $("#"+tgt_clean).offset(),
tgt_left = tgt_offset.left;
$('html, body').animate({scrollLeft:tgt_left}, 1000, "easeInOutExpo");
})
You just need to make sure that the item is an a tag with an href that corresponds to the target id element:
HTML:
go to section 1
...
<section id="one"> Section 1</section>
Hope this helps!
I have div with images inside it and need to scroll it left and right. I,ve managed to get the scrolling to work, but now I need it to stay in the displayable area.
I need to use jQuery
$('#next').click(function() {
$('#slides').animate({left: '-=80',}, 2000, function() {});
});
$('#prev').click(function() {
$('#slides').animate({left: '+=80',}, 2000, function() {});
});
The two "buttons" is used to scroll.
How do I get the slides' position.left to stay between 0 and -1120 ?
This will be the bottom of my slideshow. The large images will be at the top.
How do I change the z-index of a div ?
You change the z-index using css:
div.class {
z-index: 60;
}
You should get the width of your displayable area then by making use of the width() method.
If you have the maximum width you can use you can easily implement a check before your animation. So if the new width (current - 80) is bigger than 0, fine ... animate it. If not, don't.
Same for scrolling to the right. If it's bigger than your displayable area's width, then don't scroll.
EDIT
You changed your question slightly, so to get the current left value you can check it with:
$('#element').offset().left
This returns the current integer value of your left attribute. Thus again you can verify its current value and compare it with the one that it'd be like after you animated it. If it's too big or too small, don't scroll.
You can check the css left value is in the interval:
if(parseInt($('#slides').css('left')) > -1120 && parseInt($('#slides').css('left')) < 0){
....//animate here
}