Develop Reference

FormData not appending the data

I am just scratching my head, and do not understand, what happens here. This code has worked both in production and in my developer environment.
Here is the reference, I do exactly the same.
var fileToUpload = $('#productsFile').prop('files')[0];
var formData = new FormData();
formData.append('file', fileToUpload);
formData.append('action', 'csvUpload');
formData.append('siteId', $('#siteId').val());
console.log($('#siteId').val());
console.log(fileToUpload);
console.log(formData);
The output in the console:
10
File { name: "H00447.PriceList.csv", lastModified: 1464960003935, lastModifiedDate: Date 2016-06-03T13:20:03.935Z, size: 14859917, type: "application/vnd.ms-excel" }
FormData { }
Object has created, the values are fine, so what could be the problem here? Tested with Firefox Developer Edition.
EDIT
Here is the code to send the data to the ajax:
$.ajax({
url: ajaxUrl, // point to server-side PHP script
dataType: 'text', // what to expect back from the PHP script, if anything
cache: false,
contentType: false,
processData: false,
data: formData,
type: 'post'
}).done(function (msg) {
if (parseInt(msg) !== 0) {
alert(msg);
} else {
location.reload();
}
}).fail(function (msg) {
alert('Error: ' + msg.statusText);
});
In the ajax.php I just var_dump($_REQUEST); and shows me an empty array.
EDIT2
I tried it on another localhost environment, I've just added some random keys and values, and everything was fine, even in FF and Chrome.
So I came back to this issue, and just commented out the fileToUpload section.
The other two value was in the $_POST. If I add the file, the $_POST will be empty.
Something wrong with the file.
EDIT3
No I just tested it with a small file, what is about 3-4Kb, and everything is fine. My production file is 14Mb, I think that will be the problem.
SOLUTION
This whole thing because of the filesize. I incrased the post limit, and max file size in php.ini and viola. Things are works. Thank you for your help.

Try this to log keys and values:
formData.forEach(function (value, key) {
console.log(key, value);
});

The data is send but you need to use POST not GET:
var formData = new FormData();
formData.append('action', 'csvUpload');
var xhr = new XMLHttpRequest();
xhr.open("POST", "ajax.php", true);
xhr.send(formData);

What is wrong with this piece of code

This piece of code of a form submission is working perfectly in Google chrome meanwhile in Firefox it does not. Can somebody tell me what is wrong with my code?
$(document).ready(function(e){
/*sending post data to php script */
$("form[id='postForm']").submit(function(e){
e.preventDefault();
var text = $('#postText').val();
var formData = new FormData($(this)[0]);
formData.append('postText', text );
$.ajax({
url: "home.php?module=facebook&action=post-news&method=script",
type: "POST",
data: formData,
cache: false,
processData: false,
contentType: false,
context: this,
success: function (msg) {
window.location.reload();
}
});
e.preventDefault();
});
$('input:file').on('change', function () {
var formData = new FormData($(this)[0]);
//Append files infos
jQuery.each($(this)[0].files, function(i, file) {
formData.append('imageToPost[' + i + ']', file);
});
});
});

Quickly checked console:
TypeError: Argument 1 of FormData.constructor does not implement interface HTMLFormElement.
The problem is here:
$('input:file').on('change', function () {
var formData = new FormData($(this)[0]); <--- HERE
this is not a form, but input element. Not sure what you wanted to achieve here, but probably serialize your form. For this you need to do:
var form = $("#postForm")[0];
var formData = new FormData(form);
And then append your file.
Hope this helps.

pass data($post) to php file using javascript without callback

I need to pass data from HTML page to PHP page But without data callback ....
i'm used two method but One of them did not succeed
1)
$.ajax({
type: "POST",
url: 'phpexample.php',
data: {voteid: x },
success: function(data)
{
alert("success! X:" + data);
}
});
2)
$.post("getClassStudent.php",
{
},
function(data){
$("#div_id.php").html(data);
}
);

as i can understand, you just want to send info to a php script and don't need the response, is that right?
try this
$.post("phpexample.php", {voteid:x});
or simply remove the "succes" function from the equation if you feel more confortable using $.ajax instead of $.post
$.ajax({
type: "POST",
url: 'phpexample.php',
data: {voteid: x }
});
your fisrt example is correct, the second is not well formed.
more info:
http://api.jquery.com/jquery.post/
EDIT: to help you some more :)
<button type="button" id="element-id">click</button>
<button type="button" class="class-name">Click</button>
$(document).ready(function(){
//if you are marking ans element by class use '.class-name'
$(".class-name").click(function(){
$.post("getClassStudent.php");
});
//if marking by id element use '#id-name'
$("#element-id").click(function(){
$.post("getClassStudent.php");
});
});
be carefful with the markings, for debuggin try to use "console.log()" or "alert()" so you can see where is the problem and where the code crushes.

var formData = {
'voteid' : 'x',
};
$.ajax({
type : 'POST',
url : 'phpexample.php',
data : formData, // our data object
dataType : 'json',
encode : true
}).done(function(data) {
console.log(data);
});

Ajax Error Potentially Due to Incorrect Data Object Being Passed

Hi I am new to ajax and I am attempting to pass a Json to a Database, but I am not that far yet. Currently I am attempting to be verified that the data I am passing is being done successfully. However, I always drop into the ajax error method. I will upload my code and the way the data looks and then the error.
Thank you for your help!
<script>
function updateTable()
{
alert("Do i try to update table?");
document.getElementById("testLand").innerHTML = "Post Json";
//echo new table values for ID = x
}
function popupClick (){
var popupObj = {};
popupObj["Verified_By"] = $('#popupVBy').val();
popupObj["Date_Verified"] = $('#popupDV').val();
popupObj["Comments"] = $('#popupC').val();
popupObj["Notes"] = $('#popupN').val();
var popupString = JSON.stringify(popupObj);
alert(popupString);
$.ajax({
type: "POST",
dataType: "json",
url: "popupAjax.php",
data: popupObj,
cache: false,
success: function(data)
{
alert("Success");
updateTable();
},
error: function(data)
{
alert("there was an error in the ajax");
alert(JSON.stringify(data));
}
});
}
</script>
JSON Being Passed shown in var popupString:
Error:
popupAjax.php file (warning it's testy)
<?php
echo "Testing tests are testy";
?>

You are specifying the dataType as json. But this is the returned data type, not the type of the data you are sending.
You are returning html / text so you can just remove the dataType line:
type: "POST",
url: "popupAjax.php",
If you do want to return json, you need to build your datastructure on the server-side and send it at the end. In your test-case it would just be:
echo json_encode("Testing tests are testy");
But you could send a nested object or array as well.
As an additional note, you can use .serialize() on your form (if you use a form...) so that jQuery automatically builds an object that you can send in the ajax method. Then you don't have to do that manually.

How to send a parameter in data attribute of $.ajax() function in following scenario?

I've written one AJAX function code as follows :
$('#form').submit(function(e) {
var form = $(this);
var formdata = false;
if(window.FormData) {
formdata = new FormData(form[0]);
}
var formAction = form.attr('action');
$.ajax({
type : 'POST',
url : 'manufacturers.php',
cache : false,
data : formdata ? formdata : form.serialize(),
contentType : false,
processData : false,
success: function(response) {
if(response != 'error') {
//$('#messages').addClass('alert alert-success').text(response);
// OP requested to close the modal
$('#myModal').modal('hide');
} else {
$('#messages').addClass('alert alert-danger').text(response);
}
}
});
e.preventDefault();
});
Now here in data attribute I want to send some additional parameters with values in data attribute. How should I send these parameters to PHP file?
For clear understanding of my issue refer the following AJAX function code that I've written previously :
function GetPaymentRequest(status){
var status = $('#status_filter').val();
$.ajax({
type: "POST",
url: "view_payment_request.php",
data: {'op':'payment_request_by_status','request_status':status},
success: function(data) {
// alert(data);
}
});
}
In above function code you can see that I've passed few parameters with values viz. 'op':'payment_request_by_status','request_status':status in data attribute.
Exactly same parameters I want to pass in first AJAX function code. The already mentioned parameter "formdata ? formdata : form.serialize()" should also be there.
How should I do this? Can someone please help me in this regard?
Thanks in advance.

Add by using $.param
form.serialize() + '&' + $.param({'op':'payment_request_by_status','request_status':status});
or use serializeArray() and push new items
var data = form.serializeArray();
data.push({name:'op',value:'payment_request_by_status'}).push({name:'request_status',value:status});
then pass data

What you can do is, add two hidden fields to your already existing form, name one of them as op and set the value as payment_request_by_status and another one as request_status and the value based on the status.
When the form is serialized, it will automatically send these values also.