hi I currently have the following script and I'm trying to add a show and hide feature to it instead of just having one hide and show it. essentially "click me" shows it and the button hides it, fiddle example
http://jsfiddle.net/9M99G/
$(document).ready(function () {
var content = $('.below').hide();
$('.toggleBtn').on('click', function () {
$(this).next('.below').slideToggle();
return false;
});
});
Just do the same with the .below div and slideToggle it with $(this) :
$('.below').on('click', function(){
$(this).slideToggle();
});
demo jsFiddle
See more about slideToggle()
Use slideToggle
$('.below').on('click', function(){
$(this).slideToggle();
});
That will switch display state; if hidden it will show, if shown it will be hidden
If you want just the hide functionality for the button , this code will do
$(document).ready(function () {
var content = $('.below').hide();
$('.toggleBtn').on('click', function () {
$(this).next('.below').slideToggle();
return false;
});
$('.below').on('click', function(){
$(this).slideToggle();
});
});
Demo fiddle : http://jsfiddle.net/9M99G/4/
Or if you want to hide the Click Me while the hide button is being displayed the code below does exactly that
$(document).ready(function () {
var content = $('.below').hide();
$('.toggleBtn').on('click', function () {
$(this).hide();
$('.below').show();
return false;
});
$('.below').on('click', function () {
$(this).hide();
$('.toggleBtn').show();
return false;
});
});
Demo fiddle : http://jsfiddle.net/9M99G/6/
DEMO
Try this, use slideDown and slideUp
$(document).ready(function () {
$('.below').hide();
$('.toggleBtn').click(function () {
$(this).next('.below').slideDown('slow');
return false;
});
$('.below button').click(function () {
$(".below").slideUp('slow');
});
});
Related
This is my code:
Full code here: http://notepad.cc/casperjsstack1
this.thenOpen('https://www.1800flowers.com/webapp/wcs/stores/servlet/FDDeliveryOptionsDisplayCmd', function() {
this.waitForSelector('#BP-DeliveryCardMess_1', function() {
this.evaluate(function() {
var el = $('#giftMessages.noCard');
el.onclick();
});
});
});
Look at the picture: I want check No Gift Message
I try so much method but all false
Code HTML page here: http://notepad.cc/casperjsstack1_html
Thank you !
Have you tried click()?
this.thenOpen('https://www.1800flowers.com/webapp/wcs/stores/servlet/FDDeliveryOptionsDisplayCmd', function() {
this.waitForSelector('#BP-DeliveryCardMess_1', function() {
this.evaluate(function() {
this.click('#giftMessages.noCard'); // Click the radio button.
});
});
});
Try this.
//jQuery version using evaluation page context
this.thenOpen('https://www.1800flowers.com/webapp/wcs/stores/servlet/FDDeliveryOptionsDisplayCmd', function() {
this.waitForSelector('#BP-DeliveryCardMess_1', function() {
this.evaluate(function() {
$("#giftMessages.noCard").prop("checked", true).trigger("click");
});
});
});
//Casper version using click
this.thenOpen('https://www.1800flowers.com/webapp/wcs/stores/servlet/FDDeliveryOptionsDisplayCmd', function() {
this.waitForSelector('#BP-DeliveryCardMess_1', function() {
this.click("#giftMessages.noCard");
});
});
I want to display a different image when clicking on my image. A demo is here. When clicking on the image the image should change to an arrow pointing up instead of pointing down. How do I do that?
Here is my code:
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<td>
<div id="flip"><img src="http://i.imgur.com/YCf5zYt.png"></div>
<div id="panel" style="display: none;"><p><i><strong>CONTENT</strong></i></p>
</div>
</td>
JS
var toggled = false;
$("img").click(function () {
if (!toggled) {
$(this).css("", "url(http://i.imgur.com/YCf5zYt.png)");
toggled = true;
} else {
$(this).css("", "url(http://i.imgur.com/V4fKMWS.png)");
toggled = false;
}
$("p").slideToggle();
})
$(document).ready(function () {
$("#flip").click(function () {
$("#panel").slideToggle("slow");
});
});
Here's another solution with toggleClass() and attr() function :
See this fiddle
$(document).ready(function () {
$("img").click(function () {
$(this).toggleClass('active');
if($(this).hasClass('active')){
$(this).attr("src","http://i.imgur.com/V4fKMWS.png");
} else {
$(this).attr("src","http://i.imgur.com/YCf5zYt.png");
}
$("#panel").slideToggle();
});
});
There are a couple of issues with the code:
First of all, you have to attach all of the event handlers from within the document ready callback. As it stands right now, it is possible that event handler is not attached because image tag may be not yet loaded when you try to attach the handler.
You also have to modify the src attribute of the image, not the css's url style:
$(this).attr("src", "http://i.imgur.com/YCf5zYt.png");
you can change the attribue src.
if (!toggled) {
$(this).attr("src", "http://i.imgur.com/YCf5zYt.png");
toggled = true;
} else {
$(this).attr("src", "http://i.imgur.com/V4fKMWS.png");
toggled = false;
}
Refer link: https://jsfiddle.net/sj7o9x58/2/
there a mistakes in your code try this
var toggled = false;
$("img").click(function () {
if (!toggled) {
$(this).attr("src", "http://i.imgur.com/YCf5zYt.png");
toggled = true;
} else {
$(this).attr("src", "http://i.imgur.com/V4fKMWS.png");
toggled = false;
}
$("p").slideToggle();
});
Try to write all your code in $(document).ready(); And you have a big mistake.
You should use .slideToggle() for $("#panel"). And this is easier way to do it(without any variables):
$(document).ready(function(){
$("#flip").click(function(){
if($("#panel").css("display") === "none"){
$("#panel").slideToggle().css("display", "block");
$("img").attr("src", "http://i.imgur.com/V4fKMWS.png");
} else if($("#panel").css("display") === "block"){
$("#panel").slideToggle();
$("img").attr("src", "http://i.imgur.com/YCf5zYt.png");
}
});
});
And demo is here
$(document).ready(function () {
var toggled = true;
$("img").on('click',function () {
if (!toggled) {
$(this).attr("src", "http://i.imgur.com/YCf5zYt.png");
toggled = true;
} else {
$(this).attr("src", "http://i.imgur.com/V4fKMWS.png");
toggled = false;
}
$("#panel").slideToggle("slow");
});
});
The updated fiddle: https://jsfiddle.net/sj7o9x58/3/
I don't know if that's the image behavior you want, if it's the oposite just change te toggled initialization to false and the image by default on the src (html).
I am trying to use the same button to trigger an ajax call to add a database entry if it is clicked and then trigger a different ajax call to remove the entry it is clicked again.
I have tried using toggleClass and although the button class does change and it's appearance changes accordingly the function still thinks it has the old class name.
$(document).ready(function() {
$(".selected").on("click", function() {
$(this).text(function (i, oldText) {
return $.trim(oldText) == 'Use Image' ? 'Selected' : 'Use Image';
});
$(this).toggleClass('selected selected_btn');
});
$(".selected").on("click", function() {
alert('selected');
});
$(".selected_btn").on("click", function() {
alert('de selected');
});
});
With the present code the alert is always 'selected'.
$(document).ready(function() {
$(".selected_btn").on("click", function() {
$(this).text(function (i, oldText) {
return $.trim(oldText) == 'Use Image' ? 'Selected' : 'Use Image';
});
$(this).toggleClass('selected');
if($(this).hasClass("selected"))
alert("Selected")
else
alert("de-Selected")
});
});
here is a fiddle:
http://fiddle.jshell.net/prollygeek/3LLN2/
Here is a simple and readable example on how to do this:
$(document).ready(function() {
$('.select-img').on('click', function(){
var $el = $(this);
var isSelected = $el.attr('data-selected');
if( isSelected != 'true' ){
firstFn();
$el.html('Use Image').attr('data-selected', true)
}else{
secondFn();
$el.html('Select').attr('data-selected', false)
}
})
var firstFn = function(){
alert('first thing to do');
}
var secondFn = function(){
alert('second thing to do');
}
})
Demo
Use *Class functions:
hasClass
removeClass
addClass
Working code:
$("a").on("click", function() {
if($(this).hasClass("bob")) {
// do delete
alert("delete");
$(this).removeClass("bob");
} else {
// do insert
alert("insert");
$(this).addClass("bob");
}
});
Demo
$(".selected").on("click", function() {
alert('selected');
});
Overrides the event you put on the beginning of the document.ready, I think.
(might not be true, but I think it is)
I created jquery dropdown menu like this. I want to add slide effect on drop down menu. At the same time if I am placing my mouse over my menu tab the sub menu was opened now it is looking like one step up compare to the menu tab. I need slide like this. I here added my script.
function mainmenu() {
jQuery(" #na1").hover(function () {
//alert("hai-2");
jQuery(this).find('#content1').slideDown("fast");
}, function () {
jQuery(this).find('#content1').slideUp("fast");
});
}
$(document).ready(function () {
mainmenu();
});
Thanks in advance
$(document).ready(function () {
$("#na ul li").hover(function () {
$(this).siblings().find('ul').slideUp(400);
$(this).find('ul').slideDown(400);
}, function () {
$(this).find('ul').slideUp(400);
});
});
Demo:
http://jsfiddle.net/QkbDg/1/
Try this
$(document).ready(function () {
jQuery("#na ul li a").hover(function () {
jQuery(this).next('ul').slideDown(350);
}, function () {
jQuery(this).next('ul').slideUp(350);
});
});
DEMO
Try this:
function mainmenu(){
jQuery(" #na1").hover(function(){
jQuery(this).find('#content1').stop().slideDown("fast");
},function(){
jQuery(this).find('#content1').stop().slideUp("fast");
});
}
$(document).ready(function()
{
mainmenu();
});
Try this
function mainmenu(){
jQuery(".topm").hover(function(){
//alert("hai-2");
jQuery(this).find('.content').stop().slideDown("fast")
},function(){
jQuery(this).find('.content').stop().slideUp("fast");
});
}
$(document).ready(function()
{
mainmenu();
});
Demo : here
I want to Show and hide one tooltip on hover of an anchor. but tooltip should be there till my cursor on it.
fiddle
$('#showReasonTip').mouseover(function(){
$(this).parent().find('#reasonTip').slideDown()}).mouseout(function(){
$(this).parent().find('#reasonTip').slideUp()
}
)
thanks in advance.
Try
jQuery(function ($) {
$('#showReasonTip').hover(function () {
var $target = $('#reasonTip');
clearTimeout($target.data('hoverTimer'));
$target.stop(true, true).slideDown();
}, function () {
var $target = $('#reasonTip');
var timer = setTimeout(function () {
$target.stop(true, true).slideUp();
}, 200);
$target.data('hoverTimer', timer);
});
$($('#reasonTip')).hover(function () {
clearTimeout($(this).data('hoverTimer'));
}, function () {
$(this).stop(true, true).slideUp();
});
});
Demo: Fiddle
You should try using mouseleave instead of mouseout and that too on #reasonTip and not on #showReasonTip.
$('#showReasonTip').mouseover(function(){
$(this).parent().find('#reasonTip').slideDown()
});
$('#reasonTip').mouseleave(function(){
$(this).parent().find('#reasonTip').slideUp()
});
Here's the modified fiddle with a small change in your code.