I am trying to show the submit button when I click on the search field and I also am trying to hide it when the field closes (the is form located in the main navigation bar)...
This is my code :
$(document).ready(function(){
$("#search-click").click(function(){
$(".search-form .search-submit").css("display" , "block");
});
});
It's not working at all...this is my link : http://dev.pixstreammedia.com.s150147.gridserver.com/system/
Try this:
http://jsfiddle.net/5UJ5U/1/
HTML:
<form>
<input type="search" class="searchclick" placeholder="search">
<input type="submit" class="sub" value="search">
</form>
JS:
$(".sub").hide();
$(document).ready(function(){
$(".searchclick").click(function(){
$(".sub").fadeToggle('fast');
});
});
1.You are not showing the right id : your button has id : search-submit-button and you display block the other element but not this id, so the solution is to add #search-submit-button to your display block function.
2.As for the hiding you could do an mouseleave, to class: search-form then hide the button.
It's working the button is just tucked underneath. Also in the console the $ isn't assigned to jQuery, so I had manually use your snippet with jQuery directly.
jQuery(".search-form .search-submit").css("display" , "block");
Type that into your js console to see the button is there, but you only see a small portion of it.
Related
I'm having a problem in a checkout page of my website (wordpress based).
I have two kind of products and for each one, during checkout, I created custom fields to collect specific informations. With conditional rules (by plugin) some fields show up only if a list of specific option is checked.
When they are hidden, analysing the code, I've this situation:
<div class="form-row form-row-wide thwcfe-html-field-wrapper thwcfe-conditional-field" id="stud_no_req_field" data-name="stud_no_req" data-rules="[[[[{"operand_type":"field","value":"2","operator":"value_eq","operand":["student"]}]]]]" data-rules-action="show" style="display: none;">...</div>
When they are showing up, style attribute change in "block".
At the end of the page, I also have a button to submit the order.
<button type="submit" class="button alt" name="woocommerce_checkout_place_order" id="place_order" value="Associati" data-value="Associati">Associati</button>
I'm looking for a script that hides this button if custom file above has "display:block" and viceversa (show button if div has "display:none").
I've tried with this script (in checkout page), but nothing happens:
<script>
$(document).ready(function() {
if ($("#stud_no_req_field").style.display == "block")
{
$("#place_order").style.display = "none";
}
else
{
$("#place_order").style.display = "block";
}
});
</script>
I also need that this script is automatic (no click needed) and listens to any automatic change of div style (inside html tag).
Thank you very much!!! You are my angels!
You're using the wrong code. You should do
$("#place_order")[0].style.display = 'none'; // I added [0]
Or use jQuery API (https://api.jquery.com/css/)
$("#place_order").css('display', 'none');
I have a script that enables the disabled text box when clicking on a button. But, I just don't know how to re-disable the text box again.
The coding is below.
HTML:
<div class="input-group">
<label for="some-tbox" class="input-group-addon">Label:</label>
<input id="some-tbox" type="text" class="input-box" value="some value" disabled>
<span class="input-group-btn">
<button class="enable" type="button">button</button>
</span>
</div>
JS:
$(".enable").click(function(){
$(this).parent().parent().children(".input-box").removeAttr("disabled");
$(this).toggleClass("disable");
$(this).toggleClass("enable");
});
$(".disable").click(function(){
$(this).toggleClass("enable");
$(this).toggleClass("disable");
$(this).parent().parent().children(".input-box").attr("disabled", "disabled");
});
And I have made a fiddle out of it. But, It's not working. Here is the link.
Instead of messing with adding and removing classes, just toggle the disabled property with:
$(".enable").click(function() {
$(this).closest('.input-group').find('input').prop('disabled', !$(this).closest('.input-group').find('input').prop('disabled'))
});
jsFiddle example
The problem is this line $(".disable").click(function(){ ...})
You are binding a click event handler to a class named disabled which was not available initially during page load, it appears dynamically later.
You need to delegate the event handler to some parent which always exist and then handle the event there, in this case you can do this:
$(".input-group").on('click', '.disable', function(){
$(this).toggleClass("enable");
$(this).toggleClass("disable");
$(this).parent().parent().children(".input-box").attr("disabled", "disabled");
});
jQuery's on function
You cann't bind an element ".disable" that don't exist , In that case you can rebind it when you changed it's class. Code behind may help you:
$(".enable").on("click",enabledClick)
function enabledClick (argument) {
$(".enable").parent().parent().children(".input-box").removeAttr("disabled");
$(".enable").toggleClass("disable");
$(".enable").toggleClass("enable");
$(".disable").on("click",disabledClick)
}
function disabledClick (argument) {
$(".disable").parent().parent().children(".input-box").attr("disabled", "");
$(".disable").toggleClass("enable");
$(".disable").toggleClass("disable");
$(".enable").on("click",enabledClick)
}
I am very new to jQuery and HTML. I am trying to create a button in html that uses jQuery to make the button to prompt alert message when clicked (rather than using onclick in html). In other words, I would like to use the jquery to call up the click function for the button and then return a pop up message.
I have my input type as "button" and my value as "Check" for my button in html.
Here's my code in javascript
$(document).ready(function(){
$("button").click(function(){
alert("Pop Out");
});
but nothing is showing up
Here's a fiddle to my code
http://jsfiddle.net/0ynbv233/8/
I have my input type as "button"
Like this?
<input type="button" />
In that case, this won't work:
$("button")
That selector is looking for button elements, not input elements. You can change the element:
<button />
or you can change the selector:
$('input[type="button"]')
I did what you have done and it worked for me.
Here is what my code was.
$(function(){
$("button").click(function () {
alert("Pop Out");
});
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.9.1/jquery.min.js"></script>
<button>Click Me</button>
Hope you figure out what you are doing wrong.
I am creating a registration form where its contents are contained in DIV (hidden), then when the user clicks a button, the modal shows and the content is loaded through the ID of the DIV.
However, I am encountering a problem where the button of the DIV is not recognized in my script. I assigned a click event using jquery, but it doesn't work. Probably because the hidden DIV has conflicts with the DIV create in the modal (which will eventually have the same IDs).
Here is my script:
$('#addCollege').click(function(e){
modal.open({content: $('#addCollegeForm').html()});
e.preventDefault();`
});
This is the DIV
<div id="addCollegeForm" style="display:none">
<label>College:</label><br>
<input type="text" placeholder = "Enter college name here..." id = "collegeDescription" > <br>
<input type="button" value="Save" id= "addCollege">
</div>
Thanks and I appreciate your help.
I wrote a dialog plugin for bootstrap, and got a similar problem.
I want to pop up an existing dom element.
Here is solution:
$targetElement.detach().appendTo($window.find('.modal-body')) // $targetElement is an existing dom
Detach element and append it to container.
Don't forget to revert the element to old container.
Hope it helps.
Regards
Try moving the button that opens your dialog out of the dialog:
EDIT - something like this should work...
HTML...
<div id="addCollegeForm">things in your dialog</div>
<input type="button" value="open dialog" id="addCollege">
jquery...
$("#addCollegeForm").dialog({
autoOpen: false
});
$('#addCollege').click(function () {
$("#addCollegeForm").dialog("open");
});
http://jsfiddle.net/DTq6m/
http://api.jqueryui.com/dialog/#option-autoOpen
i have small-image class when i click on it megnefic popup open. in my megnific popup there is big image of clicked image and one button with other-form-opener class when i click on button other-form-div class with form comes up with my custom popup in this part when i click on form element they dont work as default.
<div class="megnific_opener"><img class="small-image" ></div>
<div class="megnific_popup_div">
<img class="big-image">
more-info
</div>
<div class="other-form-div">
<form>
<input type="text">
<input type="text">
<input type="text">
</form>
</div>
i give stucture of my html and i already cheked that there is not a z-index problem.
so please help me thank you.
here is my demo in jsfiddle : http://jsfiddle.net/QHh7W/
Please use Magnific popup callbacks and move your custom html inside Magnific popup when opened and move it inside body when closed. You can check below working demo.
jsFiddle demo
Although i cannot get this working as per your that is opening both popups one above another in same window.
but in case you need it like this : open second after clicking from one.
http://jsfiddle.net/yDvvQ/5/
I have added different instance of megnific for both divs.
It is working for both popups, content and form both.
You can later amend it to add more popups or return to first from second.
Please review once and comment.
Regards