Develop Reference

Time delay in js function load

There seems to be a time delay before the below mention functions starts to work. I'm not able to identify why it is so. Could anybody guide me on this??
The images do show initially but without the fade in or fade out effect but once all the images are done going the first loop, the animation works.
JS:
$(function fadeAnimation() {
$(".imageClass img:gt(0)").hide();
setInterval(function fadeAnimation() {
$(".imageClass :first-child")
.fadeOut(3000)
.next("img")
.fadeIn(3000)
.end()
.appendTo(".imageClass");
}, 5500);
});
HTML:
<div class="slidesDiv" id="cust">
<img class="imageClass" src="images/Folder1/1.jpg?" alt="" />
<img class="imageClass" src="images/Folder1/2.jpg?" alt="" />
<img class="imageClass" src="images/Folder1/3.jpg?" alt="" />
<img class="imageClass" src="images/Folder1/4.jpg?" alt="" />
<img class="imageClass" src="images/Folder1/5.jpg?" alt="" />
</div>

You have a couple issues in your code.
.imageClass are the <img>... You have to use the container's class, which is .slidesDiv.
You have to use the callback of the animations... Now, both .fadeIn() and .fadeOut are executing at the same moment.
Your timing is wrong... The animations are taking 6 seconds, but you have set the interval to 5,5 seconds.
See comments in code for the details.
$(function fadeAnimation() {
// Hide all image
$(".slidesDiv img").hide();
// Fade the first in right away.
$(".slidesDiv :first-child")
.fadeIn(3000);
// Start the interval to loo through all image
// The interval will execute for the first time in 6 seconds from now.
setInterval(function fadeAnimation() {
// Fade the first out.
$(".slidesDiv :first-child")
.fadeOut(3000, function(){ // This is a "callback" when the fade out is complete
// Fade In the next image
$(this).next("img")
.fadeIn(3000);
// append the faded out image to the end of the container.
$(this).appendTo(".slidesDiv");
});
}, 6000);
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="slidesDiv" id="cust">
<img class="imageClass" src="https://via.placeholder.com/200x200?text=1" alt="" />
<img class="imageClass" src="https://via.placeholder.com/200x200?text=2" alt="" />
<img class="imageClass" src="https://via.placeholder.com/200x200?text=3" alt="" />
<img class="imageClass" src="https://via.placeholder.com/200x200?text=4" alt="" />
<img class="imageClass" src="https://via.placeholder.com/200x200?text=5" alt="" />
</div>

Stop simple JavaScript slideshow after one loop

I know very little about JavaScript at all, but I'm looking for a solution to a simple code that I'd like to use. I'm not trying to execute any slides or fades, just a simple slideshow that switches from one image to the next. I want the slideshow to play through just once, and then stop on the last image in the sequence. Any help would be greatly appreciated!
$("#slideshow > div:gt(0)").hide();
setInterval(function() {
$('#slideshow > div:first')
.next()
.end()
.appendTo('#slideshow');
}, 3000);
As I said, it's a very simple code. The first GIF runs only once, the second GIF loops. I would like the slideshow to stop on the looping GIF. I'm wondering if the '3000' (which I know corresponds to the length of each slide) can be changed to accomplish what I'm looking for. Or else adding a stop function... which I don't know how to write.
<div id="slideshow">
<div>
<img src="https://31.media.tumblr.com/e2c4bbaeb781a3b834cd09549595393f/
tumblr_noy3q3l1dy1uwyyx9o2_1280.gif">
</div>
<div>
<img src="https://33.media.tumblr.com/1d6495399687801067d62c83c4218644/
tumblr_noy3q3l1dy1uwyyx9o1_1280.gif">
</div>
</div>

Ok I have made this with the objective of being as clear and simple for you to understand as possible, (since you new to js...)
JS/Jquery:
$(function () {
setTimeout(playSlideShow, 3000);
function playSlideShow() {
var currImgContainer = $('.showImg');
if (!$(currImgContainer).hasClass('lastImg')) {
$('.showImg').removeClass('showImg').next().addClass('showImg');
setTimeout(playSlideShow, 3000);
}
}
});
So here we find the imgContainer(div) with the class "showImg", then using chaining, we remove the class and add it to the next imgContainer(div). Therefore toggling the CSS to show/hide the image until it finds the div that has the class "lastImg".
CSS:
.slideShow > div:not(.showImg) {
display: none;
}
.showImg {
display: block;
width: 400px;
height: 400px;
}
HTML:
<div class="slideShow" id="slideshow">
<div class="showImg">
<img src="Images/img1.png" alt="" />
</div>
<div>
<img src="Images/img2.png" alt="" />
</div>
<div>
<img src="Images/img3.png" alt="" />
</div>
<div class="lastImg">
<img src="Images/img4.png" alt="" />
</div>
</div>
This way you can have as many images as you want, just make sure the last div has class "lastImg" and the first one has the class "showImg".
Here is a fiddle
Hope it helps...

Try this:
var intervalID = null;
var iterator = 0;
var intervalDuration = 3000;
var slideshow = $('#slideshow');
var divs = slideshow.find('div');
//divs.filter(':gt(0)').hide();
divs.eq(iterator).show();
intervalID = setInterval(function(){
divs.eq(iterator).hide();
iterator += 1;
if (iterator === divs.length - 1) { clearInterval(intervalID); }
divs.eq(iterator).show();
}, intervalDuration);
#slideshow > div { display: none; }
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<div id="slideshow">
<div>
<img src="https://dl.dropboxusercontent.com/u/45891870/Experiments/Codepen/PIXI/0.4/images/JS.jpg" />
</div>
<div>
<img src="https://dl.dropboxusercontent.com/u/45891870/Experiments/Codepen/PIXI/0.4/images/PIXI.jpg" />
</div>
<div>
<img src="https://dl.dropboxusercontent.com/u/45891870/Experiments/Codepen/PIXI/0.4/images/JS.jpg" />
</div>
</div>
The HTML structure is same as yours but the only thing that I have changed are the image sources (tumbler images weren't loading for me). But JavaScript has been changed completely.
Add as many DIVs as you like in your HTML to test it out. Hope it helps.
Update #1:
Added CSS to hide the divs by default.
Increased the intervalDuration to 3000. Just to make sure there is ample time for the images to be loaded.
Commented the filter line of JS.
Added another JS line right below the previous filter line.
This update should also load your GIF only when it is needed to appear, hence will not be running in the background.
Let me if this works.

Jquery cycle - slideshow with different speed transitions?

I’m trying to make a fade slideshow with different speed values for the transition effect.
I don't want to change the Timeout, or the Fx…I just want to change the speed transition value for each image...It is possible?
Thank you very much in advance!!!
This is the code:
$('#s1').cycle({
fx: 'fade',
speed: 1000, //this is that I want to change for each img!!!
timeout: 1700,
next: '#s1',
});
<div id="s1" class="pics">
<img src="img.jpg" width="450" height="300" />
<img src="img.jpg" width="450" height="300" />
<img src="img.jpg" width="450" height="300" />
</div>

I use the following property to declare per slide delays:
timeoutFn: function (a) { return $(a).data('delay') * 1000; },
/.../
which reads the "delay" data attribute from the slide.
I.e. your image tags needs to be decorated in the following manner:
<div id="s1" class="pics">
<img src="img.jpg" width="450" height="300" data-delay="1" />
<img src="img.jpg" width="450" height="300" data-delay="2" />
<img src="img.jpg" width="450" height="300" data-delay="3" />
</div>
EDIT:
I read your question too quickly. I realize now you did not want to change the delay between transitions - but rather the speed of the transition.
I have not done that myself, but one approach that might work is using the event "before" in the following manner:
$('#s1').cycle({
fx: 'fade',
speed: 1000, //this is that I want to change for each img!!!
timeout: 1700,
next: '#s1',
before: function(e1, e2, opts) { opts.speed = parseInt($(e1).data('speed')); }
});

fadein and fadeout jquery

I have this code:
<script src="http://code.jquery.com/jquery-1.8.2.js"></script>
<script src="http://code.jquery.com/ui/1.9.1/jquery-ui.js"></script>
<script>
$(function()
{
function animation()
{
$('#img0').attr('src',$('#img1').attr('src')).fadeOut(4000).attr('src',$('#img2').attr('src')).fadeIn(4000).fadeOut(4000).attr('src',$('#img3').attr('src')).fadeIn(4000).fadeOut(4000) ;
animation();
}
});
</script>
<body>
<img id="img0" width="613" height="260" alt="OffLease Only Lot" />
<img src="static/images/home/slides/SLIDERS-mP.jpg" id="img1" width="613" height="260" alt="OffLease Only Lot" hidden="true" />
<img src="static/images/home/slides/slider_usa.jpg" id="img2" width="613" height="260" alt="OffLease Only Lot" hidden="true" />
<img src="static/images/home/slides/SLIDERS-ODOMETER.jpg" id="img3" width="613" height="260" alt="OffLease Only Lot" hidden="true" />
</body>
</html>
i want slide showing the images by changing the source of image and proceed by appearing and disappearing it.
but my code didn't work
why?
how can i fix it?

If you're trying to cycle the three images, do something like this:
function animate1() {
$('#img1').fadeIn(4000, function() {
$('#img1').fadeOut(4000, animate2);
})
}
function animate2() {
// Do the same thing here, and do animate3 too
}
$(function() { $('#img0').fadeOut(4000, animate1) };
I would also take a minute to go over the jQuery fadeOut and fadeIn pages. I don't think they work the way you think they work.
http://api.jquery.com/fadeOut/
http://api.jquery.com/fadeIn/

You have to wait for an animation to finish first like this...
element$.fadeOut(4000, function () {
// Do something when faded out
element$.fadeIn(4000, function () {
// Do something when faded in
});
});

mouseover an image and show another, using jQuery

I have an image, and when I mouseover I want another image to 'slide' over the first image from the bottom up. On mouseout the image should disappear again, slide from top to bottom, showing the first image again.
How to do this with jQuery? I tried animate and slidetoggle, but I can't get it working.
EDIT: solution
<div class="image" style="width:90px;height:67px;position:relative;overflow:hidden">
<a href="#">
<img style="position:absolute;top:0;left;0;z-index:1;" class="first" src="images/stories/logos/in-dialoog.gif" alt="logo" />
<img style="position:absolute;top:0;left:0;z-index:0;" class="second" src="images/stories/logos/c-riders.gif" alt="logo" />
</a>
</div>
$('.image').mouseenter(function(){
$('.first').stop().animate({
top: '56px'
}, 800, function() {
// Animation complete.
});
});
$('.image').mouseleave(function(){
$('.first').stop().animate({
top: '0'
}, 800, function() {
// Animation complete.
});
});

Approximately something like this;
<style>
#wrap{width:200px;height:200px;position:relative;}
img{width:200px;height:200px;}
#img2{position:absolute;top:200px;left:0}
</style>
<div id='wrap'>
<img id='img1' src='blah' />
<img id='img2' src='blah' />
</div>
<script>
$(function(){
$('#wrap').mouseenter(function(){
$('#img2').stop().animate({top:'0px'})
})
}).mouseleave(function(){
$('#img2').stop().animate({top:'200px'})
});
</script>
... give or take a few variables
Or using your code (untested but should work);
<div id='wrap' style='position:relative'>
<img class="image" style="position:absolute;top:0;left;0;z-index:1;" class="first" src="images/stories/logos/in-dialoog.gif" alt="logo" />
<img style="position:absolute;top:0;left:0;z-index:0;" class="second" src="images/stories/logos/c-riders.gif" alt="logo" />
</div>
$('#wrap').mouseover(function(){
$('.second').animate({
height: 'toggle'
}, 800, function() {
// Animation complete.
});
}).mouseout(function(){
$('.second').animate({
height: 'toggle'
}, 800, function() {
// Animation complete.
});
});