I have a page linking to another separated page on the server. I would like to present a loader that finishes exactly when the second page is fully loaded. I dont use AJAX to call the second page, but a simple GET action. Is there a way to control that?
an example would be at: http://m.elal.co.il when you click on one of the buttons.
Thanks
I think the best way here is to preload page with ajax and then push all content of second page to body tag of this page.
Related
I have created a PHP/HTML document which uses jQuery to create a sliding page effect. I would like to have what the user selected on the first page correspond to what they see on the second page. I know how to do this if I was to use two separate pages however I would like to keep the sliding page effect.
The problem is that PHP is loaded first so for the second page nothing is displayed because on initially loading the page nothing is selected on the first page.
The only solution I have is to have the second page only load when the first is completed, but I have no idea how to do this. Does anyone know if its possible to have the document load at separate times?
UPDATE
On second thoughts could I use a XMLHttpRequest to achieve this? And if so how can I do this
Is it possible to make changes to the page source content through Ajax loaded by a jsp include in the main jsp ?
If not is it possible to reload that portion of the page alone (the jsp that loads some of the content) and to have a portion of the content in the page source changed ?
Details:
I've a variable called page this var gets its content from a java controller as a map of <String key,map<String key,String value>then it performs multiple actions and adds different params to the map, convert it to JSON and sends it to a jsp.
Recently I wanted to do something different,I want to add a param to the 'page' variable called contentOfThePage this variable gets its content dynamically when the document is fully loaded, after that I perform an Ajax request to the controller to add the new param, but the problem is that the new changes never makes it to the page source unless i reload the page or i navigate to another page and this is causing a lot of trouble as the page source may contain the page content of the previous page!
Any idea on how to avoid this and make changes to the page source (NOT DOM) directly ?
keep in mind that the contents are added dynamically but i need a way to change the page source without impacting the performance by requesting a reload after the ajax request succeeded
First You want to update some data that is already there after page load
you already have a json so a rest call i assume
you call it using ajax
now you added something else that you want to change
Yes it can be done actually
but not with the present set
i assume you have a single jsp and trying to change that jsp
well fit whatever you want to change in a panel like a graph or anything else
Add a button to top of the panel and on click the button url must be to the rest call so then data will be updated
I too have faced a similar problem with graphs,
i needed the graph to give updated data without refreshing the whole page,
so i put it inside a panel and wrote a rest controller that gives data for the graph and put a refresh button that calls this rest controller. This let me then update the graph without refreshing the rest of page
What I'm trying to do is make my website show 10 posts, then ask the user if he/she wants to load the "next page." What I want this "next page" button to do is load the content when the user clicks it.
The reason I want the div to just not load completely at all is for website speed. If my website hits let's say 100 posts, even if I just use a simple .hide(); function or something, then the website's still going to take it's time trying to load the 90 posts the website is hiding.
And yes I do realize if I'm worried about page performance I could just make new pages every time I reach 10 posts but that seems like it'd take a lot of time and be very confusing because it wouldn't work in order or something would be wrong with it.
You can't. If it is in the HTML document then it will be sent to the browser. It will be too late to stop it from loading at that point.
The only way to stop the div content from loading is to not have the div in the document in the first place, and then fetch more data from the server (which you would typically do with a link to the next page optionally with JavaScript progressively enhancing things to load the extra data with Ajax instead).
What you need to use is an XHR or Ajax request to get the next 10 posts, it is much better to do it this way rather than hiding them and activating them as needed, because even if you hide it the browser still had to download the content.
You should start by displaying just a few posts, and then load more as needed using XHR/Ajax.
jQuery provides some simple .ajax functions that should help you with retrieving the data as needed.
AJAX is your best bet.
For your needs you could do this two ways:
Make AJAX load more posts as soon as the user clicks the button.
As soon as your page loads (JQ ready function) you could fire an AJAX call to get 10 more posts and either print them in a DOM hidden element OR save them in some variable for later use. After you recover the posts succesfully (AJAX .success()) you could call the AJAX function again and run it again and make it repeat this process until it caches say... 100 posts in a variable or prints it in your DOM element.
You can do an ajax call every time the user clicks the button and append the result to the last div on your page using jquery
$( ".container" ).append( $( "div" ) );
If you want to create a page which will not load all the content at once and not have the user click a button, you can use lazyloading.
It was developed for loading of images, but it can be used for loading of div's too. See Layz Loading for Div
This works both when the user scrolls down and if they navigate to another page and then go back, it will only load part of the page that is visible. Meaning, if they are at the bottom, and they scroll up, it will reload the div's above.
Are there any clever ways of resetting a page back to it's original state (basically a reload) without having the screen physically look like it resets.
Basically i have a bunch of ajax requests, variables and content that i want wiped when a user clicks 'new' (currently i'm using just using location.reload(); ) but want a more graceful way of doing it.
I'm really wanting to refresh it without the screen going white for a split second and also want to retain a single modal popup i have which is open when the user clicks 'new'.
So the user clicks the 'new' button, a popup appears taking a parameter, the site refreshes and the parameter is passed to an Ajax request kicking off the start process.
If anyone could point me in the direction of what to even look for it'd be much appreciated.
"Are there any clever ways of resetting a page back to it's original state (basically a reload) without having the screen physically look like it resets."
You can't refresh the website without making it look like it refreshed, the browser needs time to display the content.
You can, however, use jQuery .load to load some standard markup into your site to make it appear as it did when it was initialized, the browser won't refresh, just like making an AJAX call doesn't require the website to refresh.
I'm, however, unable to see why you want the website to refresh if only to make an AJAX call.
The simple answer is to have the content you want to reload inside a container i.e.:
<div id="container"> page content </div>
Then when you have successfully got new data from the ajax call you can empty the container with:
$("#container").empty();
and repopulate it with
$("#container").append(newcontent);
You can use jQuery's .load to request and replace a portion of your page, e.g. a container element.
For example, calling the following on index.html would effectively "reset" the #container element:
$("#container").load("index.html #container");
See "Loading Page Fragments" on the docs for $.load.
As for resetting variables and cancelling any pending ajax requests - you could perhaps write a reset() function to do all that for you.
Another possibility would be to put data in local storage, or in the url after a # before the reload. But your options for having it look like it isn't refreshing are pretty limited outside of jQuery .load or an XHR request (which is what the jQuery load does)
I have following page with some random tips: http://www.javaexperience.com/tips
I want to display the tips only on the other pages of website so I am making an ajax call and adding whatever returned by the ajax response to a Div's HTML.
The DIV html is:
<div id="tips"><div>
The ajax call is:
jQuery("#tips").load("/tips/");
The problem is that the ajax call results in whole page content to be added to div (since the page gets appended to the div, the above jQuery code gets invoked infinitely) where as I want to add only the tips section. Is there any easy way out?
This is the expected behavior of the load method, it'll always download the entire content. You can specify that a certain part of the loaded page be parsed and placed into the calling container.
jQuery('#tips').load('url #tip1');
You need:
$('#tips').load('ajax/test.html #container');
More info on load here