I have many forms like the following on the page. Now I want change the form action based on which submit button the user clicked (and of course submit the form)
<form action="/shop/products.php" data-ajax="false" method="post">
<div data-role="fieldcontain">
<input name="submit" class="obutn" type="submit" value="Order" />
<input name="submit" class="oEbutn" type="submit" value="Extras" />
</div>
</form>
I tried with
$(".obtn").click(function() {
$(this).parent().parent().attr("action", "/shop/products.php");
});
$(".oEbtn").click(function() {
$(this).parent().parent().attr("action", "/shop/extras.php");
});
but the form is always submited to products.php. Can you tell me what's wrong?
Instead of setting the action attribute on the form itself, consider setting formaction attribute on each individual input element.
Docs: http://www.w3.org/TR/html-markup/input.submit.html#input.submit.attrs.formaction
<form data-ajax="false" method="post">
<div data-role="fieldcontain">
<input formaction="/shop/products.php"
name="submit" class="obutn" type="submit" value="Order" />
<input formaction="/shop/extras.php"
name="submit" class="oEbutn" type="submit" value="Extras" />
</div>
</form>
There are two typos:
obtn instead of obutn
oEbtn instead of oEbutn
Another suggestion is to use closest("form") to get the form that contains the clicked button.
$(".obutn").click(function() {
$(this).closest("form").attr("action", "/shop/products.php");
});
$(".oEbutn").click(function() {
$(this).closest("form").attr("action", "/shop/extras.php");
});
$("form").on("submit", function () {
alert($(this).attr("action"));
});
JSFIDDLE
Capture the submit event and determine which button was clicked. From that, you can change the action of the form.
Here's a link on how to do that.
How can I get the button that caused the submit from the form submit event?
Also, don't give the form the action until the click happens at all, it is superfluous.
<form data-ajax="false" method="post">
<div data-role="fieldcontain">
<input name="submit" class="obutn" type="submit" value="Order" />
<input name="submit" class="oEbutn" type="submit" value="Extras" />
</div>
</form>
What if you try it out with a switch instead? Something like:
<input name="submit" id = "1" class="obutn" type="submit" value="Order" />
<input name="submit" id = "2" class="oEbutn" type="submit" value="Extras" />
And then in JavaScript we have:
//param: The Id attr of the button that was clicked
function postTo(id){
switch(id){
case 1: postProducts();
break;
case 2: postExtras();
break;
default: //Do something else
}
}
Just an idea. Haven´t tested that yet, but maybe it could be helpful. I hope so.
Related
If I have a simple html form with two submit buttons:
<form method="POST" class="submit_form main_form" action="myaction">
<input type="submit" name="goback" value="Go Back" />
<input type="submit" name="confirm" value="Confirm">
<input type="hidden" name="secret" value="hello"/>
</form>
It is possible to only post the hidden input if the "confirm" submit is clicked?
If the "goback" submit is clicked the hidden input should be ignored. I know how to accomplish this with JavaScript but was wondering if it can be done with just html.
For anyone wondering, this is how you do this in JavaScript:
<script>
var elements = document.getElementsByClassName('submit_form');
elements[0].addEventListener(
'submit',
function(event) {
if(event.explicitOriginalTarget.name === 'goback'){
var hiddenInput = document.querySelector("input[name='step']");
hiddenInput.setAttribute("disabled", "disabled");
}
}
);
</script>
You could put the buttons in 2 separate forms:
<form method="POST" class="submit_form main_form" action="myaction">
<input type="submit" name="goback" value="Go Back" />
</form>
<form method="POST" class="submit_form main_form" action="myaction">
<input type="submit" name="confirm" value="Confirm">
<input type="hidden" name="secret" value="hello"/>
</form>
That way the secret field will only be posted if the confirm button is clicked.
If you want to do it in the php code you can leave your form as is
and check if isset($_POST["confirm"]) to check if the confirm button was the one clicked.
I have a form where I would like to hide the submit button unless the input is focussed/selected.
There is only one input apart from the submit.
I need to do this using pure JS (or perhaps CSS/Sass), not jQuery etc.
Basic example:
<form>
<input type="text" placeholder="Example field">
<input type="submit value="Submit">
</form>
First get references to your objects, so change the HTML for example :
<form>
<input id="input_1" type="text" placeholder="Example field">
<input id="submit" type="submit" value="Submit" />
</form>
With some CSS we will hide the submit by default:
#submit{
display:none;
}
We have added Id's, now we add the event listeners for focus on input..
document.getElementById("input_1").addEventListener('focus', function(){
document.getElementById("submit").style.display = 'block';
}
, true);
The second param into the eventListener will execute when the event is fired..
You will need to do more work on this..
https://jsfiddle.net/7uzkzr67/
Here is the pure CSS solution;
.showonfocus{
display:none;
}
.inputfield:focus + .showonfocus{
display:inline;
}
<form>
<input type="text" placeholder="Example field" class="inputfield">
<input type="submit" value="Submit" class="showonfocus">
</form>
You can use the onblur and onfocus events to manipulate your html elements. You can try something like,
HTML
<form>
<input type="text" placeholder="Example field" onblur="setVisible('hidden');" onfocus="setVisible('visible');">
<input id="submit" type="submit" value="Submit" style="visibility:hidden">
</form>
Javscript
function setVisible(state) {
document.getElementById("submit").style.visibility = state;
}
Here is the working DEMO: https://jsfiddle.net/qbotxpL6/
Hope this helps!
I created HTML form which has two buttons, one for calling java script for form validations and the other one back to the previous page, the two buttons act as submit and validate the inputs.
Here is the code for the form and the button:
<form id = "myform" method="post" action="SearchForCustomer" onsubmit="return validateForm()">
<input type="submit" value="Search" style="width: 100%;" onclick="toggleTable();" />
<input type="button" value="back" style="width: 100%;" onclick="document.forms[0].action = 'homePage.jsp'; return true;" />
</form>
I want the back button to only back whatever the validations was, any suggestions?
Thanks in Advance.
Actually i didnt get your question but why to use input[type=submit] to goto any page (or back)?
It should be:
<input type="button"...
type="submit" will submit form in either case.
You have two buttons of type submit. Have only 1.
<form id = "myform" method="post" action="SearchForCustomer" onsubmit="return validateForm()">
<input type="submit" name = "searchButton" id = "searchButton" value="Search" style="width: 100%;" onclick="toggleTable();" />
<input type="button" value="back" style="width: 100%;" onclick="document.forms[0].action = 'homePage.jsp'; return true;" />
</form>
whenever i click on submit button it fires alert("empty username") but goes a head and directs me to checklogin.php...how can i avoid that and let it remain on the page unless the field is not empty?
</body>
</html>
<script type="text/javascript"></script>
function RequiredFields(){
var username=document.forms["login"]["username"].value;
if (username==""||username==null){
alert("empty username")
document.login.username.focus();
if(document.all||document.getElementById){
return false;
}
}
}
</script>
<form action="checklogin.php" method="POST" onSubmit="RequiredFields()">
Username<input type="text" name="username"/>
Password<input type="password" name="password"/>
<input type="submit" value="Login" />
</form>
</body>
</html>
in the submit input you can add the event handler of onsubmit like this:
<input type="submit" value="submit form" onsubmit="return RequiredFields();"/>
the RequiredFields will return false if not all the required fields are full and the submit process will stop.
When you change your submit to this it won't submit if RequiredFields returns false.
<input type="submit" value="Login" onsubmit="return RequiredFields();"/>
Use this code
<input type="submit" value="Login" onclick="return RequiredFields()" />
I think this might work.
function xyz(event)
{
event.preventDefault(); // while the function returns false
}
also you may use HTML5 attribute required to avoid javascript overburden.
<*input type="" required>*
I am new to forms, and Javascript, so please be forgiving.
I have a form that looks like this:
<form method="post" action="control" name="myform">
<input type="submit" name="Name" value="Do A"/>
<input type="submit" name="Name" value="Do B" />
<input type="submit" name="Name" value="Do C" />
<input type="submit" name="Name" value="Close" />
</form>
I need to change this so that there are two buttons, and the form is submitted using javascript dependent on some external conditions, so I want it to look something like this:
<form method="post" action="control" name="myform">
<script>
function submitForm(form){
if(someConditionA){
submit the form so that the script performs same action as if the button Do A had been clicked
} if (someConditionB){
submit the form so that the script performs same action as if the button Do B had been clicked
} if (someConditionC){
submit the form so that the script performs same action as if the button Do C had been clicked
}
}
function closeForm(form){
window.close();
}
</script>
<button name="doAction" onClick="SubmitForm(this.form)">Do Action<\button>
<button name="close" onClick="SubmitForm(this.form)">Close<\button>
</form>
How can I implement the function submitForm?
Thanks
Add a hidden field with the same name as the original submit buttons:
<input type="HIDDEN" name="Name" value=""/>
Set the value of that field based on your conditions:
function submitForm(form){
if(someConditionA){
form.Name.value = "Do A";
} if (someConditionB){
form.Name.value = "Do B";
} if (someConditionC){
form.Name.value = "Do C";
}
form.submit();
}
Change the new Close button to this:
<button name="close" onClick="this.form.Name.value='Close';this.form.submit();">Close<\button>
I haven't tested this, so it may contain a mistake or two, but that's the general idea. (+1 for 'this.form', not many folks know about that, nice.)
Have just figured out the answer to my question:
The way to do it is to have a hidden field:
<input type="hidden" name="Name" value=""/>
Then in the function, set this hidden field to have the same value as the respective button.
Well, you should simply name your submit buttons differently.
<form method="post" action="control" name="myform">
<input type="submit" name="SubmitA" value="Do A"/>
<input type="submit" name="SubmitB" value="Do B" />
</form>
This way, when submitted, the server will be able to distinguish which submit was clicked.
not sure if I got your Problem right, but why dont you just make a click event on those submit buttons?
like
$('#mysendbtn').click(function(){ ...do A });