I have an array that looks like this:
var locationsArray = [['title1','description1','12'],['title2','description2','7'],['title3','description3','57']];
I can't figure out what type of array this is. More importantly, I'm gonna have to create one based on the info there. So, if the number on the end is greater than 10 then create a brand new array in the same exact style, but only with the title and description.
var newArray = [];
// just a guess
if(locationsArray[0,2]>10){
//add to my newArray like this : ['title1','description1'],['title3','description3']
?
}
How can I do it?
Try like below,
var newArray = [];
for (var i = 0; i < locationsArray.length; i++) {
if (parseInt(locationsArray[i][2], 10) > 10) {
newArray.push([locationsArray[i][0], locationsArray[i][1]]);
}
}
DEMO: http://jsfiddle.net/cT6NV/
It's an array of arrays, also known as a 2-dimensional array. Each index contains its own array that has its own set of indexes.
For instance, if I retrieve locationsArray[0] I get ['title1','description1','12']. If I needed to get the title from the first array, I can access it by locationsArray[0][0] to get 'title1'.
Completing your example:
var newArray = [];
// just a guess
if(locationsArray[0][2]>10){
newArray.push( [ locationsArray[0][0], locationsArray[0][1] ] );
}
throw that in a loop and you're good to go.
It's an array of arrays of strings.
Each time there is this : [], it defines an array, and the content can be anything (such as another array, in your case).
So, if we take the following example :
var myArray = ["string", "string2", ["string3-1", "string3-2"]];
The values would be as such :
myArray[0] == "string"
myArray[1] == "string2"
myArray[2][0] == "string3-1"
myArray[2][1] == "string3-2"
There can be as many levels of depth as your RAM can handle.
locationsArray is an array of arrays. The first [] operator indexes into the main array (e.g. locationsArray[0] = ['title1','description1','12']) while a second [] operation indexes into the array that the first index pointed to (e.g. locationsArray[0][1] = 'description1').
Your newArray looks like it needs to be the same thing.
It's an array of array.
var newArray = [];
var locationsArray = [
['title1','description1','12'],
['title2','description2','7'],
['title3','description3','57']
];
for(i = 0; i < locationsArray.length; i++) {
if (locationsArray[i][2] > 10) {
newArray .push([locationsArray[i][0], locationsArray[i][1]]);
}
}
console.log(newArray );
Related
I am trying to get unique values from two arrays which looks like that:
array[{A,B,C},{C,D,E},{1,3,2},....]
both looks the same.
I tried to add them using concat and the get unique values from looping.
So I ended up with this:
function uniqueValues() {
var ss = SpreadsheetApp.getActiveSpreadsheet();
var srcSheet = ss.getSheetByName("arr1");
const array1 = srcSheet.getRange(1, 1, srcSheet.getLastRow(), srcSheet.getLastColumn()).getValues();
var srcSheet1 = ss.getSheetByName("arr2");
const array2 = srcSheet1.getRange(1, 1, srcSheet1.getLastRow(), srcSheet1.getLastColumn()).getValues();
var dodaj = array1.concat(array2);
for (var i=0; i<dodaj.length; i++) {
var listI = dodaj[i];
loopJ: for (var j=0; j<dodaj.length; j++) {
var listJ = dodaj[j];
if (listI === listJ) continue;
for (var k=listJ.length; k>=0; k--) {
if (listJ[k] !== listI[k]) continue loopJ;
}
dodaj.splice(j, 1);
}
}
var result = ss.getSheetByName("test").getRange(2, 5, dodaj.length, 3).setValues(dodaj);
//Logger.log(dodaj);
}
It was working well when array looked like this array[{A,B},{C,D}] but with three elements it started to return duplicates as well... I have no idea what can be wrong.
If I understand you correctly, you want to retrieve the unique rows from the values in arr1 and arr2. That is to say, you want to remove duplicate inner arrays from dodaj.
After using concat to merge the two arrays, you could do the following:
Use JSON.stringify() to transform each inner array to a string, in order to compare them without iterating through them.
Use the Set constructor and the spread syntax in order to remove the duplicate strings (see this answer).
Transform the strings back to arrays with JSON.parse().
Code snippet:
var dodaj = array1.concat(array2);
dodaj = [...new Set(dodaj.map(JSON.stringify))].map(JSON.parse);
var result = ss.getSheetByName("test").getRange(2, 5, dodaj.length, dodaj[0].length).setValues(dodaj);
I made a multidimensional array today which creates 4 new arrays within the first array. when I console.log my array it says that there are 0 items in it, but i do see my 4 arrays each with other items. See the console.log below for a clearer image:
vm.allGroupsInClassifications = [];
datacontext.graph.getAllGroups().then(function (data) {
var groups = [];
// get all clasification names and put them in the array and create a new array
for (var k in vm.classificationNames) {
var groupName = vm.classificationNames[k];
groups[groupName] = new Array();
}
// go through all the groups and sort them based on their classification
for (var i = 0; i < data.length; i++) {
if (data[i].classification != null) {
modifyGroupContent(data[i], groups, 0);
}
else if (data[i].classification == null)
modifyGroupContent(data[i], groups, 1);
}
vm.allGroupsInClassifications = groups;
console.log(vm.allGroupsInClassifications);
any help would be appreciated. Cheers!
Because you have no indexes. groups[groupName] = new Array(); won't add an item to your array, because all your groupName variables are not numbers. And thus you have an array-object-like thing.
If your groupName's were say 0,1,2 and 3, when you console.log the object, you will get the last number+1 (in this case 4).
Here you can access your arrays with the keys - so in this case vm.allGroupsInClassifications['Confidential'] will return your array.
But since you don't have actual numeric indexes, the length of your object-array thing is 0.
Hope you understand
It's because your array is incorrect. You have an array with keys :
[
"Algemeen" : [...],
"Confidential" : [...]
]
This is incorrect, as arrays can't have keys. Javascript being Javascript, it allows you to define it nonetheless, but when you ask for its length, it's quite unable to answer and says 0. It should be an object :
{
"Algemeen" : [...],
"Confidential" : [...]
}
If you really want to keep an array of arrays, remove the keys :
[ [...],[...] ]
Now the length is 2.
I have an JavaScript array:
var arr = [["A",["05",90]],["A",["04",240]],["A",["03",235]],["B",["00",123]],["B",["01",234]]];
I want final array to look like:
var final = [["A",[["05",90],["04",240],["03",235]]],["B",[["00",123],["01",234]]]];
The final array is formed by combining all the 2nd element of 2 dimensional array when the 1st element matches.
Please advice how can this be achieved in JavaScript
Object keys are generally the easiest way to create groups like this
var tmp = {}; // temporary grouping object
// loop over data
arr.forEach(function (item) {
// check if group started
if (!tmp.hasOwnProperty(item[0])) {
tmp[item[0]] = [];
}
// push data to group
tmp[item[0]].push(item[1]);
});
// map temp object to results array
var results = Object.keys(tmp).map(function (key) {
return [key, tmp[key]];
});
DEMO
If you start with the array you gave:
var arr = [["A",["05",90]],["A",["04",240]],["A",["03",235]],["B",["00",123]],["B",["01",234]]];
then create a new array to store the values:
var final = [];
and simply combine all of the third-level elements (such as ["05",90] and ["01",234]) of each second-level ones (such as "A" and "B") by looping through the array:
for(var i = 0; i < arr.length; i++) {
var found = false;
for(var j = 0; j < final.length; j++) {
if(arr[i][0] == final[j][0]) {
final[j][1].push(arr[i][1]);
found = true;
break;
}
}
if(!found) {
final[final.length] = [arr[i][0], [[arr[i][1][0], arr[i][1][1]]]];
}
}
This is essentially a sorting method: if the "key" is equal to one in the final array, then it adds it to that one. If not, then appends it to the end of final.
Here's the working example on JSFiddle: link.
This outputs the array:
["A", [["05", 90], ["04", 240], ["03", 235]]], ["B", [["00", 123], ["01", 234]]]
as requested.
Also, as #PaulS commented, it would be recommended to use Objects instead as Strings, to make them Key-Value pairs. But in my answer I stuck with arrays.
I have not been able to figure out how to properly accomplish this.
I have a JS array of objects that looks like this:
[{"num":"09599","name":"KCC","id":null},{"num":"000027","name":"Johns","id":null}]
I would like to convert this into a simple, single JS array, without any of the keys, it should look like this:
[
"09599",
"KCC",
"000027",
"Johns" ]
The IDs can be dropped entirely. Any help would be really appreciated.
Simply iterate the original array, pick the interesting keys and accumulate them in another array, like this
var keys = ['num', 'name'],
result = [];
for (var i = 0; i < data.length; i += 1) {
// Get the current object to be processed
var currentObject = data[i];
for (var j = 0; j < keys.length; j += 1) {
// Get the current key to be picked from the object
var currentKey = keys[j];
// Get the value corresponding to the key from the object and
// push it to the array
result.push(currentObject[currentKey]);
}
}
console.log(result);
// [ '09599', 'KCC', '000027', 'Johns' ]
Here, data is the original array in the question. keys is an array of keys which you like to extract from the objects.
If you want to do this purely with functional programming technique, then you can use Array.prototype.reduce, Array.prototype.concat and Array.prototype.map, like this
var keys = ['num', 'name'];
console.log(data.reduce(function (result, currentObject) {
return result.concat(keys.map(function (currentKey) {
return currentObject[currentKey];
}));
}, []));
// [ '09599', 'KCC', '000027', 'Johns' ]
You can use Object.keys() and .forEach() method to iterate through your array of object, and use .map() to build your filtered array.
var array = [{"num":"09599","name":"KCC","id":null},{"num":"000027","name":"Johns","id":null}];
var filtered = array.map(function(elm){
var tmp = [];
//Loop over keys of object elm
Object.keys(elm).forEach(function(value){
//If key not equal to id
value !== 'id'
//Push element to temporary array
? tmp.push(elm[value])
//otherwise, do nothing
: false
});
//return our array
return tmp;
});
//Flat our filtered array
filtered = [].concat.apply([], filtered);
console.log(filtered);
//["09599", "KCC", "000027", "Johns"]
How about using map :
var data = [
{"num":"09599","name":"KCC","id":null}
{"num":"000027","name":"Johns","id":null}
];
var result = data.map(function(obj) {
return [
obj.num,
obj.name,
obj.id
];
});
Result holds dynamic value in array but after sorting the result also get sorted but I don't want it to get sorted. But after sorting its also get sorted. Why is that?
$scope.arreyList = result;
var sorted_arr = $scope.arreyList.sort();
$scope.countRowSame = [];
for (var i = 0; i < sorted_arr.length - 1; i++) {
if (sorted_arr[i + 1].SupplierId == sorted_arr[i].SupplierId) {
$scope.countRowSame.push(sorted_arr[i].SupplierId);
}
}
sort sorts the array in place. So this line:
var sorted_arr = $scope.arreyList.sort();
sorts the $scope.arreyList, and returns a reference to that same array. It doesn't create a sorted copy of the array.
If you want to make a copy and sort that, use slice:
var sorted_arr = $scope.arreyList.slice(0).sort();
In addition to #Crowder's answer you can use angular.copy() to clone the array.
$scope.arreyList = angular.copy(result);
var sorted_arr = $scope.arreyList.sort();