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Using javascript or python regular expressions I want to determine if the number is 1-99 how to make it?

var category = prompt("where do you go? (1~99)", "");
hello
Using regular expressions I want to determine if the category is 1-99.
How can I solve it?
Thank you if you let me know.

You can use character classes to match digits, like this [0-9]. If you put two of them together you'll match 00 - 99. If you put a ? after one of them, then it's optional, so you'll match 0 - 99. To enforce 1-99, make the non-optional one like this [1-9]. Finally, you need to make sure there's nothing before or after the one or two digits using ^, which matches the beginning of the string, and $ which matches the end.
if (category.match(/^[1-9][0-9]?$/)){
console.log("ok")
} else {
console.log("not ok")
}

In JavaScript you can use test() method with RE for 1-99 as shown below:
var one_to_ninetynine = /^[1-9][0-9]?$/i;
if(one_to_ninetynine.test(category)) {
console.log("The number is between 1-99");
} else {
console.log("The number is NOT between 1-99");
}

must at least have number and characters regex

I still don't understand how to use regex and there is regex like this :
/^[a-zA-Z0-9\s]+$/
and i use it in javascript
$('#oldPass, #newPass, #confpass').keydown(function (e) {
var inputValue = e.key;
if(inputValue.match(/^[a-zA-Z0-9\s]+$/)){
return;
}else{
e.preventDefault();
}
});
it works, i can't type anything beside alphanumeric, but how can i make that the new password must contain combination number and characters?

Minimum of 8 letters with atleast one letter and number.
^(?=.*[A-Za-z])(?=.*\d)[A-Za-z\d]{8,}
check this link for verification
https://regex101.com/r/DcxNSc/1

Regex to validate a password [duplicate]

This question already has answers here:
Closed 10 years ago.
Possible Duplicate:
Password validation regex
between 8 and 16 characters, with at least 1 character from each of the 3 character classes -alphabetic upper and lower case, numeric, symbols.
I have this code, but it doesn't work, when I write more than 16 characters, gives it as valid, but it should not; the it should to work ok with 3 character classes, but it works with 4, where's my mistake??
http://jsbin.com/ugesow/1/edit
<label for="pass">Enter Pass: </label>
<input type="text" id="pass" onkeyup="validate()">
Script
function validate() {
valor = document.getElementById('pass').value;
if (!(/(?=.{8,16})(?=.*?[^\w\s])(?=.*?[0-9])(?=.*?[A-Z]).*?[a-z].*/.test(valor))) {
document.getElementById('pass').style.backgroundColor = "red";
} else {
document.getElementById('pass').style.backgroundColor = "#adff2f";
}
}

Regular expressions are not a panacea. It's not too hard to do it, mixing with regular code:
function validatePassword(password) {
// First, check the length.
// Please see my comment on the question about maximum password lengths.
if(password.length < 8 || password.length > 16) return false;
// Next, check for alphabetic characters.
if(!/[A-Z]/i.match(password)) return false;
// Next, check for numbers.
if(!/\d/.match(password)) return false;
// Next, check for anything besides those.
if(!/[^A-Z\d]/i.match(password)) return false;
// If we're here, it's valid.
return true;
}
However, I'd look into something like zxcvbn, a password checker, which I think is a better password quality checker, checking things like common dictionary words after un-13375p3/-\kification and dealing with entropy decently. It is used, among others, by Dropbox. Try it here.

You need to anchor the match to the beginning of the string, and anchor the first lookahead to the end:
^(?=.{8,16}$)
Also, the last lookahead needs to be split in two:
(?=.*?[A-Z])(?=.*?[a-z])

Why don't you just test for the three character sets with regular expressions:
[A-Za-z0-9]+
Then count the length of the string to validate the length.

What about this range:
/[A-Za-z0-9$-/:-?{-~!"^_`\[\]]/
So you can check first
/[A-Za-z]+/
then
/\d+/
and finally
/[$-/:-?{-~!"^_`\[\]]+/
If it passes you can check the length.
You can see this link to see why the symbols work.

What's wrong with my JavaScript regex / regex syntax?

I need a regex to use with javascript/jquery that fits these rules...
it will include 10 digits
if there is a leading 1 or +1 it should be ignored
valid characters allowed in the field are... 0-9,(), and -
I found a regex at Snipplr (the first one), but its not working. First of all, I'm not even sure if that regex fits my rules. Secondly, its allowing inputs like &^%$$#%^adfafsd. I believe the error is in my code not the regex. For example, are there supposed to be quotes around the expression?
Here is the code that is supposed to be validating the phone field...
$('#phone').bind('blur', function() {
var pattern = new RegExp("^(?:\+?1\s*(?:[.-]\s*)?)?(?:\(\s*([2-9]1[02-9]|[2-9][02-8]1|[2-9][02-8][02-9])\s*\)|([2-9]1[02-9]|[2-9][02-8]1|[2-9][02-8][02-9]))\s*(?:[.-]\s*)?([2-9]1[02-9]|[2-9][02-9]1|[2-9][02-9]{2})\s*(?:[.-]\s*)?([0-9]{4})$");
if(pattern.test($('#phone').val())){
$("#phone").addClass("error");
return false;
}else{
$("#phone").removeClass("error");
return true;
}
return true;
})

When you're not using the literal form ( /[regex]/ ), you need to escape the regex string. Try this instead:
var regex = /^(?:\+?1\s*(?:[.-]\s*)?)?(?:\(\s*([2-9]1[02-9]|[2-9][02-8]1|[2-9][02-8][02-9])\s*\)|([2-9]1[02-9]|[2-9][02-8]1|[2-9][02-8][02-9]))\s*(?:[.-]\s*)?([2-9]1[02-9]|[2-9][02-9]1|[2-9][02-9]{2})\s*(?:[.-]\s*)?([0-9]{4})$/;
if(regex.test($('#phone').val()){ ... }

if there is a leading 1 or +1 it should be ignored
it will include 10 digits
valid characters allowed in the field are... 0-9,(), and -
That could be matched with an expression like:
/^(?:\+?1)?[()-]*(?:\d[()-]*){10}$/

Test Password with Regex

I want to test a passwprd which must have at least 6 characters and 1 number in it. What regex string I can use with JS to get this done?
UPDATED
I forgot to write it must have at least 6 alpha characters and 1 numeric character but it should also allow special characters or any other character. Can you please modify your answers? I greatly appreciated your responses

This does smell a little like a homework question, but oh well. You can actually accomplish this concisely using a single regular expression and the "look ahead" feature.
/(?=.{6}).*\d.*/.test("helelo1")
The first bit in the brackets says "peek ahead to see if there's 6 characters". Following this we check for any number of characters, followed by a number, followed by any number of characters.
It is even possible to accomplish your goal in a single regex without having the faculty of look ahead... It's just a little hard to look at the solution and not wince:
new RegExp("[0-9].....|" +
".[0-9]....|" +
"..[0-9]...|" +
"...[0-9]..|" +
"....[0-9].|" +
".....[0-9]").test("password1")

Try this:
password.match(/(?=.*\d).{6}/);
More info here.

As far as I know this is best done with a combination of string functions and regex:
if( myPass.match(/[a-zA-Z]/).length >= 6 && myPass.match(/\d/g).length ) {
// Good passwords are good!
}
EDIT: Updated to include the new stipulations. Special characters are allowed, but not required.

if (/.{6,}/.test(password) && /\d/.test(password)) {
// success
} else {
// fail
}

/^(?=[\w\d]{6,}$)(?=.*\d)/.test(password)
requires 6 or more characters (letters, numbers or _)
requires at least one digit
won't allow any special characters

This is a js to check password,
it checks min 7 chars, contains 1 Upper case and 1 digit and 1 special character and must not contain a space, hope it will help you.
pwLength = this.value.length;
if (pwLength > 7 && pwLength < 21) {
charLengthIcon.removeClass("fail").addClass("pass");
}
else charLengthIcon.removeClass("pass").addClass("fail");
if (this.value.match(/[A-Z]/g)) {
capLetterIcon.removeClass("fail").addClass("pass");
}
else capLetterIcon.removeClass("pass").addClass("fail");
if (this.value.match(/[0-9]/g)) {
numberIcon.removeClass("fail").addClass("pass");
}
else numberIcon.removeClass("pass").addClass("fail");
if (this.value.match(/[##$%!$&~*^(){}?><.,;:"'-+=|]/g)) {
splcharIcon.removeClass("fail").addClass("pass");
}
else splcharIcon.removeClass("pass").addClass("fail");
if (this.value.match(/[\s/]/g)) {
whiteSpce.removeClass("pass").addClass("fail");
}
else whiteSpce.removeClass("fail").addClass("pass");
confirmPW();
});