I have a fixed div on the right of my page like this:
This is my html:
<a id="toggle" class="open"><img src="_styles/images/open_close.png" alt="openclose" /></a>
<div class="tweetdetails" style="width: 0px;">
<p class="screenname">#BachelorGDM</p><br>
<img src="linktoimage" alt="image_user"><br>
<p class="createdon">Created on: Mar 8, 2013</p><br>
<hr>
<p class="text">Here is some text</p>
</div>
This is my CSS:
.tweetdetails{
color:white;
padding:10px 50px;
position: fixed;
right:0px;
width:300px;
z-index: 999;
background-color: #FFF;
height:100%;
background-color: black;
border-left: 5px solid rgb(127,255,255);
}
.open{
background-repeat: no-repeat;
background-size: 50px auto;
color:red;
position: fixed;
right:400px;
top:50%;
}
In my Javascript I have:
$("#toggle").click(function(){
$(".tweetdetails").animate({width:'0px'}, 500);
$("#toggle").animate({right: "-=300"}, 500);
})
But I always have an outcome like this:
How can I make sure I see nothing anymore? (I think it has something to do with the padding ...)
Check the fiddle if you're lazy ;) http://jsfiddle.net/tbleckert/UERHX/
That's because your padding will make the div 400px wide instead of 300px. You can add box-sizing to your div and add some extra width like this:
.tweetdetails {
box-sizing: border-box;
width: 400px; // Since we added box-sizing
}
The box-sizing will make sure the div stays with the width you define. And then animate the toggle's right to -400px. Remeber to add vendor prefixes to box-sizing (-moz and -webkit).
But! The problem will still remain so I would suggest animating the right attribute instead of the width. And that will work.
I would suggest you put the #toggle inside the .tweetdetails and absolute position it outside. That way you will only have to make one animation as the #toggle will follow. Also you can do this with css transitions just by adding a class instead.
.tweetdetails {
right: -400px;
transition: 0.5s right; // Add vendor prefixes
}
.tweetdetails.open {
right: 0;
}
$('#toggle').click(function () {
$('.tweetdetails').toggleClass('open');
});
I've made a fiddle to show you what I mean: http://jsfiddle.net/tbleckert/UERHX/
As a side note you shouldn't use ID's in your CSS but you should use them in your javascript. It's a good practise to add ID's to elements that you know you will use in your scripts (just don't go crazy, sometimes several elements applies and they should be classes so they can be looped easy).
You can make it more dynamic , without magic numbers:
$(".tweetdetails").animate({width:'0px' , padding:'0px'}, 500);
$("#toggle").animate({right: "-=" + ( $(".tweetdetails").outerWidth() ) }, 500);
.outerWidth is width+padding+border , have a look: http://api.jquery.com/outerWidth/
(Edited , thanks to #tbleckert)
I guess this is what you want:
http://jsfiddle.net/balintbako/XJbqD/
<a id="toggle" class="open"><img src="_styles/images/open_close.png" alt="openclose" /></a>
<div class="tweetdetails" style="width: 0px;">
<p class="screenname">#BachelorGDM</p>
<br/>
<img src="linktoimage" alt="image_user"></img>
<br/>
<p class="createdon">Created on: Mar 8, 2013</p>
<br/>
<hr/>
<p class="text">Here is some text</p>
</div>
CSS
.tweetdetails {
color:white;
position: fixed;
right:0px;
z-index: 999;
background-color: #FFF;
height:100%;
background-color: black;
border-left: 5px solid rgb(127, 255, 255);
}
.open {
background-repeat: no-repeat;
background-size: 50px auto;
color:red;
position: fixed;
right:5px;
top:50%;
}
JS
$("#toggle").click(function () {
if ($("#toggle").hasClass("opened")) {
$(".tweetdetails").animate({
width: '0px',
padding: '0px'
}, 500);
$("#toggle").animate({
right: "-=" + 400
}, 500);
} else {
$(".tweetdetails").animate({
width: '300px',
padding: '10px 50px'
}, 500);
$("#toggle").animate({
right: "+=" + 400
}, 500);
}
$("#toggle").toggleClass("opened");
});
$(".tweetdetails").css('padding', '10px 0').animate({width:'0px'}, 500);
Related
$(".raindrop1").clone().removeClass("raindrop1").addClass("raindropDelete").appendTo("body").css({
left: $(".shape").position().left - 29.50,
top: $(".shape").position().top + 1,
position: "relative"
}).animate({
top: "+=1000"
}, function() {
$(".raindropDelete").remove();
});
body {
background: rgb(0, 0, 0);
}
.shape {
border-radius: 50px;
width: 10px;
height: 10px;
background-color: white;
position: absolute;
left: 50%;
top: 50%;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="shape" onclick="curse()"></div>
<img src='http://images.clipartpanda.com/raindrop-clipart-RTGdn5bTL.png' width="15px" class="raindrop1">
I got this bit of code but I just can't seem to get it to work the way I want to. I want to make an image fall down to the bottom of the screen but to delete itself just before a scrollbar appears.
JS:
$(".raindrop1").clone().removeClass("raindrop1").addClass("raindropDelete").appendTo("body").css({
left: $(".shape").position().left - 29.50,
top: $(".shape").position().top + 1,
position: "relative"
}).animate({top :"+=1000"}, function() {
$(".raindropDelete").remove();
});
HTML:
<div class = "shape" onclick = "curse()"></div>
<img src = 'http://images.clipartpanda.com/raindrop-clipart-RTGdn5bTL.png' width = "15px" class = "raindrop1">
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
and CSS:
body{
background: rgb(0, 0, 0);
}
.shape{
border-radius: 50px;
width: 10px;
height: 10px;
background-color: white;
position: absolute;
left: 50%;
top: 50%;
}
Am I doing anything wrong?
JSFiddle
You are trying to remove your droplet in the function that is used to do something when animation is completed. So droplet animation is still going until it will reach +1000px from the top.
To remove before it falls below the window it's possible to use step option for animate method. What it does is looking what happens during animation and you can remove the droplet if when it falls below the edge.
Step Function
The second version of .animate() provides a step option — a callback
function that is fired at each step of the animation. This function is
useful for enabling custom animation types or altering the animation
as it is occurring. It accepts two arguments (now and fx), and this is
set to the DOM element being animated.
now: the numeric value of the property being animated at each step
fx: a reference to the jQuery.fx prototype object, which contains a number
of properties such as elem for the animated element, start and end for
the first and last value of the animated property, respectively, and
prop for the property being animated.
So what I've done is created a step function that each step looks if droplet is reached the edge of the window. If condition is met - just remove the droplet
$(".raindrop1").clone()
.removeClass("raindrop1")
.addClass("raindropDelete")
.appendTo("body").css({
left: $(".shape").position().left - 29.50,
top: $(".shape").position().top + 1,
position: "relative"
})
.animate({top :"+=100"},
{step: function(now) {
if (now+50 >= $(window).height())
$(".raindropDelete").remove();
}
},
function() {});
body{
background: rgb(0, 0, 0);
}
.shape{
border-radius: 50px;
width: 10px;
height: 10px;
background-color: white;
position: absolute;
left: 50%;
top: 50%;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class = "shape" onclick = "curse()"></div>
<img src = 'http://images.clipartpanda.com/raindrop-clipart-RTGdn5bTL.png' width = "15px" class = "raindrop1">
using this css you can stick your image to the bottom of the window in all new browsers
.fix{
position:fixed;
bottom:0px;
left:50%;
}
<img src="yourimagepath" class="fix"/>
and for IE6 you can use
position:absolute; instead of fixed. It will position the image on the bottom of the page but as you scroll up the image will scroll with the page. Unfortunately position:fixed in not supported in IE6
Using this code you can detect if the user has reached to the bottom of the page. Here you can add your code for deleting the image. If you put the code here the image will be deleted automatic if the user reaches to the bottom of the page.
window.onscroll = function(ev) {
if ((window.innerHeight + window.scrollY) >= document.body.offsetHeight) {
// you're at the bottom of the page
}
};
You can use sticky elements. They are elements on a page that will not be scrolled out of view. In other words it sticks to a visible area (viewport or scrolling box). You can create this with CSS using position: sticky;.
[Ref: http://www.hongkiat.com/blog/useful-css-tricks-you-might-have-overlooked/]
Look at the following code for an example:
https://codepen.io/rpsthecoder/pen/zGYXEX
HTML:
<h4>Scroll to see the sticky element <em>sticking</em></h4>
<div class="extra"></div>
<br />
<div id="wrapper">
<div id="sticky">
sticky
</div>
</div>
<br />
<div class="extra"></div>
CSS:
#sticky {
position: sticky;
background: #F762BC;
width: 100px;
height: 100px;
top: 70px;
left: 10px;
display: flex;
justify-content:center;
align-items:center;
box-shadow: 0 0 6px #000;
text-shadow: 0 0 4px #fff
}
#wrapper {
width: 75%;
margin: auto;
height: 400px;
background-color: #ccc;
}
.extra{
background: #ccc;
width: 75%;
margin: auto;
height: 100px;
}
body {
height: 1000px;
font-family: georgia;
}
h4{
text-align: center;
}
i found this kinda styled anchor name in this website http://maplestory.nexon.net/
can anyone know how to do this? What is that called?
This is a sample code, try like this
html
<div id="mydiv"></div>
<a href="#" id="backtotop" ></a>
<div id="mydiv1"></div>
script
$(window).scroll(function(){
$('#backtotop').stop().animate({ top: $(window).scrollTop()+100 }, 500);
});
css
#mydiv
{
background-color:red;
height:1000px;
width:300px;
}
#backtotop {
z-index: 81;
position: absolute;
left: 300px;
width: 64px;
height: 93px;
background: url(http://nxcache.nexon.net/maplestory/img/bg/bg-backtotop.png) 0 0 no-repeat;
}
and here is the demo,
DEmo
One more example of such feature implementation:
var $toTop = $('#to-top').click(function() {
$('body').animate({
scrollTop: 0
});
});
$(window).scroll(function() {
$toTop.toggle($(window).scrollTop() > 100);
})
.trigger('scroll');
Demo: http://jsfiddle.net/d5czx/
its css try this code
{
z-index: 81;
display: none;
position: absolute;
right: -53px;
width: 64px;
height: 93px;
background: url('Image URL') no-repeat scroll 0px 0px transparent;
}
I think not just css is being used, for the style and position yes but for the scrolling, probably done with jquery
I'm trying to do what many have asked before, but even after trying everything I still can't get the results I want.
I have an image 600px by 1600px, 4 images of 600px by 400px in a vertical line. I want to show 600px by 400px of the image at any one time. Ideally I would be able to hover over an element somewhere on my page and move the image upwards to reveal the other portions of the 600px by 400px image. In effect, I'd have 4 images viewable by hovering over 4 the elements.
I've tried various css3 and jquery solution but none have worked. I would appreciate any help with this.
HTML
<div class="mainimage">
<div class="buttonsection">
<div class="button1">Button 1</div>
<div class="button2">Button 2</div>
<div class="button3">Button 3</div>
<div class="button4">Button 4</div>
</div><!--end of buttonsection-->
<div class="rollingimage">
<img src="IMG/four-pics.png">
</div><!--end of rollingimage-->
</div><!--end of mainimage-->
</div><!--end of main content-->
CSS
.mainimage {
position: relative;
top: 0px;
left: 0px;
width: 900px;
height: 400px;
border: 2px solid #E78F25;
margin: 0 10px 20px 0;
}
.buttonsection {
width: 290px;
height: 400px;
position: relative;
float: left;
}
.button1,
.button2,
.button3,
.button4 {
display: inline;
height: 98px;
width: 290px;
border: 1px solid #E78F24;
text-align: center;
float: left;
}
.rollingimage {
width: 598px;
height: 400px;
position: relative;
overflow: hidden;
top: 0px;
left: 0px;
float: right;
}
jquery
$(document).ready(function(){
$(".button1").hover(function(){
$('.rollingimage').stop().animate({'top': '-200px'}, 1500);
});
});
Here is the jsfidle: http://jsfiddle.net/dirtyd77/jCvYm/1/
Thanks yet again
Gary
Just for fun, no JS:
http://jsfiddle.net/coma/MTWdb/5/
HTML
<div id="foo">
Button 1
Button 2
Button 3
Button 4
<div></div>
</div>
CSS
#foo {
width: 400px;
border: 2px solid #E78F25;
position: relative;
}
#foo > div {
position: absolute;
top: 0;
right: 0;
bottom: 0;
width: 200px;
background: #fff url(http://placekitten.com/600/1600) no-repeat 0 0;
transition: background-position .5s;
}
#foo > a {
display: block;
width: 200px;
line-height: 100px;
text-align: center;
text-decoration: none;
}
#foo > a + a {
border-top: 1px solid #E78F25;
}
#foo > a:nth-child(1):hover ~ div {
background-position: 0 0;
}
#foo > a:nth-child(2):hover ~ div {
background-position: 0 -400px;
}
#foo > a:nth-child(3):hover ~ div {
background-position: 0 -800px;
}
#foo > a:nth-child(4):hover ~ div {
background-position: 0 -1200px;
}
You need to change the positioning of the image inside the div, not the div itself. To animate my example, you could add CSS transitions for better performance than JS animations.
http://jsfiddle.net/jCvYm/8/
$('.rollingimage').find('img')
As Dom mentioned, the jsFiddle you provided didn't reference the jQuery library. It also didn't included any actual images, and only contained code for one of the three buttons. I doubt those were the original problems you were having, though. (The missing reference to jQuery might have been.)
Once I had those straightened out, I noticed that hovering the button caused the picture to slide out of the screen, instead of scrolling. The simplest way to fix that is to move the img element, instead of moving the div. (The more natural way would be to change the scroll position of the div, but I don't recall how to do that off the top of my head.)
Added CSS:
.rollingimage img {
position: relative;
}
New JS:
$(document).ready(function(){
$(".button1").hover(function(){
$('.rollingimage img').stop().animate({'top': '0px'}, 1500);
});
$(".button2").hover(function(){
$('.rollingimage img').stop().animate({'top': '-400px'}, 1500);
});
$(".button3").hover(function(){
$('.rollingimage img').stop().animate({'top': '-800px'}, 1500);
});
$(".button4").hover(function(){
$('.rollingimage img').stop().animate({'top': '-1200px'}, 1500);
});
});
jsFiddle: http://jsfiddle.net/jCvYm/6/
I'm trying to change one image to another on mouseover. Specifically, when the visitor hovers over this:
The image will change to this:
The Current Code
I'd like to do this as lightweight as possible. But the image-background CSS thing doesn't work for me. My code is as follows:
<div id="featured-box-right"><a href="/videos/"
target="_self"><img src="../images/box-featured-home-right.png" title="videos"
alt="videos" width="300" height="150"></a></div>
But when I do this to the CSS:
#featured-box-right a:hover
{
background-image: url(../images/box-featured-home-right-hover.png);
}
The effect doesn't turn out right; it's not a background. It's an actual image. Any guidance as to how I can achieve this as lightweight as possible would be greatly appreciated!
The lightweight method is to use CSS, and use the property background-image of the div:
jsFiddle
<div id="featured-box-right"></div>
CSS:
#featured-box-right {
width: 300px;
height: 150px;
background-image: url('http://i.stack.imgur.com/OywDf.png');
}
#featured-box-right:hover {
background-image: url('http://i.stack.imgur.com/aRJOk.png');
}
You should use css image sprites techniques and do not use img tag here use css background property. You should try something below. you can use cllass or id or parent child relationship that is totally up to you.
<div id="featured-box-right">
</div>
css:
#img1
{
background: url(../images/box-featured-home-right.png);
}
#img1:hover
{
background: url(../images/box-featured-home-right-hover.png);
}
Remove the <img/> tag altogether and try this css.
#featured-box-right a {
background-image: url(../images/box-featured-home-right.png);
}
#featured-box-right a:hover {
background-image: url(../images/box-featured-home-right-hover.png);
}
CSS Sprites is a technique where you use a background-image, a set width and height, and adjust the background-position to display only the portion you need to show. This way you can use a single image and display lots of different graphics with it, saving server requests and speeding up page load times:
HTML:
<img src="images/arrow-sprite.png" alt="arrow" class="clip pos-1" />
CSS:
.clip { position: absolute; top: 0; left: 0; }
.pos-1 { clip:rect(0 48px 48px 0); }
.pos-2 { clip:rect(0 96px 48px 48px); left: -48px; }
.pos-3 { clip:rect(48px 48px 96px 0); top: -48px; }
.pos-4 { clip:rect(48px 96px 96px 48px); top: -48px;
left: -48px; }
Took from here
You can delete the <img> tag and use CSS background iamge method, but you need to combine the 2 pic into one (one on top and one on bottom)
next, you need to use this code:
#featured-box-right {
width: 300px;
height: 150px;
background-image: url(image url here) center top;
}
#featured-box-right:hover {
background-image: url(image url here) center bottom;
}
Using this method makes you need only 1 image
No images (background or otherwise) are required.
This comes out to only 3.84% the size of your two images combined:http://fiddle.jshell.net/gWytK/show/:
<!doctype html>
<html>
<head>
<title></title>
<style>
body {
margin: 8px;
}
#links {
list-style: none;
margin: 0;
padding: 0;
display: block !important;
display: inline-block;
overflow: hidden;
}
#links li {
float: left;
width: 300px;
height: 150px;
overflow: hidden;
background: #000000;
border-radius: 20px;
}
#links a {
display: block;
font: bold 30px/30px 'comic sans ms', sans-serif;
padding: 40px 66px 100px;
color: #5496ff;
text-decoration: none;
text-transform: capitalize;
text-shadow: 0 0 100px #ffffff, 0 0 100px #ffffff;
}
#links a:after {
content: ' >>';
}
#links a:hover,
#links a:focus {
color: #1b1b1b;
background: #5496ff;
text-shadow: none;
}
</style>
</head>
<body>
<ul id="links">
<li>
Our video collection
</li>
</ul>
</body>
</html>
No image property in CSS. In order to get the desired effect you should replace it with background-image and delete the img tag from your HTML code.
#featured-box-right
{
background-image: url(../images/box-featured-home-right.png);
}
#featured-box-right:hover
{
background-image: url(../images/box-featured-home-right-hover.png);
}
Mozilla.com has this tab on the top of their site that you can click and a menu drops down. I have a client who wants me to do the same thing but upside down, from the bottom half of the page. Apparently this is a really hard request. How do I make something like tabzilla that goes up and either overlaps or pushes the content away? Thanks!
Update: I love you guys.
Edit: http://hemakessites.com/mayukh/4/ Why does the top "Sign In/Register" pop down and the "Toggle" on the bottom pops up? I'm not seeing the difference besides 'top' and 'bottom' in the css. How does that change the direction of the popup?
Also, clicking the '337-9147' will expand the menu. I only want the button region to be clickable. How can I accomplish this?
You guys are awesome and I'm going to return the favor by answering some questions on here when I get time.
I took a similar approach as others, in that you set a div to have a fixed, or absolute position at the bottom of the screen (depending on whether the tab should always be visible, or only at the very bottom). Then, you can write some very simple javascript to vary the height of the element, and as the bottom is fixed, it will cause the tab to rise into the screen.
Essentially all you need is
.container{
position: absolute;
bottom: -1px;
}
And
$('.container').toggle(function(){
$(this).animate({height:'205px'}, 500)
},function(){
$(this).animate({height:'20px'}, 200)
});
Here's a jsfiddle demo.
Here's a jQuery solution, which is smoother than css3:
So, you'll want to do something like this jsfiddle (NOTE: This requires jQuery):
http://jsfiddle.net/cFkn2/
$(document).ready(function() {
$('#tab').click(function() {
if ($('#tab').css('height') == '20px') {
$('#tab').animate({
height: '100px'
}, 1000);
}
else {
$('#tab').animate({
height: '20px'
}, 1000);
};
});
});
and
#tab{
position: absolute;
bottom: 0;
width: 100%;
background-color: red;
height:20px;
}
and
<div id="tab">CONTENT</div>
Style, edit, and add easing to taste.
I was lazy to make here click handler, so it is css3 only hover sample
I used fixed position with {top: 100%}, transition for animation, margin <0 to show;
HTML
<div id="menu">
<div id="handler">handler</div>
<div id="menucontent">
menu menu<br>
menu menu<br>
</div>
</div>
<div id="content">
<div> text text text</div>
<div> text text text</div>
<!-- many of them -->
<div> text text text</div>
<div> text text text</div>
<div> text text text</div>
</div>
CSS:
#content > div {
font-size: 2em;
height: 2.1em;
border: 1px solid black;
margin-top: 10px;
}
#menu {
left: 30px;
position: fixed;
font-size: 20px;
width: 300px;
height: 300px;
top: 100%;
border: 1px solid red;
background: white;
-webkit-transition: all 1s;
-mozilla-transition: all 1s;
-o-transition: all 1s;
transition: all 1s;
}
#menu #handler {
position: absolute;
top: -40px;
background: green;
font-size: 30px;
height: 40px;
padding-left: 5px;
padding-right: 5px;
left: 10px;
}
#menu:hover {
margin-top: -300px;
}
with click, or
JS:
$(function() {
$('#menu #handler').click(function() {
$('#menu').toggleClass('shown');
});
});
in css change hover to class shown
#menu.shown {
margin-top: -300px;
}