I'm trying to create a JS code which displays tthe tomorrow's date.
This is the code I tried :
var d = new Date.today().addDays(1).toString("dd-mm-yyyy");
but it won't work for me.
How can I solve it ?
var todayDate = new Date();
todayDate .setDate(todayDate .getDate() + 1);
Then todayDate contains tomorrow date
Try this :
var d = new Date();
var tomorrowDate = d.getDate() + 1;
d.setDate(tomorrowDate);
document.write("Tommorow date : " + d );
Output :
Tommorow date : Fri Jul 05 2013 19:16:50 GMT+0530 (IST)
var d = new Date();
d.setDate(d.getDate() + 1)
console.log(d)
If you're going to deal a lot with dates, I'd recommend you to use Moment.js. It allows you to do exactly what you want, aswell much more things:
var date = moment().add("days", 1);
// If displaying this date, use the following to format it in your culture.
// Will be mm-dd-yyyy in en-US, I believe
date.format("L");
Docs: http://momentjs.com/docs/
Related
Hi, I would like to add 12 months and subtract 1 day for my current
date.
Example :
valStartDate :2018-01-20
expected_date:2019-01-19
I try below code but error "getFullYear() not a function to allow"
this.endDate =this.valStartDate.getFullYear()+1+'-'+this.valStartDate.getMonth()+'-'+(this.valStartDate.getDate()-1);
Ensure that your given start date is a date and not a string.
var startDate = new Date(2018, 0, 20);
var startDatePlus12Months = new Date(startDate.setMonth(startDate.getMonth() + 12));
var expectedDate = new Date(startDatePlus12Months.getFullYear(), startDatePlus12Months.getMonth(), startDatePlus12Months.getDate() - 1);
Here is a method of abstracting the date you want, apply this the variable and you should be good to go.
var date = new Date(); // now
var newDate = new Date(date.getFullYear() + 1, date.getMonth(), date.getDate() - 1);
console.log(newDate.toLocaleDateString());
this.valStartDate.getFullYear() In order for this to work, this.valStartDate must be a valid javascript date and look the same format as new Date(); would give you.
Fri Apr 26 2019 11:52:15 GMT+0100 (British Summer Time)
this.endDate = new Date(this.endDate); // <= maybe you get a string date...
this.endDate.setMonth(this.endDate.getMonth() + 12);
this.endDate.setDate(this.endDate.getDate() - 1);
If you're getting your date from a server or from a previous Json format, maybe you need to convert it from string to Date first: this.endDate = new Date(this.endDate);. It seems this is your case.
This is easy with the help of Moment.js:
const startDate = moment('2018-01-20');
const endDate = startDate.add(12, 'months').subtract(1, 'days').toDate();
how to convert default date in javascript to YYYY-MM-DDTHH:MM:SS format.
new Date() returns Sun Aug 07 2016 16:38:34 GMT+0000 (UTC)
and i need the current date to above format.
As new Date().toISOString() will return current UTC time, to get local time in ISO String format we have to get time from new Date() function like the following method
document.write(new Date(new Date().toString().split('GMT')[0]+' UTC').toISOString().split('.')[0]);
You can use moment.js library to achieve this.
Try:
var moment = require('moment')
let dateNow = moment().format('YYYY-MM-DDTHH:MM:SS')
This could work :
var date = new Date();
console.log(date.getFullYear() + "-" + (date.getMonth()+1) + "-" + date.getDate() + " " + date.getHours() + ":" + date.getMinutes() + ":" + date.getSeconds());
For use the date in ISO 8601 format run the command lines below on NodeJS console or on browser console:
$ node
> var today = new Date(); // or
> var today = new Date(2016, 8, 7, 14, 06, 30); // or
> var today = new Date('2016-08-07T14:06:30');
> today; // Show the date in standard USA format. Grrrr!
> today.toISOString();
For more information, consult the documentation:
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Date
moment is to large, you can use fecha
import fecha from 'fecha'
const uTime ="2019-10-21T18:57:33"
fecha.format(fecha.parse(uTime, "YYYY-MM-DD'T'HH:mm:ss"), 'YYYY.MM.DD HH:mm:ss')
// console.log(2019.10.21 18:57:33)
let date = new Date(Date.now());
date = now.toISOString().substr(0,now.toISOString().indexOf("."));
//2021-07-26T09:07:59
use this code:
new Date(new Date().toString().split('GMT')[0]+' UTC').toISOString().split('.')[0]);
I am trying to add a year to todays date. I am working in a system that does not allow you to use standard JavaScript.
For instance, to get todays date I have to use:
javascript:now();
I have tried:
javascript:now(+1);
I have never seen this before, but am in need of adding one year to todays date...
Has anyone seen getting current date this way before? And if so, how could I add a year?
Use the Date.prototype.setFullYear method to set the year to what you want it to be.
For example:
const aYearFromNow = new Date();
aYearFromNow.setFullYear(aYearFromNow.getFullYear() + 1);
console.log(aYearFromNow);
There really isn't another way to work with dates in JavaScript if these methods aren't present in the environment you are working with.
You can create a new date object with todays date using the following code:
var d = new Date();
console.log(d);
// => Sun Oct 11 2015 14:46:51 GMT-0700 (PDT)
If you want to create a date a specific time, you can pass the new Date constructor arguments
var d = new Date(2014);
console.log(d)
// => Wed Dec 31 1969 16:00:02 GMT-0800 (PST)
If you want to take todays date and add a year, you can first create a date object, access the relevant properties, and then use them to create a new date object
var d = new Date();
var year = d.getFullYear();
var month = d.getMonth();
var day = d.getDate();
var c = new Date(year + 1, month, day);
console.log(c);
// => Tue Oct 11 2016 00:00:00 GMT-0700 (PDT)
You can read more about the methods on the date object on MDN
Date Object
One liner as suggested here
How to determine one year from now in Javascript
by JP DeVries
new Date(new Date().setFullYear(new Date().getFullYear() + 1))
Or you can get the number of years from somewhere in a variable:
const nr_years = 3;
new Date(new Date().setFullYear(new Date().getFullYear() + nr_years))
This code adds the amount of years required for a date.
var d = new Date();
// => Tue Oct 01 2017 00:00:00 GMT-0700 (PDT)
var amountOfYearsRequired = 2;
d.setFullYear(d.getFullYear() + amountOfYearsRequired);
// => Tue Oct 01 2019 00:00:00 GMT-0700 (PDT)
I like to keep it in a single line, you can use a self calling function for this eg:
If you want to get the timestamp of +1 year in a single line
console.log(
(d => d.setFullYear(d.getFullYear() + 1))(new Date)
)
If you want to get Date object with single line
console.log(
(d => new Date(d.getFullYear() + 1, d.getMonth(), d.getDate()))(new Date)
)
In Angular, This is how you Calculate Date
today = new Date();
year = this.today.getFullYear();
month = this.today.getMonth();
day = this.today.getDate();
//To go 18 years back
yearsBack18= new Date(this.year - 18, this.month, this.day);
//To go to same day next year
nextYear= new Date(this.year + 1, this.month, this.day);
var d = new Date();
var year = d.getFullYear();
var month = d.getMonth();
var day = d.getDate();
var fulldate = new Date(year + 1, month, day);
var toDate = fulldate.toISOString().slice(0, 10);
$("#txtToDate").val(toDate);
output : 2020-01-02
//This piece of code will handle the leap year addition as well.
function updateExpiryDate(controlID, value) {
if ( $("#ICMEffectiveDate").val() != '' &&
$("#ICMTermYears").val() != '') {
var effectiveDate = $("#ICMEffectiveDate").val();
var date = new Date(effectiveDate);
var termYears = $("#ICMTermYears").val();
date = new Date(date.setYear(date.getFullYear() + parseInt(termYears)));
var expiryDate = (date.getMonth() + 1) + '/' + date.getDate() + '/' + date.getFullYear();
$('#ICMExpiryDate').val(expiryDate);
}
}
var yearsToAdd = 5;
var current = new Date().toISOString().split('T')[0];
var addedYears = Number(this.minDate.split('-')[0]) + yearsToAdd + '-12-31';
var dateStart = $('input[id=orderdate-0]').val();
var timeStart = $('input[id=ordertime-0]').val();
var dateEnd = $('input[id=orderdate-1]').val();
var timeEnd = $('input[id=orderime-1]').val();
var startDate = new Date(dateStart + " " + timeStart);
var endDate = new Date(dateEnd + " " + timeEnd);
startDate.getTime();
alert(startDate);
i am trying to combine dateStart which is '2013-12-11' and timeStart which is '11:00' and trying to generate date out of it. But i get alert like invalid date. Is there anything wrong in code.?
The Date constructor is very particular about the date string formats it accepts.
Examples:
Dec 25, 1995
Wed, 09 Aug 1995 00:00:00
2011-10-10T14:48:00 (JavaScript 1.8.5+)
There is another constructor that take in the individual components of the date. If you break up your date strings into components you can use the following:
new Date(year, month, day, hour, minute);
Use moment JS plugin http://momentjs.com/
It's a date library for parsing, validating, manipulating, and formatting dates.
That is not a valid format for the parse function, you can use this instead:
var arr = dateStart.split('-');
var timeArr = timeStart.split(':');
new Date(arr[0], arr[1] -1, arr[2], timeArr[0] -1, timeArr[1] -1);
Read this.
Live DEMO
I found the current day as Mar 27 2012 ....
var currentday = currentday.format("mmm d yyyy");
I want to find the add three days with this value.
i.e. i need the output as Mar 30 2012.
I also need to find the starting and ending date of a calendar. i.e. Feb 26 2012 - Mar 31 2012 to display the current month as displaying in calendar month view.
Can any one help me on this please....
var currentday = new Date();
var nextDay = new Date();
nextDay.setDate(currentday.getDate() + 4);
//Set number of days you want to compute to
var days=4;
//Get current date or whatever date you want to compute from
var currentDate=new Date();
var nDaysFromNow=new Date();
nDaysFromNow.setDate(currentDate.getDate()+days);
You can add days using the getDate() function like so:
var someDate = new Date();
someDate = someDate.getDate() + 3;
See code below.. Hope it helps
var days = 4;
var next = new Date((new Date).getTime() + ((1000*3600*24) *days));