I want to interchange columns in two tables.if "a" is selected and dragged all "1" should move automatically.
http://jsfiddle.net/9LGrm/
<table id="a">
<tr>
<td>a</td>
<td>b</td>
<td>c</td>
<td>d</td>
</tr>
</table>
<table id="b">
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
</table>
I have tried this plugin:
http://www.danvk.org/wp/dragtable/
https://github.com/jebaird/dragtable
it uses single table I can't change the structure of the table!
Here is the Solution.
The HTML:
<table class="draggable" id="a"><thead><tr>
<th>a</th>
<th>b</th>
<th>c</th>
<th>d</th>
</tr></thead>
<tbody>
<tr>
<td>1</td><td>2</td><td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td><td>2</td><td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td><td>2</td><td>3</td>
<td>4</td>
</tr>
</tbody><tfoot></tfoot></table>
The CSS:
#a
{
border: 1px black;
}
th{font-weight:normal;}
Hope this helps.
Related
mytable.php
<table id="tableid">
<thead>
<tr>
<th scope="col">A</th>
<th scope="col">B</th>
<th scope="col">C</th>
<th scope="col">D</th>
</tr>
</thead>
<tbody>
<tr>
<td>0</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>5</td>
<td>6</td>
<td>7</td>
<td>8</td>
</tr>
<tr>
<td>9</td>
<td>10</td>
<td>11</td>
<td>12</td>
</tr>
</tbody>
</table>
Hello Guys, Can anyone help me how to convert my code to the Datatables? Sorry Guys for this question I try to convert but it didn't work. I'm a beginner and still learning how to use tables
Script
$(document).ready(function() {
$('#example').DataTable();
} );
HTML
<table id="example" class="display" style="width:100%">
<tr>
......
</tr>
</table>
In addition to the above code, the following Javascript library files are loaded for use in this example:
https://code.jquery.com/jquery-3.5.1.js
https://cdn.datatables.net/1.10.21/js/jquery.dataTables.min.js
I have a very long table with horizontal scrolling. Is it possible to implement a fixed row inside this table without horizontal scroll.
<div class="container" style="width:500px;height:100px;overflow:auto;position:relative;">
<table style="width:1500px;">
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
<td>5</td>
<td>6</td>
<td>7</td>
</tr>
<tr style="width:500px;height:200px;left:0;right:0">
<td colspan="7" style="width:500px;">
<div id="noscroll" style="display: inline-block;">A row unaffected by horizontal scroll</div>
</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
<td>5</td>
<td>6</td>
<td>7</td>
</tr>
</table>
</div>
EDIT: What if I need two cell in the fixed row?
<tr class="fixed-row">
<td colspan="3">
A row unaffected by
</td>
<td colspan="3">
horizontal scroll
</td>
</tr>
https://jsfiddle.net/7nz6ys2m/2/
Try the following:
<div class="container" style="width:500px;overflow:auto;position:relative;">
<table style="width:1500px;">
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
<td>5</td>
<td>6</td>
<td>7</td>
</tr>
<tr style="width:500px;left:0;right:0">
<td colspan="7" style="width:500px;height:22px;position: relative;">
<div id="noscroll" style="display: inline-block;position: fixed;transform: translateY(-50%);">
A row unaffected by horizontal scroll
</div>
</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
<td>5</td>
<td>6</td>
<td>7</td>
</tr>
</table>
</div>
What I did:
Give the noscroll-div position:fixed; and reset its position with transform. Then I set the height of its parent td to a fixed height of 22px (the other td are all 22px) and set its position to relative.
In case you need multiple td in the fixed row, I would rather take multiple div inside one td, and float them left. see this:
<div class="container" style="width:500px;overflow:auto;position:relative;">
<table style="width:1500px;">
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
<td>5</td>
<td>6</td>
<td>7</td>
</tr>
<tr style="width:500px;left:0;right:0;height:22px;position: relative;">
<td style="position: fixed;" colspan="7">
<div style="width:250px;float: left;">
test1
</div>
<div style="width:250px;float:left;">
test2
</div>
</div>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
<td>5</td>
<td>6</td>
<td>7</td>
</tr>
</table>
</div>
With a little bit of jQuery, we can get the behavior with safe vertical scrolling.
<div class="container" style="width:500px;height:300px;overflow:auto;">
<table style="width:1500px;height:500px;">
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
<td>5</td>
<td>6</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
<td>5</td>
<td>6</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
<td>5</td>
<td>6</td>
</tr>
<tr style="">
<td colspan="6" style="">
<div class="fixed-row">A row unaffected by horizontal scroll</div>
</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
<td>5</td>
<td>6</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
<td>5</td>
<td>6</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
<td>5</td>
<td>6</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
<td>5</td>
<td>6</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
<td>5</td>
<td>6</td>
</tr>
</table>
</div>
<script
src="https://code.jquery.com/jquery-2.2.4.min.js"
integrity="sha256-BbhdlvQf/xTY9gja0Dq3HiwQF8LaCRTXxZKRutelT44="
crossorigin="anonymous"></script>
<script>
$(".container").scroll(function () {
$(".fixed-row").css("margin-left",$(".container").scrollLeft() + "px");
});
</script>
<style>
table{
border-collapse: collapse;
}
table td, table th {
border: 1px solid #ddd;
padding: 8px;
}
table tr:nth-child(even){background-color: #f2f2f2;}
table tr:hover {background-color: #ddd;}
table th {
padding-top: 12px;
padding-bottom: 12px;
text-align: left;
background-color: #4CAF50;
color: white;
}
.fixed-row {
display: inline-block;
width: 500px;
text-align: center;
}
</style>
https://jsfiddle.net/7nz6ys2m/4/
I got a table with several trs. I want to select 5 trs in a row and give them a background color, then take the next 5 trs and give them another background color - like even and odd, but with 5 elements as a block.
This is what I have tried
var trs = $('table.small-only tr');
for (var i = 1; i < trs.length; i += 5) {
if (i%2 == 0){
// select even blocks
}else {
// select odd blocks
}
}
This doesn't work though.
How can I select blocks containing 5 trs and give the even and odd blocks different background colors in a proper way?
I found a work around:
for (var i = 1; i < trs.length; i += 5) {
trs.slice(i, i + 5).wrapAll("<div></div>");
}
and
div {
&:nth-of-type(odd) {
background: #f2f2f2 !important;
}
}
But clearly putting divs around trs in a table isn't a good way.
Here is my example:
function getRandomColor() {
var letters = '0123456789ABCDEF';
var color = '#';
for (var i = 0; i < 6; i++ ) {
color += letters[Math.floor(Math.random() * 16)];
}
return color;
}
var my_table_rows= $('.my-table tr');
var color;
for (var i = 0; i < my_table_rows.length; i++){
if (i % 5 === 0) color = getRandomColor();
my_table_rows.eq(i).css('background', color);
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<table class="my-table">
<tr><td>1</td></tr>
<tr><td>2</td></tr>
<tr><td>3</td></tr>
<tr><td>4</td></tr>
<tr><td>5</td></tr>
<tr><td>6</td></tr>
<tr><td>7</td></tr>
<tr><td>8</td></tr>
<tr><td>9</td></tr>
<tr><td>10</td></tr>
<tr><td>11</td></tr>
<tr><td>12</td></tr>
<tr><td>13</td></tr>
<tr><td>14</td></tr>
<tr><td>15</td></tr>
<tr><td>16</td></tr>
<tr><td>17</td></tr>
</table>
To achieve this you can loop through the tr elements in the table stepping over the number of rows you want per group. You can then use slice() to retrieve the set number of rows before calling addClass() on them. Try this:
var groupSize = 5;
var classes = ['group1', 'group2'];
var $rows = $("table.small-only tr");
for(var i = 0; i < $rows.length; i += groupSize) {
$rows.slice(i, i + groupSize).addClass(classes[i / groupSize % classes.length]);
}
.group1 { background-color: #C00; }
.group2 { background-color: #0C0; }
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<table class="small-only">
<tr><td>1</td></tr>
<tr><td>2</td></tr>
<tr><td>3</td></tr>
<tr><td>4</td></tr>
<tr><td>5</td></tr>
<tr><td>6</td></tr>
<tr><td>7</td></tr>
<tr><td>8</td></tr>
<tr><td>9</td></tr>
<tr><td>10</td></tr>
<tr><td>11</td></tr>
<tr><td>12</td></tr>
</table>
but clearly putting divs around trs in a table isnt a good way
No, it is invalid html. However you can use <tbody> instead of <div>
A table can have any number of <tbody> elements
You can do like that way
HTML
<table class="table">
<tr><td>test</td></tr>
<tr><td>test</td></tr>
<tr><td>test</td></tr>
<tr><td>test</td></tr>
<tr><td>test</td></tr>
<tr><td>test</td></tr>
<tr><td>test</td></tr>
<tr><td>test</td></tr>
<tr><td>test</td></tr>
<tr><td>test</td></tr>
<tr><td>test</td></tr>
<tr><td>test</td></tr>
<tr><td>test</td></tr>
<tr><td>test</td></tr>
<tr><td>test</td></tr>
<tr><td>test</td></tr>
<tr><td>test</td></tr>
<tr><td>test</td></tr>
<tr><td>test</td></tr>
<tr><td>test</td></tr>
<tr><td>test</td></tr>
<tr><td>test</td></tr>
<tr><td>test</td></tr>
<tr><td>test</td></tr>
<tr><td>test</td></tr>
</table>
Jquery
$(function(){
var limit = 5;
var arr = ['red','green','yellow','blue','orange'];
$('.table tr').each(function(i,e){
var ind = parseInt((i/limit));
$(this).css('background',arr[ind]);
})
})
You can also use CSS selector :nth-child(xn) and :not():
tr:nth-child(10n - 5)~ tr:not(:nth-child(10n + 1)):not(:nth-child(10n + 2)):not(:nth-child(10n + 3)):not(:nth-child(10n + 4)):not(:nth-child(10n + 5)) {background-color:gray}
tr {
background: turquoise;
counter-increment: trs;
}
tr:nth-child(10n - 5)~ tr:not(:nth-child(10n + 1)):not(:nth-child(10n + 2)):not(:nth-child(10n + 3)):not(:nth-child(10n + 4)):not(:nth-child(10n + 5)) {
background: tomato
}
/* check row numbers */
tr:before {
content: counter(trs);
display: table-cell;
padding: 0.25em;
border: solid;
background: yellow;
}
tr:nth-child(odd):before {
background: gray;
}
td {
padding: 0.25em;
border: solid;
}
<table>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
</table>
This should be any easy one for you. I want to have a table with rows that expand. I am trying to implement JQuery accordion on class="Accordion1".
it does not work at all.
What am I doing wrong?
...
<script>
$(function() {
$( "th.Accordion1").accordion();
});
</script>
</head>
<body>
<table>
<tbody>
<tr>
<th colspan="2" class="Accordion1">GROUP 1</th>
</tr>
<tr>
<th>Name</th>
<th>Note</th>
</tr>
<tr>
<td>1</td>
<td>-</td>
</tr>
<tr>
<td>2</td>
<td>-</td>
</tr>
<tr>
<td>3</td>
<td>-</td>
</tr>
<tr>
<th colspan="2" class="Accordion1">GROUP 2</th>
</tr>
<tr>
<th>Name</th>
<th>Note</th>
</tr>
<tr>
<td>1</td>
<td>-</td>
</tr>
<tr>
<td>2</td>
<td>-</td>
</tr>
</tbody>
</table>
Thanks!
I believe you want to use the header option of jQuery Accordion.
$(function () {
$('table').accordion({header: '.accordion1' });
});
http://api.jqueryui.com/accordion/#option-header
I realize that this post is quite old but I have two different solutions for the problem stated and thought to post them anyway, maybe someone is thankful for it.
You can find two options on my Pen.
One including "Group 1" and "Group 2"...
<div class="options" id="op1">
<div class="accordion">
<h3>GROUP 1</h3>
<table>
<thead>
<th>Name</th>
<th>Note</th>
</thead>
<tbody>
<tr>
<td>1</td>
<td>-</td>
</tr>
<tr>
<td>2</td>
<td>-</td>
</tr>
<tr>
<td>3</td>
<td>-</td>
</tr>
</tbody>
</table>
<h3>GROUP 2</h3>
<table>
<thead>
<th>Name</th>
<th>Note</th>
</thead>
<tbody>
<tr>
<td>1</td>
<td>-</td>
</tr>
<tr>
<td>2</td>
<td>-</td>
</tr>
</tbody>
</table>
</div>
</div>
And one without
<div class="options" id="op2">
<table>
<thead>
<th>Name</th>
<th>Note</th>
</thead>
<tbody>
<tr>
<td>1</td>
<td>-</td>
</tr>
<tr>
<td>2</td>
<td>-</td>
</tr>
<tr>
<td>3</td>
<td>-</td>
</tr>
</tbody>
<thead>
<th>Name</th>
<th>Note</th>
</thead>
<tbody>
<tr>
<td>1</td>
<td>-</td>
</tr>
<tr>
<td>2</td>
<td>-</td>
</tr>
</tbody>
</table>
</div>
Be aware that for this to work you have to include jquery and jquery-ui!
The options I've added for the accordion and the CSS are optional... ;)
I have a table dynamically generated by php. In this table have information for different semester (such as : first, second, third etc). Now i want to show specific semester information if user click a link from same table without a query. I am newbie in this forum and its my first question. sorry for poor english. !
My code
<table id="course_offering" class="table table-striped table-hover custab ">
<thead>
<tr>
<th>Course Code</th>
<th>Course title</th>
<th>Credit Hours</th>
<th>Contact Hours</th>
<th>Pre Requisite</th>
<th>Course Type</th>
<th>Year</th>
<th>Semester</th>
<th>Offering Year</th>
<th>Offering Session</th>
</tr>
</thead>
<tbody>
<tr>
<td>EEE 2505</td>
<td>Electrical </td>
<td>2</td>
<td>3</td>
<td></td>
<td>Theory</td>
<td>2</td>
<td>1</td>
<td>2014</td>
<td> Spring </td>
</tr>
<tr>
<td>EEE 2505</td>
<td>Electrical </td>
<td>2</td>
<td>3</td>
<td></td>
<td>Theory</td>
<td>2</td>
<td>4</td>
<td>2015</td>
<td> Spring </td>
</tr>
<tr>
<td>EEE 2505</td>
<td>Electrical </td>
<td>2</td>
<td>3</td>
<td></td>
<td>Theory</td>
<td>2</td>
<td>4</td>
<td>2014</td>
<td> Spring </td>
</tr>
<tr>
<td>EEE 2505</td>
<td>Electrical </td>
<td>2</td>
<td>3</td>
<td></td>
<td>Theory</td>
<td>2</td>
<td>4</td>
<td>2014</td>
<td> Spring </td>
</tr>
<tr>
<td>EEE 2505</td>
<td>Electrical </td>
<td>2</td>
<td>3</td>
<td></td>
<td>Theory</td>
<td>2</td>
<td>4</td>
<td>2014</td>
<td> Spring </td>
</tr>
<tr>
<td>EEE 2505</td>
<td>Electrical </td>
<td>2</td>
<td>3</td>
<td></td>
<td>Theory</td>
<td>2</td>
<td>4</td>
<td>2014</td>
<td> Spring </td>
</tr>
<tr>
<td>EEE 2505</td>
<td>Electrical </td>
<td>2</td>
<td>3</td>
<td></td>
<td>Theory</td>
<td>2</td>
<td>4</td>
<td>2014</td>
<td> Spring </td>
</tr>
</tbody>
</table>
here is a working example:
http://jsfiddle.net/K7PjR/1/
function getRowsByText(text) {
var resultRows = $();
$('tr').each(function () {
var row = $(this);
var rowText = row.text().trim();
if (rowText === text) {
resultRows = resultRows.add(row); //return the row
}
});
return resultRows;
}
getRowsByText('apple').css('color', 'red');
getRowsByText('orange').css('color', 'orange');
HTML:
<table>
<tr>
<td>apple</td>
</tr>
<tr>
<td>orange</td>
</tr>
<tr>
<td>bannana</td>
</tr>