Javascript toggle (one at a time) - javascript

Im looking for a simple way to only have one div open at a time. Im using an accordian style vertical navigation and when I click on one, it displays the div below, when I click on another, it does the same. I would like the previous div to hide again when I click on a different nav link.
This is the javascript im using to get it to open and close:
<script type="text/javascript">
<!--
function toggle_visibility(id) {
var e = document.getElementById(id);
if(e.style.display == 'block')
e.style.display = 'none';
else
e.style.display = 'block';
}
//-->
</script>
Is there something else I can add that will close the div if another is opened?

A very simple way would be to just keep track of the previously opened element:
(function() { // using an IIFE to prevent polluting the global namespace
var opened_element = null;
window.toggle_visibility = function(id) {
var e = document.getElementById(id);
if (opened_element && opened_element !== e) {
opened_element.style.display = 'none';
}
if(e.style.display == 'block') {
e.style.display = 'none';
}
else {
e.style.display = 'block';
}
opened_element = e;
};
}());

Give them all the same class. Hide them all by classname and show the one you clicked on with the id passed.

The best way is to:
Use CSS to hide all of your DIVs
When you want to display one; add a
class to your open div called "active" or whatever
Then apply css to
that class with display: block or what ever.
As Jason said in his comment you can do this with jQuery or you can do it without.
jQuery will provide animation support and easier manipulation of classes.
jQuery Toggle Class

Since you're not using JQuery, I assume you want a Javascript answer, you can do this by giving your divs some unique classname like "menudiv", then appending something like the following to your function:
var menu_divs = document.getElementsByClassName("menudiv");
for ( var i = 0; i < menu_divs.length; i++ ) {
if ( menu_divs[i] != e )
menu_divs[i].style.display = 'none';
}

Related

How do I make the div dissapear after onclick nr 2?

I tried this but obv it didnt work. Im very new to JS, how do I do this?
function test() {
if(document.getElementById('div1').style.display = 'block'){
document.getElementById('div1').style.display = 'none';
}
if(document.getElementById('div1').style.display = 'none'){
document.getElementById('div1').style.display = 'block';
}
}
The code you have (once corrected) will toggle visibility but won't make an element invisible on the 2nd time a user clicks on it.
I've set up a JSFiddle here that uses plain JavaScript in order to do what you're asking in the title of the question.
Let's assume that your HTML looks something like this, with a DIV that has a class name of "tester":
<div class="tester">This is a triumph.</div>
<p>I'm writing a note here; huge success</p>
One way of achieving this is to add a data element to the DIV to track the number of clicks and then, when the number of clicks hits two, we hide it. The code for that looks like this:
document.getElementsByClassName("tester")[0].onclick = function(targ) {
if(!targ.target.hasAttribute("data-click")) {
targ.target.setAttribute("data-click",0);
}
var currClicks = +targ.target.getAttribute("data-click");
if(currClicks==2){
targ.target.style.display = "none";
} else {
targ.target.setAttribute("data-click", currClicks+1);
}
};
Again, this will get you the functionality you asked about in your question but does not match your code sample as it doesn't really do what you want. If you need any more information on this feel free to ask, but I think this will get you what you're looking for.
It shouldn't be =, it should be == in JavaScript if condition and twice if condition always setting style.display = 'block', so either use else if or simply else.
<div id="div1" style="display:block"></div>
function test() {
if (document.getElementById('div1').style.display == 'block') {
document.getElementById('div1').style.display = 'none';
}
else if(document.getElementById('div1').style.display == 'none') {
document.getElementById('div1').style.display = 'block';
}
}
or
function test() {
if (document.getElementById('div1').style.display == 'block') {
document.getElementById('div1').style.display = 'none';
}
else{
document.getElementById('div1').style.display = 'block';
}
}

Where to put slideDown() in javascript function

I'm trying to add slideDown('400') in this javascript. But dont know where to put it.
<script type="text/javascript">
function toggle_visibility(id) {
var e = document.getElementById(id);
if (e.style.display == 'none')
e.style.display = 'block';
else
e.style.display = 'none';
}
</script>
Iv'e tried this, but it does not work:
<script type="text/javascript">
function toggle_visibility(id) {
var e = document.getElementById(id);
if (e.style.display == 'none')
e.slideDown('400').style.display = 'block';
else
e.style.display = 'none';
}
</script>
If you really need to keep inline with the syntax you already have, try this:
$(e).slideDown('400')...
Prior to the change above, you were attempting to call a jQuery function on a standard DOM element, it has no knowledge of what slideDown is as it's not a jQuery object.
NOTE: I would have a good read of the jQuery docs if I were you. Getting the element by ID in this way presents problems already solved by the jQuery library. It seems you're not fully embracing what it's capable of.
You could, instead, have:
var e = $('#' + id);
e.slideDown(400);

Functions takes 2 clicks to show hidden div

I have a small bit of javascript for showing and hiding a div.
function hidefooter(){
var button = document.getElementById('footerbutton');
button.onclick = function() {
var div = document.getElementById('footerbox');
if (div.style.display !== 'block') {
div.style.display = 'block';
}
else {
div.style.display = 'none';
}
};
}
The div starts {display:none;}. I looked around online and could only find people saying it was an html thing. My problem with that was that when i first wrote it the "block" and "none" values were switched and it took 3 clicks to work. Any help would be great.
update: A better explanation. This code does exactly what i want but you have to click twice to get the effect to work. At first i had the "block" and "none" properties switched and it took 3 clicks to get it to work. The footer starts out {display:none;}. I put it up online so a friend could take a look at it. the url is http://www.miettegoesplaces.com. click on the purple foot button on the right.
update 2: sorted the problem was i was calling the onClick twice. this is the simplified working version.
function hideFooter(){
var div = document.getElementById('footerbox');
if (div.style.display !== 'block') {
div.style.display = 'block';
}
else {
div.style.display = 'none';
}
};
thanks for everyones comments and advice.
You have added click event twice here.
First, you are calling onClick event on button.
Inside hidefooter() function, you have defined button.onclick = function() {...}
remove button.onclick = function() {} and use like this :
function hidefooter(){
var button = document.getElementById('footerbutton');
var div = document.getElementById('footerbox');
if (div.style.display != 'block') {
div.style.display = 'block';
}
else {
div.style.display = 'none';
}
Here is the working fiddle.
you need to add "display: none" to your footer's style
You can use window.getComputedStyle(elem) for Firefox, Opera, Safari and Chrome or elem.currentStyle for IE
var button = document.getElementById('footerbutton');
button.onclick = function() {
var div = document.getElementById('footerbox');
var style = window.getComputedStyle(div);
if (style.display !== 'block') {
div.style.display = 'block';
}
else {
div.style.display = 'none';
}
};
Just remove the code that you use to define a button that handles events and add an onClick() event to your button instead
This code will work as you want it
function hidefooter(){
var div = document.getElementById('footerbox');
if (div.style.display !== 'block') {
div.style.display = 'block';
}
else {
div.style.display = 'none';
}
}
But make sure your button code looks like this:
<button id="footerbutton" onClick="hidefooter()">Hide Footer</button>
Pay attention to onClick="hidefooter()"
And make sure your div is still display:none;
I believe the problem was that you're using the 'hide' button to define what it does and THEN do the hiding work. You should add an event handler that calls the hidefooter() function instead which has nothing but the footer hiding code.

Javascript - Hide other divs when one is clicked, but no double click

I used the answer to this question for a problem I originally had:
JavaScript - Hide all other divs
It works for what I need to do, but I want to make it so that when you click on original div you used to activate the slide, it doesn't hide that displaying slide. So you don't have a double click for the current active div.
<script>
var divState = {};
function showhide(id) {
if (document.getElementById) {
var divid = document.getElementById(id);
divState[id] = (divState[id]) ? false : true;
//close others
for (var div in divState){
if (divState[div] && div != id){
document.getElementById(div).style.display = 'none';
divState[div] = false;
}
}
divid.style.display = (divid.style.display == 'block' ? 'none' : 'block');
}
}
</script>
You can check my project here, when you try to click on a character, it changes slides, but when you double click on them, it hides the slide you are looking at. I want to block the "hide" function, so if you are looking at a characters slide. You can't click their illustration again to switch it off. But if you click a different character, it will hide/switch the slides:
http://www.redvelvetevents.com/tracy/newtest_july2013.htm
Hopefully this is making sense. What do I need to add to the code above so the current div won't activate the HIDE function for that specific slide? Only when you click a different character.
Thanks!
You can change your code to this:
var divState = {};
function showhide(id) {
if (document.getElementById) {
var divid = document.getElementById(id);
divState[id] = true;//I changed this line
//close others
for (var div in divState){
if (divState[div] && div != id){
document.getElementById(div).style.display = 'none';
divState[div] = false;
}
}
divid.style.display = 'block';//I changed this line
}
}

Set focus on a div in a javascript function

So I have a javascript function that displays the div that I am hiding, I am wondering how I then setfocus on the div so it goes down right to it on the page. I say setfocus because I have tried it earlier but it didnt work. Here is the function and the idea of focusing that i have.
<script>
function toggle_travelarea(id) {
var e = document.getElementById(id);
document.getElementById("canada").style.display = 'none';
document.getElementById("asia").style.display = 'none';
document.getElementById("australia").style.display = 'none';
document.getElementById("newzealand").style.display = 'none';
document.getElementById("africa").style.display = 'none';
document.getElementById("usa").style.display = 'none';
document.getElementById("samerica").style.display = 'none';
document.getElementById("europe").style.display = 'none';
e.style.display = 'block';
document.getElementByClassName('slidedeck').focus()
}
</script>
area i want to set focus to!
<div class="slidedeck">
Actually thought this didnt work but used an href to the anchor div id and then an onclick for the function and it worked properly. Thanks for the input everyone
I'm afraid you have to do a bit with math and use scrollTo.
Here's example -> http://jsbin.com/epozur/4
Basically:
HTML
<div id="hidden">
</div>
<button id="show">show</button>
JS
var btn = document.getElementById('show'),
hidden = document.getElementById('hidden');
btn.addEventListener('click', function () {
hidden.style.display = 'block';
scrollTo(0, hidden.offsetTop);
});
That should give you idea how to go further.
mz

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