Generate Array Javascript - javascript

I want to generate an array in jQuery/JS, which contains "code"+[0-9] or [a-z].
So it will look like that.
code0, code1 ..., codeA, codeB
The only working way now is to write them manually and I am sure this is a dumb way and there is a way to generate this automatically.
If you give an answer with a reference to some article where I can learn how to do similar stuff, I would be grateful.
Thank you.

For a-z using the ASCII table and the JavaScript fromCharCode() function:
var a = [];
for(var i=97; i<=122; i++)
{
a.push("code" + String.fromCharCode(i));
}
For 0-9:
var a = [];
for(var i=0; i<=9; i++)
{
a.push("code" + i);
}

I'm using the unicode hexcode to loop through the whole symbols from 0-z:
var arr = [];
for (var i = 0x30; i < 0x7b;i++){
// skip non word characters
// without regex, faster, but not as elegant:
// if(i==0x3a){i=0x41}
// if(i==0x5b){i=0x61}
char = String.fromCharCode(i);
while(!/\w/.test(char)){char = String.fromCharCode(i++)};
// generate your code
var res = "code"+char;
// use your result
arr.push(res);
}
console.log(arr);
Here goes your example.
Docs:
Unicode Table
for loop
fromCharCode
JS Array and it's methods

you can generate array in javascript by using following code.
var arr = [];
for (var i = 0; i < 5; i++) {
arr.push("code"+ i);
}
please refer following links.
https://developer.mozilla.org/en/docs/JavaScript/Reference/Global_Objects/Array
http://www.scriptingmaster.com/javascript/JavaScript-arrays.asp

a = [];
for(i = 48; i < 91; i++) {
if (i==58) i = 65
a.push("code" + String.fromCharCode(i));
}
alert(a.join(',')) // or cou can print to console of browser: console.log(a);

Related

get all variations of a string javascript

I want to get all the variations of a certain string. This string will be broken up by dashes. And the letters can only vary within those dashes.
For instance, let's say I pass DFI3-334-FG12 then I want to get all variations of that string for instance:
FI3-334-G12
FI3-334-F12
FI3-334-FG2
FI3-334-FG1
DI3-334-G12
DI3-334-F12
DI3-334-FG2
DI3-334-FG1
DF3-334-G12
DF3-334-F12
DF3-334-FG2
DF3-334-FG1
DFI-334-G12
DFI-334-F12
DFI-334-FG2
DFI-334-FG1
Can anyone assist with this? I have attempted loops but I only get as far as breaking it up and getting different parts of it:
FI3,DI3,DF3,DFI
334
G12,F12,FG2,FG1
This is my code:
$('#filter').on('click',function() {
var input = $('#code').val();
var parts = input.split("-");
var fixed = Array();
for(var i=0;i<parts.length; i++) {
if(parts[i].length != 3) {
k = 0;
fixed[i] = new Array();
for(var c=0;c<parts[i].length;c++) {
fixed[i][k] = parts[i].replace(parts[i].charAt(c),"");
k++;
}
} else {
fixed[i] = parts[i];
}
}
var final = Array();
$.each(fixed,function(i) {
$('#code_result').append(fixed[i] + "<br>");
})
});
If you know how many segments there are (3 in this case), you can use loops to get every possible combination.
See my example here:
http://jsfiddle.net/a6647m9e/1/
for(var i=0; i<parts[0].length; ++i) {
for(var j=0; j<parts[1].length; ++j) {
for(var k=0; k<parts[2].length; ++k) {
strings.push(parts[0][i]+'-'+parts[1][j]+'-'+parts[2][k]);
}
}
}
And just so you know, you're looking at (2^parts[0].length - 1) * (2^parts[1].length - 1) * (2^parts[2].length - 1) combinations (1575 in this case), taking out the blank combinations.
Note: this is all dependent on what your definition of "all possible combinations" is.
var string= 'DFI3-334-FG12';
var parts = string.split('-');
for(var i=0;i<parts[0].length;i++)
for(var j=0;j<parts[2].length;j++){
p1 = parts[0].substring(0,i)+parts[0].substring(i+1,parts[0].length);
p2 = parts[2].substring(0,j)+parts[2].substring(j+1,parts[2].length);
console.log(p1+'-'+parts[1]+'-'+p2);
}

Javascript breaking up string and reverse it

I am trying to figure out how to break up a sting to groups of five and reverse each one individually. I want it to work for any string, (there is no delimiter for splitting)
For example, if the variable is:
Iwanttobreakthisintogroupsoffiveandreverse
I would want it to return:
tnawI erbot ihtka otnis puorg iffos dnaev rever es
How do I go about this?
var str = "Iwanttobreakthisintogroupsoffiveandreverse"
var result = [];
str.replace(/.{1,5}/g, function(m) {
result.push(m.split('').reverse().join(''));
});
result.join(' ');
// "tnawI erbot ihtka otnis puorg iffos dnaev rever es"
var input="Iwanttobreakthisintogroupsoffiveandreverse";
var matches = input.match(/.{1,5}/g);
for (i = 0; i < matches.length; ++i) {
matches[i] = matches[i].split("").reverse().join("");
}
alert(matches);
It pops up tnawI,erbot,ihtka,otnis,puorg,iffos,dnaev,rever,es
You could try this:
var chars = "Iwanttobreakthisintogroupsoffiveandreverse".split('')
var str_rev = []
for (i = 0; i < chars.length; i += 5)
str_rev.push( chars.slice(i, i + 5).reverse().join('') )
Convert to char array using split(''). This allows you to use array methods like reverse and slice
Loop through the char array taking 5 element slices
reverse the elements, join the chars to create a string, and add it to rev_str

Retrieve substring between two characters

I have string like this
var str = "#it
itA
itB
_
#et
etA
etB
_
etC
etD"
How can I retrieve elements between # and _. As of now I am splitting the text with new line but unable to workout this. Please help me on this. Please use this fiddle http://jsfiddle.net/h728C/2/
IF you simply want the FIRST string BETWEEN you can use:
var mys= str.substring(str.indexOf('#')+1,str.indexOf("_"));
this returns: "it itA itB"
I've posted some solution in fidde. It uses the Regex
var str = $('#a').text();
var pattern = /#([\s\S]*?)(?=_)/g;
var result = str.match(pattern);
for (var i = 0; i < result.length; i++) {
if (result[i].length > 1) {
result[i] = result[i].substring(1, result[i].length);
}
alert(result[i]);
}
Strip the end and beginning.
Edit
I've updated the fiddle and the code. Now it strips the beginning # and ending _.
You can use either. Whichever is convenient.
​
​
I don't really get why but this works:
var str = $('#a').text();
var results = [];
$.each(str.split("_"), function(){
var a = this.toString().split("#");
if(a.length===2) results.push(a[1]);
});
console.log(results);​
You can use this kind of regex:
str.replace(/\s/g, "").match(/#(.*?)_/g, "$1");
See this fiddle.
one line solution to get the array
var arrStr = str.split(/[#_]/);
I would not recommend using regex here as it can be done more efficiently through other methods.
function extractString(template, initChar, finalChar) {
let i = 0;
let data = [];
do {
if (template[i] == initChar) {
for (let j = i + 1; j < template.length; j++) {
if (template[j] == finalChar) {
data[data.length] = template.slice(i + 1, j);
i = j + 1;
break;
}
}
}
}
while (++i < template.length);
console.log(data)
return data;
}
extractString("#adj#, #brown# fox jumps over the lazy #dog#.","#","#");

how to make string as array in java script?

I have a string value like:
1,2,3;4,5,6;7,8,9;a,b,c;d,e,f;g,h,i
I need to convert it into array in JavaScript like
1 2 3
4 5 6
7 8 9
etc.
Can any one please suggest me a way how to do this?
You are looking for String.split. In your case, you need to split twice. Once with ; to split the string into chunks, then separately split each chunk with , to reach the array structure you are looking for.
function chunkSplit(str) {
var chunks = str.split(';'), // split str on ';'
nChunks = chunks.length,
n = 0;
for (; n < nChunks; ++n) {
chunks[n] = chunks[n].split(','); // split each chunk with ','
}
return chunks;
}
var arr = chunkSplit("1,2,3;4,5,6;7,8,9;a,b,c;d,e,f;g,h,i");
If you need a multi-dimensional array you can try :
var array = yourString.split(';');
var arrCount = array.length;
for (var i = 0; i < arrCount; i++)
{
array[i] = array[i].split(',');
}
Try the following:
var yourString = '1,2,3;4,5,6;7,8,9;a,b,c;d,e,f;g,h,i';
var array = [];
yourString.split(';').forEach(function(value) {
array.push(value.split(','));
});
jsFiddle Demo
Note: .forEach() not supported in IE <=8
The following split command should help:
yourArray = yourString.split(";");

Javascript array from string of numbers

I am trying to work with arrays in javascript. Consider the following code:
var visList = '1234,5678,9'
var visListArray = new Array(visList);
for (i = 0; i <= visListArray.length - 1; i++)
{
alert(visListArray[i]);
}
Why doesn't this split the array into individual numbers instead of all of them clumped together?
Any help would be really appreciated.
Many thanks
Create the array by calling split() on the string:
var visList = '1234,5678,9'
var visListArray = visList.split(",");
You cannot substitue a string that looks like code for actual code. While this would work:
var visListArray = new Array(1234,5678,9);
Yours doesn't because the string is not interpreted by the Array constructor as 3 comma separated arguments, it is interpreted as one string.
Edit: Note that calling split() on a string results in an Array of strings. If you want an Array of numbers, you'll need to iterate the Array converting each string to a number. One convenient way to do that is to use the map() method:
visListArray = visList.split(",").map(function (item) {
return +item;
});
See the compatibility note for using map() in older browsers.
because its an string, try this:
var visList = '1234,5678,9'
var visListArray = [].concat(visList.split(','));
for (i = 0; i <= visListArray.length - 1; i++) {
alert(visListArray[i]);
}
You have to use string.split
var visList = '1234,5678,9'
var visListArray = visList.split(",");
for (i = 0; i <= visListArray.length - 1; i++)
{
alert(visListArray[i]);
}
To convert a symbol-separated list into an array, you may use split(symbol):
var list = "1221,2323,4554,7667".split(",");
for (var i = 0, il = list.length; i < il; i++) {
alert( +list[i] ); // a casting from string to number
}

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