Develop Reference

Click function into click function

I thought that if I put one click function into click function it was only proceeding the second click function if it was clicked, but when I click the first the codes for second one is running... I thought that if i clicked the second one it should have run the codes.
I mean when I clicked the second one then the codes are visible and doing as they should do, but If click like first function 3 times without to click the second and suddenly click on the second, it is behaving like the codes have run three times.
$(".click1").click(function () {
alert("hej");
$(".click2").
function ({
alert("bye");
});
});
My intention is to only make the second click to run when it is really clicked and not run the codes if I click the first one!
To be more clear. When I click first, it says hej and if I click three time then it will say hej 3x but when I suddenly click click2 it showing bye three times but I only clicked once.
Can anyone explain me why this is happening? and How i can prevent this to happen?
Thanks for the help!
EDIT!!
function click_back() {
current_question_for_answer.splice(0,1);
$("#tillbaka_question").fadeTo("slow", 0.2);
$("#tillbaka_question").off("click");
$(".questions").hide();
$(".containing_boxes").show();
$(".answered_box").remove();
var numbers_of_answered_question = history.length - 1;
for (var i = numbers_of_answered_question; i > -1; i--) {
current_question.push(i);
$(".containing_boxes").prepend('<div class="answered_box">'+i+'</div>');
$("div.containing_boxes > div:nth-child("+history.length+")").css("background-color", "green");
$(".containing_boxes").hide();
$(".containing_boxes").fadeIn(100);
}
$("div.containing_boxes > div").not(":last-child").click(answered_box);
$("div.containing_boxes > div:nth-child("+history.length+")").click(function () {
$("div.containing_boxes > div:nth-child("+history.length+")").click(function () { }) this function should only work if I click it. I can not seperate this code in two new function. If I do it, then the whole system will stop working.....

Because you clicked on click1 3 times, the click event on click2 is 3x created. Thats why it will alert 'bye' 3 times.

You should Unbind click event before binding New click event
$(".click1").click(function () {
alert("hej");
$(".click2").unbind('click');
$(".click2").bind('click',function (){
alert("bye");
});
});
Live Demo

The first click is attaching another click handler which means the second click will fire multiple times, so every time you click it you will get a lot of "bye"s. To avoid this, you can simply set a variable like var isClicked = 0 on load, and then before attaching the handler to click2, check if isClicked == 0, if true then set isClicked = 1 so it only works once
var isClicked = 0;
$(".click1").click(function () {
alert("hej");
if ( isClicked == 0 ) {
isClicked = 1;
$(".click2").
function ({
alert("bye");
});
}
});

I think, his is what you are after:
$(".click1").click(function () { alert("hej"); });
$(".click2").click(function () { alert("bye"); });

Try this:
var click1 = false;
$(".click1").click(function () {
alert("hej");
click1 = true;
});
$(".click2").click(function() {
if (click1 === true) {
alert("bye");
click1 = false;
}
});

Every time you click 1st button, You are registering click event for the 2nd button, so if you click 1st button 5x then 2nd button click event will be registered 5x
The solution is that
You make sure that every time you click 1st button you unregister click event for 2nd button, then register it again

swapped radio overlaying each other after swapping

Something wrong with the event handler, as on mouse leave the div opens and closes 3 times.
also the radio that is swapped get over layed or offset.
I have tried everything, i think it has something to do with the way i am using the event.preventDefault();
UPDATE__
Menu opening 3x fixed, but the swapped radio in the div still overlaps any ideas?
http://www.apecharmony.co.uk
// RADIO BUTTON
$("input[name='domain_ext']").each(function () {
$("#domaindropradio1").attr('checked', 'checked');
var lbl = $(this).parent("label").text();
if ($(this).prop('checked')) {
$(this).hide();
$(this).after("<div class='radioButtonOn'>" + lbl + "</div>");
} else {
$(this).hide();
$(this).after("<div class='radioButtonOff'>" + lbl + "</div>");
}
});
$("input[type=radio]").change(function () {
$(this).siblings('.radioButtonOff').add('.radioButtonOn').toggleClass('radioButtonOff radioButtonOn');
});
// RIBBON RADIO DROPBOX
$('div.ribbonBoxarrow').click(function () {
$('.ribbonBoxarrow li').show('medium');
});
$('.ribbonBoxarrow li').mouseleave(function () {
$(this).hide('slow');
});
$("input[name='domain_ext']").parent('label').click(function () {
$('.ribbonBoxarrow li').hide('slow');
event.preventDefault();
});
//SWAP SECECTED RADIO
$("div.radiogroup2").on("click", ":radio", function () {
var l = $(this).closest('label');
var r = $('#radioselected');
r.removeAttr('id');
l.before(r.closest('label'));
$(this).attr('id', 'radioselected');
l.prependTo('.radiogroup1');
});

In response to:
the div opens and closes 3 times.
Your animations are triggering more events than you'd like. Also, your preventDefault() isn't preventing other click events from firing.
For your $("input[name='domain_ext']").parent('label') click event, try this:
$("input[name='domain_ext']").parent('label').click(function () {
$('.ribbonBoxarrow li').mouseleave();
event.stopImmediatePropagation();
});
For your second issue:
also the radio that is swapped get over layed or offset.
It looks like you're prepending radio buttons to an element with the radiogroup1 class, but you may want your radio buttons to be within the nested table element.

Solved, using tables to hold elements is what was causing the problem. If it is required then you would have to target the cell for swap.

Hiding Bootstrap Popover on Click Outside Popover

I'm trying to hide the Bootstrap Popover when the user clicks anywhere outside the popover. (I'm really not sure why the creators of Bootstrap decided not to provide this functionality.)
I found the following code on the web but I really don't understand it.
// Hide popover on click anywhere on the document except itself
$(document).click(function(e) {
// Check for click on the popup itself
$('.popover').click(function() {
return false; // Do nothing
});
// Clicking on document other than popup then hide the popup
$('.pop').popover('hide');
});
The main thing I find confusing is the line $('.popover').click(function() { return false; });. Doesn't this line add an event handler for the click event? How does that prevent the call to popover('hide') that follows from hiding the popover?
And has anyone seen a better technique?
Note: I know variations of this question has been asked here before, but the answers to those questions involve code more complex than the code above. So my question is really about the code above

I made http://jsfiddle.net/BcczZ/2/, which hopefully answers your question
Example HTML
<div class="well>
<a class="btn" data-toggle="popover" data-content="content.">Popover</a>
<a class="btn btn-danger bad">Bad button</a>
</div>
JS
var $popover = $('[data-toggle=popover]').popover();
//first event handler for bad button
$('.bad').click(function () {
alert("clicked");
});
$(document).on("click", function (e) {
var $target = $(e.target),
var isPopover = $target.is('[data-toggle=popover]'),
inPopover = $target.closest('.popover').length > 0
//Does nothing, only prints on console and wastes memory. BAD CODE, REMOVE IT
$('.bad').click(function () {
console.log('clicked');
return false;
});
//hide only if clicked on button or inside popover
if (!isPopover && !inPopover) $popover.popover('hide');
});
As I mentioned in my comment, event handlers don't get overwritten, they just stack. Since there is already an event handler on the .bad button, it will be fired, along with any other event handler
Open your console in the jsfiddle, press 5 times somewhere on the page (not the popover button) and then click bad button you should see clicked printed the same amount of times you pressed
Hope it helps
P.S:
If you think about it, you already saw this happening, especially in jQuery.
Think of all the $(document).ready(...) that exist in a page using multiple jquery plugins. That line just registers an event handler on the document's ready event

I just did a more event based solution.
var $toggle = $('.your-popover-button');
$toggle.popover();
var hidePopover = function() {
$toggle.popover('hide');
};
$toggle.on('shown', function () {
var $popover = $toggle.next();
$popover.on('mousedown', function(e) {
e.stopPropagation();
});
$toggle.on('mousedown', function(e) {
e.stopPropagation();
});
$(document).on('mousedown',hidePopover);
});
$toggle.on('hidden', function () {
$(document).off('mousedown', hidePopover);
});

short answer
insert this to bootstrap min.js
when popout onblur will hide popover
when popout more than one, older popover will be hide
$count=0;$(document).click(function(evt){if($count==0){$count++;}else{$('[data-toggle="popover"]').popover('hide');$count=0;}});$('[data-toggle="popover"]').popover();$('[data-toggle="popover"]').on('click', function(e){$('[data-toggle="popover"]').not(this).popover('hide');$count=0;});

None of the above solutions worked 100% for me because I had to click twice on another, or the same, popover to open it again. I have written the solution from scratch to be simple and effective.
$('[data-toggle="popover"]').popover({
html:true,
trigger: "manual",
animation: false
});
$(document).on('click','body',function(e){
$('[data-toggle="popover"]').each(function () {
$(this).popover('hide');
});
if (e.target.hasAttribute('data-toggle') && e.target.getAttribute('data-toggle') === 'popover') {
e.preventDefault();
$(e.target).popover('show');
}
else if (e.target.parentElement.hasAttribute('data-toggle') && e.target.parentElement.getAttribute('data-toggle') === 'popover') {
e.preventDefault();
$(e.target.parentElement).popover('show');
}
});

My solution, works 100%, for Bootstrap v3
$('html').on('click', function(e) {
if(typeof $(e.target).data('original-title') !== 'undefined'){
$('[data-original-title]').not(e.target).popover('hide');
}
if($(e.target).parents().is('[data-original-title]')){
$('[data-original-title]').not($(e.target).closest('[data-original-title]')).popover('hide');
}
if (typeof $(e.target).data('original-title') == 'undefined' &&
!$(e.target).parents().is('.popover.in') && !$(e.target).parents().is('[data-original-title]')) {
$('[data-original-title]').popover('hide');
}
});

Do not fire one event if already fired another

I have a code like this:
$('#foo').on('click', function(e) {
//do something
});
$('form input').on('change', function(e) {
//do some other things
));
First and second events do actually the same things with the same input field, but in different way. The problem is, that when I click the #foo element - form change element fires as well. I need form change to fire always when the content of input is changing, but not when #foo element is clicked.
That's the question )). How to do this?
Here is the code on jsfiddle: http://jsfiddle.net/QhXyj/1/

What happens is that onChange fires when the focus leaves the #input. In your case, this coincides with clicking on the button. Try pressing Tab, THEN clicking on the button.
To handle this particular case, one solution is to delay the call to the change event enough check if the button got clicked in the meantime. In practice 100 milisecond worked. Here's the code:
$().ready(function() {
var stopTheChangeBecauseTheButtonWasClicked = false;
$('#button').on('click', function(e) {
stopTheChangeBecauseTheButtonWasClicked = true;
$('#wtf').html("I don't need to change #input in this case");
});
$('#input').on('change', function(e) {
var self = this;
setTimeout(function doTheChange() {
if (!stopTheChangeBecauseTheButtonWasClicked) {
$(self).val($(self).val() + ' - changed!');
} else {
stopTheChangeBecauseTheButtonWasClicked = false;
}
}, 100);
});
});
And the fiddle - http://jsfiddle.net/dandv/QhXyj/11/

It's only natural that a change event on a blurred element fires before the clicked element is focused. If you don't want to use a timeout ("do something X ms after the input was changed unless in between a button was clicked", as proposed by Dan) - and timeouts are ugly - you only could go doing those actions twice. After the input is changed, save its state and do something. If then - somewhen later - the button is clicked, retrieve the saved state and do the something similar. I guess this is what you actually wanted for your UI behaviour, not all users are that fast. If one leaves the input (e.g. by pressing Tab), and then later activates the button "independently", do you really want to execute both actions?
var inputval = null, changedval = null;
$('form input').on('change', function(e) {
inputval = this.value;
// do some things with it and save them to
changedval = …
// you might use the value property of the input itself
));
$('#foo').on('click', function(e) {
// do something with inputval
});
$('form …').on('any other action') {
// you might want to invalidate the cache:
inputval = changedval;
// so that from now on a click operates with the new value
});

$(function() {
$('#button').on('click', function() {
//use text() not html() here
$('#wtf').text("I don't need to change #input in this case");
});
//fire on blur, that is when user types and presses tab
$('#input').on('blur', function() {
alert("clicked"); //this doesn't fire when you click button
$(this).val($(this).val()+' - changed!');
});
});​
Here's the Fiddle

$('form input').on('change', function(e) {
// don't do the thing if the input is #foo
if ( $(this).attrib('id') == 'foo' ) return;
//do some other things
));
UPDATE
How about this:
$().ready(function() {
$('#button').on('click', function(e) {
$('#wtf').html("I don't need to change #input in this case");
});
$('#input').on('change', function(e) {
// determine id #input is in focus
if ( ! $(this).is(":focus") ) return;
$(this).val($(this).val()+' - changed!');
});
});

Prevent 'click' event from firing multiple times + issue with fading

Morning folks. Have an issue with a simple jQuery gallery i'm making. It lets the user cycle through a collection of images via some buttons and at the same time, rotates through these images on a timer. My problem is that the user is able to click the button multiple times which queues up the fade in animation and repeats it over and over, e.g. user clicks button 5 times > same image fades in/out 5 times > gallery moves to next image.
I've tried using:
$('#homeGalleryImage li a').unbind('click');
After the click event is fired and then rebinding:
$('#homeGalleryImage li a').bind('click');
After it's done but this simply removes the click event after pressing a button once and never rebinds to it?
I've also tried disabling the button via:
$('#homeGalleryImage li a').attr('disabled', true);
To no avail... ?
There is a secondary issue where if you manage to click a button while the image is in a transition, the next image appears 'faded' as if the opacity has been lowered? Very strange... Here is the code for button clicks:
var i = 1;
var timerVal = 3000;
$(function () {
$("#homeGalleryControls li a").click(function () {
var image = $(this).data('image');
$('#galleryImage').fadeOut(0, function () {
$('#galleryImage').attr("src", image);
});
$('#galleryImage').fadeIn('slow');
$('.galleryButton').attr("src", "/Content/Images/Design/btn_default.gif");
$(this).find('img').attr("src", "/Content/Images/Design/btn_checked.gif");
i = $(this).data('index') + 1;
if (i == 4) {
i = 0;
}
timerVal = 0;
});
});
Here is the code that cycles through the images on a timer:
//Cycle through gallery images on a timer
window.setInterval(swapImage, timerVal);
function swapImage() {
$('#galleryImage').fadeOut(0, function () {
var imgArray = ["/Content/Images/Design/gallery placeholder.jpg", "/Content/Images/Design/1.jpg", "/Content/Images/Design/2.jpg", "/Content/Images/Design/3.jpg"];
var image = imgArray[i];
i++;
if (i == 4) {
i = 0;
}
$('#galleryImage').attr("src", image);
$('#galleryImage').fadeIn('slow');
});
var currentButton = $('#homeGalleryControls li a img').get(i - 1);
$('.galleryButton').attr("src", "/Content/Images/Design/btn_default.gif");
$(currentButton).attr("src", "/Content/Images/Design/btn_checked.gif");
}
I realise it might be a better idea to use a plugin but I'm very new to jQuery and I'd like to learn something rather than using some ready made code.
Any help at all, is much appreciated.
Thankyou

You could always try adding something to the element to cancel the click event?
For example
$(".element").click(function(e) {
if ( $(this).hasClass("unclickable") ) {
e.preventDefault();
} else {
$(this).addClass("unclickable");
//Your code continues here
//Remember to remove the unclickable class when you want it to run again.
}
}):
In your case you could try adding a check on the click.
$('#homeGalleryImage li a').attr('data-disabled', "disabled");
Then inside your click event
if ( $(this).attr("data-disabled" == "disabled") {
e.preventDefault();
} else {
//Ready to go here
}
Edit
Here is a working example showing the element becoming unclickable. http://jsfiddle.net/FmyFS/2/

if you want to make sure that the registered event is fired only once, you should use jQuery's one :
.one( events [, data ], handler ) Returns: jQuery
Description: Attach a handler to an event for the elements. The handler is executed at most once per element per event type.
see examples:
using jQuery: https://codepen.io/loicjaouen/pen/RwweLVx
// add an even listener that will run only once
$("#click_here_button").one("click", once_callback);
using vanilly JS: https://codepen.io/loicjaouen/pen/gOOBXYq
// add a listener that run only once
button.addEventListener('click', once_callback, {capture: true, once: true});