Develop Reference

Jquery - Windows Load how to keep longer

I have one simple questions i want to keep longer to show but what i try not working. i making something wrong probably.
My part of html
<div id="preloader">
<div id="status">
<p class="center-text">
test <br>test <img src="images/myemail.gif">
<em>test</em>
</p>
</div>
</div>
Js my part
// JavaScript Document
(function ($) {
$(window).load(function() {
$("#status").fadeOut();
$("#preloader").delay(400).fadeOut("medium");
});
}(jQuery));
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="preloader">
<div id="status">
<p class="center-text">
test<br>test<img src="images/myemail.gif">
<em>test</em>
</p>
</div>
</div>
I want to keep more longer preloader and status after load. I was settimeout or add to hide and show ready functions but nothing change it
Thank you

You used fade out for div#status, the div#preloader still there but you didn't see any after div#status fade out.
I suggest you should
$(window).load(function() {
setTimeout(function() {
//$("#status").fadeOut();
$("#preloader").fadeOut("medium");
}, 400);
});

If you want the div#preloader to remain on screen for longer, then just remove the fade out of div#status:
$(window).load(function() {
$("#preloader").delay(400).fadeOut("medium");
});

Click an Image to Reveal Content

I have searched an searched for answer to this question but can't seem to find an answer that works for me. What I'm wanting is an image that presents itself on the page as with a normal tag. I want the image to be clickable, and when it is clicked, some content will drop down below it for a description of the image, etc. Then, when the image is clicked again, it will hide the content.
My (beginner) javascript attempt looks like this:
<script type="text/javascript" src="//code.jquery.com/jquery-1.9.1.js">
$(window).load(function(){
$(".header").click(function () {
$header = $(this);
//getting the next element
$content = $header.next();
//open up the content needed - toggle the slide- if visible, slide up, if not slidedown.
$content.slideToggle(500, function () {
//execute this after slideToggle is done
//change text of header based on visibility of content div
$header.text(function () {
//change text based on condition
return $content.is(":visible") ? "Collapse" : "Expand";
});
});
The HTML is this:
<div class="container">
<div class="header"><img src="Placeholders/placeholder.jpg" width="500" height="333"></div>
<div class="content" style="display: none;">
The words should be here.
</div>
Any help would be appreciated, and I apologize if this has been answered elsewhere. I couldn't find it.

You need a separate script tag for your code. You can't reuse the one that's importing jQuery.
<script type="text/javascript" src="//code.jquery.com/jquery-1.9.1.js"></script>
<script type="text/javascript">
// Your code
</script>

Try this html:
<div class="container">
<div class="header"><img src="Placeholders/placeholder.jpg" width="500" height="333"></div>
<div class="content" style="height: 0px;overflow:hidden;">
The words should be here.
</div>
And this script:
$(document).ready(function(){
$(".header").click(function () {
if($(".content").height() === 0){
$(".content").animate({height: "20px"}, 500);
}else{
$(".content").animate({height: "0px"}, 500);
}
});
})
On jsfiddle: https://jsfiddle.net/wef1o0b5/

Trying to build a gallery, how to fade out currently displayed div and fade in the next one?

I'm currently working on a new personal portfolio site using very basic html/css/jquery code. I'm trying to build my own gallery to display my work (instead of using an already existing one like lightbox) but I've run into an annoying issue: I've tried to make the "forward-button" display the immediate following div but instead it fades in all the following divs. Here's my (condensed) code:
HTML:
<!--navigation buttons for gallery-->
<a id="back-button"><img src="image.png" /></a>
<a id="forward-button"><img src="image.png"/></a>
<!--gallery begins here-->
<div id="gallery">
<div id="first-div" class="work-display">
<img src="images/albumust-display.png" class="work-image" />
<div class="caption" id="wd1c">
<p class="caption-text">caption</p>
</div>
</div>
<div id="second-div" class="work-display">
<img src="images/ce-display.png" class="work-image" />
<div class="caption">
<p class="caption-text">caption</p>
</div>
</div>
<div id="third-div" class="work-display">
<img src="images/display.png" class="work-image" />
<div class="caption">
<p class="caption-text">caption</p>
</div>
</div>
CSS (all divs inside gallery are hidden by default):
.work-display {
display:none;
position:absolute;
}
What I'm trying to do with Jquery is that everytime someone opens a thumbnail, give the corresponding div that displays the image on full size a "true" state of "active" and then fade in, like this:
$( "#thumb-1" ).click(function(){
$( "#first-div" ).prop("active",true);
$( "#first-div" ).fadeIn();
});
all divs originally have a state of "active" = false:
$( "#gallery" ).children("div").prop("active",false);
then this is what I've tried to do with the "forward-button":
$("#forward-button").click(function () {
$("#gallery").find( $("div").prop("active",true) )
.prop("active",false)
.fadeOut()
.next().fadeIn();
$(".caption").fadeIn();
});
But then what it does is that instead of fading in only the next div, it fades all the divs that come after. what am I doing wrong?
I'm very new to Javascript/Jquery so probably this isn't the smartest way to go about this, if you have a simpler solution, do tell me.

I couldn't test it properly, because I don't have the whole code (and the images either). But this should do the trick:
$(function () {
$("#gallery div").attr("active", false);
$("#thumb-1").click(function () {
$("#first-div").attr("active", true).fadeIn();
});
$("#forward-button").click(function () {
$("#gallery div[active=true]:first")
.attr("active", false)
.fadeOut()
.next()
.attr("active", true)
.fadeIn();
});
$("#back-button").click(function () {
$("#gallery div[active=true]:first")
.attr("active", false)
.fadeOut()
.prev()
.attr("active", true)
.fadeIn();
});
});
Kind of demo: http://jsfiddle.net/W8VLh/13/

Just in case you have a reason to use 'active' properties instead of classes:
$("#forward-button").click(function () {
$("#gallery").find( "div[active='true']")
.prop("active",false)
.fadeOut()
.next().fadeIn().prop("active",true);
$(".caption").fadeIn();
});

JQuery Is not working properly on mouseenter and mouseleave

Hi I am making an effect that is when Mouse Enter in div one button shows in that div and when user mouse leave that area again button hide.
It works but the problem is that I have used div many times so I have used class for div definition.
So when Mouse enter in one div other div also affected.
Code :
jQuery:
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.10.2/jquery.min.js"></script>
<script>
$(document).ready(function(){
$("#container").mouseenter(function(){
$(":button").show();
});
$("#container").mouseleave(function(){
$(":button").hide();
});
});
</script>
jsp code :
<div id="container">
<div class="mainitemlist">
<div class="mainitemlistimage">
<a href="product?pid=3">
<img src="product_images/Tulips1760331818.jpg" height="125px" width="100px" style="border-radius:2px;">
</a>
</div>
<div class="mainitemlistname"><div align="center">Nokia Lumia 925</div></div>
<div class="mainitemlistprice"><div align="center">38000</div></div>
<div class="mainitemlistfeatures"><div align="center">null</div>
<button type="button" style="display: none;">Hide me</button></div>
</div>
<div class="mainitemlist">
<div class="mainitemlistimage">
<a href="product?pid=5">
<img src="product_images/Jellyfish456319058.jpg" height="125px" width="100px" style="border-radius:2px;">
</a>
</div>
<div class="mainitemlistname"><div align="center">HCL Me</div></div>
<div class="mainitemlistprice"><div align="center">40000</div></div>
<div class="mainitemlistfeatures"><div align="center">null</div>
<button type="button" style="display: none;">Hide me</button></div>
</div>
</div>
I have try to put Jquery on class="mainitemlist" but It's not working.
So I have added in id="container".
Anyone have idea, why it's not working ???

You can do this:
$(document).ready(function () {
$(".mainitemlist").mouseenter(function () {
$(this).find(":button").show();
}).mouseleave(function () {
$(this).find(":button").hide();
});
});
Demo: Fiddle
When you used the class mainitemlist you were not using the function scope properly using $(this) and hence it showing all the button on mouseenter, since you used the code:
$(":button").show();
UPDATE
$(document).ready(function () {
$(document).on('mouseenter', '.mainitemlist', function () {
$(this).find(":button").show();
}).on('mouseleave', '.mainitemlist', function () {
$(this).find(":button").hide();
});
});

try:
$(document).ready(function(){
$("#container").mouseenter(function(){
$("#container button").show();
});
$("#container").mouseleave(function(){
$("#container button").hide();
});
});
check out this fiddle.
b.t.w, you have 2 divs with the id of container. this is probably a mistake, and if not, it's bad practice.
hope that helps.

$("#container").mouseenter(function(){
$(this).find('#yourbutton').show();
});
$("#container").mouseleave(function(){
$(this).find('#yourbutton').hide();
});

javascript code to make a div slide down and up (show/hide)

I have a page and I have little question mark images next to sections where if the question mark image is clicked, a div right below the section will appear sliding the rest of the page down. Essentially a slide down/slide up javascript function.
Ex:
Section Title (? IMG)
<div id="section">blah blah blah</div>
<br><br>
Section Title 2 (? IMG)
<div id="section2">Blah2 blah2 blah2</div>
In my example above, the content inside div section and div section2 is hidden at first, but when the ? IMG is clicked for that section, the content will reveal itself and the rest of the page will slide down at the same time to make room for the content inside the divs. And on reverse, if the question mark image is clicked while content is shown, it will slide up and hide itself and the page below will slide up as well filling the gap.
How would I write this? I need it expandable so I can add multiple div's which can be titled accordingly and expanded individually.
Thanks

With jQuery you can do this:
HTML:
<div id="clickme">
Click here
</div>
<img id="book" src="book.png" alt="" width="100" height="123" />
Script:
$('#clickme').click(function() {
$('#book').slideDown('slow', function() {
// Animation complete.
});
});
Source: jQuery docs http://api.jquery.com/slideDown/
To include jQuery on a HTML page, you can use the following in the head:
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.9.1/jquery.min.js"></script>
You could also download it yourself at place it on the server you want.
EDIT: Full answer with ready code then....
HTML:
<h1 id="id1" class="clickme">click1</h1>
<div id="section1">blah blah blah</div>
<br><br>
<h1 id="id2" class="clickme">click2</h1>
<div id="section2">Blah2 blah2 blah2</div>
SCRIPT
$('.clickme').click(function() {
$(this).next().slideToggle('slow', function() {
// Animation complete.
});
});

Try this for instance:-
<div class="wrapper">
<div class="btn">section Title (? IMG)</div>
<div class="section">blah blah blah</div>
</div>
<div class="wrapper">
<div class="btn">section Title (? IMG)</div>
<div class="section">Blah2 blah2 blah2</div>
</div>
<script>
$(function(){
$('.btn').click(function(e){
$(this).parent().toggleClass('slideOut');
});
});
</script>
.section{
display:none;
}
.slideOut .section{
display:block;
}
.btn
{
cursor:pointer;
}