Resizing Images As Window is Resized? - javascript

Currently I have four images side by side. When the window is resized or viewed on a smaller device it does a line jump (three images and the fourth one beneath it). However what I want is for all four images to just shrink relative to the window size. To make it clear, I've included some images and my code. Here's the jsfiddle as well: http://jsfiddle.net/hxeJb/
^ That is what I currently have.
^ That is what I want to achieve.
HTML:
<div id="headerline">
<img src="http://s21.postimg.org/l6t6akypj/line.jpg"/>
</div>
<div id="menu">
<img class ="blog" src="http://s18.postimg.org/il7hbk7i1/image.png">
<img class ="music" src="http://s18.postimg.org/4st2fxgqh/image.png">
<img class ="projects" src="http://s18.postimg.org/sxtrxn115/image.png">
<img class ="bio" src="http://s18.postimg.org/5xn4lb37d/image.png">
</div>
CSS:
#headerline {
width: 100%;
overflow: hidden;
margin: -10px auto 20px auto;
}
#menu {
max-width: 700px;
text-align: center;
margin: auto;
}
#menu img {
width: 150px;
}

http://jsfiddle.net/hxeJb/2/
#menu img {
width: 20%;
}
See if this help you, just don't provide a fixed width, let image width relative to its parent width

Observing your CSS part in jsFiddle, I think assigning width in percentage rather than fixed pixels will resolve your problem.
You can try this instead of current CSS.
#menu img {
width: 31.33%;
}
Hope this might help you.

The other answers are probably all correct but you may want to add a max-width: 150px; so that hte image does not expand too big and lose quality.
#menu img {
width: 30%;
max-width: 150px;
}
Fiddle: http://jsfiddle.net/hxeJb/4/

Try with the width in percentage to set the image size as per the browser width. It's always preferable to set the width in percentage(instead of pixel) while re-sizing the element based on window re-sizing.
#menu img {
width: 25%; //give the width as per the requirement
}
Hope this will solve your problem :)

Related

how to fix the position of div to bottom right of div containing background image

I have html sturcture
<div id="bg" class="layer">
<img id="trackmap" src="images/back_2416.jpg" width="1208" height="768" class=" ui-draggable map-icon" usemap="#main-map" data-zoom-image="images/background_zoom.jpg" data-big="images/background_zoom.jpg" style="position: relative; left: -439px; top: -272.6px; margin: 0px; display: inline-block; height: 1327.2px; width: 2088px;">
<div id="nav-text">LOREM IPSUM.</div>
</div>
Jquery
var windowHeight = $("#trackmap").height();
var windowWidth = $("#trackmap").width();
var text_height=((windowHeight)-(100));
$("#nav-text").css("top",windowHeight);
Css
.layer {
position: absolute;
width: 1208px;
height: 768px;
}
#nav-text{
z-index: 200;
color: white;
position: absolute;
font-size: 10px;
margin-left: 715px;
width: 310px;
height: 10px;
position: fixed;
bottom: 5px;}
I just want to fix the nav-text to the bottom right whatsoever.. Now i problem i am facing is theres zoom function on the trackmap.. which increases the height and width of the image ..so the text comes in between of the image ..intereferring with the image.. I have tried taking the image width height using jquery ..but somehow its not working
I am not sure I am following your issue here, but it sounds like you are trying to get a div to be in the bottom-right of another div no matter what size it is. That can be done by setting the parent div position to relative which you have, and the child div position to absolute. You have that set but then override it by setting the position to fixed lower in the CSS. You will also want to set the bottom to 0 and the right to 0.
This will position the child div to the bottom right of the parent div. Then you can get rid of your jQuery. Hopefully this helps.
Ok.. I am in a hurry to catch the bus.. but here's a fiddle that illustrates the idea..
basically you will need to use the scrolltop and left parameters to do so:
$(".container").on("scroll", function() {
$(".nav-text").css("top", $(this).prop("scrollTop") + 130);
$(".nav-text").css("left", $(this).prop("scrollLeft") + 120);
});
but move the scrolls first.. sorry I need to go now..
You can achieve this by not fixing the .layer width and height, using display:inline-block; to prevent the div from filling the whole container width. At that point, the .layer size will match the image size whatever it is.
Finally you just need to set the text to absolute position and bottom and right properties too.
.parent{
display:inline-block;
position:relative;
}
.children{
position:absolute;
bottom:0;
right:0;
}
Here is the fiddle explaining
And here is the proof it works even if the image size is changed(click on the image).
Fiddle 2

Make HTML element fill rest of page

I have the following HTML.
<body>
<nav>..</nav>
<div class='container'>
<div class='row' id='header'>
...
</div>
<div class='row' id='content'>
...
</div>
</div>
</body>
My aim is to have the header remain constant height, while the content fill the rest of the page (I have a Highchart in there). I have tried to use the information here: how do I give a div a responsive height and here: http://codethatworks.blogspot.co.uk/2012/05/responsive-full-height-columns-using.html and here Make a div fill the height of the remaining screen space - but with no luck.
My basic understanding is that I set the body height to 100%, and the header height to say 25% and the content to say 75%. Is the nav confusing things here?
Please note that I am using Bootstrap 3.
It's not just the body you need to set to 100% height, it's all the parents of those two 'rows'. So in your case, html, body, .container.
html, body {
height: 100%;
}
body > .container {
height: 100%;
}
nav {
position: absolute;
top: 50px;
}
#header {
height: 25%;
background: yellow;
}
#content {
height: 75%;
background: red;
}
If you don't set your nav to be positioned absolutely, then it'll cause a scrollbar as it's pushing the content down and making the total height more than 100%.
Demo here!
You can use the viewport percentage. See this fiddle
Relevant lines:
#header
{
height: 25vh;
...
}
#content
{
height:75vh;
...
}
In this case you don't have to set the height of body, html, etc. If you want it to fill the page without padding you would add:
body
{
padding:0px;
margin:0px;
}
See support here.
See this answer for more details.
For the nav element, you either need to make this absolutely positioned as suggested in other answers or give up some percentage of the page for the nav. E.g. make content height 65vh and nav height 10vh.

Vertical middle alignment of image within div? [duplicate]

This question already has answers here:
Closed 10 years ago.
Possible Duplicate:
vertical alignment of image inside a div
OK, this what I'm trying to do :
I'm having an empty div (a box), with almost no height.
I'm making an AJAX request to load some content into it.
Before loading the content, I want to display in a typical "ajax loading" rotating gif.
I've managed to :
Center the img horizontally (by putting it inside another div with text-align:center;)
What is left :
Be able to give some height to that empty div. (easy)
Vertically align the image, so that it appears on the very center of the box. (I've got absolutely no idea how to do this. I'm currently setting an upper margin, which works for one particular box, but which wouldn't work if the box already has some different height...)
How would you go about it?? (Any possible idea is acceptable. CSS/Javascript whatever...)
http://jsfiddle.net/teresko/5mG2y/
The basic idea is the use display: table-cell; and then vertical-align: middle;
the HTML
<div class="container">
<div class="holder">
<img class="stuff" src="path/to/image.png">
</div>
</div>
the CSS:
.container{
/* the container in which image is placed */
height: 300px;
margin: 0 auto;
width: 200px;
}
.holder{
display: table-cell;
width: 100%;
vertical-align: middle;
height: inherit;
}
.stuff{
display: block;
}
This way the placement of image will not depend on dimensions of container. It also can be adjusted to be in horizontal center too. All you have to do is to add .stuff{ margin: 0 auto;}.
Don't forget that table-cell is not the correct usage. You don't want images to be trated as table cells, since table cells should only contain table data.
Just raising a caution flag. Stick to the semantics.
it's better to use the answer from that other thread.
This:
#container { position: relative; }
#container img {
position: absolute;
left: 50%;
top: 50%;
margin-top: /* -1/2 the height of the image */
margin-left: /* -1/2 the width of the image */
}
Good luck!
With jQuery
//HTML
<div><img src="loader.gif" class="loader" alt="Loader" /></div>
//JS
$.fn.centeringIn = function(){
var pere = this.parent();
(pere.css("position") == 'static') ? pere.css("position","relative"):pere.css("position");
this.css({
'position' : 'absolute',
'top' : ( pere.height() - this.height() )/2+'px',
'left' : ( pere.width() - this.width() )/2+'px'
});
}
$(document).ready( function() {
$('.loader').centeringIn();
});
Add some margin-top to the image style so that it is aligned in the middle of the div. Say your div is 50px height and your image has a height of 5px. Then make your margin-top 20px to put it in the middle.

Position badge over corner of image automatically

I have a layout where images "float" within a certain area. The layout looks like this:
The source like this:
<div class="free_tile">
<a class="img_container canonical" href="/photos/10">
<img class="canonical" src="http://s3.amazonaws.com/t4e-development/photos/1/10/andrew_burleson_10_tile.jpg?1303238025" alt="Andrew_burleson_10_tile">
<!-- EDIT: I am aware that I can put the badge here. See the edit notes and image below. -->
</a>
<div class="location">Houston</div>
<div class="taxonomy"> T6 | Conduit | Infrastructure </div>
</div>
The CSS looks like this (in SCSS):
div.free_tile { width: 176px; height: 206px; float: left; margin: 0 20px 20px 0; position: relative;
&.last { margin: 0 0 20px 0; }
a.img_container { display: block; width: 176px; height: 158px; text-align: center; line-height: 156px; margin-bottom: 10px; }
img { margin: 0; border: 1px solid $dark3; display: inline-block; vertical-align: middle; #include boxShadow;
&.canonical { border: 1px solid $transect; }
}
.location, .taxonomy { width: 176px; }
.location { font-weight: 700; }
.taxonomy { line-height: 10px; font-size: 10px; text-transform: uppercase; height: 20px; overflow: hidden; }
}
div.transect_badge { height: 20px; width: 20px; background: url('/images/transect-badge.png'); }
So, basically the images are sitting vertically-aligned middle and text-aligned center, and they have a maximum width of 176 and max height of 158, but they're cropped to maintain the original aspect ratio so the actual top corner of each image falls differently depending on which image it is.
I have a badge that I'd like to put in the top corner of certain images (when the image is "canonical"). You see the style for this above (div.transect_badge).
The problem, of course, is I don't know where the top corner of the image will be so I can't hardcode the position via CSS.
I assume that I'll need to do this via jQuery or something. So, I started with a jQuery method to automatically append the badge div to any canonical images. That works fine, but I can't figure out how to position it over the top left corner.
How can this be done? (ideally using just HTML and CSS, but realistically using JS/jQuery)
--EDIT--
Here's the problem: The image is floating inside a container, so the corner of the image might fall anywhere inside the outer limits of the container. Here's an example of what happens if I try to use position:absolute; top:0; left:0 inside the same container the image is bound by:
It took some tryouts, but here it is: the size independent image badge positioner.
HTML:
<div class="tile">
<span class="photo">
<img src="/photos/10.jpg" alt="10" /><ins></ins>
</span>
<p class="location">Houston</p>
<p class="taxonomy">T6 | Conduit | Infrastructure</p>
</div>
CSS:
.tile {
float: left;
width: 176px;
height: 206px;
margin: 0 20px 20px 0;
}
.photo {
display: block;
width: 176px;
height: 158px;
text-align: center;
line-height: 158px;
margin-bottom: 10px;
}
a {
display: inline-block;
position: relative;
line-height: 0;
}
img {
border: none;
vertical-align: middle;
}
ins {
background: url('/images/badge.png') no-repeat 0 0;
position: absolute;
left: 0;
top: 0;
width: 20px;
height: 20px;
}
Example:
In previous less successful attempts (see edit history), the problem was getting the image vertically centered ánd to get its parent the same size (in order to position the badge in the top-left of that parent). As inline element that parent doesn't care about the height of its contents and thus remains to small, but as block element it stretches to hís parent's size and thus got to high, see demonstration fiddle. The trick seems to be to give that parent a very small line-height (e.g. 0) and display it as an inline-block. That way the parent will grow according to its childs.
Tested in Opera 11, Chrome 11, IE8, IE9, FF4 and Safari 5 with all DTD's. IE7 fails, but a center-top alignment of the photo with badge at the right position isn't that bad at all. Works also for IE7 now because I deleted the spaces in the markup within the a tag. Haha, how weird!
EDIT3: This solution is very similar to my original solution. I didn't really look at your code much so I should have noticed this earlier. Your a tag is already wrapping each image so you can just add the badge in there and position it absolute. The a tag doesn't need width/height. Also you must add the badge image at the beginning of your a tag.
Demo: http://jsfiddle.net/wdm954/czxj2/1/
div.free_tile {
width: 176px;
height: 206px;
float: left;
}
a.img_container {
display: block;
margin-bottom: 10px;
}
span.transect_badge {
display:block;
position: absolute;
height: 20px;
width: 20px;
background-image: url('/images/transect-badge.png');
}
HTML...
<a class="img_container canonical" href="/photos/10">
<span class="transect_badge"></span>
<img class="canonical" src="path/to/img" />
</a>
Other solutions...
In my code I'm using SPAN tags so simulate images, but it's the same idea. The badge image, when positioned absolute, will create the desired effect.
Demo: http://jsfiddle.net/wdm954/62faE/
EDIT: In the case that you need jQuery to position. This should work (where .box is your container and .corner is the badge image)...
$('.box').each(function() {
$(this).find('.corner')
.css('margin-top', ( $(this).width() - $(this).find('.img').width() ) / 2);
$(this).find('.corner')
.css('margin-left', ( $(this).height() - $(this).find('.img').height() ) / 2);
});
EDIT2: Another solution would be to wrap each image with a new container. You would have to move the code that you use to center each image to the class of the new wrapping container.
Demo: http://jsfiddle.net/wdm954/62faE/1/
$('.img').wrap('<span class="imgwrap" />');
$('.imgwrap').prepend('<span class="badge" />');
Technically you can just add something like this to your HTML though without using jQuery to insert it.
Use an element other than <div>, e.g. <span> and put it inside your <a> element after the <img> element. Then, give the <a> element position:relative; and the <span> gets position:absolute; top:0px; left:0px;. That is, if you don't mind the badge also being part of the same link - but it's the easiest way. Also, the reason for using <span> is to keep your HTML4 valid, <div> would still be HTML5 valid, however.
I did find one solution using jQuery. I don't prefer this because it noticably impacts page loading, but it is acceptable if nothing else will work. I'm more interested in NGLN's idea which seems promising but I haven't entirely figured out yet. However, since this thread has picked up a lot of traffic I thought I'd post one solution that I came up with for future readers to consider:
Given this markup:
<div class="free_tile">
<a class="img_container canonical" href="/photos/10">
<img class="canonical" src="http://s3.amazonaws.com/t4e-development/photos/1/10/andrew_burleson_10_tile.jpg?1303238025" alt="Andrew_burleson_10_tile">
<span class="transect-badge"></span>
</a>
<div class="location">Houston</div>
<div class="taxonomy"> T6 | Conduit | Infrastructure </div>
</div>
Same CSS as in question except:
span.transect-badge { display: block; height: 20px; width: 20px; position: absolute; background: url('/images/transect-badge.png'); }
Then this jQuery solves the problem:
$(function() {
$('img.canonical').load( function() {
var position = $(this).position();
$(this).next().css({ 'top': position.top+1, 'left': position.left+1 });
});
});
Like I said, though, this incurs noticeable run-time on the client end, so I'd prefer to use a non JS solution if I can. I'll continue to leave this question open while I test out and give feedback on the other solutions offered, with hopes of finding one of them workable without JS.

CSS or JavaScript to highlight certain area of image opacity

I'm looking to do something like this but with CSS or JavaScript.
I need to highlight a certain part of an image but everything I find is how to do it in Photoshop. Can I do this with CSS or maybe JavaScript?
Am I even asking the right question?
EDIT:
Well here is a great submission but I have a follow up question:
I need this for a mobile device and portrait and landscape views as well for many devices like: iOS, iPad, Android, WebOS, Etc... So the fixed position I'm not sure will work.
Any advice?
You could use background-position with absolutely positioned divs as follows:
CSS:
.container {
position:relative;
height:455px;
width:606px;
}
.container div {
position:absolute;
background-image:url(http://www.beachphotos.cn/wp-content/uploads/2010/07/indoensianbeach.jpg);
}
.container .bg-image {
opacity:0.3;
height:455px;
width:606px;
}
.container div.highlight-region {
height:50px;
width:50px;
opacity:0;
}
.container div.highlight-region:hover {
opacity:1;
}
HTML:
<div class="container">
<div class="bg-image"></div>
<div class="highlight-region" style="top:50px;left:50px;background-position: -50px -50px;"></div>
<div class="highlight-region" style="top:150px;left:150px;background-position: -150px -150px;"></div>
</div>
Please see http://jsfiddle.net/MT4T7/ for an example
Credit to beachphotos.com for using their image.
EDIT (response to OP comment): Please also see http://jsfiddle.net/zLazD/ I turned off the hover aspect. also added some borders.
CSS changes:
.container div.highlight-region {
height:50px;
width:50px;
border: 3px solid white;
}
/* removed :hover section */
You can probably fake it, here is a sample:
http://jsfiddle.net/erick/JMBFS/3/
I covered the image with an opaque element. The color of the element is the same as the background of the image. Used z-index to put it on top.
You sure can. For example, most crop plugins provide "highlighting" as the basis of their UI. So for a complete cross-browser solution, just use an existing plugin, like Jcrop.
Of course, you might want it to be fixed, in which case you can programmatically tell the plugin which section to highlight and that the user shouldn't be able to move it, and then it will act as a highlighter, not a cropper.
These are the steps you can take to highlight a part of an image:
Access the image in JavaScript, and dynamically add another identical image immediately after it. (this could be done just in HTML, but it would change the semantics of your markup)
Position the second image over the first image
Apply a css mask on the second image so that only the "highlighted" part shows up
When the user hovers over the images' container, adjust the opacity of the first image.
I can provide more technical details on this later if need be.
What about overlaying the cropped image (with 100% opacity) on top of the whole image (with 30% opacity)?
This answer is only a proof of concept
body {
margin: 0 0 0 0;
padding: 0 0 0 0;
}
.img {
position: absolute;
top: 0;
left: 0;
}
.img-base {
opacity: 0.3;
z-index: -99;
}
.img-overlay {
opacity: 1.0;
}
.cropper{
width: 150px; /* input width and height of the box here */
height: 120px;
overflow: hidden;
position: relative;
padding: 0 0 0 0;
margin: 0 0 0 0;
left: 90px; top: 170px; /* input starting location of the box here */
}
#overlay1 {
position: absolute;
left: 0px; right: 0px;
margin-left: -90px; margin-top: -170px; /* input starting location of the box here */
}
<img src="https://images.unsplash.com/photo-1583355862089-81e9e6e50f7a?ixlib=rb-1.2.1&ixid=eyJhcHBfaWQiOjEyMDd9&auto=format&fit=crop&w=334&q=80" class="img img-base">
<div class="cropper">
<img src="https://images.unsplash.com/photo-1583355862089-81e9e6e50f7a?ixlib=rb-1.2.1&ixid=eyJhcHBfaWQiOjEyMDd9&auto=format&fit=crop&w=334&q=80" class="img img-overlay" id="overlay1">
</div>

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