I am working on a password validation script.
The following code is working fine with numbers, upper- and lower-case letters.
The only problem in .press the spacebar key, length is more than 8,
display return true.
not allowed to only special characters.
$("#password").keyup(function () {
var validated = true;
if (this.value.length < 8)
validated = false;
if (!/\d/.test(this.value))
validated = false;
if (!/[a-z]/.test(this.value))
validated = false;
if (!/[A-Z]/.test(this.value))
validated = false;
if (!/[##$%\&^\-\+=!*.?~]/.test(this.value))
validated = false;
if (/[^0-9a-zA-Z##$%^&+=!*,.?~]/.test(this.value))
validated = false;
$('#password_strength').text(validated ? "Good" : "Too Weak");
When checking for symbols in your password using regex, you'll want to escape them so they're taken as the literal character, not the regex meaning of the character. For more information, I would recommend checking out:
http://www.javascriptkit.com/javatutors/redev2.shtml
https://developer.mozilla.org/en-US/docs/JavaScript/Guide/Regular_Expressions
Related
I need to check for password by using java script regular expression. for the password check, it should have at least two digit, it can contain special character, it has letters as well.
I believe the following script should do the trick. If you're going to use this script, you'll need a button that calls the function with the inputted password as its argument. I hope this helps.
var password;
var passValid = false;
function checkPass(enteredPass) {
if(enteredPass.length >= 2) { //Makes sure that the entered password is equal to or higher than the minimum length
var numsFound = 0;
var letterFound = false;
var splitPass = enteredPass.split("");
for(i=0; i < enteredPass.length; i++) { //Checks all characters for letters and numbers
if(splitPass[i] >= 0 && splitPass[i] <= 9) {
numsFound++;
} else if(splitPass[i] >= "a" && splitPass[i] <= "z" || splitPass[i] >= "A" && splitPass[i] <= "Z") {
letterFound = true;
};
if(numsFound >= 2 && letterFound) { //Successful scenario
password = enteredPass;
console.log("the entered password is valid, updated password successfully");
return;
};
};
};
console.log("the entered password is invalid, update cancelled"); //Error scenario
};
I have framed regular expression, which should check for alphanumeric along with set of special characters and find at least 2 digits.
\(?=(?:[^0-9]*[0-9]){2,})[a-zA-Z0-9!#$*\-.\/?_&,]{1,}\
I took the help of https://regex101.com site for reference & testing.
I am using following script to validate password. Aims For validations are :
Password field should not be empty
Password Length should be between 6 and 10 characters
Password should not contain spaces and special characters
Password should be Alphanumeric.
But With following code , it passes first 3 aims but even after entering Alphanumeric text, it is till alerting:
"Password Should Contain Alphabet And Numbers Both".
Need your help
Code is :
if(document.subForm.password.value==""){
alert("Please Enter Your Desired Password....");
document.subForm.password.focus();
return false;
}
if(document.subForm.password.value.length < 6 || document.subForm.password.value.length > 10){
alert("Password Length Should Be In Between 6 And 10 Characters.");
document.subForm.password.focus();
return false;
}
var re = /^[\w\A-Z]+$/;
if(!re.test(document.subForm.password.value)) {
alert ("Your Password Has Spaces In Between The Words \n\nOr\n\nIt Contains Special Characters.\n\nThese Are Not Allowed.\n\nPlease Remove Them And Try Again.");
document.subForm.password.focus();
return false;
}
var realphanumeric = /^[a-z_A-Z_0-9]+$/;
if (!realphanumeric.test(document.subForm.password.value)){
alert("Password Should Contain Alphabet And Numbers Both");
document.subForm.password.focus();
return false;
}
Aragon0 suggested to use an open-source script from dropbox to check password strength. I recommend checking it out.
If you'd like one regular expresion to check everything:
^\w{6,10}$
Explanation:
From start (^ ) to end ($) of the string...
match only alphanumeric characters ([A-Za-z_0-9]),
with a length of 6-10 characters ({6-10})
If you want to force the user to have at least one number you can do that like this:
^(?![A-Za-z_]+$)\w{6,10}$
Your regex
/^[a-z_A-Z_0-9]+$/
doesn't do what you want. It will match the password "Test" but not "te#st".
You could use two regexes, which both need to match:
/[a-zA-Z]+/
/[0-9]+/
Btw, you should not enforce alphanumeric passwords or length constraints. You could use Dropbox's password strength script (https://github.com/dropbox/zxcvbn)
Some sample code with zxcvbn:
<script src="//cdn.jsdelivr.net/zxcvbn/1.0/zxcvbn-async.js" />
<script>
var result = zxcvbn(document.subForm.password.value);
if(result.entropy<56) // 56 is very secure, you could also lower it to 48 if you need to.
{
alert("Your password is too weak. It would be cracked " + result.crack_time_display);
return false;
}
</script>
I have got a task to restrict the input field from non English languages.Only English should be enter on the field.
MY textbox is
<input type="text"/>
The function is
$(document).on("keypress", "input[type='text'] function (event) {
return suppressNonEng(event);
});
function suppressNonEng(EventKey) {
var key = EventKey.which || EventKey.keyCode;
if (key > 128) { sefAlert("Only English is allowed"); return false; }
else { return true; }
}
Its worked in the case of Chinese,Greek and some other also.But in the case of Spanish,French, its not working because the same ASCII character is used in the English and French. Is there any solution for this problem?please help
Fiddle
Its pretty simple. You need to match every character entered with a regex that checks whether the character entered is from the English alphabet, or not.
$("#mytextbox").on("keypress", function(event) {
var englishAlphabetAndWhiteSpace = /[A-Za-z ]/g;
var key = String.fromCharCode(event.which);
if (englishAlphabetAndWhiteSpace.test(key)) {
return true;
}
alert ("this is not in English");//put any message here!!!
});
After your comments:
Every key on the keyboard has a keycode. So when you press a key like E, the computer will interpret it as a keycode (69, in this case). It's difficult to make the computer understand the difference between French E or English E.
If you dont want to alert the user, just replace the alert with return false;.
If you need to detect the browser language:
Use this:
var userLang = navigator.language || navigator.userLanguage;
alert ("The language you are using is: " + userLang);
if(userLang!=whatever-you-want){
alert("only whatever-you-want allowed!!!")
}
Check your language
You could use Regex and allow only a-zA-z without any accents or funny letters.
I am trying to validate an input for zip codes, now this zip code should work for US, CANADA, UK, all the countries but omit any special characters, so i tried, checking for invalid characters first if that passes then i check for the zip code to either be US or if not just to make sure there are valid characters and not more than 8 (space in between them is ok as long as its now US(which includes - for 5 + 4)
The problem I am having is that 11215 for example is returning as false for the valid character validation and 11215## is returning false also.
Here are my regex:
var reg1 = /^[\^$%#!#&\*:<>\?\/\\~\{\}\(\)\+|]+$/;
var reg2 = /(^\d{5}$)|(^\d{5}-\d{4}$)|(([a-z0-9]{8})*$)/
var isOk = reg1.test("11215"); // returns false!
if(isOk)
{
isOk = isOk && reg2.test("11215");
}
var isOk2 = reg1.test("11215##"); // returns false also!
if(isOk2)
{
isOk2 = isOk2 && reg2.test("11215##");
}
The test for "bad chars", reg1 will always be false unless your string is made entirely of "bad chars". I don't think this is the behaviour you wanted.
var matchBad = /[^\s\da-z\-]/i;
// Match all non-whitespace, non-digit, non-alpabet, non-hyphen
if (false === matchBad.test("11215")) { // no bad chars detected
console.log('pass!');
// continue checking validity..
} else { // bad chars detected
console.log('fail!);
}
Your first regex is testing whether the entire string has those characters. If you want containment, remove the ^ and $ denoting the beginning and ending of your regex:
var reg1 = /[\^$%#!#&\*:<>\?\/\\~\{\}\(\)\+|]/;
This may be only part of the problem but it should get you somewhere. Note I also removed the + since it really only needs to match one character to detect a bad character.
Also another note of design. Your regex that exactly matches the pattern should really be sufficient for testing this. I'm not quite familiar though with the third type of zip, but you might want to make it capture the entire string (with ^ and $)
Javascript should be like below
<script type="text/javascript">
function IsValidZipCode(zipcode) {
var isValid = /^[0-9]{5}(?:-[0-9]{4})?$/.test(zipcode);
if (!isValid){
alert('Invalid ZipCode');
document.getElementById("zipcode").value = "";
}
}
</script>
Zipcode text should be
<input id="zipcode" class="zipcode" type="text" placeholder="Your Zipcode?" name="zipcode" onchange="IsValidZipCode(this.form.zipcode.value)" required >
I would like to check if users enter correct phone number in, with help of jQuery, so far I got to this stage:
var phone = $("input#phone").val();
if (phone !== "") {
//Check if phone is numeric
$("label#phone_error").show(); //Show error
$("input#phone").focus(); //Focus on field
return false;
}
Basically it checks if phone number was entered and if it was, I would like to check if it is a numeric value and if it is not display the error messages.
Could anyone help with checking if it is numeric?
Try this ... it will make sure that the string "phone" only contains digits and will at least contain one digit
if(phone.match(/^\d+$/)) {
// your code here
}
There is a built-in function in jQuery to check this (isNumeric), so try the following:
var phone = $("input#phone").val();
if (phone !== "" && !$.isNumeric(phone)) {
//Check if phone is numeric
$("label#phone_error").show(); //Show error
$("input#phone").focus(); //Focus on field
return false;
}
You can use jQuery method to check whether a value is numeric or other type.
$.isNumeric()
Example
$.isNumeric("46")
true
$.isNumeric(46)
true
$.isNumeric("dfd")
false
I used this to check if all the text boxes had numeric values:
if(!$.isNumeric($('input:text').val())) {
alert("All the text boxes must have numeric values!");
return false;
}
or for one:
$.isNumeric($("txtBox").val());
Available with jQuery 1.7.
http://docs.jquery.com/Plugins/Validation/CustomMethods/phoneUS
Check that out. It should be just what you're looking for. A US phone validation plugin for jQuery.
If you want to do it on your own, you're going to be in for a good amount of work. Check out the isNaN() function. It tells you if it is not a number. You're also going to want to brush up on your regular expressions for validation. If you're using RegEx, you can go without isNaN(), as you'll be testing for that anyway.
I used this:
jQuery.validator.addMethod("phoneUS", function(phone_number, element) {
phone_number = phone_number.replace(/\s+/g, "");
return this.optional(element) || phone_number.length > 9 &&
phone_number.match(/^(1-?)?(\([2-9]\d{2}\)|[2-9]\d{2})-?[2-9]\d{2}-?\d{4}$/);
}, "Please specify a valid phone number");
if (!(/^[-+]?\d*\.?\d*$/.test(document.getElementById('txtRemittanceNumber').value))){
alert('Please enter only numbers into amount textbox.')
}
else
{
alert('Right Number');
}
I hope this code may help you.
in this code if condition will return true if there is any legal decimal number of any number of decimal places. and alert will come up with the message "Right Number" other wise it will show a alert popup with message "Please enter only numbers into amount textbox.".
Thanks... :)
for future visitors, you can add this functon that allow user to enter only numbers: you will only have to add jquery and the class name to the input check that into http://jsfiddle.net/celia/dvnL9has/2/
$('.phone_number').keypress(function(event){
var numero= String.fromCharCode(event.keyCode);
var myArray = ['0','1','2','3','4','5','6','7','8','9',0,1,2,3,4,5,6,7,8,9];
index = myArray.indexOf(numero);// 1
var longeur= $('.phone_number').val().length;
if(window.getSelection){
text = window.getSelection().toString();
} if(index>=0&text.length>0){
}else if(index>=0&longeur<10){
}else {return false;} });
I used this kind of validation .... checks the pasted text and if it contains alphabets, shows an error for user and then clear out the box after delay for the user to check the text and make appropriate changes.
$('#txtbox').on('paste', function (e) {
var $this = $(this);
setTimeout(function (e) {
if (($this.val()).match(/[^0-9]/g))
{
$("#errormsg").html("Only Numerical Characters allowed").show().delay(2500).fadeOut("slow");
setTimeout(function (e) {
$this.val(null);
},2500);
}
}, 5);
});
This isn't an exact answer to the question, but one other option for phone validation, is to ensure the number gets entered in the format you are expecting.
Here is a function I have worked on that when set to the onInput event, will strip any non-numerical inputs, and auto-insert dashes at the "right" spot, assuming xxx-xxx-xxxx is the desired output.
<input oninput="formatPhone()">
function formatPhone(e) {
var x = e.target.value.replace(/\D/g, '').match(/(\d{0,3})(\d{0,3})(\d{0,4})/);
e.target.value = !x[2] ? x[1] : x[1] + '-' + x[2] + (x[3] ? '-' + x[3] : '');
}