I need help finding an object in an array of jQuery selectors by attribute.
This is the code used for selection of the inputs elements in a table:
var tableInputs = $('#clienti-table input:not(#additionalAds)');
In variable tableInputs there are 13 input elements. I need to find each element by the id attribute.
Is there any way to do it?
Hope someone can help me.
Thanks in advance.
You can loop over the colleciton with .each():
tableInputs.each(function(){
var elem = this; //do something with this.
var id = elem.attr('id');
});
Or you can extract an element with a particular id, like this:
var $myElem = tableInputs.find('#myId');
... or by specifying the context in which to look for your element, like this:
var $myElem = $('#myId', tableElements);
You can use filter to get the element with a given id.
tableInputs.filter('#'+someid);// this gives you the element in the selection with id `someid`
You can use a for loop:
for (var i = 0; i < tableInputs.length; i++) {
console.log(tableInputs[i].id);
}
Try this... $('#clienti-table input:not([id='additionalAds']));
Please try using .find()
el = $('#clienti-table input:not(#additionalAds)').find('#id');
http://api.jquery.com/find/
Related
What I would like to do:
var myDIv = document.getElementById('myDivID');
myDIv.getImmediateChildren;
something like this:
var children = document.getElementById('myDivID').childNodes
Try Like this
var myDIv = document.getElementById('myDivID');
myDIv.Children;
To get all children, use :
myDiv.children
example here : https://jsfiddle.net/vgncd96t/
-
To get the first child, use :
myDiv.firstElementChild
example here : https://jsfiddle.net/vgncd96t/1/
-
To get the last child, use :
myDiv.lastElementChild
example here : https://jsfiddle.net/vgncd96t/2/
You can do something like:
var myDIv = document.getElementById('myDivID');
var children = myDiv.children;
That will get you all children of the element.
There are even more options, like if you want only the first child, you can do:
var firstChild = myDiv.firstElementChild;
document.getElementById("myDivID").children[0]
will give you the first immediate child element
I am trying to filter an array with grep to apply CSS. My code is like below.
var depos = $('.panel-default > .panel-heading');
var chkd = ['ABC','XYZ'];
var found_p = $.grep(depos, function(v) {
return jQuery.inArray(v.innerText,chkd);
});
The first issue is that found_p is not filtering the needed array values from chkd. After filtering it, how can I apply CSS? I tried like below but it fails
$(found_p[0]).css('background-color', 'red');
Can anybody help me out with this.
Assuming from your code that you're trying to find the elements that have innerText matching a value in the chkd array, you can use the filter() method. Try this:
var $depos = $('.panel-default > .panel-heading');
var chkd = ['ABC','XYZ'];
var $found_p = $depos.filter(function() {
return $.inArray($(this).text(), chkd) != -1;
});
The $found_p variable will then hold a jQuery object with all matched elements. You can apply CSS to them like this:
$found_p.css('background-color', 'red');
Example fiddle
However, I would suggest using CSS classes instead of adding inline styles as it is much better practice.
I have a form that has multiple input, select, textarea elements. With jQuery, How can I get the name attribute values of each element? I have tried the following but its not working:
var names = $('[name]');
names.each(function(){
console.log(names.attr('name'));
})
You need to use this within the each() to refer to the element within the current iteration. Your current code is attempting to get the name of a set of elements which is logically incorrect. Try this:
var names = $('[name]');
names.each(function(){
console.log($(this).attr('name'));
})
You are still using names within your each function. Try this:
var names = $('[name]');
names.each(function(index, name){
console.log($(name).attr('name'));
})
This should loop around all the required elements and output the name and value to the console.
$('input,select,textarea').each(function() {
var thisname = $(this).attr('name');
var thisval = $(this).val();
console.log('name = ' + thisname);
console.log('value = ' + thisval);
});
You can try this way too.
var $name = $("[name]");
$name.get().map(function(elem,index){
console.log($(elem).attr("name"));
});
Add a class to all the elements you wish to get the names of.
Then you get all the elements from that class and iterate them to get their names.
formElements = $('.form-element');
for(key in formElements) {
name = formElements[key].attr('name');
// do what you wish with the element's name
}
P.S. You may need to wrap formElements[key] in $(), have not tested it.
// Selects elements that have the 'name' attribute, with any value.
var htmlElements = $("[name]");
$.each(htmlElements, function(index, htmlElement){
// this function is called for each html element wich has attribute 'name'
var $element = $(htmlElement);
// Get name attribute for input, select, textarea only
if ($element.is("input") ||
$element.is("select") ||
$element.is("textarea")) {
console.log($element.attr("name"));
}
});
Give your input ID then call attr() method
$("#id").attr("name");
i'm still new in html javascript. I want to ask can i use for loop to optimize or make this dynamic
var port = [];
port[0]=$('#slcPort_0').val();
port[1]=$('#slcPort_1').val();
port[2]=$('#slcPort_2').val();
port[3]=$('#slcPort_3').val();
port[4]=$('#slcPort_4').val();
i used this code in function to retrieve data from html form
thanks
You could use:
// selects all the elements whose 'id' starts-with "slcPort_":
var port = $('[id^=slcPort_]').map(function(){
// returns the value from those elements:
return this.value;
// converts to an array:
}).get();
This isn't guaranteed to be in numerical order, though it will be in order of the appearance of those elements in the DOM.
References:
Attribute-starts-with ([attribute^=value]) selector.
get().
map().
Simply, you can do the following:
var port = Array();
for (i = 0; i < 5; i++){
port[i] = $("#slcPort_"+i).val();
}
DEMO: http://jsbin.com/yiyaruweja/1/
It might make more sense to give all those elements a class, like slcPort. Then something like
var port = [];
$.each($('.slcPort'), function(index,value) {
port[index] = $(value).val();
});
Much prettier. Plus all those elements are related anyways, so just class em up.
$.each documentation
This is the html code
<div class="extra-sub-block sub-block-experience">
<h6 style="display:inline;" id="exp-pos-0" class="extra-sub-block-head sub-block-head-experience">CEO</h6>
</div>
<div class="extra-sub-block sub-block-experience">
<h6 style="display:inline;" id="exp-pos-1" class="extra-sub-block-head sub-block-head-experience">COO</h6>
</div>
There are several such similar structures. Now I try to extract the values from each block.
var temp=document.getElementsByClassName('sub-block-experience');
var result=$(temp[0]+"#exp-pos-0");
This throws an error. I followed selecting element inside another DOM
I also tried
var temp=document.getElementsByClassName('sub-block-experience');
var result=temp[0].find('h6');
This doesn't work as well. What am I doing wrong here. Help?
For extracting the values from all blocks, you can use .map() function as follows:
var results = $('.extra-sub-block-head').map(function(){
return $(this).text();
})
Demo
side note: Since id is unique in a document, you can directly access the element using id selector like var result= $("#exp-pos-0");instead of var result=$(temp[0]+"#exp-pos-0");
Try, var result=$(temp[0]).find('h6');
Even, in the documentation link that you gave in question, it shows that you should wrap your result from document.getElementById in $() to be applied with jQuery. What it does is, that it converts the native javascript object into a jquery object.
Demo
function testIt(){
var tags, index;
tags = document.getElementsByTagName('h6');
for (index = 0; index < inputs.length; ++index) {
//do something ...
}
}
If I am correct you are trying to get ceo and coo?.If that's the case then with jquery:
var x= $('.extra-sub-block h6');
//values are
$(x[O]).html();
$(x[1]).html();
You could also use plain javascript:
var result = document.querySelectorAll('.sub-block-experience h6');
Or if you like it separate:
var temp = document.querySelectorAll('.sub-block-experience');
var result = [];
for(var i = 0, elem; elem = temp[i]; i++) {
result = result.concat(elem.querySelectorAll('h6'));
}
But be aware of the browser compatability of querySelectorAll and querySelector.