Develop Reference

How to define a line break in extendscript for Adobe Indesign

I am using extendscript to build some invoices from downloaded plaintext emails (.txt)
At points in the file there are lines of text that look like "Order Number: 123456" and then the line ends. I have a script made from parts I found on this site that finds the end of "Order Number:" in order to get a starting position of a substring. I want to use where the return key was hit to go to the next line as the second index number to finish the substring. To do this, I have another piece of script from the helpful people of this site that makes an array out of the indexes of every instance of a character. I will then use whichever array object is a higher number than the first number for the substring.
It's a bit convoluted, but I'm not great with Javascript yet, and if there is an easier way, I don't know it.
What is the character I need to use to emulate a return key in a txt file in javascript for extendscript for indesign?
Thank you.
I have tried things like \n and \r\n and ^p both with and without quotes around them but none of those seem to show up in the array when I try them.
//Load Email as String
var b = new File("~/Desktop/Test/email.txt");
b.open('r');
var str = "";
while (!b.eof)
str += b.readln();
b.close();
var orderNumberLocation = str.search("Order Number: ") + 14;
var orderNumber = str.substring(orderNumberLocation, ARRAY NUMBER GOES HERE)
var loc = orderNumberLocation.lineNumber
function indexes(source, find) {
var result = [];
for (i = 0; i < source.length; ++i) {
// If you want to search case insensitive use
// if (source.substring(i, i + find.length).toLowerCase() == find) {
if (source.substring(i, i + find.length) == find) {
result.push(i);
}
}
alert(result)
}
indexes(str, NEW PARAGRAPH CHARACTER GOES HERE)
I want all my line breaks to show up as an array of indexes in the variable "result".
Edit: My method of importing stripped all line breaks from the document. Using the code below instead works better. Now \n works.
var file = File("~/Desktop/Test/email.txt", "utf-8");
file.open("r");
var str = file.read();
file.close();

You need to use Regular Expressions. Depending on the fields do you need to search, you'l need to tweek the regular expressions, but I can give you a point. If the fields on the email are separated by new lines, something like that will work:
var str; //your string
var fields = {}
var lookFor = /(Order Number:|Adress:).*?\n/g;
str.replace(lookFor, function(match){
var order = match.split(':');
var field = order[0].replace(/\s/g, '');//remove all spaces
var value = order[1];
fields[field]= value;
})
With (Order Number:|Adress:) you are looking for the fields, you can add more fields separated the by the or character | ,inside the parenthessis. The .*?\n operators matches any character till the first break line appears. The g flag indicates that you want to look for all matches. Then you call str.replace, beacause it allows you to perfom a single task on each match. So, if the separator of the field and the value is a colon ':', then you split the match into an array of two values: ['Order number', 12345], and then, store that matches into an object. That code wil produce:
fields = {
OrderNumber: 12345,
Adresss: "my fake adress 000"
}

Please try \n and \r
Example: indexes(str, "\r");

If i've understood well, wat you need is to str.split():
function indexes(source, find) {
var order;
var result = [];
var orders = source.split('\n'); //returns an array of strings: ["order: 12345", "order:54321", ...]
for (var i = 0, l = orders.length; i < l; i++)
{
order = orders[i];
if (order.match(/find/) != null){
result.push(i)
}
}
return result;
}

JavaScript how to split a string every n characters while ignoring ANSI codes

How would you approach splitting a JavaScript string every n characters while ignoring the ansi codes? (so splitting every n + length of ansi characters contained in that string)
It is important to keep the ansi code in the final array.
I know using regex you'd write something like /.{1,3}/, but how would you ignore the ansi chars in the count?
Example:
Given \033[34mHey \033[35myou\033[0m, how would you split every 3 chars to get:
[
'\033[34mHey',
' \033[35myo',
'u\033[0m'
]

Here is a way to achieve what you need:
s = "\033[34mHey \033[35myou\033[0mfd\033[1m";
chunks = s.match(/(?:(?:\033\[[0-9;]*m)*.?){1,3}/g);
var arr = [];
[].forEach.call(chunks, function(a) {
if (!/^(?:\033\[[0-9;]*m)*$/.test(a)) {
arr.push(a);
}
});
document.getElementById("r").innerHTML = JSON.stringify(arr);
<div id="r"/>
Note that octal codes can be used directly in the regex. We filter all the empty and ANSI-color code only elements in the forEach call.

You can match ANSI color escapes as \x1B\[[\d;]*m, and only count all characters except escapes [^\x1B]
/(?:(?:\x1B\[[\d;]*m)*[^\x1B]){1,3}/g
Also, to include escapes in the end of string as part of the last token:
/(?:(?:\x1B\[[\d;]*m)*[^\x1B]){1,3}(?:(?:\x1B\[[\d;]*m)+$)?/g
Code
subject = "\033[34mHey y\033[0mou\033[0m";
pattern = /(?:(?:\x1B\[[\d;]*m)*[^\x1B]){1,3}(?:(?:\x1B\[[\d;]*m)+$)?/g;
result = subject.match(pattern);
document.write('<pre>' + JSON.stringify(result) + '</pre>');

Using String.substring for Words

I have the following example where I am putting a limit on the characters entered in the Textarea:
var tlength = $(this).val().length;
$(this).val($(this).val().substring(0, maxchars));
var tlength = $(this).val().length;
remain = maxchars - parseInt(tlength);
$('#remain').text(remain);
where maxchars is the number of characters. How can I change this example to work with words, so instead of restricting chars, I restrict to a number of words.
http://jsfiddle.net/PzESw/106/

I think you need to change one string of your code to something like this:
$(this).val($(this).val().split(' ').slice(0, maxchars).join(' '));
This code splits text in an array of words (you may need another workflow), removes extra words and joins them back

A simple way would be to converting the full String into array of words.
For example you're having a String as:
var words = "Hi, My name is Afzaal Ahmad Zeeshan.";
var arrayOfWords = words.split(" "); // split at a white space
Now, you'll have an array of words. Loop it using
for (i = 0; i < words.length; i++) {
/* write them all, or limit them in the for loop! */
}
This way, you can write the number of words in the document. Instead of characters!

Repeat a function in Javascript with .length

I have a long string.
var string = "This is a long string."
I also have a function to download the string to "path".
downloadfunction{... 'echo "'+string+'" >> '+path;}
How do I execute this function for every 2 letters of the string? Read somewhere about using ".length" but not sure how to implement it in this case. I also do not want to split the string into an array. The download function should help split the string to download 2 letters progressively.
I.e. I would like to download the string 2 letters at a time.
EDIT: To clarify, the string needs to be downloaded x characters at a time as the download would break if it exceeds that limit.

Here is an example that is commented on how to do this:
var string = 'a really really really long string \
that I want to split by two letters at a time';
// this needs to be ceiling so that it always rounds up on odd numbers
// otherwise the last letter may be left out
var iterations = Math.ceil(string.length / 2);
for (var i = 0; i < iterations; i++) {
// we are iterating over half of the length but want to go two letters at a time
var j = i*2;
// make a new string with the first letter
var letters = string[j]
// this is an if statement to check if there is a second letter
// if there is concat it to the first letter
// otherwise the last set of an odd length would concat `undefined` to it
if (string[j+1]) { letters += string[j+1]; }
// call your function here passing `letters` to it
downloadfunction{... 'echo "' + letters + '" >> '+path;}
}

count string length
divide by 2 round up or down what ever you like
then do a for loop of the amount after the devision.
Somethig like this
//Your string that is downloaded
var string = "This is a long string."
//calculate the amount of character in the string
var amount = string.length;
//divide the string by 2
var roundnr = amount/2;
for (var i=0;i<Math.round(roundnr);i++)
{
//do something here for every 2 characters in the string
}

Jquery check if special char exists in text value

i need to check if a textarea contains some special characters, so i need to count them 2 (SMS lenght).
I wrote this piece of code but seems that it doesn't find no special chars, also if write only "€€€"
Could you please help me? Also if you would to rewrite directly function, without problem. Thank tou!
var SPECIAL_CHARS = Array('€', '%');
function charUsed() {
var count = $('#text').val().length;
var chars = $('#text').val().split("");
var numberOfSpecialChars = 0;
if ($.inArray(chars, SPECIAL_CHARS) > -1) {
numberOfSpecialChars++;
}
return count + numberOfSpecialChars;
} // function

A rewrite :
var nbSpecialChars = $('#text').val().split(/[€%]/).length - 1;
The idea is to make an array of strings, using your special characters as separator :
'some € chars %' => ["some ", " chars ", ""]
and then use the length of this array to deduce the count of those chars. There are many other (faster) solutions but this one is short.

http://jsfiddle.net/KSm7J/
var chars = $('#text').val().match(/[€%]/g).length;
alert(chars);